Re: Trying to map findAll to $form->select()
> find('list')
Works like magic! Thank you Chris!
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Re: Trying to map findAll to $form->select()
On Tue, Jul 15, 2008 at 10:39 AM, Igor <[EMAIL PROTECTED]> wrote:
> Is it possible to map this array in such a way so the output looks
> something like the example below? Or is it a matter of passing right
> query to findAll() to produce a asimpler array?
>
>
> Stage 2
> Stage 3
>
>
$this->Stage->find('list') should generate an array that you can pass
to form->select()
--
Chris Hartjes
Motto for 2008: "Moving from herding elephants to handling snakes..."
@TheKeyBoard: http://www.littlehart.net/atthekeyboard
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Trying to map findAll to $form->select()
Could anyone point me in the right direction with this one please?
I'm trying to pass some values to my view...
$stages = $this->Stage->findAll(
null, array('id', 'name'), null, null
);
$this->set('stages', $stages);
... this is what's being passed...
Array
(
[0] => Array
(
[Stage] => Array
(
[id] => 2
[name] => Stage 2
)
)
[1] => Array
(
[Stage] => Array
(
[id] => 3
[name] => Stage 3
)
)
)
Unfortunately $form->select('stageID', $stages, null, array(),
'Stage'); outputs some strangeness.
Is it possible to map this array in such a way so the output looks
something like the example below? Or is it a matter of passing right
query to findAll() to produce a asimpler array?
Stage 2
Stage 3
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