Re: Rendering an element with Jquery
The easiest way would be an AJAX action that renders the element with the given POST data. The you can just use the rendered HTML and inject it into the DOM. Kind regards Thomas Am 14.09.2011 16:55, schrieb 8vius: Hey all, got a little problem here. I wanna do something similar to what twitter does when you post a new tweet, that it automatically adds itself to the stream. I have made an element for this, the element receives my model data and sets it up properly but I'm not sure how to pass in the data from Jquery (I receive a JSON object). So what are my options here? How can I accomplish this? -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php
Re: Rendering an element with Jquery
Can you be a little more explicit? I have my ajax action set up that will return a json encoded array. How can I get the html for the element from my controller? Maybe some example code? I'm a bit of a noob with this in general. Thank you. On Sep 14, 11:05 am, Thomas Ploch profipl...@googlemail.com wrote: The easiest way would be an AJAX action that renders the element with the given POST data. The you can just use the rendered HTML and inject it into the DOM. Kind regards Thomas Am 14.09.2011 16:55, schrieb 8vius: Hey all, got a little problem here. I wanna do something similar to what twitter does when you post a new tweet, that it automatically adds itself to the stream. I have made an element for this, the element receives my model data and sets it up properly but I'm not sure how to pass in the data from Jquery (I receive a JSON object). So what are my options here? How can I accomplish this? -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php
Re: Rendering an element with Jquery
As an addition, check out http://book.cakephp.org/view/980/render Am 14.09.2011 17:14, schrieb 8vius: Can you be a little more explicit? I have my ajax action set up that will return a json encoded array. How can I get the html for the element from my controller? Maybe some example code? I'm a bit of a noob with this in general. Thank you. On Sep 14, 11:05 am, Thomas Plochprofipl...@googlemail.com wrote: The easiest way would be an AJAX action that renders the element with the given POST data. The you can just use the rendered HTML and inject it into the DOM. Kind regards Thomas Am 14.09.2011 16:55, schrieb 8vius: Hey all, got a little problem here. I wanna do something similar to what twitter does when you post a new tweet, that it automatically adds itself to the stream. I have made an element for this, the element receives my model data and sets it up properly but I'm not sure how to pass in the data from Jquery (I receive a JSON object). So what are my options here? How can I accomplish this? -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php
Re: Rendering an element with Jquery
hmmm I don't use the request handler to do my ajax requests, I just echo out the response, would that work ? doing echo $this-render()? On Sep 14, 11:36 am, Thomas Ploch profipl...@googlemail.com wrote: As an addition, check outhttp://book.cakephp.org/view/980/render Am 14.09.2011 17:14, schrieb 8vius: Can you be a little more explicit? I have my ajax action set up that will return a json encoded array. How can I get the html for the element from my controller? Maybe some example code? I'm a bit of a noob with this in general. Thank you. On Sep 14, 11:05 am, Thomas Plochprofipl...@googlemail.com wrote: The easiest way would be an AJAX action that renders the element with the given POST data. The you can just use the rendered HTML and inject it into the DOM. Kind regards Thomas Am 14.09.2011 16:55, schrieb 8vius: Hey all, got a little problem here. I wanna do something similar to what twitter does when you post a new tweet, that it automatically adds itself to the stream. I have made an element for this, the element receives my model data and sets it up properly but I'm not sure how to pass in the data from Jquery (I receive a JSON object). So what are my options here? How can I accomplish this? -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php
Re: Rendering an element with Jquery
The RequestHandler Component is not doing any requests, it just verifies that the current request indeed is an AJAX request, so you can check in an action and i.e. render an element with an AJAX layout instead of rendering the whole view. You can of course generate the HTML with javascript using the returned JSON object ( http://api.jquery.com/jQuery.template ). But in my oppinion it is way easier to do the data handling in the action, and just render the element's HTML with $this-render() and use that in the success callback of the jQuery $.post method, appending the rendered HTML into a DOM node. Am 14.09.2011 17:51, schrieb 8vius: hmmm I don't use the request handler to do my ajax requests, I just echo out the response, would that work ? doing echo $this-render()? On Sep 14, 11:36 am, Thomas Plochprofipl...@googlemail.com wrote: As an addition, check outhttp://book.cakephp.org/view/980/render Am 14.09.2011 17:14, schrieb 8vius: Can you be a little more explicit? I have my ajax action set up that will return a json encoded array. How can I get the html for the element from my controller? Maybe some example code? I'm a bit of a noob with this in general. Thank you. On Sep 14, 11:05 am, Thomas Plochprofipl...@googlemail.comwrote: The easiest way would be an AJAX action that renders the element with the given POST data. The you can just use the rendered HTML and inject it into the DOM. Kind regards Thomas Am 14.09.2011 16:55, schrieb 8vius: Hey all, got a little problem here. I wanna do something similar to what twitter does when you post a new tweet, that it automatically adds itself to the stream. I have made an element for this, the element receives my model data and sets it up properly but I'm not sure how to pass in the data from Jquery (I receive a JSON object). So what are my options here? How can I accomplish this? -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php
Re: Rendering an element with Jquery
And how can I pass an array into the view? I do it in other parts of
my code just doing $this-render('element', $data) but it's giving me
an error here
On Sep 14, 11:59 am, Thomas Ploch profipl...@googlemail.com wrote:
The RequestHandler Component is not doing any requests, it just verifies
that the current request indeed is an AJAX request, so you can check in
an action and i.e. render an element with an AJAX layout instead of
rendering the whole view. You can of course generate the HTML with
javascript using the returned JSON object
(http://api.jquery.com/jQuery.template). But in my oppinion it is way
easier to do the data handling in the action, and just render the
element's HTML with $this-render() and use that in the success callback
of the jQuery $.post method, appending the rendered HTML into a DOM node.
Am 14.09.2011 17:51, schrieb 8vius:
hmmm I don't use the request handler to do my ajax requests, I just
echo out the response, would that work ? doing echo $this-render()?
On Sep 14, 11:36 am, Thomas Plochprofipl...@googlemail.com wrote:
As an addition, check outhttp://book.cakephp.org/view/980/render
Am 14.09.2011 17:14, schrieb 8vius:
Can you be a little more explicit? I have my ajax action set up that
will return a json encoded array. How can I get the html for the
element from my controller? Maybe some example code? I'm a bit of a
noob with this in general. Thank you.
On Sep 14, 11:05 am, Thomas Plochprofipl...@googlemail.com wrote:
The easiest way would be an AJAX action that renders the element with
the given POST data. The you can just use the rendered HTML and inject
it into the DOM.
Kind regards
Thomas
Am 14.09.2011 16:55, schrieb 8vius:
Hey all, got a little problem here. I wanna do something similar to
what twitter does when you post a new tweet, that it automatically
adds itself to the stream. I have made an element for this, the
element receives my model data and sets it up properly but I'm not
sure how to pass in the data from Jquery (I receive a JSON object). So
what are my options here? How can I accomplish this?
--
Our newest site for the community: CakePHP Video Tutorials
http://tv.cakephp.org
Check out the new CakePHP Questions site http://ask.cakephp.org and help others
with their CakePHP related questions.
To unsubscribe from this group, send email to
cake-php+unsubscr...@googlegroups.com For more options, visit this group at
http://groups.google.com/group/cake-php
Re: Rendering an element with Jquery
I meant $this-element('element', $data);
On Sep 14, 12:06 pm, 8vius lmd...@gmail.com wrote:
And how can I pass an array into the view? I do it in other parts of
my code just doing $this-render('element', $data) but it's giving me
an error here
On Sep 14, 11:59 am, Thomas Ploch profipl...@googlemail.com wrote:
The RequestHandler Component is not doing any requests, it just verifies
that the current request indeed is an AJAX request, so you can check in
an action and i.e. render an element with an AJAX layout instead of
rendering the whole view. You can of course generate the HTML with
javascript using the returned JSON object
(http://api.jquery.com/jQuery.template). But in my oppinion it is way
easier to do the data handling in the action, and just render the
element's HTML with $this-render() and use that in the success callback
of the jQuery $.post method, appending the rendered HTML into a DOM node.
Am 14.09.2011 17:51, schrieb 8vius:
hmmm I don't use the request handler to do my ajax requests, I just
echo out the response, would that work ? doing echo $this-render()?
On Sep 14, 11:36 am, Thomas Plochprofipl...@googlemail.com wrote:
As an addition, check outhttp://book.cakephp.org/view/980/render
Am 14.09.2011 17:14, schrieb 8vius:
Can you be a little more explicit? I have my ajax action set up that
will return a json encoded array. How can I get the html for the
element from my controller? Maybe some example code? I'm a bit of a
noob with this in general. Thank you.
On Sep 14, 11:05 am, Thomas Plochprofipl...@googlemail.com wrote:
The easiest way would be an AJAX action that renders the element with
the given POST data. The you can just use the rendered HTML and inject
it into the DOM.
Kind regards
Thomas
Am 14.09.2011 16:55, schrieb 8vius:
Hey all, got a little problem here. I wanna do something similar to
what twitter does when you post a new tweet, that it automatically
adds itself to the stream. I have made an element for this, the
element receives my model data and sets it up properly but I'm not
sure how to pass in the data from Jquery (I receive a JSON object). So
what are my options here? How can I accomplish this?
--
Our newest site for the community: CakePHP Video Tutorials
http://tv.cakephp.org
Check out the new CakePHP Questions site http://ask.cakephp.org and help others
with their CakePHP related questions.
To unsubscribe from this group, send email to
cake-php+unsubscr...@googlegroups.com For more options, visit this group at
http://groups.google.com/group/cake-php
Re: Rendering an element with Jquery
Also, I'm testing your solution, and it is outputting the element html
data but for some reason it's outputting a bunch of other data from
the controller, like:
$___dataForView = array()
$loadHelpers= true
$cached = false
$session= SessionHelper
SessionHelper::$helpers = array
SessionHelper::$__active = true
SessionHelper::$valid = false
SessionHelper::$error = false
SessionHelper::$_userAgent = 082aaf941d57844d51008967f7e4ca5a
and it's a lot of that
On Sep 14, 12:07 pm, 8vius lmd...@gmail.com wrote:
I meant $this-element('element', $data);
On Sep 14, 12:06 pm, 8vius lmd...@gmail.com wrote:
And how can I pass an array into the view? I do it in other parts of
my code just doing $this-render('element', $data) but it's giving me
an error here
On Sep 14, 11:59 am, Thomas Ploch profipl...@googlemail.com wrote:
The RequestHandler Component is not doing any requests, it just verifies
that the current request indeed is an AJAX request, so you can check in
an action and i.e. render an element with an AJAX layout instead of
rendering the whole view. You can of course generate the HTML with
javascript using the returned JSON object
(http://api.jquery.com/jQuery.template). But in my oppinion it is way
easier to do the data handling in the action, and just render the
element's HTML with $this-render() and use that in the success callback
of the jQuery $.post method, appending the rendered HTML into a DOM node.
Am 14.09.2011 17:51, schrieb 8vius:
hmmm I don't use the request handler to do my ajax requests, I just
echo out the response, would that work ? doing echo $this-render()?
On Sep 14, 11:36 am, Thomas Plochprofipl...@googlemail.com wrote:
As an addition, check outhttp://book.cakephp.org/view/980/render
Am 14.09.2011 17:14, schrieb 8vius:
Can you be a little more explicit? I have my ajax action set up that
will return a json encoded array. How can I get the html for the
element from my controller? Maybe some example code? I'm a bit of a
noob with this in general. Thank you.
On Sep 14, 11:05 am, Thomas Plochprofipl...@googlemail.com wrote:
The easiest way would be an AJAX action that renders the element with
the given POST data. The you can just use the rendered HTML and
inject
it into the DOM.
Kind regards
Thomas
Am 14.09.2011 16:55, schrieb 8vius:
Hey all, got a little problem here. I wanna do something similar to
what twitter does when you post a new tweet, that it automatically
adds itself to the stream. I have made an element for this, the
element receives my model data and sets it up properly but I'm not
sure how to pass in the data from Jquery (I receive a JSON object).
So
what are my options here? How can I accomplish this?
--
Our newest site for the community: CakePHP Video Tutorials
http://tv.cakephp.org
Check out the new CakePHP Questions site http://ask.cakephp.org and help others
with their CakePHP related questions.
To unsubscribe from this group, send email to
cake-php+unsubscr...@googlegroups.com For more options, visit this group at
http://groups.google.com/group/cake-php
Re: Rendering an element with Jquery
erm, the same as you would set it to any other view:
?php
function action() {
[...]
// inside your action
$myArray = array('tweet' = 'feep feep feep');
// or $myArray = json_decode($yourJsonObject, true);
// Set the variable just like any other var
$this-set(compact('myArray'));
// This will render the element in '/views/elements/element.ctp' with
the data in $myArray
// So you can access $myArray in the element just like a normal
view var
$this-render('/elements/element');
}
Am 14.09.2011 18:06, schrieb 8vius:
And how can I pass an array into the view? I do it in other parts of
my code just doing $this-render('element', $data) but it's giving me
an error here
On Sep 14, 11:59 am, Thomas Plochprofipl...@googlemail.com wrote:
The RequestHandler Component is not doing any requests, it just verifies
that the current request indeed is an AJAX request, so you can check in
an action and i.e. render an element with an AJAX layout instead of
rendering the whole view. You can of course generate the HTML with
javascript using the returned JSON object
(http://api.jquery.com/jQuery.template). But in my oppinion it is way
easier to do the data handling in the action, and just render the
element's HTML with $this-render() and use that in the success callback
of the jQuery $.post method, appending the rendered HTML into a DOM node.
Am 14.09.2011 17:51, schrieb 8vius:
hmmm I don't use the request handler to do my ajax requests, I just
echo out the response, would that work ? doing echo $this-render()?
On Sep 14, 11:36 am, Thomas Plochprofipl...@googlemail.comwrote:
As an addition, check outhttp://book.cakephp.org/view/980/render
Am 14.09.2011 17:14, schrieb 8vius:
Can you be a little more explicit? I have my ajax action set up that
will return a json encoded array. How can I get the html for the
element from my controller? Maybe some example code? I'm a bit of a
noob with this in general. Thank you.
On Sep 14, 11:05 am, Thomas Plochprofipl...@googlemail.com wrote:
The easiest way would be an AJAX action that renders the element with
the given POST data. The you can just use the rendered HTML and inject
it into the DOM.
Kind regards
Thomas
Am 14.09.2011 16:55, schrieb 8vius:
Hey all, got a little problem here. I wanna do something similar to
what twitter does when you post a new tweet, that it automatically
adds itself to the stream. I have made an element for this, the
element receives my model data and sets it up properly but I'm not
sure how to pass in the data from Jquery (I receive a JSON object). So
what are my options here? How can I accomplish this?
--
Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org
Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions.
To unsubscribe from this group, send email to
cake-php+unsubscr...@googlegroups.com For more options, visit this group at
http://groups.google.com/group/cake-php
Re: Rendering an element with Jquery
Thank you very much Thomas, got the response back properly with the
html code, still getting some errors so gotta see what's wrong with
that.
On Sep 14, 12:14 pm, Thomas Ploch profipl...@googlemail.com wrote:
erm, the same as you would set it to any other view:
?php
function action() {
[...]
// inside your action
$myArray = array('tweet' = 'feep feep feep');
// or $myArray = json_decode($yourJsonObject, true);
// Set the variable just like any other var
$this-set(compact('myArray'));
// This will render the element in '/views/elements/element.ctp' with
the data in $myArray
// So you can access $myArray in the element just like a normal
view var
$this-render('/elements/element');
}
Am 14.09.2011 18:06, schrieb 8vius:
And how can I pass an array into the view? I do it in other parts of
my code just doing $this-render('element', $data) but it's giving me
an error here
On Sep 14, 11:59 am, Thomas Plochprofipl...@googlemail.com wrote:
The RequestHandler Component is not doing any requests, it just verifies
that the current request indeed is an AJAX request, so you can check in
an action and i.e. render an element with an AJAX layout instead of
rendering the whole view. You can of course generate the HTML with
javascript using the returned JSON object
(http://api.jquery.com/jQuery.template). But in my oppinion it is way
easier to do the data handling in the action, and just render the
element's HTML with $this-render() and use that in the success callback
of the jQuery $.post method, appending the rendered HTML into a DOM node.
Am 14.09.2011 17:51, schrieb 8vius:
hmmm I don't use the request handler to do my ajax requests, I just
echo out the response, would that work ? doing echo $this-render()?
On Sep 14, 11:36 am, Thomas Plochprofipl...@googlemail.com wrote:
As an addition, check outhttp://book.cakephp.org/view/980/render
Am 14.09.2011 17:14, schrieb 8vius:
Can you be a little more explicit? I have my ajax action set up that
will return a json encoded array. How can I get the html for the
element from my controller? Maybe some example code? I'm a bit of a
noob with this in general. Thank you.
On Sep 14, 11:05 am, Thomas Plochprofipl...@googlemail.com wrote:
The easiest way would be an AJAX action that renders the element with
the given POST data. The you can just use the rendered HTML and inject
it into the DOM.
Kind regards
Thomas
Am 14.09.2011 16:55, schrieb 8vius:
Hey all, got a little problem here. I wanna do something similar to
what twitter does when you post a new tweet, that it automatically
adds itself to the stream. I have made an element for this, the
element receives my model data and sets it up properly but I'm not
sure how to pass in the data from Jquery (I receive a JSON object). So
what are my options here? How can I accomplish this?
--
Our newest site for the community: CakePHP Video Tutorials
http://tv.cakephp.org
Check out the new CakePHP Questions site http://ask.cakephp.org and help others
with their CakePHP related questions.
To unsubscribe from this group, send email to
cake-php+unsubscr...@googlegroups.com For more options, visit this group at
http://groups.google.com/group/cake-php
