Re: [OSL | CCIE_Voice] Catalyst 6500 QoS Marking

2008-03-14 Thread ccievoice1
Hmm, thanks for the complicated explaination :-p

Also, just wondering can I reuse the policer aggregate VVLAN-VOICE for
another acl?

Example:

set qos acl ip IPPHONE dscp 46 aggregate VVLAN-VOICE udp 177.1.101.0
255.255.255.0 any range 16384 32767
set qos acl ip VOICE dscp 46 aggregate VVLAN-VOICE udp
177.1.102.0<http://177.1.101.0/>
255.255.255.0 any range 16384 32767

Thanks and best regards.

On Sat, Mar 15, 2008 at 12:00 AM, Juan Lopez Hernandez -X (jlopezhe - IBM -
INS at Cisco) <[EMAIL PROTECTED]> wrote:

>  burst size for Cat6K uses a Tc of .25ms. Hence Bc = rate x 0.00025 or
> [1518x8], whichever is the greated value.
> The 1518*8 comes from the worst case MTU for ethernet, expressed in
> bits/s. Round it up to 13Kbps. If burst size would be smaller, all
> ethernet traffic would be policed, which is not the intention.
> ps: cat6k always uses Kbps as units
>
> cheers,
> Juan
>
>
>  --
> *From:* [EMAIL PROTECTED] [mailto:
> [EMAIL PROTECTED] *On Behalf Of *ccievoice1
> *Sent:* Friday, March 14, 2008 4:48 PM
> *To:* CCIE Maillist
> *Subject:* [OSL | CCIE_Voice] Catalyst 6500 QoS Marking
>
> !
> !
>
> set qos cos-dscp-map 0 8 16 24 32 46 48 56
> set qos policed-dscp-map 0,24,26,46:8
> set qos policer aggregate VVLAN-VOICE rate 128 burst 8000 drop
> set qos policer aggregate VVLAN-CALL-SIGNALING rate 32 burst 8000 policed-dscp
>
> set qos acl ip IPPHONE dscp 46 aggregate VVLAN-VOICE udp 177.1.101.0 
> 255.255.255.0 any range 16384 32767
> set qos acl ip IPPHONE dscp 24 aggregate VVLAN-CALL-SIGNALING tcp 177.1.101.0 
> 255.255.255.0 any range 2000 2002
>
> commit qos acl IPPHONE
>
> set port qos 2/45 trust-device ciscoipphone
> set qos acl map IPPHONE 2/45
> !
> !
>
> Question: on policer aggregate, burst is to specifies the burst size; valid 
> values are 1 to 32000 kilobits. So what value do we use? And how to calculate 
> the value?
>
> Thanks.
>
>


Re: [OSL | CCIE_Voice] Catalyst 6500 QoS Marking

2008-03-14 Thread Juan Lopez Hernandez -X (jlopezhe - IBM - INS at Cisco)
burst size for Cat6K uses a Tc of .25ms. Hence Bc = rate x 0.00025 or
[1518x8], whichever is the greated value. 
The 1518*8 comes from the worst case MTU for ethernet, expressed in
bits/s. Round it up to 13Kbps. If burst size would be smaller, all
ethernet traffic would be policed, which is not the intention.
ps: cat6k always uses Kbps as units
 
cheers,
Juan
 



From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of ccievoice1
Sent: Friday, March 14, 2008 4:48 PM
To: CCIE Maillist
Subject: [OSL | CCIE_Voice] Catalyst 6500 QoS Marking


!
!
set qos cos-dscp-map 0 8 16 24 32 46 48 56
set qos policed-dscp-map 0,24,26,46:8
set qos policer aggregate VVLAN-VOICE rate 128 burst 8000 drop
set qos policer aggregate VVLAN-CALL-SIGNALING rate 32 burst 8000
policed-dscp


set qos acl ip IPPHONE dscp 46 aggregate VVLAN-VOICE udp 177.1.101.0
255.255.255.0 any range 16384 32767
set qos acl ip IPPHONE dscp 24 aggregate VVLAN-CALL-SIGNALING tcp
177.1.101.0 255.255.255.0 any range 2000 2002

commit qos acl IPPHONE

set port qos 2/45 trust-device ciscoipphone
set qos acl map IPPHONE 2/45
!
!

Question: on policer aggregate, burst is to specifies the burst size;
valid values are 1 to 32000 kilobits. So what value do we use? And how
to calculate the value?


Thanks.



[OSL | CCIE_Voice] Catalyst 6500 QoS Marking

2008-03-14 Thread ccievoice1
!
!
set qos cos-dscp-map 0 8 16 24 32 46 48 56
set qos policed-dscp-map 0,24,26,46:8
set qos policer aggregate VVLAN-VOICE rate 128 burst 8000 drop
set qos policer aggregate VVLAN-CALL-SIGNALING rate 32 burst 8000 policed-dscp

set qos acl ip IPPHONE dscp 46 aggregate VVLAN-VOICE udp 177.1.101.0
255.255.255.0 any range 16384 32767
set qos acl ip IPPHONE dscp 24 aggregate VVLAN-CALL-SIGNALING tcp
177.1.101.0 255.255.255.0 any range 2000 2002
commit qos acl IPPHONE

set port qos 2/45 trust-device ciscoipphone
set qos acl map IPPHONE 2/45
!
!

Question: on policer aggregate, burst is to specifies the burst size;
valid values are 1 to 32000 kilobits. So what value do we use? And how
to calculate the value?

Thanks.