Problem using the prototype function $F()
Hi
I have this view:
?php
echo $javascript-codeBlock(
function createNewArticle(id) {
var name = $F('sectionName');
alert(name);
}
);
?
input type=text id=sectionName size=25
When I try this view with my browser I get this error:
Notice: Undefined variable: F in ..
How I can resolve this ?
Many Thanks
Marco
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Re: Problem using the prototype function $F()
On 5/7/07, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
Hi
I have this view:
?php
echo $javascript-codeBlock(
function createNewArticle(id) {
var name = $F('sectionName');
alert(name);
}
);
?
input type=text id=sectionName size=25
When I try this view with my browser I get this error:
Notice: Undefined variable: F in ..
While this is not a CakePHP-related question, first thing you should
do is make sure that Prototype is actually being loaded.
--
Chris Hartjes
My motto for 2007: Just build it, damnit!
@TheBallpark - http://www.littlehart.net/attheballpark
@TheKeyboard - http://www.littlehart.net/atthekeyboard
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Re: Problem using the prototype function $F()
Maybe php is interpreting $F as a variable, so try using single quotes
for the code block, like echo $javascript-codeBlock(' ...
$F(sectionName) ...
On May 7, 10:06 am, [EMAIL PROTECTED]
[EMAIL PROTECTED] wrote:
Hi
I have this view:
?php
echo $javascript-codeBlock(
function createNewArticle(id) {
var name = $F('sectionName');
alert(name);
}
);
?
input type=text id=sectionName size=25
When I try this view with my browser I get this error:
Notice: Undefined variable: F in ..
How I can resolve this ?
Many Thanks
Marco
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups Cake
PHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
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Re: Problem using the prototype function $F()
The problem is that Cake interprets $f like a php variable.
I must use \$f to resolve the problem
On 7 Mag, 15:40, Chris Hartjes [EMAIL PROTECTED] wrote:
On 5/7/07, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
Hi
I have this view:
?php
echo $javascript-codeBlock(
function createNewArticle(id) {
var name = $F('sectionName');
alert(name);
}
);
?
input type=text id=sectionName size=25
When I try this view with my browser I get this error:
Notice: Undefined variable: F in ..
While this is not a CakePHP-related question, first thing you should
do is make sure that Prototype is actually being loaded.
--
Chris Hartjes
My motto for 2007: Just build it, damnit!
@TheBallpark -http://www.littlehart.net/attheballpark
@TheKeyboard -http://www.littlehart.net/atthekeyboard
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups Cake
PHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
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Re: Problem using the prototype function $F()
Prototype is loaded because I use other functions and these work
correctly
I think the problem is that Cake interprets $f like a php variable
On 7 Mag, 15:40, Chris Hartjes [EMAIL PROTECTED] wrote:
On 5/7/07, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
Hi
I have this view:
?php
echo $javascript-codeBlock(
function createNewArticle(id) {
var name = $F('sectionName');
alert(name);
}
);
?
input type=text id=sectionName size=25
When I try this view with my browser I get this error:
Notice: Undefined variable: F in ..
While this is not a CakePHP-related question, first thing you should
do is make sure that Prototype is actually being loaded.
--
Chris Hartjes
My motto for 2007: Just build it, damnit!
@TheBallpark -http://www.littlehart.net/attheballpark
@TheKeyboard -http://www.littlehart.net/atthekeyboard- Nascondi testo tra
virgolette -
- Mostra testo tra virgolette -
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You received this message because you are subscribed to the Google Groups Cake
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To post to this group, send email to cake-php@googlegroups.com
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Re: Problem using the prototype function $F()
Prototype is loaded because I use other functions and these work
correctly
The problem is that Cake interprets $f like a php variable.
I must use \$f
On 7 Mag, 15:06, [EMAIL PROTECTED] [EMAIL PROTECTED]
wrote:
Hi
I have this view:
?php
echo $javascript-codeBlock(
function createNewArticle(id) {
var name = $F('sectionName');
alert(name);
}
);
?
input type=text id=sectionName size=25
When I try this view with my browser I get this error:
Notice: Undefined variable: F in ..
How I can resolve this ?
Many Thanks
Marco
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups Cake
PHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
http://groups.google.com/group/cake-php?hl=en
-~--~~~~--~~--~--~---
Re: Problem using the prototype function $F()
Yes the problem is exactly that php is interpreting $F as a variable
On 7 Mag, 16:06, bernardo [EMAIL PROTECTED] wrote:
Maybe php is interpreting $F as a variable, so try using single quotes
for the code block, like echo $javascript-codeBlock(' ...
$F(sectionName) ...
On May 7, 10:06 am, [EMAIL PROTECTED]
[EMAIL PROTECTED] wrote:
Hi
I have this view:
?php
echo $javascript-codeBlock(
function createNewArticle(id) {
var name = $F('sectionName');
alert(name);
}
);
?
input type=text id=sectionName size=25
When I try this view with my browser I get this error:
Notice: Undefined variable: F in ..
How I can resolve this ?
Many Thanks
Marco
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups Cake
PHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
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RE: Problem using the prototype function $F()
Ok, I think *WE GOT IT* :) -MI --- Remember, smart coders answer ten questions for every question they ask. So be smart, be cool, and share your knowledge. BAKE ON! blog: http://www.MarianoIglesias.com.ar -Mensaje original- De: cake-php@googlegroups.com [mailto:[EMAIL PROTECTED] En nombre de [EMAIL PROTECTED] Enviado el: Lunes, 07 de Mayo de 2007 11:21 a.m. Para: Cake PHP Asunto: Re: Problem using the prototype function $F() Yes the problem is exactly that php is interpreting $F as a variable --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Cake PHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Problem using the prototype function $F()
Yes the problem is exactly that php is interpreting $F as a variable
escape the $
var name = \$F('sectionName');
--
/**
* @author Larry E. Masters
* @var string $userName
* @param string $realName
* @returns string aka PhpNut
* @access public
*/
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