Re: Using Javascript-link Inside An Element

2010-06-08 Thread Dima
My original implementation did exactly what you describe but I was
hoping that it could be done otherwise.  Guess not.

Thanks,
Dima

On Jun 7, 8:12 pm, calvin cal...@rottenrecords.com wrote:
 You only use echo when you're linking them inline. So you would never
 have something like:

 echo $javascript-link($scriptname, false);

 It would either be:

 echo $javascript-link($scriptname);

 or:

 $javascript-link($scriptname, false);

 Unfortunately, you can't use the $scripts_for_layout variable in the
 layout or elements included from the layout because usually by that
 point the variable has already been printed out.

 Your best bet would be to just place inline link calls in the header
 section of the layout.

Check out the new CakePHP Questions site http://cakeqs.org and help others with 
their CakePHP related questions.

You received this message because you are subscribed to the Google Groups 
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to
cake-php+unsubscr...@googlegroups.com For more options, visit this group at 
http://groups.google.com/group/cake-php?hl=en


Re: Using Javascript-link Inside An Element

2010-06-08 Thread calvin
I know, it sucks. I think I did manage to achieve a similar result in
a very roundabout way in one of my older applications, but it's not
really worth the hassle; Cake just isn't set up for it.

On Jun 8, 7:15 am, Dima dmitriy.pind...@gmail.com wrote:
 My original implementation did exactly what you describe but I was
 hoping that it could be done otherwise.  Guess not.

 Thanks,
 Dima

 On Jun 7, 8:12 pm, calvin cal...@rottenrecords.com wrote:

  You only use echo when you're linking them inline. So you would never
  have something like:

  echo $javascript-link($scriptname, false);

  It would either be:

  echo $javascript-link($scriptname);

  or:

  $javascript-link($scriptname, false);

  Unfortunately, you can't use the $scripts_for_layout variable in the
  layout or elements included from the layout because usually by that
  point the variable has already been printed out.

  Your best bet would be to just place inline link calls in the header
  section of the layout.

Check out the new CakePHP Questions site http://cakeqs.org and help others with 
their CakePHP related questions.

You received this message because you are subscribed to the Google Groups 
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to
cake-php+unsubscr...@googlegroups.com For more options, visit this group at 
http://groups.google.com/group/cake-php?hl=en


Using Javascript-link Inside An Element

2010-06-07 Thread Dima
I'm pretty new to CakePHP so it is likely that my issue is rather
simple to fix.  I have a custom element which I created called
nav_menu.cpt.  I call this element from default.cpt using:

?php echo $this-element('nav_menu'); ?

For my element to work properly, I need to import 3x .js files and
1x .css file; I have placed these files in /webroot/js/ and /webroot/
css/ respectively and am attempting to call them inside the element
like so:

?php
$javascript-link('mootools-for-dropdown', false);
$javascript-link('UvumiDropdown-compressed', false);
$javascript-link('nav_menu', false);
$html-css('uvumi-dropdown');
?

However, when the page loads and I check page source, it doesn't
include these files in the header.  I've also tried calling this
following line in default.cpt with no success:

?php e($scripts_for_layout); ?

What am I doing wrong??

Thanks,
Dima

Check out the new CakePHP Questions site http://cakeqs.org and help others with 
their CakePHP related questions.

You received this message because you are subscribed to the Google Groups 
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to
cake-php+unsubscr...@googlegroups.com For more options, visit this group at 
http://groups.google.com/group/cake-php?hl=en


Re: Using Javascript-link Inside An Element

2010-06-07 Thread vekija
you have to echo those :)

echo $javascript-link('mootools-for-dropdown', false);

On Jun 7, 8:43 pm, Dima dmitriy.pind...@gmail.com wrote:
 I'm pretty new to CakePHP so it is likely that my issue is rather
 simple to fix.  I have a custom element which I created called
 nav_menu.cpt.  I call this element from default.cpt using:

 ?php echo $this-element('nav_menu'); ?

 For my element to work properly, I need to import 3x .js files and
 1x .css file; I have placed these files in /webroot/js/ and /webroot/
 css/ respectively and am attempting to call them inside the element
 like so:

 ?php
         $javascript-link('mootools-for-dropdown', false);
         $javascript-link('UvumiDropdown-compressed', false);
         $javascript-link('nav_menu', false);
         $html-css('uvumi-dropdown');
 ?

 However, when the page loads and I check page source, it doesn't
 include these files in the header.  I've also tried calling this
 following line in default.cpt with no success:

 ?php e($scripts_for_layout); ?

 What am I doing wrong??

 Thanks,
 Dima

Check out the new CakePHP Questions site http://cakeqs.org and help others with 
their CakePHP related questions.

You received this message because you are subscribed to the Google Groups 
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to
cake-php+unsubscr...@googlegroups.com For more options, visit this group at 
http://groups.google.com/group/cake-php?hl=en


Re: Using Javascript-link Inside An Element

2010-06-07 Thread Dima
vekija, thanks a ton for your help!!  I added echo in front of all 4
of the lines in nav_menu.cpt.  I was immediately able to see the style
sheets kick in; however, when I look at page source, it still doesn't
show those files in the page header and is not displaying correctly.
Am I using the ?php e($scripts_for_layout); ? correctly?  Does it
have to go before/after a certain point in the header?

Thanks again,
Dima

On Jun 7, 4:10 pm, vekija vedran.konto...@gmail.com wrote:
 you have to echo those :)

 echo $javascript-link('mootools-for-dropdown', false);

 On Jun 7, 8:43 pm, Dima dmitriy.pind...@gmail.com wrote:

  I'm pretty new to CakePHP so it is likely that my issue is rather
  simple to fix.  I have a custom element which I created called
  nav_menu.cpt.  I call this element from default.cpt using:

  ?php echo $this-element('nav_menu'); ?

  For my element to work properly, I need to import 3x .js files and
  1x .css file; I have placed these files in /webroot/js/ and /webroot/
  css/ respectively and am attempting to call them inside the element
  like so:

  ?php
          $javascript-link('mootools-for-dropdown', false);
          $javascript-link('UvumiDropdown-compressed', false);
          $javascript-link('nav_menu', false);
          $html-css('uvumi-dropdown');
  ?

  However, when the page loads and I check page source, it doesn't
  include these files in the header.  I've also tried calling this
  following line in default.cpt with no success:

  ?php e($scripts_for_layout); ?

  What am I doing wrong??

  Thanks,
  Dima

Check out the new CakePHP Questions site http://cakeqs.org and help others with 
their CakePHP related questions.

You received this message because you are subscribed to the Google Groups 
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to
cake-php+unsubscr...@googlegroups.com For more options, visit this group at 
http://groups.google.com/group/cake-php?hl=en


Re: Using Javascript-link Inside An Element

2010-06-07 Thread calvin
You only use echo when you're linking them inline. So you would never
have something like:

echo $javascript-link($scriptname, false);

It would either be:

echo $javascript-link($scriptname);

or:

$javascript-link($scriptname, false);

Unfortunately, you can't use the $scripts_for_layout variable in the
layout or elements included from the layout because usually by that
point the variable has already been printed out.

Your best bet would be to just place inline link calls in the header
section of the layout.

On Jun 7, 2:51 pm, Dima dmitriy.pind...@gmail.com wrote:
 vekija, thanks a ton for your help!!  I added echo in front of all 4
 of the lines in nav_menu.cpt.  I was immediately able to see the style
 sheets kick in; however, when I look at page source, it still doesn't
 show those files in the page header and is not displaying correctly.
 Am I using the ?php e($scripts_for_layout); ? correctly?  Does it
 have to go before/after a certain point in the header?

 Thanks again,
 Dima

 On Jun 7, 4:10 pm, vekija vedran.konto...@gmail.com wrote:

  you have to echo those :)

  echo $javascript-link('mootools-for-dropdown', false);

  On Jun 7, 8:43 pm, Dima dmitriy.pind...@gmail.com wrote:

   I'm pretty new to CakePHP so it is likely that my issue is rather
   simple to fix.  I have a custom element which I created called
   nav_menu.cpt.  I call this element from default.cpt using:

   ?php echo $this-element('nav_menu'); ?

   For my element to work properly, I need to import 3x .js files and
   1x .css file; I have placed these files in /webroot/js/ and /webroot/
   css/ respectively and am attempting to call them inside the element
   like so:

   ?php
   $javascript-link('mootools-for-dropdown', false);
   $javascript-link('UvumiDropdown-compressed', false);
   $javascript-link('nav_menu', false);
   $html-css('uvumi-dropdown');
   ?

   However, when the page loads and I check page source, it doesn't
   include these files in the header.  I've also tried calling this
   following line in default.cpt with no success:

   ?php e($scripts_for_layout); ?

   What am I doing wrong??

   Thanks,
   Dima

Check out the new CakePHP Questions site http://cakeqs.org and help others with 
their CakePHP related questions.

You received this message because you are subscribed to the Google Groups 
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to
cake-php+unsubscr...@googlegroups.com For more options, visit this group at 
http://groups.google.com/group/cake-php?hl=en


Re: Using Javascript link

2009-08-12 Thread Sarah

Nevermind, I finally figured out the location of the images.

I set the 'address' of the alt pictures to:

cake/../img/picturename.gif

so it would have been:
element.src = cake/../img/picturename.gif

:)

--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups 
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to 
cake-php+unsubscr...@googlegroups.com
For more options, visit this group at 
http://groups.google.com/group/cake-php?hl=en
-~--~~~~--~~--~--~---



Re: Using Javascript link

2009-08-12 Thread brian

Sorry, I forgot to get back to you; I was in the middle of a crisis.

cake/../img/picturename.gif

That path doesn't look right. I think there's something deeper wrong.

And what about that head in your view? Is it so, or is that actually
in your layout?

And, what I meant about rollovers is that, when you do:

element.src = images/mesogamesHover.gif;

... you're forcing the script to download the image as the user hovers
over the link. So you're bound to see some lag. It's better to preload
them in some way. By creating image objects and assigning a src to
them, the script will download the images to the client. Then in your
rollover function, you assign the src of the relevant Image object to
your element. The swap will happen immediately.

On Wed, Aug 12, 2009 at 3:12 PM, Sarahsarah.e.p.jo...@gmail.com wrote:

 Nevermind, I finally figured out the location of the images.

 I set the 'address' of the alt pictures to:

 cake/../img/picturename.gif

 so it would have been:
 element.src = cake/../img/picturename.gif

 :)

 


--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups 
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to 
cake-php+unsubscr...@googlegroups.com
For more options, visit this group at 
http://groups.google.com/group/cake-php?hl=en
-~--~~~~--~~--~--~---



Re: Using Javascript link

2009-08-11 Thread Sarah

My original javascript code actually worked on a site (no setup with
cakephp).  The problem I'm having is linking everything together.  I
do appreciate the advice w/ the javascript though.  :)
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups 
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to 
cake-php+unsubscr...@googlegroups.com
For more options, visit this group at 
http://groups.google.com/group/cake-php?hl=en
-~--~~~~--~~--~--~---



Re: Using Javascript link

2009-08-10 Thread Sarah

Thank you for your reply.

I don't fully understand your advice.

I understand that HtmlHelper will expect a relative path from webroot/
img, but if it is already in the 'img' folder, why would I need to
pass '/img/' + filename ?  Will the javascript code look for the Hover
images in the img folder?  Or will it look for it in the js folder?

You recommend that I create the image objects and then set element.src
= foo.src ?  (Just wanting to clarify what you mean).

Thank you very much for your help.
I hope to hear back.

Thanks,
~Sarah

On Aug 9, 8:20 pm, brian bally.z...@gmail.com wrote:
 You have a head in your view? No the layout? Does the HTML source look 
 right?

 Anyway, your onHover function won't work because you're not passing
 the full path to the image. Remember that HtmlHelper expectes a
 relative path from webroot/img. However, you're only passing the
 filename, instead of '/img/'+filename.

 Also, if you're going to do your rollovers like this, you'd be better
 off preloading them by creating Image objects and assigning the src to
 them. eg.

 var foo = new Image();
 foo.src = '/img/foo.gif';
 var foo_hover = new Image();
 foo_hover.src = '/img/foo_hover.gif';

 In reality, it'd be better t create an array of those. Pass the name
 or key, plus the stat--on or off--to your function, where you swap
 element.src with src of whichever Image is required.

 On Sun, Aug 9, 2009 at 8:09 PM, Sarahsarah.e.p.jo...@gmail.com wrote:

  I assume you want only the relevant parts.

  In my view I have:

  head
         meta http-equiv=Content-Type content=text/html;
  charset=ISO-8859-1
     titleAnimal Tlatoque/title
     ?php echo $javascript-link('evoicesindex'); ?
     ?php echo $html-css('evoices'); ?
   /head

     div id=library class=mapElement
         ?php echo $html-link($html-image('Library3Sized.gif', array
  ('alt'='Library', 'onmouseover'='onHover(this)',
  'onmouseout'='onUnHover(this)')), array('controller'='evoices',
  'action'='library'), array('escape'=false)); ?
     /div

  Then I use it like so (I have an onUnHover written too )in my
  evoicesindex.js which is located in webroot/js

  function onHover(element){

     if(element.alt == Games)
         element.src = images/mesogamesHover.gif;

     if(element.alt == House)
         element.src = images/mesohouseHover.gif;

     if(element.alt == Library)
         element.src = Library3Sized.gif;

     if(element.alt == Adventure Game)
         element.src = images/forestHover.gif;

     if(element.alt == School House)
         element.src = images/mesoschoolHover1.gif;

  }

  Please let me know if I should just post the whole files...

  Thanks for you help,
  ~S
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups 
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to 
cake-php+unsubscr...@googlegroups.com
For more options, visit this group at 
http://groups.google.com/group/cake-php?hl=en
-~--~~~~--~~--~--~---



Re: Using Javascript link

2009-08-09 Thread brian

It could be a lot of things. Can you post your code?

On Sat, Aug 8, 2009 at 9:32 PM, Sarahsarah.e.p.jo...@gmail.com wrote:

 I'm having trouble getting my javascript to work.

 The api recommends using link and putting the scripts and contents
 into the webroot/js folder.  I tried this, but it isn't working.

 I'm trying to create a hover for an image...I included the functions
 in the second parameter of $html-image().

 Is there something I'm missing?

 I would appreciate any advice.

 Thanks,
 ~S
 


--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups 
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to 
cake-php+unsubscr...@googlegroups.com
For more options, visit this group at 
http://groups.google.com/group/cake-php?hl=en
-~--~~~~--~~--~--~---



Re: Using Javascript link

2009-08-09 Thread Vijay Kumbhar
Hello Sarah,

Can you please paste your code here so that we can help you right a way.
With out telling the pros  cons for that...

On Sun, Aug 9, 2009 at 9:38 PM, brian bally.z...@gmail.com wrote:


 It could be a lot of things. Can you post your code?

 On Sat, Aug 8, 2009 at 9:32 PM, Sarahsarah.e.p.jo...@gmail.com wrote:
 
  I'm having trouble getting my javascript to work.
 
  The api recommends using link and putting the scripts and contents
  into the webroot/js folder.  I tried this, but it isn't working.
 
  I'm trying to create a hover for an image...I included the functions
  in the second parameter of $html-image().
 
  Is there something I'm missing?
 
  I would appreciate any advice.
 
  Thanks,
  ~S
  
 

 



-- 
Thanks  Regards,
Vijayk.
Co-founder (www.weboniselab.com)

You Bring the Dreams, We'll Bring the Means

--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups 
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to 
cake-php+unsubscr...@googlegroups.com
For more options, visit this group at 
http://groups.google.com/group/cake-php?hl=en
-~--~~~~--~~--~--~---



Re: Using Javascript link

2009-08-09 Thread Vijay Kumbhar
Hello Sarah,

Can you please paste the code here so that we can help you right a
way.

On Sun, Aug 9, 2009 at 9:38 PM, brian bally.z...@gmail.com wrote:


 It could be a lot of things. Can you post your code?

 On Sat, Aug 8, 2009 at 9:32 PM, Sarahsarah.e.p.jo...@gmail.com wrote:
 
  I'm having trouble getting my javascript to work.
 
  The api recommends using link and putting the scripts and contents
  into the webroot/js folder.  I tried this, but it isn't working.
 
  I'm trying to create a hover for an image...I included the functions
  in the second parameter of $html-image().
 
  Is there something I'm missing?
 
  I would appreciate any advice.
 
  Thanks,
  ~S
  
 

 



-- 
Thanks  Regards,
Vijayk.
Co-founder (www.weboniselab.com)

You Bring the Dreams, We'll Bring the Means

--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups 
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to 
cake-php+unsubscr...@googlegroups.com
For more options, visit this group at 
http://groups.google.com/group/cake-php?hl=en
-~--~~~~--~~--~--~---



Re: Using Javascript link

2009-08-09 Thread Sarah

I assume you want only the relevant parts.

In my view I have:

head
meta http-equiv=Content-Type content=text/html;
charset=ISO-8859-1
titleAnimal Tlatoque/title
?php echo $javascript-link('evoicesindex'); ?
?php echo $html-css('evoices'); ?
  /head


div id=library class=mapElement
?php echo $html-link($html-image('Library3Sized.gif', array
('alt'='Library', 'onmouseover'='onHover(this)',
'onmouseout'='onUnHover(this)')), array('controller'='evoices',
'action'='library'), array('escape'=false)); ?
/div

Then I use it like so (I have an onUnHover written too )in my
evoicesindex.js which is located in webroot/js

function onHover(element){

if(element.alt == Games)
element.src = images/mesogamesHover.gif;

if(element.alt == House)
element.src = images/mesohouseHover.gif;

if(element.alt == Library)
element.src = Library3Sized.gif;

if(element.alt == Adventure Game)
element.src = images/forestHover.gif;

if(element.alt == School House)
element.src = images/mesoschoolHover1.gif;

}

Please let me know if I should just post the whole files...

Thanks for you help,
~S

--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups 
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to 
cake-php+unsubscr...@googlegroups.com
For more options, visit this group at 
http://groups.google.com/group/cake-php?hl=en
-~--~~~~--~~--~--~---



Re: Using Javascript link

2009-08-09 Thread brian

You have a head in your view? No the layout? Does the HTML source look right?

Anyway, your onHover function won't work because you're not passing
the full path to the image. Remember that HtmlHelper expectes a
relative path from webroot/img. However, you're only passing the
filename, instead of '/img/'+filename.

Also, if you're going to do your rollovers like this, you'd be better
off preloading them by creating Image objects and assigning the src to
them. eg.

var foo = new Image();
foo.src = '/img/foo.gif';
var foo_hover = new Image();
foo_hover.src = '/img/foo_hover.gif';

In reality, it'd be better t create an array of those. Pass the name
or key, plus the stat--on or off--to your function, where you swap
element.src with src of whichever Image is required.

On Sun, Aug 9, 2009 at 8:09 PM, Sarahsarah.e.p.jo...@gmail.com wrote:

 I assume you want only the relevant parts.

 In my view I have:

 head
        meta http-equiv=Content-Type content=text/html;
 charset=ISO-8859-1
    titleAnimal Tlatoque/title
    ?php echo $javascript-link('evoicesindex'); ?
    ?php echo $html-css('evoices'); ?
  /head


    div id=library class=mapElement
        ?php echo $html-link($html-image('Library3Sized.gif', array
 ('alt'='Library', 'onmouseover'='onHover(this)',
 'onmouseout'='onUnHover(this)')), array('controller'='evoices',
 'action'='library'), array('escape'=false)); ?
    /div

 Then I use it like so (I have an onUnHover written too )in my
 evoicesindex.js which is located in webroot/js

 function onHover(element){

    if(element.alt == Games)
        element.src = images/mesogamesHover.gif;

    if(element.alt == House)
        element.src = images/mesohouseHover.gif;

    if(element.alt == Library)
        element.src = Library3Sized.gif;

    if(element.alt == Adventure Game)
        element.src = images/forestHover.gif;

    if(element.alt == School House)
        element.src = images/mesoschoolHover1.gif;

 }

 Please let me know if I should just post the whole files...

 Thanks for you help,
 ~S

 


--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups 
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to 
cake-php+unsubscr...@googlegroups.com
For more options, visit this group at 
http://groups.google.com/group/cake-php?hl=en
-~--~~~~--~~--~--~---



Using Javascript link

2009-08-08 Thread Sarah

I'm having trouble getting my javascript to work.

The api recommends using link and putting the scripts and contents
into the webroot/js folder.  I tried this, but it isn't working.

I'm trying to create a hover for an image...I included the functions
in the second parameter of $html-image().

Is there something I'm missing?

I would appreciate any advice.

Thanks,
~S
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups 
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to 
cake-php+unsubscr...@googlegroups.com
For more options, visit this group at 
http://groups.google.com/group/cake-php?hl=en
-~--~~~~--~~--~--~---



Using $javascript-link('somefile', false) in an element doesn't work

2008-05-28 Thread dericknwq

Erm, it seems like the $scripts_for_layout var is populated before the
elements are rendered so it doesn't contain the scripts which you add
it in an element.

My scenario:
/posts/view/123

and in view.ctp:
$this-element('456')

and in 456.ctp:
$javascript-link('somefile', false)

It doesn't work. It does if I link it in view.ctp as per normal
though. Anyone had similar issues or is this meant to be?


--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups 
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at 
http://groups.google.com/group/cake-php?hl=en
-~--~~~~--~~--~--~---