Re: get current url as array

2011-12-31 Thread euromark 
any feedback?
seems like this is a missing functionality.

example:
admin/authplugin/users/edit/2

I would expect to find some router method to get

$url = array(
'admin' = 1
'plugin' = 'authplugin'
'controller' = 'users'
'action' = 'edit'
2
)
for example
maybe with Router::urlAsArray()
which would be similar to the result of Router::parse() but it already
contains the passed and named params as expected
to easily adjust it before passing it to Html::url() or Html::link():

$url[#] = 'somehash';
or
$url[] = 'somepassedparam';
or
$url['key'] = 'somenamedparam';

echo $this-Html-link('Title', $url);




On 28 Dez., 21:59, euromark dereurom...@googlemail.com wrote:
 ...or for any url for that matter (for adding some named/pass params
 etc)

 PS: I forgot
         if (isset($urlParams['prefix'])) {
                 unset($urlParams['prefix']);
         }

 On 28 Dez., 21:04, euromark dereurom...@googlemail.com wrote:







  am I missing sth or is there no url() method etc for returning the
  current url as array?
  I only know this way:

                  $urlParams = Router::getParams(true);
                  $urlParams = am($urlParams, $urlParams['named'],
  $urlParams['pass']);
                  unset($urlParams['named']);
                  unset($urlParams['pass']);

  but it seems a little bit like overhead...
  does anyone know how to do that easier?
  maybe we should introduce Router::urlAsArray()
  with default NULL = return current ?

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Re: get current url as array

2011-12-31 Thread mike karthauser 
You should be able to get the data you need in $this-params.

Mike Karthauser
Brightstorm limited
Tel: 07939252144

On 31 Dec 2011, at 12:01, euromark dereurom...@googlemail.com wrote:

 any feedback?
 seems like this is a missing functionality.
 
 example:
 admin/authplugin/users/edit/2
 
 I would expect to find some router method to get
 
 $url = array(
'admin' = 1
'plugin' = 'authplugin'
'controller' = 'users'
'action' = 'edit'
2
 )
 for example
 maybe with Router::urlAsArray()
 which would be similar to the result of Router::parse() but it already
 contains the passed and named params as expected
 to easily adjust it before passing it to Html::url() or Html::link():
 
 $url[#] = 'somehash';
 or
 $url[] = 'somepassedparam';
 or
 $url['key'] = 'somenamedparam';
 
 echo $this-Html-link('Title', $url);
 
 
 
 
 On 28 Dez., 21:59, euromark dereurom...@googlemail.com wrote:
 ...or for any url for that matter (for adding some named/pass params
 etc)
 
 PS: I forgot
 if (isset($urlParams['prefix'])) {
 unset($urlParams['prefix']);
 }
 
 On 28 Dez., 21:04, euromark dereurom...@googlemail.com wrote:
 
 
 
 
 
 
 
 am I missing sth or is there no url() method etc for returning the
 current url as array?
 I only know this way:
 
 $urlParams = Router::getParams(true);
 $urlParams = am($urlParams, $urlParams['named'],
 $urlParams['pass']);
 unset($urlParams['named']);
 unset($urlParams['pass']);
 
 but it seems a little bit like overhead...
 does anyone know how to do that easier?
 maybe we should introduce Router::urlAsArray()
 with default NULL = return current ?
 
 -- 
 Our newest site for the community: CakePHP Video Tutorials 
 http://tv.cakephp.org 
 Check out the new CakePHP Questions site http://ask.cakephp.org and help 
 others with their CakePHP related questions.
 
 
 To unsubscribe from this group, send email to
 cake-php+unsubscr...@googlegroups.com For more options, visit this group at 
 http://groups.google.com/group/cake-php
 

-- 
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http://tv.cakephp.org 
Check out the new CakePHP Questions site http://ask.cakephp.org and help others 
with their CakePHP related questions.


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Re: get current url as array

2011-12-31 Thread euromark 
I am talking about the complete array to be passed to Html::url() /
Html::link()
of course there are tons of ways to get the data itself
just saw today: Router::parse($this-request-here(false));
besides 10 other ways.

but you would either have to manually join them:
array('controller'=$this-params['controller'], ...)
or you would have to merge or unset a lot of stuff from it (see above
example with Router::getParams(true);)

out of the box we can only retrieve the final string (in the view
layer with Html::url()) - which is unfortunate in an environment where
every url is usually array-based...



On 31 Dez., 13:04, mike karthauser mi...@brightstorm.co.uk wrote:
 You should be able to get the data you need in $this-params.

 Mike Karthauser
 Brightstorm limited
 Tel: 07939252144

 On 31 Dec 2011, at 12:01, euromark dereurom...@googlemail.com wrote:







  any feedback?
  seems like this is a missing functionality.

  example:
  admin/authplugin/users/edit/2

  I would expect to find some router method to get

  $url = array(
     'admin' = 1
     'plugin' = 'authplugin'
     'controller' = 'users'
     'action' = 'edit'
     2
  )
  for example
  maybe with Router::urlAsArray()
  which would be similar to the result of Router::parse() but it already
  contains the passed and named params as expected
  to easily adjust it before passing it to Html::url() or Html::link():

  $url[#] = 'somehash';
  or
  $url[] = 'somepassedparam';
  or
  $url['key'] = 'somenamedparam';

  echo $this-Html-link('Title', $url);

  On 28 Dez., 21:59, euromark dereurom...@googlemail.com wrote:
  ...or for any url for that matter (for adding some named/pass params
  etc)

  PS: I forgot
          if (isset($urlParams['prefix'])) {
                  unset($urlParams['prefix']);
          }

  On 28 Dez., 21:04, euromark dereurom...@googlemail.com wrote:

  am I missing sth or is there no url() method etc for returning the
  current url as array?
  I only know this way:

                  $urlParams = Router::getParams(true);
                  $urlParams = am($urlParams, $urlParams['named'],
  $urlParams['pass']);
                  unset($urlParams['named']);
                  unset($urlParams['pass']);

  but it seems a little bit like overhead...
  does anyone know how to do that easier?
  maybe we should introduce Router::urlAsArray()
  with default NULL = return current ?

  --
  Our newest site for the community: CakePHP Video 
  Tutorialshttp://tv.cakephp.org
  Check out the new CakePHP Questions sitehttp://ask.cakephp.organd help 
  others with their CakePHP related questions.

  To unsubscribe from this group, send email to
  cake-php+unsubscr...@googlegroups.com For more options, visit this group 
  athttp://groups.google.com/group/cake-php

-- 
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http://tv.cakephp.org 
Check out the new CakePHP Questions site http://ask.cakephp.org and help others 
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get current url as array

2011-12-28 Thread euromark 
am I missing sth or is there no url() method etc for returning the
current url as array?
I only know this way:

$urlParams = Router::getParams(true);
$urlParams = am($urlParams, $urlParams['named'],
$urlParams['pass']);
unset($urlParams['named']);
unset($urlParams['pass']);

but it seems a little bit like overhead...
does anyone know how to do that easier?
maybe we should introduce Router::urlAsArray()
with default NULL = return current ?

-- 
Our newest site for the community: CakePHP Video Tutorials 
http://tv.cakephp.org 
Check out the new CakePHP Questions site http://ask.cakephp.org and help others 
with their CakePHP related questions.


To unsubscribe from this group, send email to
cake-php+unsubscr...@googlegroups.com For more options, visit this group at 
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Re: get current url as array

2011-12-28 Thread euromark 
...or for any url for that matter (for adding some named/pass params
etc)

PS: I forgot
if (isset($urlParams['prefix'])) {
unset($urlParams['prefix']);
}




On 28 Dez., 21:04, euromark dereurom...@googlemail.com wrote:
 am I missing sth or is there no url() method etc for returning the
 current url as array?
 I only know this way:

                 $urlParams = Router::getParams(true);
                 $urlParams = am($urlParams, $urlParams['named'],
 $urlParams['pass']);
                 unset($urlParams['named']);
                 unset($urlParams['pass']);

 but it seems a little bit like overhead...
 does anyone know how to do that easier?
 maybe we should introduce Router::urlAsArray()
 with default NULL = return current ?

-- 
Our newest site for the community: CakePHP Video Tutorials 
http://tv.cakephp.org 
Check out the new CakePHP Questions site http://ask.cakephp.org and help others 
with their CakePHP related questions.


To unsubscribe from this group, send email to
cake-php+unsubscr...@googlegroups.com For more options, visit this group at 
http://groups.google.com/group/cake-php