[CentOS] Stripe vs Cylinder alignement...
Hi, I modified my kickstart to do some custom partioning and formating in a pre-install script. I am trying to align the partitions on the RAID stripe (and format with a correct stride). But, sfdisk complains that it does not start/end on a cylinder boundary (used -L option to limit complaining). Since the cylinder size is not a multiple of the stripe size, I cannot align on both. I tried to align the begining on the stripe and the end on the end of a cylinder, but sfdisk still compains... Basicaly, I have a 128KB (256 sectors) stripe, and 255*32 = 8160 sectors cylinders. What I am doing is: begin = ( begin / 256 ) * 256 end = ( end / 8160 ) * 8160 -1 So, for my first partition (96MB): begin=256 size = ( ( 96 * 1024 * 2 ) / 8160 ) * 8160 = 195840 sectors end = 195840 - 1 - 256 = 195583 Any idea what I am doing wrong in my calculations or logic? Thx, JD ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] Stripe vs Cylinder alignement...
So, for my first partition (96MB): begin=256 size = ( ( 96 * 1024 * 2 ) / 8160 ) * 8160 = 195840 sectors end = 195840 - 1 - 256 = 195583 Oops, I meant: begin = 256 size = 96 * 1024 * 2 = 196608 sectors end = ( ( begin + size ) / 8160 ) * 8160 - 1 = 195839 aligned_size = end - begin + 1 = 195584 Maybe... I am a bit confused ^_^ JD ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] Stripe vs Cylinder alignement...
Cylinders are largely logical - even in magnetic disks you have no way of knowing if the logical cylinder matches up with the physical construct of a cylinder on the disk medium - in any modern(15 years ?) disk they won't. Don't worry about cylinders, just align your fs to the stripe/sector. Obviously, the concept of a cylinder starts to go out the window with RAID, SSD's, etc. More information about partition alignment here - http://www.ocztechnologyforum.com/forum/showpost.php?p=335049postcount=134 --Blake Original Message Subject: [CentOS] Stripe vs Cylinder alignement... From: John Doe jd...@yahoo.com To: centos@centos.org Date: Friday, October 30, 2009 9:45:59 AM Hi, I modified my kickstart to do some custom partioning and formating in a pre-install script. I am trying to align the partitions on the RAID stripe (and format with a correct stride). But, sfdisk complains that it does not start/end on a cylinder boundary (used -L option to limit complaining). Since the cylinder size is not a multiple of the stripe size, I cannot align on both. I tried to align the begining on the stripe and the end on the end of a cylinder, but sfdisk still compains... Basicaly, I have a 128KB (256 sectors) stripe, and 255*32 = 8160 sectors cylinders. What I am doing is: begin = ( begin / 256 ) * 256 end = ( end / 8160 ) * 8160 -1 So, for my first partition (96MB): begin=256 size = ( ( 96 * 1024 * 2 ) / 8160 ) * 8160 = 195840 sectors end = 195840 - 1 - 256 = 195583 Any idea what I am doing wrong in my calculations or logic? Thx, JD ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] Stripe vs Cylinder alignement...
On 10/30/09, John Doe jd...@yahoo.com wrote: Hi, I modified my kickstart to do some custom partioning and formating in a pre-install script. I am trying to align the partitions on the RAID stripe (and format with a correct stride). But, sfdisk complains that it does not start/end on a cylinder boundary (used -L option to limit complaining). Since the cylinder size is not a multiple of the stripe size, I cannot align on both. I tried to align the begining on the stripe and the end on the end of a cylinder, but sfdisk still compains... Basicaly, I have a 128KB (256 sectors) stripe, and 255*32 = 8160 sectors cylinders. What I am doing is: begin = ( begin / 256 ) * 256 end = ( end / 8160 ) * 8160 -1 So, for my first partition (96MB): begin=256 size = ( ( 96 * 1024 * 2 ) / 8160 ) * 8160 = 195840 sectors end = 195840 - 1 - 256 = 195583 Any idea what I am doing wrong in my calculations or logic? Logic! Well not logic but knowledge about the physical layer inside the disk. Most disks today do not have a constant number of blocks per track/ cylinder. Most disk partitioning tools just guess and do some rounding. There can be one, two or even three zones on the surface with different blocks per track on each. One strategy is to look at the buffer setup and size of a disk and match stripe sizes to work with memory not blocks per cylinder. Note that a drive with an 8MB buffer uses some for read and some for write. Some research or testing can expose the ratio. Another strategy is to partition devices exactly the same. LBA (Logical block addressing) hides the physical layer -- NiftyCluster T o m M i t c h e l l ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] Stripe vs Cylinder alignement...
At Fri, 30 Oct 2009 11:14:54 -0500 CentOS mailing list centos@centos.org wrote: Cylinders are largely logical - even in magnetic disks you have no way of knowing if the logical cylinder matches up with the physical construct of a cylinder on the disk medium - in any modern(15 years ?) disk they won't. Don't worry about cylinders, just align your fs to the stripe/sector. Cylinders only ever existed (as a *physicly mapped* thing) with MFM, RLL, and early IDE hard drives (IDE drives grew out of 'hard cards', which were MFM/RLL drives bolted to a XT (pre/early ISA) expansion card with a MFM/RLL drive controller). (And yes, floppies. Not sure about CD/DVD-ROMS, but that is a completely different can of worms.) SCSI disks *never* had any physical mapping for cylinders, heads, OR sectors. The SCSI command protocol uses LBA addressing and has from day one. At this point, CHS addressing is pretty much a BIOS 'fantasy' for any modern disks. Obviously, the concept of a cylinder starts to go out the window with RAID, SSD's, etc. More information about partition alignment here - http://www.ocztechnologyforum.com/forum/showpost.php?p=335049postcount=134 --Blake Original Message Subject: [CentOS] Stripe vs Cylinder alignement... From: John Doe jd...@yahoo.com To: centos@centos.org Date: Friday, October 30, 2009 9:45:59 AM Hi, I modified my kickstart to do some custom partioning and formating in a pre-install script. I am trying to align the partitions on the RAID stripe (and format with a correct stride). But, sfdisk complains that it does not start/end on a cylinder boundary (used -L option to limit complaining). Since the cylinder size is not a multiple of the stripe size, I cannot align on both. I tried to align the begining on the stripe and the end on the end of a cylinder, but sfdisk still compains... Basicaly, I have a 128KB (256 sectors) stripe, and 255*32 = 8160 sectors cylinders. What I am doing is: begin = ( begin / 256 ) * 256 end = ( end / 8160 ) * 8160 -1 So, for my first partition (96MB): begin=256 size = ( ( 96 * 1024 * 2 ) / 8160 ) * 8160 = 195840 sectors end = 195840 - 1 - 256 = 195583 Any idea what I am doing wrong in my calculations or logic? Thx, JD ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos -- Robert Heller -- 978-544-6933 Deepwoods Software-- Download the Model Railroad System http://www.deepsoft.com/ -- Binaries for Linux and MS-Windows hel...@deepsoft.com -- http://www.deepsoft.com/ModelRailroadSystem/ ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
