Of course!! Thanks for the help. BTW, had to change id to something
else as it was conflicting with another id.
Peter -
On Jul 20, 3:53 pm, francky06l [EMAIL PROTECTED] wrote:
renderElement('representation_type_select', array('id' = $id))
On Jul 20, 8:26 pm, peterhf [EMAIL PROTECTED] wrote:
I have an, representation_type_select.thtml, which consists of a
selectTag.
?=
$html-selectTag(
$model_name . '/type_' . $id,
array(
'option_1' = 'option_1',
.
.
.
'option_n' = 'option_nr'
),
'',
array('id' = 'type_' . $id, 'size' = '6',
'multiple' = 'multiple', 'class' = 'classname'),
null,
false,
false
);
?
This select tag is used multiple times in a form and its name needs to
be different for each use, therefore the $id variable. The
$model_name is set in the controller and appears correctly in the
rendered html. However, I have not been able successfully pass the
value of $id to the $this-renderElement('representation_type_select'). The
value of $id does
not appear as a postfix to either 'type_' in the html. I tried ?php
$id = '1'; echo $this-renderElement('representation_type_select'); ?
Thanks in advance for any suggestions.
Peter -
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