Re: [CentOS] script help
Dear Chloe, John Doe`s script is a good start, even though it will work for single words space separated. The LINE Variable only passes the Arguments as single words to ($1 and $2 respectively). I will also work on something for you too... On Thu, Jun 18, 2009 at 10:34 AM, John Doe wrote: > > From: chloe K > > I have a file. list.txt (two columns) > > > > column1column2 > > nameaddress > > > > I need to put in the letter file letter.txt eg: > > > > Dear: Chloe > > Address: CA > > > > Can I use this > > > > for i `cat list.txt` | sed 's/Chloe/$i.1; /CA/$i.2/g' $i.letter.txt > > For single words space separated: > > cat list.txt | while read LINE >do > set $LINE > printf "Dear: %s\nAddress: %s\n" $1 $2 >> $1.letter.txt >done > > JD > > > > > ___ > CentOS mailing list > CentOS@centos.org > http://lists.centos.org/mailman/listinfo/centos > ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help
From: chloe K > I have a file. list.txt (two columns) > > column1column2 > nameaddress > > I need to put in the letter file letter.txt eg: > > Dear: Chloe > Address: CA > > Can I use this > > for i `cat list.txt` | sed 's/Chloe/$i.1; /CA/$i.2/g' $i.letter.txt For single words space separated: cat list.txt | while read LINE do set $LINE printf "Dear: %s\nAddress: %s\n" $1 $2 >> $1.letter.txt done JD ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help
Hi
If your file has only 2 columns and there is no space exists in 2nd
column then you can use this script
#!/bin/sh
FILE="list.txt"
OUTPUT="out.txt"
while read VAL
do
VAL1=$(echo $VAL | awk '{print $1}' )
VAL2=$(echo $VAL | awk '{print $2}' )
echo "DEAR: $VAL1" >> $OUPUT
echo "DEAR: $VAL2" >> $OUPUT
echo " ">> $OUTPUT
done<$FILE
if you have spaces in between your 2nd column you might have to format
the file using awk/sed
so that there would be a valid delimeter between column1 and column2
column 1| column2 here we can use '|' as the delimeter and change awk
statement
to awk -F '| ' '{print $1}' or something like this.
--
Regards,
Mohan.
chloe K wrote:
Hi
I have a file. list.txt (two columns)
column1column2
nameaddress
I need to put in the letter file letter.txt eg:
Dear: Chloe
Address: CA
Can I use this
for i `cat list.txt` | sed 's/Chloe/$i.1; /CA/$i.2/g' $i.letter.txt
Thank you for your help
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Re: [CentOS] script help
chloe K wrote: > Hi > > I have a file. list.txt (two columns) > > column1column2 nameaddress > > > I need to put in the letter file letter.txt eg: > > Dear: Chloe Address: CA > > Can I use this > > for i `cat list.txt` | sed 's/Chloe/$i.1; /CA/$i.2/g' $i.letter.txt > > Thank you for your help > #!/bin/sh while read NAME ADDRESS do sed -e"s/Chloe/$NAME/" -e"s/CA/$ADDRESS/" $NAME.letter.txt done http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help
On Wed, 17 Jun 2009 11:16:58 -0700 MHR wrote: > > >I've never seen any shell or sed syntax that allows you to subscript a >line like this. You should read up on awk, although there is no >simple way to do dual file processing along these lines. Easy way to do this with awk is to have the first part of the script use awk to get the name and address. and then use them as arguments to a second invocation of awk. -- Julian Thomas: j...@jt-mj.nethttp://jt-mj.net In the beautiful Genesee Valley of Western New York State! -- -- You will always be lucky if you know how to make friends with strange cats. - Colonial American proverb ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help
Hi Chloe, Please start by reading this: http://www.catb.org/~esr/faqs/smart-questions.html On Wed, Jun 17, 2009 at 13:54, chloe K wrote: > I have a file. list.txt (two columns) Separated by what? Tabs? Spaces? Can the fields themselves have spaces in them? Do you have many records, one per row? Please give a more informative example of the file you have... > I need to put in the letter file letter.txt eg: > > Dear: Chloe > Address: CA Is that supposed to be a template? What are you trying to achieve? Replace "Chloe" with the first field and "CA" with the second field of the list.txt file? Create one file per row of list.txt? If you ask vague questions all you will have are vague answers... HTH, Filipe ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help
There is going to be a problem with your sed line as the semi-column is not helping matters. You can try using a database for easy retrieval with your script. I hope it puts you on the way. On Wed, Jun 17, 2009 at 7:16 PM, Brian wrote: > > Can I use this > > > > for i `cat list.txt` | sed 's/Chloe/$i.1; /CA/$i.2/g' $i.letter.txt > > > > Why don't you just try it and see if it works? > ___ > CentOS mailing list > CentOS@centos.org > http://lists.centos.org/mailman/listinfo/centos > ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help
On Wed, Jun 17, 2009 at 11:16 AM, Brian wrote: >> Can I use this >> >> for i `cat list.txt` | sed 's/Chloe/$i.1; /CA/$i.2/g' $i.letter.txt >> > > Why don't you just try it and see if it works? There _is_ that, but it won't :-) mhr ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help
On Wed, Jun 17, 2009 at 10:54 AM, chloe K wrote: > Hi > > I have a file. list.txt (two columns) > > column1 column2 > name address > > I need to put in the letter file letter.txt eg: > > Dear: Chloe > Address: CA > > Can I use this > > for i `cat list.txt` | sed 's/Chloe/$i.1; /CA/$i.2/g' $i.letter.txt > I've never seen any shell or sed syntax that allows you to subscript a line like this. You should read up on awk, although there is no simple way to do dual file processing along these lines. (An awk script for this would need to know it has two files to process and read in the first one, then print it with replacements from the second one.) Also, if the above were to work, it would be "for i in `cat" - the "in" is part of "for" syntax Man pages are really handy for this sort of thing HTH mhr ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help
> Can I use this > > for i `cat list.txt` | sed 's/Chloe/$i.1; /CA/$i.2/g' $i.letter.txt > Why don't you just try it and see if it works? ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
[CentOS] script help
Hi I have a file. list.txt (two columns) column1 column2 name address I need to put in the letter file letter.txt eg: Dear: Chloe Address: CA Can I use this for i `cat list.txt` | sed 's/Chloe/$i.1; /CA/$i.2/g' $i.letter.txt Thank you for your help __ Looking for the perfect gift? Give the gift of Flickr! http://www.flickr.com/gift/___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help - '3rd last field'
On Mon, 2009-06-08 at 08:01 -0400, William L. Maltby wrote: > > 2. Inside that, use the set command to change the field separator to "." > Correction: IFS (the Interfield Separator) is just another variable. Just regular assignment will set it. -- Bill ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help - '3rd last field'
On Mon, 2009-06-08 at 10:29 +0100, Tom Brown wrote: > Hi > > I need some logic to work out a value for me - this value is _always_ > the 3rd last field in a string seperated by '.' but the string could be > 5 or 6 fields long, e.g > > foo.bar.VALUE.baz.lala > > foor.bar.gigi.VALUE.baz.lala > > I need to find VALUE - if this were python or something i could do it > but this has to be in shell - > > Any clues? Without trying to make code this early in the A.M., I'll give an algorithm that will work entirely in shell. Then the man page should give the details. 1. Make a subshell, either as a separate file or inline using braces-type stuff 2. Inside that, use the set command to change the field separator to "." 3. Use the set command with the string use wish to parse. This sets each field into $1, $2, ... 4. Alternate algorithm # 1 Use the shell variable $# (IIRC) to see how many you have. Use the shell's math capabilities to calculate the variable number you want Use the shell to generate a command (eval, backslashes, ...) to reference that variable 5. Alternate algorithm # 2 do a while loop until $# = 3 (if it's already <= to 3, next is skipped shift access $1 6. Alternate algorithm # 3 If $# > 3 use shell math ability to calculate how many shifts needed use shift with that number as parameter access $1 > > thanks > HTH -- Bill ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help - '3rd last field'
On Mon, Jun 08, 2009 at 10:56:09AM +0100, Tom Brown wrote:
>
> >echo foo.bar.VALUE.baz.lala | awk -F. '{ print $(NF-2); }'
>
> excellent - just what i needed
awk is probably the most readable way. In traditional shell stuff like
this used to be done in awk or sed
awk -F. '{print $(NF-2)}'
sed -n 's/^.*\.\([^\.]*\)\.[^\.]*\.[^\.]*$/\1/p'
Now you _can_ do it totally inside a modern shell in a variety of ways.
Here are three options (tested with ksh93; _should_ work in bash, but
not tested)
1) Use IFS to split the string
a=foo.var.VALUE.baz.lala
OIFS="$IFS"
IFS="."
set -- $a
IFS="$OIFS"
shift $#-3
echo $1
2) variation using arrays
a=foo.var.VALUE.baz.lala
OIFS="$IFS"
IFS="."
set -A A -- $a
IFS="$OIFS"
let x=${#A[*]}-3
echo ${A[$x]}
3) Using string pattern matching
a=foo.var.VALUE.baz.lala
front=${a%.*.*.*}
b=${a#$front.}
b=${b%%.*}
echo $b
--
rgds
Stephen
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Re: [CentOS] script help - '3rd last field'
>echo foo.bar.VALUE.baz.lala | awk -F. '{ print $(NF-2); }'
>
>
excellent - just what i needed
thanks
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Re: [CentOS] script help - '3rd last field'
muhammad panji wrote:
...
> awk -F\. {'print $3'}
> awk -F\. {'print $5'}
> awk -F\. {'print $6'}
awk -F\. {'print $(NF-2)'}
Mogens
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Re: [CentOS] script help - '3rd last field'
> I am pretty sure there is a way in awk to figure out how many fields
> you have, then take the total # of fields -3 each time to get the
> third last one. Just heading out the door and off hand can't remember
> how it would be done.
>
>
i can do it in cheetah templating with
set myloc = $getVar("hostname","")split('.')[-3]
the -3 says the last 3rd field in the string - i need the same so maybe
awk can do this
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Re: [CentOS] script help - '3rd last field'
Hi.
echo foo.bar.VALUE.baz.lala | awk -F. '{ print $(NF-2); }'
--
Alex S.
On 08.06.2009 13:29, Tom Brown wrote:
> Hi
>
> I need some logic to work out a value for me - this value is _always_
> the 3rd last field in a string seperated by '.' but the string could be
> 5 or 6 fields long, e.g
>
> foo.bar.VALUE.baz.lala
>
> foor.bar.gigi.VALUE.baz.lala
>
> I need to find VALUE - if this were python or something i could do it
> but this has to be in shell -
>
> Any clues?
>
> thanks
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> http://lists.centos.org/mailman/listinfo/centos
>
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Re: [CentOS] script help - '3rd last field'
On Mon, Jun 8, 2009 at 5:29 AM, Tom Brown wrote: > Hi > > I need some logic to work out a value for me - this value is _always_ > the 3rd last field in a string seperated by '.' but the string could be > 5 or 6 fields long, e.g > > foo.bar.VALUE.baz.lala > > foor.bar.gigi.VALUE.baz.lala > > I need to find VALUE - if this were python or something i could do it > but this has to be in shell - > > Any clues? > > thanks > ___ > CentOS mailing list > CentOS@centos.org > http://lists.centos.org/mailman/listinfo/centos > I am pretty sure there is a way in awk to figure out how many fields you have, then take the total # of fields -3 each time to get the third last one. Just heading out the door and off hand can't remember how it would be done. Jacques B. ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help - '3rd last field'
Sehr geehrte Damen und Herren, ich bin ab dem 15.06.2009 wieder zurück im Büro. Bitte wenden Sie sich in dringenden Fällen an Simon Schillings [simon.schilli...@rm-solutions.de] Viele Grüße, Michael Kettel ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help - '3rd last field'
Is there anyway you can tell which field it will be in (i.e. to use as
a search clause, so "search for the field with X properties"?)
Ultimately to get the data in the X'th field you are going to need
either awk or sed (they can both easily do this, awk probably easier
than sed)
You need to work out how you will know which field it will be in i.e.
the first, second, third? My shell scripting is rubbish but I would
guess it would go something like;
myString = "first.second.VALUE.fourth.fith"
awk -F\. {'print 3'} myString
This would print the third field seperated by a '.' (full stop/period)
of myString
That's a rubbishy wild stab in the dark as im rubbish at shell scripting.
I would actually bet money I have made things more complex hahahah!
Sorry, i tried :'(
James.
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Version: 3.1
GIT/MU/U dpu s: a--> C++>$ U+> L++> B-> P+> E?> W+++>$ N K W++ O M++>$ V-
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Re: [CentOS] script help - '3rd last field'
michael.ket...@rm-solutions.de wrote: > Sehr geehrte Damen und Herren, > > ich bin ab dem 15.06.2009 wieder zurück im Büro. > Bitte wenden Sie sich in dringenden Fällen an Simon Schillings > [simon.schilli...@rm-solutions.de] > > Viele Grüße, > Michael Kettel You can resubcribe then, when you are back. Please do not use autoresponders if you do not know how they work. No regards, Ralph pgp6bs1DJZG73.pgp Description: PGP signature ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help - '3rd last field'
Sehr geehrte Damen und Herren, ich bin ab dem 15.06.2009 wieder zurück im Büro. Bitte wenden Sie sich in dringenden Fällen an Simon Schillings [simon.schilli...@rm-solutions.de] Viele Grüße, Michael Kettel ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help - '3rd last field'
Sehr geehrte Damen und Herren, ich bin ab dem 15.06.2009 wieder zurück im Büro. Bitte wenden Sie sich in dringenden Fällen an Simon Schillings [simon.schilli...@rm-solutions.de] Viele Grüße, Michael Kettel ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help - '3rd last field'
Sehr geehrte Damen und Herren, ich bin ab dem 15.06.2009 wieder zurück im Büro. Bitte wenden Sie sich in dringenden Fällen an Simon Schillings [simon.schilli...@rm-solutions.de] Viele Grüße, Michael Kettel ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help - '3rd last field'
On Mon, Jun 8, 2009 at 4:29 PM, Tom Brown wrote:
> Hi
>
> I need some logic to work out a value for me - this value is _always_
> the 3rd last field in a string seperated by '.' but the string could be
> 5 or 6 fields long, e.g
>
> foo.bar.VALUE.baz.lala
>
> foor.bar.gigi.VALUE.baz.lala
>
> I need to find VALUE - if this were python or something i could do it
> but this has to be in shell -
awk -F\. {'print $3'}
awk -F\. {'print $5'}
awk -F\. {'print $6'}
--
Muhammad Panji
http://sumodirjo.wordpress.com
http://www.kurungsiku.web.id
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Re: [CentOS] script help - '3rd last field'
Sehr geehrte Damen und Herren, ich bin ab dem 15.06.2009 wieder zurück im Büro. Bitte wenden Sie sich in dringenden Fällen an Simon Schillings [simon.schilli...@rm-solutions.de] Viele Grüße, Michael Kettel ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help - '3rd last field'
Sehr geehrte Damen und Herren, ich bin ab dem 15.06.2009 wieder zurück im Büro. Bitte wenden Sie sich in dringenden Fällen an Simon Schillings [simon.schilli...@rm-solutions.de] Viele Grüße, Michael Kettel ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help - '3rd last field'
Sehr geehrte Damen und Herren, ich bin ab dem 15.06.2009 wieder zurück im Büro. Bitte wenden Sie sich in dringenden Fällen an Simon Schillings [simon.schilli...@rm-solutions.de] Viele Grüße, Michael Kettel ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help - '3rd last field'
Sehr geehrte Damen und Herren, ich bin ab dem 15.06.2009 wieder zurück im Büro. Bitte wenden Sie sich in dringenden Fällen an Simon Schillings [simon.schilli...@rm-solutions.de] Viele Grüße, Michael Kettel ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help - '3rd last field'
Sehr geehrte Damen und Herren, ich bin ab dem 15.06.2009 wieder zurück im Büro. Bitte wenden Sie sich in dringenden Fällen an Simon Schillings [simon.schilli...@rm-solutions.de] Viele Grüße, Michael Kettel ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help - '3rd last field'
Sehr geehrte Damen und Herren, ich bin ab dem 15.06.2009 wieder zurück im Büro. Bitte wenden Sie sich in dringenden Fällen an Simon Schillings [simon.schilli...@rm-solutions.de] Viele Grüße, Michael Kettel ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
[CentOS] script help - '3rd last field'
Hi I need some logic to work out a value for me - this value is _always_ the 3rd last field in a string seperated by '.' but the string could be 5 or 6 fields long, e.g foo.bar.VALUE.baz.lala foor.bar.gigi.VALUE.baz.lala I need to find VALUE - if this were python or something i could do it but this has to be in shell - Any clues? thanks ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
RE: [CentOS] script help
Michael D. Kralka wrote:
>
> Ross S. W. Walker wrote:
> >
> > Try:
> >
> > # find -type d -name dir-192.168.\* -exec mv \{\} `echo
> > \{\} | sed 's/192\.168\./10\.0\./'` \;
> >
> > That should recursively rename all directories from one
> naming scheme to
> > another.
>
> ... except for the fact that the `echo \{\} ...` will be evaluated by
> the shell and not find, so this is the same as:
>
> find -type d -name dir-192.168.\* -exec mv \{\} \{\} \;
>
> Not very useful ;)
Yes, thanks for pointing that out, it would have to be put into a
loop then.
# for dir in `find -type d -name dir-192.168.\* -print`; do
# mv $dir `echo $dir | sed 's/192\.168\./10\.0\./'`
# done
I also just saw the earlier post on the 'rename' command which does it
all for the OP and should be a lot faster then a shell script.
-Ross
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Re: [CentOS] script help
[EMAIL PROTECTED] wrote: Was there an problem with Frank's response from earlier? rename 192.168 10.0 dir* Bah! It's too simple! :-) -- Toby Bluhm Midwest Instruments Inc. 30825 Aurora Road Suite 100 Solon Ohio 44139 440-424-2240 ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help
Try:
# find -type d -name dir-192.168.\* -exec mv \{\} `echo \{\} | sed
's/192\.168\./10\.0\./'` \;
That should recursively rename all directories from one naming scheme to
another.
-Ross
-Original Message-
From: [EMAIL PROTECTED] <[EMAIL PROTECTED]>
To: CentOS mailing list
Sent: Fri Nov 02 09:28:45 2007
Subject: Re: [CentOS] script help
I run it but it has error.
sed 's/^dir-192\.168/dir-10\.0/'`
sed: read error on dir-192.168.0.31: Is a directory
--- Toby Bluhm <[EMAIL PROTECTED]> wrote:
> Toby Bluhm wrote:
> > adrian kok wrote:
> >> Hi Phil
> >>
> >> thank you
> >>
> >> But I have several hundred those pattern
> directories!
> >>
> >> I did think to cat those directories in a file
> >> "olddir"
> >>
> >> eg:
> >>
> >> dir-192.168.30.0 dir-192.168.30.144
> dir-192.168.30.184
> >>
> >>
> >> and sed 's/dir-192.168/dir-10.0/g' olddir >
> newdir
> >>
> >> but i don't know how to move
> >> rename the directories in olddir to newdir
> >>
> >> Thank you again
> >>
> >>
> >>
> >
> > Assuming dir-192.168* are all in one directory
> level, cd to that dir:
> >
> > for olddir in `ls -1 | grep dir-192.168`
> > do
> > newdir=`echo $olddir | sed
> 's/^dir-192.168/dir-10.0/'`
> > mv $olddir $newdir
> > done
> >
> >
>
> That sed line should be:
> 's/^dir-192\.168/dir-10\.0/'`
>
>
> --
> Toby Bluhm
> Midwest Instruments Inc.
> 30825 Aurora Road Suite 100
> Solon Ohio 44139
> 440-424-2240
>
>
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RE: [CentOS] script help
> > I run it but it has error. > > sed 's/^dir-192\.168/dir-10\.0/'` > sed: read error on dir-192.168.0.31: Is a directory > Was there an problem with Frank's response from earlier? rename 192.168 10.0 dir* It is a nice simple solution. You don't have to loop, or use extra commands, just copy and paste that one command to your machine, and all directories will be renamed. I just did it on 1000 directories, and it took 0.052 seconds: [EMAIL PROTECTED] test]$ ls -ld dir-192.168.0.* | wc -l 1000 [EMAIL PROTECTED] test]$ time rename 192.168 10.0 dir* real0m0.052s user0m0.012s sys 0m0.040s [EMAIL PROTECTED] test]$ ls -ld dir-10.0.0.* | wc -l 1000 Mike ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help
Ross S. W. Walker wrote:
>
> Try:
>
> # find -type d -name dir-192.168.\* -exec mv \{\} `echo
> \{\} | sed 's/192\.168\./10\.0\./'` \;
>
> That should recursively rename all directories from one naming scheme to
> another.
... except for the fact that the `echo \{\} ...` will be evaluated by
the shell and not find, so this is the same as:
find -type d -name dir-192.168.\* -exec mv \{\} \{\} \;
Not very useful ;)
Cheers,
Michael
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Re: [CentOS] script help
I run it but it has error. sed 's/^dir-192\.168/dir-10\.0/'` sed: read error on dir-192.168.0.31: Is a directory --- Toby Bluhm <[EMAIL PROTECTED]> wrote: > Toby Bluhm wrote: > > adrian kok wrote: > >> Hi Phil > >> > >> thank you > >> > >> But I have several hundred those pattern > directories! > >> > >> I did think to cat those directories in a file > >> "olddir" > >> > >> eg: > >> > >> dir-192.168.30.0 dir-192.168.30.144 > dir-192.168.30.184 > >> > >> > >> and sed 's/dir-192.168/dir-10.0/g' olddir > > newdir > >> > >> but i don't know how to move > >> rename the directories in olddir to newdir > >> > >> Thank you again > >> > >> > >> > > > > Assuming dir-192.168* are all in one directory > level, cd to that dir: > > > > for olddir in `ls -1 | grep dir-192.168` > > do > > newdir=`echo $olddir | sed > 's/^dir-192.168/dir-10.0/'` > > mv $olddir $newdir > > done > > > > > > That sed line should be: > 's/^dir-192\.168/dir-10\.0/'` > > > -- > Toby Bluhm > Midwest Instruments Inc. > 30825 Aurora Road Suite 100 > Solon Ohio 44139 > 440-424-2240 > > > ___ > CentOS mailing list > CentOS@centos.org > http://lists.centos.org/mailman/listinfo/centos > Send instant messages to your online friends http://uk.messenger.yahoo.com ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help
Toby Bluhm wrote: adrian kok wrote: Hi Phil thank you But I have several hundred those pattern directories! I did think to cat those directories in a file "olddir" eg: dir-192.168.30.0 dir-192.168.30.144 dir-192.168.30.184 and sed 's/dir-192.168/dir-10.0/g' olddir > newdir but i don't know how to move rename the directories in olddir to newdir Thank you again Assuming dir-192.168* are all in one directory level, cd to that dir: for olddir in `ls -1 | grep dir-192.168` do newdir=`echo $olddir | sed 's/^dir-192.168/dir-10.0/'` mv $olddir $newdir done That sed line should be: 's/^dir-192\.168/dir-10\.0/'` -- Toby Bluhm Midwest Instruments Inc. 30825 Aurora Road Suite 100 Solon Ohio 44139 440-424-2240 ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help
adrian kok wrote: Hi Phil thank you But I have several hundred those pattern directories! I did think to cat those directories in a file "olddir" eg: dir-192.168.30.0 dir-192.168.30.144 dir-192.168.30.184 and sed 's/dir-192.168/dir-10.0/g' olddir > newdir but i don't know how to move rename the directories in olddir to newdir Thank you again Assuming dir-192.168* are all in one directory level, cd to that dir: for olddir in `ls -1 | grep dir-192.168` do newdir=`echo $olddir | sed 's/^dir-192.168/dir-10.0/'` mv $olddir $newdir done -- Toby Bluhm Midwest Instruments Inc. 30825 Aurora Road Suite 100 Solon Ohio 44139 440-424-2240 ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help
On Fri, 02 Nov 2007 03:18:35 +0800 (CST) adrian kok <[EMAIL PROTECTED]> wrote: > But I have several hundred those pattern directories! What's wrong with the rename command? -- MELVILLE THEATRE ~ Melville Sask ~ http://www.melvilletheatre.com ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help
Hi Phil thank you But I have several hundred those pattern directories! I did think to cat those directories in a file "olddir" eg: dir-192.168.30.0 dir-192.168.30.144 dir-192.168.30.184 and sed 's/dir-192.168/dir-10.0/g' olddir > newdir but i don't know how to move rename the directories in olddir to newdir Thank you again --- Phil Schaffner <[EMAIL PROTECTED]> wrote: > On Fri, 2007-11-02 at 02:22 +0800, adrian kok wrote: > > Hi all > > > > how can I have script to rename the following > > directory pattern from > > > > > > > > from > > > > dir-192.168.30.0 > > dir-192.168.30.144 > > dir-192.168.30.184 > > > > > > To: > > > > > > dir-10.0.30.0 > > dir-10.0.30.144 > > dir-10.0.30.184 > > If you are just renaming directories, or files, and > not files in > directories, the following should work: > > for i in 0 144 184 ; do mv dir-192.168.30.$i > dir-10.0.30.$i ; done > > Or in a bit prettier form: > > for i in 0 144 184 > do > mv dir-192.168.30.$i dir-10.0.30.$i > done > > > Phil > > > ___ > CentOS mailing list > CentOS@centos.org > http://lists.centos.org/mailman/listinfo/centos > Send instant messages to your online friends http://uk.messenger.yahoo.com ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help
On Fri, 2007-11-02 at 02:22 +0800, adrian kok wrote: > Hi all > > how can I have script to rename the following > directory pattern from > > > > from > > dir-192.168.30.0 > dir-192.168.30.144 > dir-192.168.30.184 > > > To: > > > dir-10.0.30.0 > dir-10.0.30.144 > dir-10.0.30.184 If you are just renaming directories, or files, and not files in directories, the following should work: for i in 0 144 184 ; do mv dir-192.168.30.$i dir-10.0.30.$i ; done Or in a bit prettier form: for i in 0 144 184 do mv dir-192.168.30.$i dir-10.0.30.$i done Phil ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help
adrian kok wrote: Hi all how can I have script to rename the following directory pattern from from dir-192.168.30.0 dir-192.168.30.144 dir-192.168.30.184 To: dir-10.0.30.0 dir-10.0.30.144 dir-10.0.30.184 If this is to rename individual files from 192.168.30.0=>192.168.30.144 then for (( i = 0 ; i <= 143; i++ )) do mv 192.168.30.$i 10.0.30.$i done thank you You're welcome. http://www.freeos.com/guides/lsst/ -- James A. Peltier Technical Director, RHCE SCIRF | GrUVi @ Simon Fraser University - Burnaby Campus Phone : 778-782-3610 Fax : 778-782-3045 Mobile : 778-840-6434 E-Mail : [EMAIL PROTECTED] Website : http://gruvi.cs.sfu.ca | http://scirf.cs.sfu.ca MSN : [EMAIL PROTECTED] ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help
On Fri, 02 Nov 2007 02:22:30 +0800 (CST) adrian kok <[EMAIL PROTECTED]> wrote: > how can I have script to rename the following > directory pattern from > > dir-192.168.30.0To: dir-10.0.30.0 rename 192.168 10.0 dir* -- MELVILLE THEATRE ~ Melville Sask ~ http://www.melvilletheatre.com ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
[CentOS] script help
Hi all how can I have script to rename the following directory pattern from from dir-192.168.30.0 dir-192.168.30.144 dir-192.168.30.184 To: dir-10.0.30.0 dir-10.0.30.144 dir-10.0.30.184 thank you Send instant messages to your online friends http://uk.messenger.yahoo.com ___ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Re: [CentOS] script help
On Fri, Oct 26, 2007 at 06:56:05PM +0800, Anup Shukla wrote:
> MOUNTER=`ssh $i "mount | grep data | awk '{print \\$1,\\$2,\\$3}'"`
>
> This is what i tried and worked for me.
Why not be simpler, run the "mount" on the remote machine but the grep
and awk on the local machine; no quoting issue at all then
MOUNTER=`ssh $i mount | grep data | awk '{print $1,$2,$3}'`
(more network data, less remote processing)
--
rgds
Stephen
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Re: [CentOS] script help
Correction.
MOUNTER=`ssh $i "mount | grep data | awk '{print \\$1,\\$2,\\$3}'"`
This is what i tried and worked for me.
bingo! gold star - thanks!!
I need to query mount as these are nfs mounts configre by an automounter
and so not in the fstab
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Re: [CentOS] script help
On Fri, Oct 26, 2007 at 11:52:50AM +0100, Luciano Rocha wrote:
> On Fri, Oct 26, 2007 at 11:28:37AM +0100, Tom Brown wrote:
> > Hi
> >
> > I am sure the answer here is really easy but i am stuck!
> >
> > # mount | grep data | awk '{print$1,$2,$3}'
> >
> > gives me the info i require locally, however i need to execute this over
> > about 1000 hosts so i run things remotely using ssh something like
> >
> > # MOUNTER=`ssh $i 'mount | grep data | awk '{print$1,$2,$3}''`
> >
> > however this fails as at the end of the line there are 2 ticks eg '
> > together
> > -
> >
> > Can anyone offer me some syntax help please?
>
> Well, you don't need to run the grep and awk on the other side:
>
> MOUNTER=`ssh $i mount | awk '/data/{print $1,$2,$3}'`
>
> But you can live without the call to mount, too:
> MOUNTER=`ssh $i awk "'/data/{print $1,$2,$3}'" /etc/mtab`
Oops, wrong c&p:
MOUNTER=`ssh $i awk "'/data/{print \$1,\$2,\$3}'" /etc/mtab`
--
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Re: [CentOS] script help
On Fri, Oct 26, 2007 at 11:28:37AM +0100, Tom Brown wrote:
> Hi
>
> I am sure the answer here is really easy but i am stuck!
>
> # mount | grep data | awk '{print$1,$2,$3}'
>
> gives me the info i require locally, however i need to execute this over
> about 1000 hosts so i run things remotely using ssh something like
>
> # MOUNTER=`ssh $i 'mount | grep data | awk '{print$1,$2,$3}''`
>
> however this fails as at the end of the line there are 2 ticks eg ' together
> -
>
> Can anyone offer me some syntax help please?
Well, you don't need to run the grep and awk on the other side:
MOUNTER=`ssh $i mount | awk '/data/{print $1,$2,$3}'`
But you can live without the call to mount, too:
MOUNTER=`ssh $i awk "'/data/{print $1,$2,$3}'" /etc/mtab`
--
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Re: [CentOS] script help
Anup Shukla wrote:
Tom Brown wrote:
How about
# MOUNTER=`ssh $i "mount | grep data | awk '{print \$1,\$2,\$3}'"`
alas no
MOUNTER=`ssh $i 'mount | grep data | awk "{print \$1, \$2, \$3}"'`
results in
awk: {print , , }
awk:^ syntax error
awk: {print , , }
awk: ^ syntax error
awk: {print , , }
awk:^ syntax error
awk: cmd. line:1: {print , , }
awk: cmd. line:1: ^ unexpected newline or end of string
Sorry,
MOUNTER=`ssh $i 'mount | grep data | awk "{print \\$1,\\$2,\\$3}"'`
Correction.
MOUNTER=`ssh $i "mount | grep data | awk '{print \\$1,\\$2,\\$3}'"`
This is what i tried and worked for me.
Regards,
A.S
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Re: [CentOS] script help
Tom Brown wrote:
How about
# MOUNTER=`ssh $i "mount | grep data | awk '{print \$1,\$2,\$3}'"`
alas no
MOUNTER=`ssh $i 'mount | grep data | awk "{print \$1, \$2, \$3}"'`
results in
awk: {print , , }
awk:^ syntax error
awk: {print , , }
awk: ^ syntax error
awk: {print , , }
awk:^ syntax error
awk: cmd. line:1: {print , , }
awk: cmd. line:1: ^ unexpected newline or end of string
Sorry,
MOUNTER=`ssh $i 'mount | grep data | awk "{print \\$1,\\$2,\\$3}"'`
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Re: [CentOS] script help
How about
# MOUNTER=`ssh $i "mount | grep data | awk '{print \$1,\$2,\$3}'"`
alas no
MOUNTER=`ssh $i 'mount | grep data | awk "{print \$1, \$2, \$3}"'`
results in
awk: {print , , }
awk:^ syntax error
awk: {print , , }
awk: ^ syntax error
awk: {print , , }
awk:^ syntax error
awk: cmd. line:1: {print , , }
awk: cmd. line:1: ^ unexpected newline or end of string
oops and actually doing what you asked results in the same
MOUNTER=`ssh $i "mount | grep data | awk '{print \$1, \$2, \$3}'"`
awk: {print , , }
awk:^ syntax error
awk: {print , , }
awk: ^ syntax error
awk: {print , , }
awk:^ syntax error
awk: cmd. line:1: {print , , }
awk: cmd. line:1: ^ unexpected newline or end of string
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Re: [CentOS] script help
How about
# MOUNTER=`ssh $i "mount | grep data | awk '{print \$1,\$2,\$3}'"`
alas no
MOUNTER=`ssh $i 'mount | grep data | awk "{print \$1, \$2, \$3}"'`
results in
awk: {print , , }
awk:^ syntax error
awk: {print , , }
awk: ^ syntax error
awk: {print , , }
awk:^ syntax error
awk: cmd. line:1: {print , , }
awk: cmd. line:1: ^ unexpected newline or end of string
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Re: [CentOS] script help
Tom Brown wrote:
# MOUNTER=`ssh $i 'mount | grep data | awk '{print$1,$2,$3}''`
How about
# MOUNTER=`ssh $i "mount | grep data | awk '{print \$1,\$2,\$3}'"`
Regards
A.S
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Re: [CentOS] script help
On Oct 26, 2007, at 6:28, Tom Brown wrote:
I am sure the answer here is really easy but i am stuck!
Getting the quoting right for remote commands in the shell is never
an easy thing :-).
# mount | grep data | awk '{print$1,$2,$3}'
gives me the info i require locally, however i need to execute this
over about 1000 hosts so i run things remotely using ssh something
like
# MOUNTER=`ssh $i 'mount | grep data | awk '{print$1,$2,$3}''`
however this fails as at the end of the line there are 2 ticks eg '
together -
Can anyone offer me some syntax help please?
I can usually get this to work with some trial an error by doubling
up quotes and using backslahes but it's a frustrating experience.
Instead, I use a different technique: I put a script in a network
accessible place (i.e., a common NFS mount) and then use ssh to
execute that script.
Alfred
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[CentOS] script help
Hi
I am sure the answer here is really easy but i am stuck!
# mount | grep data | awk '{print$1,$2,$3}'
gives me the info i require locally, however i need to execute this over
about 1000 hosts so i run things remotely using ssh something like
# MOUNTER=`ssh $i 'mount | grep data | awk '{print$1,$2,$3}''`
however this fails as at the end of the line there are 2 ticks eg '
together -
Can anyone offer me some syntax help please?
thanks
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