Re: jQuery $.ajax() and on success result processing?

[bunyan]

If you want just to get the rendered view and put its contents into an
element on a page, use

$this->layout = 'ajax';

in action, and then assign the rendered view to whatever you need with
jQuery.

If you don't need to render a view, you can return action results in
xml, json or etc.

Fanck wrote:
> Hi,
>
> I'm new to jQuery, but I wonder if it is possible to return a result
> via controller that jQuery can handle on success?
>
> I'm trying to POST data to an "add" method, and on success loading the
> view with the right $id. Anyone know how to do that?
>
> thanks
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Re: jQuery $.ajax() and on success result processing?

[Marcin Domanski aka kabturek]

Hi
> I'm new to jQuery, but I wonder if it is possible to return a result
> via controller that jQuery can handle on success?
Maybe send the data in JSON ? (see the javascript helper) or PHP built-
in json extension...

> I'm trying to POST data to an "add" method, and on success loading the
> view with the right $id. Anyone know how to do that?

I'm not really getting why you need jqery for that ;)

greets,
kabturek
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Re: jQuery $.ajax() and on success result processing?

[Action]

I would also like to know.

On Oct 9, 6:14 am, Fanck <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I'm new tojQuery, but I wonder if it is possible to return a result
> via controller thatjQuerycan handle on success?
>
> I'm trying to POST data to an "add" method, and on success loading the
> view with the right $id. Anyone know how to do that?
>
> thanks
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jQuery $.ajax() and on success result processing?

[Fanck]

Hi,

I'm new to jQuery, but I wonder if it is possible to return a result
via controller that jQuery can handle on success?

I'm trying to POST data to an "add" method, and on success loading the
view with the right $id. Anyone know how to do that?

thanks


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