Re: CakePHP 2.6.X Pagination Sort Errors

2015-03-21 Thread David Cole
As luck would have it, after completing more section it started functioning 
properly. Very strange that an error like this would simply disappear... I 
have noticed that by using the sort function that it does not maintain 
pretty url's. It's uses /admin/pages?sort=Page.idorder=asc

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CakePHP 2.6.X Pagination Sort Errors

2015-03-21 Thread David Cole
I am faced a new issues regarding CakePHP 2.6.X and pagination; I've never 
had this issue before and it only happens when attempting to use 
$this-Paginator-sort(...) in a view.

$this-Paginator-sort('Page.id', 'ID', array('model' = 'Page'));

$this-Paginator-sort('Page.id', 'ID');

$this-Paginator-sort('id');

I've done the normal setup of the pagination object in the controller

$this-Paginator-settings = array(
'contain' = false, 
'group' = 'Page.id', 
'order' = 'Page.name ASC', 
'limit' = 20
); 

$results = $this-Paginator-paginate('Page');

I am getting this in the view file

Warning (2): array_filter() expects parameter 1 to be array, null given [
CORE/Cake/View/Helper/PaginatorHelper.php, line 435] 

Warning (2): array_merge() [function.array-merge]: Argument #1 is not an 
array [CORE/Cake/View/Helper/PaginatorHelper.php, line 435]

Upon tracking the issue it stems from the params function on line 126 in 
the pagination helper, on line 131 it is returning null because 
request-params['paging'] is null.

if (!isset($this-request-params['paging']) || empty($this-request-params
['paging'][$model])) { return null; }

With the above explained, why is request-params['paging'] null? Shouldn't 
it be populated with information as it is in other sections? Is the sort 
function broken or am I missing something? Any help would be greatly 
appreciated.

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Pagination Sort, Resetting Data

2014-02-27 Thread Eric Chan
Hello,

I just starting baking with CakePHP and I'm slowly grasping the basics.

So far I've created a view to display all the data in table format from a 
table in the database with pagination.
There is a column in the table that contains browser information (Firefox, 
Chrome, Safari...etc).
So on the view I made some checkboxes using Form-checkbox, with each check 
box representing a browser. 
When the the submit button is pressed, the POST request is sent to the 
searchByBrowser function in the controller and 
the view is updated with the appropiate data.

Now I am adding sort() functionality using Paginator-sort() and it sorts 
by the specified column just fine.  

However, when I use the searchByBrower function to get the appropiate view 
and then try and sort the displayed data, it resets everything
to showing all the full dataset and the checkbox is no longer checked.

Is there a way to get everything to work the way it should with just 
CakePHP?

Thanks.


https://lh5.googleusercontent.com/-LCH0weRW-7I/Uw67CrrwNYI/AL0/BheSsX7F6CM/s1600/2.png

1 - Full data set view


https://lh5.googleusercontent.com/-0s4vsxnDZ_Q/Uw67Fc0t-SI/AL8/vxPjY_HSK4E/s1600/3.png

2 - Just Firefox data

https://lh3.googleusercontent.com/-yDNtPKrJf3I/Uw66_loiPYI/ALs/qUYZso_zCcg/s1600/1.png

3 - Sorted on http_method, full dataset again (instead of just firefox data)





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Re: Pagination Sort, Resetting Data

2014-02-27 Thread tfirvin

你是用 Paginator-sort() 產生的連結(我知道這裡你把它變成checkbox了),再點擊它的時候,已經不是 post request;
但取而代之是傳入 querystring 或是 named parameters,這時候你的 searchByBrowser 
應該要在接收到這些與sort有關的參數時,
最後要再指定給 $this-request-data,這樣 view 在被 rendering 的時候就會把 request data 的值填回你的 
Form 表單。



Eric Chan eric.hf.c...@gmail.com 於 2014/2/27 下午12:14 寫道:

 Hello,
 
 I just starting baking with CakePHP and I'm slowly grasping the basics.
 
 So far I've created a view to display all the data in table format from a 
 table in the database with pagination.
 There is a column in the table that contains browser information (Firefox, 
 Chrome, Safari...etc).
 So on the view I made some checkboxes using Form-checkbox, with each check 
 box representing a browser. 
 When the the submit button is pressed, the POST request is sent to the 
 searchByBrowser function in the controller and 
 the view is updated with the appropiate data.
 
 Now I am adding sort() functionality using Paginator-sort() and it sorts by 
 the specified column just fine.  
 
 However, when I use the searchByBrower function to get the appropiate view 
 and then try and sort the displayed data, it resets everything
 to showing all the full dataset and the checkbox is no longer checked.
 
 Is there a way to get everything to work the way it should with just CakePHP?
 
 Thanks.
 
 
 
 
 1 - Full data set view
 
 
 
 
 
 2 - Just Firefox data
 
 
 
 3 - Sorted on http_method, full dataset again (instead of just firefox data)
 
 
 
 
 
 
 
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Pagination-sort associated Model

2013-05-06 Thread Levavasseur Jacques
Hello,
I use cakephp 2.3.4
When I use paginator-sort on a field of model default I have no problem.
But if I want to sort on a field associated, sorting is the default.
I use the code: $this-Paginator-sort(Model.NOM','HeaderName')
when I look at $ this- params is what I get, you can see it at the attach 
file
Thank for your help

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params = array(
'plugin' = null,
'controller' = 'defaultModels',
'action' = 'index',
'named' = array(
'sort' = 'newModel.NOM',
'direction' = 'asc'
),
'pass' = array(),
'isAjax' = false,
'paging' = array(
'defaultModel' = array(
'page' = (int) 1,
'current' = (int) 15,
'count' = (int) 40,
'prevPage' = false,
'nextPage' = true,
'pageCount' = (int) 3,
'order' = array(
'defaultModel.NOM' = 'asc'
),
'limit' = (int) 15,
'options' = array(
'order' = array(
'defaultModel.NOM' = 'asc'
),
'sort' = 'newModel.NOM',
'direction' = 'asc'
),
'paramType' = 'named'
)
),
'models' = array(
'defaultModel' = array(
'plugin' = null,
'className' = 'defaultModel'
),
'newModel' = array(
'plugin' = null,
'className' = 'newModel'
)
)
)




Re: Pagination: Sort by count of related model (e.g. User - Posts)

2010-06-15 Thread dtemes
Depending on how precise your information should be you can add a
number_of_posts field to your users table and update the count
periodically, you can also keep the field updated with database
triggers, or create an action to run the update query from cakephp
admin pages on demand.

That's just another way of dealing with it.

Regards


On 13 jun, 13:11, DigitalDude e.blumsten...@googlemail.com wrote:
 Hey,

 I have a problem here and need to fix it. It's about the following
 situation:

 I have a model User that has a relation to some entrie, let's say
 Posts. I want to paginate the User-Model and add a counting of the
 user's posts to my index of Users. So I will have the following table-
 structure in my view:

 Id Name Posts Actions
 2  Ben      5       view/edit/delete
 5  Mary    8       view/edit/delete

 The first two columns are easy to sort, but HOW can I sort my
 paginated user-array by the count of the related Post-entries?

 I would really appreciate some help here, because I just cannot find a
 way to do this... :(

 Regards,

 DD

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Pagination: Sort by count of related model (e.g. User - Posts)

2010-06-13 Thread DigitalDude
Hey,

I have a problem here and need to fix it. It's about the following
situation:

I have a model User that has a relation to some entrie, let's say
Posts. I want to paginate the User-Model and add a counting of the
user's posts to my index of Users. So I will have the following table-
structure in my view:

Id Name Posts Actions
2  Ben  5   view/edit/delete
5  Mary8   view/edit/delete

The first two columns are easy to sort, but HOW can I sort my
paginated user-array by the count of the related Post-entries?

I would really appreciate some help here, because I just cannot find a
way to do this... :(

Regards,

DD

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Re: Pagination: Sort by count of related model (e.g. User - Posts)

2010-06-13 Thread calvin
Ideally, you should be able to create post_count as a virtualField and
then sort by that, by as the cookbook states, the paginator can't
order by virtualFields of associated models, so you wouldn't be able
to sort by it. But there are two simple workarounds for this:
http://book.cakephp.org/view/1608/Virtual-fields

On Jun 13, 4:11 am, DigitalDude e.blumsten...@googlemail.com wrote:
 Hey,

 I have a problem here and need to fix it. It's about the following
 situation:

 I have a model User that has a relation to some entrie, let's say
 Posts. I want to paginate the User-Model and add a counting of the
 user's posts to my index of Users. So I will have the following table-
 structure in my view:

 Id Name Posts Actions
 2  Ben      5       view/edit/delete
 5  Mary    8       view/edit/delete

 The first two columns are easy to sort, but HOW can I sort my
 paginated user-array by the count of the related Post-entries?

 I would really appreciate some help here, because I just cannot find a
 way to do this... :(

 Regards,

 DD

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their CakePHP related questions.

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Re: Pagination: Sort by count of related model (e.g. User - Posts)

2010-06-13 Thread John Andersen
Would using the belongsTo models counterCache not be a better
solution, so that it will not be necessary to perform the counting
every time the users are listed with the post count?

Mentioned in the CakePHP book at:
http://book.cakephp.org/view/1042/belongsTo

Enjoy,
   John

On Jun 13, 3:42 pm, calvin cal...@rottenrecords.com wrote:
 Ideally, you should be able to create post_count as a virtualField and
 then sort by that, by as the cookbook states, the paginator can't
 order by virtualFields of associated models, so you wouldn't be able
 to sort by it. But there are two simple workarounds for 
 this:http://book.cakephp.org/view/1608/Virtual-fields

[snip]

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Pagination Sort

2010-05-04 Thread sijo jose
Hi guys,

I have this model Structure -

Model 1 - Union

var $belongsTo = array(
'Address' = array(
'className' = 'Address',
'foreignKey' = 'address_id',
'conditions' = '',
'fields' = '',
'order' = ''
) );


Model 2 - Address

var $belongsTo = array(
'District' = array(
'className' = 'District',
'foreignKey' = 'district_id',
'conditions' = '',
'fields' = '',
'order' = ''
)
);

Model 3  District.
 with fields name and code both varchar.


Now I would like to paginate the Unions which should be ordered in ASC by
Union.Address.District.name ASC

Is that possible and if so how should i write the paginate.

Urgent help need. I am stuck here.





Regards,
-- 
Sijo Jose Chakramakkil

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Re: Pagination Sort

2010-05-04 Thread Andrei Mita
I believe paginate documentation in the book has a similar example.


On Tue, May 4, 2010 at 9:48 AM, sijo jose jose.s...@gmail.com wrote:

 Hi guys,

 I have this model Structure -

 Model 1 - Union

 var $belongsTo = array(
 'Address' = array(
  'className' = 'Address',
 'foreignKey' = 'address_id',
  'conditions' = '',
 'fields' = '',
  'order' = ''
 ) );


 Model 2 - Address

 var $belongsTo = array(
 'District' = array(
 'className' = 'District',
  'foreignKey' = 'district_id',
 'conditions' = '',
  'fields' = '',
 'order' = ''
 )
  );

 Model 3  District.
  with fields name and code both varchar.


 Now I would like to paginate the Unions which should be ordered in ASC by
 Union.Address.District.name ASC

 Is that possible and if so how should i write the paginate.

 Urgent help need. I am stuck here.





 Regards,
 --
 Sijo Jose Chakramakkil

 Check out the new CakePHP Questions site http://cakeqs.org and help others
 with their CakePHP related questions.

 You received this message because you are subscribed to the Google Groups
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Re: Pagination Sort

2010-05-04 Thread Andrei Mita
Check out the 2 links below:
http://book.cakephp.org/view/164/Pagination
http://book.cakephp.org/view/858/Using-Containable-with-pagination


On Tue, May 4, 2010 at 11:07 AM, Andrei Mita andrei.m...@gmail.com wrote:

 I believe paginate documentation in the book has a similar example.



 On Tue, May 4, 2010 at 9:48 AM, sijo jose jose.s...@gmail.com wrote:

 Hi guys,

 I have this model Structure -

 Model 1 - Union

 var $belongsTo = array(
 'Address' = array(
  'className' = 'Address',
 'foreignKey' = 'address_id',
  'conditions' = '',
 'fields' = '',
  'order' = ''
 ) );


 Model 2 - Address

 var $belongsTo = array(
 'District' = array(
 'className' = 'District',
  'foreignKey' = 'district_id',
 'conditions' = '',
  'fields' = '',
 'order' = ''
 )
  );

 Model 3  District.
  with fields name and code both varchar.


 Now I would like to paginate the Unions which should be ordered in ASC by
 Union.Address.District.name ASC

 Is that possible and if so how should i write the paginate.

 Urgent help need. I am stuck here.





 Regards,
 --
 Sijo Jose Chakramakkil

 Check out the new CakePHP Questions site http://cakeqs.org and help
 others with their CakePHP related questions.

 You received this message because you are subscribed to the Google Groups
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Re: Pagination Sort

2010-05-04 Thread sijo jose
Well thanks for the prompt reply

I have this model Structure -

Model 1 - Union

var $belongsTo = array(
'Address' = array(
'className' = 'Address',
'foreignKey' = 'address_id',
'conditions' = '',
'fields' = '',
'order' = ''
) );


Model 2 - Address

var $belongsTo = array(
'District' = array(
'className' = 'District',
'foreignKey' = 'district_id',
'conditions' = '',
'fields' = '',
'order' = ''
)
);

Model 3  District.
 with fields name and code both varchar.

Now when I paginate UNION  like this

$this-paginate = array(
'order' = array('Address.street' = 'ASC'),
);


it works fine.

What I need is the next level that is District which is related to Address,
but not to UNION

On Tue, May 4, 2010 at 1:39 PM, Andrei Mita andrei.m...@gmail.com wrote:

 Check out the 2 links below:
 http://book.cakephp.org/view/164/Pagination
 http://book.cakephp.org/view/858/Using-Containable-with-pagination



 On Tue, May 4, 2010 at 11:07 AM, Andrei Mita andrei.m...@gmail.comwrote:

 I believe paginate documentation in the book has a similar example.



 On Tue, May 4, 2010 at 9:48 AM, sijo jose jose.s...@gmail.com wrote:

 Hi guys,

 I have this model Structure -

 Model 1 - Union

 var $belongsTo = array(
 'Address' = array(
  'className' = 'Address',
 'foreignKey' = 'address_id',
  'conditions' = '',
 'fields' = '',
  'order' = ''
 ) );


 Model 2 - Address

 var $belongsTo = array(
 'District' = array(
 'className' = 'District',
  'foreignKey' = 'district_id',
 'conditions' = '',
  'fields' = '',
 'order' = ''
 )
  );

 Model 3  District.
  with fields name and code both varchar.


 Now I would like to paginate the Unions which should be ordered in ASC by
 Union.Address.District.name ASC

 Is that possible and if so how should i write the paginate.

 Urgent help need. I am stuck here.





 Regards,
 --
 Sijo Jose Chakramakkil

 Check out the new CakePHP Questions site http://cakeqs.org and help
 others with their CakePHP related questions.

 You received this message because you are subscribed to the Google Groups
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 others with their CakePHP related questions.

 You received this message because you are subscribed to the Google Groups
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-- 
Sijo Jose Chakramakkil

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Pagination sort() tweaks

2007-09-02 Thread Dave

I was curious if anyone would like to comment on these few changes
I've made to the pagination helper.

I've noticed that regardless everything is always sorted asc, which
for me didn't work as I need to be able to sort asc or desc from links
next to the field names. (EG: Name (Asc) | (Desc))

So in order to do this, I pilfered through the pagination helper and
tweaked it a little bit.

function sort($title, $key = null, $options = array()) {
$options = am(array('url' = array(), 'model' = null, 'dir' =
null), $options);
$url = $options['url'];
unset($options['url']);

if (empty($key)) {
$key = $title;
$title = Inflector::humanize(preg_replace('/_id$/', '', 
$title));
}

if (isset($options['dir'])) {
$dir = $options['dir'];
unset($options['dir']);
} elseif ($this-sortKey($options['model']) == $key  $this-
sortDir($options['model']) == 'asc') {
$dir = 'desc';
}

if (isset($options['model'])) {
$key = $options['model'].'.'.$key;
unset($options['model']);
}

$url = am(array('sort' = $key, 'direction' = $dir), $url,
array('order' = null));
return $this-link($title, $url, $options);
}

Basically just added the dir option, and the ability to append the key
with the model name sense currently in 1.2 it doesn't appear to accept
the model option. By accept I mean actually perform something, from
what I've seen prior to my changes it would sort by default.name
instead of say, state.name.

very odd considering that this should work?

?php echo $paginator-sort('blah', 'name', array('dir' = 'desc',
'model' = 'Business'));?

But apparently doesn't.

Thanks,
Dave


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