Re: populate form contents ajax
Which version are you using ? Strange syntax for the url in your $ajax-
submit (should be /Controller/method) .
On Jun 18, 8:22 pm, varunkrish [EMAIL PROTECTED] wrote:
Thanks for the quick reply
I have a text box which contains the post id and a edit form in the
div id=edit below
?php echo $ajax-form(array('action'=$html-url('ajaxedit/')))?
?php echo $html-input('Post/id') ?
?php echo $ajax-submit('Load Phone', array('url' =
'ajaxedit/','update'='ajaxpost'))?
div id=ajaxpost
?php echo $html-input('Post/name', array('size' = '20'))?
/div
In Controller i Have the ajaxedit method
function ajaxedit($id=null){
if(!empty($this-data)){
$this-Post-id = $id;
$this-data = $this-Post-read();
print_r($Post);
$this-layout = ajax;
}
}
But i get only the id in the view after ajax update. Name is empty ?
why ?
thanks,
Varun
On Jun 17, 3:39 am, francky06l [EMAIL PROTECTED] wrote:
One more thing, with ajax you very often need to set the parameter
update of link, submit, remote_function etc ... This update whould
match the div you will update into the view. Your rendering view
would be enclosed into $ajax-div('updatedivname') / $ajax-
divEnd(...)
On Jun 17, 12:35 am, francky06l [EMAIL PROTECTED] wrote:
for the controller aspect it does not change anything posting data
using ajax or not. The data posted are accessible in the same way
($this-params['data']['Controller'] .. for example).
The same approach for the rendering. Now everything resides into which
parts of the view you update with you ajax call (basically doing ajax
will not affect your controller code). The difference wiht ajax
resides into the view (thtml ot tcp).
On Jun 16, 8:47 pm, varunkrish [EMAIL PROTECTED] wrote:
?php echo $ajax-form(array('action'=$html-url('edit')))?
div id=editAll style=display:noneLoading..?php echo
$html-image('spinner.gif',array('alt'='Saving..','id'='editAllimg'))?
/div
?php print $ajax-submit('Load Post', array('url' =
'editAll/','update'='posts','frequency'='2','loading'=Element.show('editAll');,'loaded'=Element.hide('editAll');));?
I have a view for add post , but i have text input for edit post . if
i type a post id in the edit post and give read.. the form contents
should be populated via ajax ?
my doubt is i know how to save data (add or edit) via ajax by sending
data to the controller
but how to get back data from the controller and populate form
contents ?
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Re: populate form contents ajax
for the controller aspect it does not change anything posting data
using ajax or not. The data posted are accessible in the same way
($this-params['data']['Controller'] .. for example).
The same approach for the rendering. Now everything resides into which
parts of the view you update with you ajax call (basically doing ajax
will not affect your controller code). The difference wiht ajax
resides into the view (thtml ot tcp).
On Jun 16, 8:47 pm, varunkrish [EMAIL PROTECTED] wrote:
?php echo $ajax-form(array('action'=$html-url('edit')))?
div id=editAll style=display:noneLoading..?php echo
$html-image('spinner.gif',array('alt'='Saving..','id'='editAllimg'))?
/div
?php print $ajax-submit('Load Post', array('url' =
'editAll/','update'='posts','frequency'='2','loading'=Element.show('editAll');,'loaded'=Element.hide('editAll');));?
I have a view for add post , but i have text input for edit post . if
i type a post id in the edit post and give read.. the form contents
should be populated via ajax ?
my doubt is i know how to save data (add or edit) via ajax by sending
data to the controller
but how to get back data from the controller and populate form
contents ?
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups Cake
PHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
http://groups.google.com/group/cake-php?hl=en
-~--~~~~--~~--~--~---
Re: populate form contents ajax
One more thing, with ajax you very often need to set the parameter
update of link, submit, remote_function etc ... This update whould
match the div you will update into the view. Your rendering view
would be enclosed into $ajax-div('updatedivname') / $ajax-
divEnd(...)
On Jun 17, 12:35 am, francky06l [EMAIL PROTECTED] wrote:
for the controller aspect it does not change anything posting data
using ajax or not. The data posted are accessible in the same way
($this-params['data']['Controller'] .. for example).
The same approach for the rendering. Now everything resides into which
parts of the view you update with you ajax call (basically doing ajax
will not affect your controller code). The difference wiht ajax
resides into the view (thtml ot tcp).
On Jun 16, 8:47 pm, varunkrish [EMAIL PROTECTED] wrote:
?php echo $ajax-form(array('action'=$html-url('edit')))?
div id=editAll style=display:noneLoading..?php echo
$html-image('spinner.gif',array('alt'='Saving..','id'='editAllimg'))?
/div
?php print $ajax-submit('Load Post', array('url' =
'editAll/','update'='posts','frequency'='2','loading'=Element.show('editAll');,'loaded'=Element.hide('editAll');));?
I have a view for add post , but i have text input for edit post . if
i type a post id in the edit post and give read.. the form contents
should be populated via ajax ?
my doubt is i know how to save data (add or edit) via ajax by sending
data to the controller
but how to get back data from the controller and populate form
contents ?
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups Cake
PHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
http://groups.google.com/group/cake-php?hl=en
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