Re: [Caml-list] Question about the -dlambda option of ocamlc/ocamlopt

2009-03-25 Thread Alp Mestan
Thanks Romain !

On Wed, Mar 25, 2009 at 10:02 AM, Romain Bardou wrote:

> Alp Mestan a écrit :
>
>  Hi,
>>
>> I'm currently studying the lambda code generation phase of the standard
>> OCaml compiler.
>>
>> You can take a look at this for an example :
>> http://blog.mestan.fr/2009/03/22/ocaml-and-dlambda-1/
>>
>> I'm wondering what is 'makeblock' for ?
>> And why is there '/' after every variable/function name ? Isn't
>> the name sufficient for identifying variables ?
>>
>> Thanks !
>>
>
> If I recall correctly, makeblock is for block allocation and is used to
> make empty blocks for everything that does not fit in just one integer.
>
> The / is used to uniquely identify identifiers. In this example :
>
> let x = 1 in let x = 2 in x
>
> The / allows you to know which "let" variable is represented by
> the "x" at the end.
>
> --
> Romain Bardou
>



-- 
Alp Mestan
In charge of the C++ section on Developpez.com.
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Re: [Caml-list] Question about the -dlambda option of ocamlc/ocamlopt

2009-03-25 Thread Romain Bardou

Alp Mestan a écrit :

Hi,

I'm currently studying the lambda code generation phase of the standard 
OCaml compiler.


You can take a look at this for an example : 
http://blog.mestan.fr/2009/03/22/ocaml-and-dlambda-1/


I'm wondering what is 'makeblock' for ?
And why is there '/' after every variable/function name ? 
Isn't the name sufficient for identifying variables ?


Thanks !


If I recall correctly, makeblock is for block allocation and is used to 
make empty blocks for everything that does not fit in just one integer.


The / is used to uniquely identify identifiers. In this example :

let x = 1 in let x = 2 in x

The / allows you to know which "let" variable is represented 
by the "x" at the end.


--
Romain Bardou

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