Regular Expression Help

2011-06-14 Thread Patrick Kerley

I have a regular expression issue.

I have information that says:

~{Test Information/a/li


That in a series of processing should look like ~{Test Information}~/a/li
 
Any idea in a rereplace how I can replace anything that is ~{*/a/li with 
~{*}~/a/li

Thanks
Pat

-
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kerl...@yahoo.com


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Re: Regular Expression Help

2011-06-14 Thread Patrick Santora

If you'd like you can use the underlying java implementation of replaceAll.

Cfset str = ~{Test Information2/a/li~{Test Information/a/li~{Test
Information4/a/li~{Test Information/a/li /
cfdump var=#str.replaceAll( ([a-zA-Z0-9])/a/li, $1}~/a/li )#
/

Should show: ~{Test Information2}~/a/li~{Test
Information}~/a/li~{Test Information4}~/a/li~{Test
Information}~/a/li

-Pat

On Tue, Jun 14, 2011 at 7:49 AM, Patrick Kerley kerl...@yahoo.com wrote:


 I have a regular expression issue.

 I have information that says:

 ~{Test Information/a/li


 That in a series of processing should look like ~{Test
 Information}~/a/li

 Any idea in a rereplace how I can replace anything that is ~{*/a/li
 with ~{*}~/a/li

 Thanks
 Pat

 -
 Patrick Kerley
 kerl...@yahoo.com
 

 

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Re: Regular Expression Help

2011-06-14 Thread Patrick Santora

This might be more of what you are looking for. It captures special
characters as well and should fit more in line to what you want.

Cfset str = ~{Test Infor$%mation2$/a/li~{Test
Information/a/li~{Test Information4/a/li~{Test Information/a/li
/
cfdump var=#str.replaceAll( (~\{.*?)/a/li, $1}~/a/li )# /

2011/6/14 Patrick Santora patwe...@gmail.com

 If you'd like you can use the underlying java implementation of replaceAll.

 Cfset str = ~{Test Information2/a/li~{Test Information/a/li~{Test
 Information4/a/li~{Test Information/a/li /
 cfdump var=#str.replaceAll( ([a-zA-Z0-9])/a/li, $1}~/a/li )#
 /

 Should show: ~{Test Information2}~/a/li~{Test
 Information}~/a/li~{Test Information4}~/a/li~{Test
 Information}~/a/li

 -Pat


 On Tue, Jun 14, 2011 at 7:49 AM, Patrick Kerley kerl...@yahoo.com wrote:


 I have a regular expression issue.

 I have information that says:

 ~{Test Information/a/li


 That in a series of processing should look like ~{Test
 Information}~/a/li

 Any idea in a rereplace how I can replace anything that is ~{*/a/li
 with ~{*}~/a/li

 Thanks
 Pat

 -
 Patrick Kerley
 kerl...@yahoo.com
 

 

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Re: Regular Expression Help

2011-06-14 Thread Peter Boughton

Give this a go:

cfset Result = InputText.replaceAll
( '~\{(?:(?!/a).)+(?!\}~)(?=/a/li)'
, '$0}~'
) /


It uses the java replaceAll regex function so that it can do the negative 
lookbehind to ensure existing correct items are not changed, meaning it can be 
run multiple times.

Accepts any character (except newline) until it finds a closing A tag.

If newlines are required, that's just a one character change:

'~\{(?s:(?!/a).)+(?!\}~)(?=/a/li)'

(Which adds the 's' flag into what was a non-capturing group, meaning '.' also 
matches newlines.)


If there's the possibly of a '~{' appearing outside this context, it may need 
extra limits applied to work correctly.

Assuming there should not be any tags inside the ~{...}~ part, I would change 
the '.' for a '[^]' which makes it a bit 'safer':

'~\{(?:(?!/a)[^])+(?!\}~)(?=/a/li)' 

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Re: Regular Expression Help

2011-06-14 Thread Patrick Kerley

Thanks that did it.


I hate regular expressions (or maybe am in awe of their power) but you're my 
new best friend.


 
-
Patrick Kerley
kerl...@yahoo.com
-



From: Peter Boughton bought...@gmail.com
To: cf-talk cf-talk@houseoffusion.com
Sent: Tuesday, June 14, 2011 12:16 PM
Subject: Re: Regular Expression Help


Give this a go:

    cfset Result = InputText.replaceAll
        ( '~\{(?:(?!/a).)+(?!\}~)(?=/a/li)'
        , '$0}~'
        ) /


It uses the java replaceAll regex function so that it can do the negative 
lookbehind to ensure existing correct items are not changed, meaning it can be 
run multiple times.

Accepts any character (except newline) until it finds a closing A tag.

If newlines are required, that's just a one character change:

    '~\{(?s:(?!/a).)+(?!\}~)(?=/a/li)'

(Which adds the 's' flag into what was a non-capturing group, meaning '.' also 
matches newlines.)


If there's the possibly of a '~{' appearing outside this context, it may need 
extra limits applied to work correctly.

Assuming there should not be any tags inside the ~{...}~ part, I would change 
the '.' for a '[^]' which makes it a bit 'safer':

    '~\{(?:(?!/a)[^])+(?!\}~)(?=/a/li)' 



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Regular Expression help

2008-10-31 Thread Matthew Friedman
Please help, banging my head against a wall and my deadline is up...

I need to search a text filed of html formatted text to see if the user enter 
in bad words

I have it all set to go but the regexp is giving me trouble.

I am looping over the list of badwords and checking the variable skills.

cfif REFindnocase(([\]+#badword#+[\]),skills)

The issue is that if the word kiss is a bad word I need to be able to flag it 
if it is wrapped by html tags i.e. brkiss the pony/br and I only want kiss 
not kissing.

Please help with the regexp to get this done.
Thank you in advance.


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Re: Regular Expression help

2008-10-31 Thread Jason Fisher
I think you want something like this:

cfif REFindnocase(([\s\]#badword#[\s\]),skills)

You may want to expand it to non-alphanumeric wrappers, though, to catch 
punctuation: he gave her a kiss.

cfif REFindnocase(([\W]#badword#[\W]),skills)

which is the same as 

cfif REFindnocase(([^a-zA-Z0-9_]#badword#[^a-zA-Z0-9_]),skills)




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Re: Regular Expression help

2008-10-31 Thread Matthew Friedman
Not sure what I am doing wrong but this is not working.

I have the string kissess are goodbrkissbrthe girlfriend

Kiss is a badword, and this regexp is not picking it up.

Please advise and thanks for your help.

Matt

 I think you want something like this:
 
 cfif REFindnocase(([\s\]#badword#[\s\]),skills)
 
 You may want to expand it to non-alphanumeric wrappers, though, to 
 catch punctuation: he gave her a kiss.
 
 cfif REFindnocase(([\W]#badword#[\W]),skills)
 
 which is the same as 
 
 cfif REFindnocase(([^a-zA-Z0-9_]#badword#[^a-zA-Z0-9_]),skills)
 
 


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Re: Regular Expression help

2008-10-31 Thread Jason Fisher
Hm, that should work, certainly.  Did you try that 3rd option?

cfif REFindnocase(([^a-zA-Z0-9_]#badword#[^a-zA-Z0-9_]),skills)

That should find any use of the word 'kiss' when it's surrounded by any 
non-alpha characters.  Sadly I don't have access to my CF environment right at 
the moment, so I can't test :(


Not sure what I am doing wrong but this is not working.

I have the string kissess are goodbrkissbrthe girlfriend

Kiss is a badword, and this regexp is not picking it up.

Please advise and thanks for your help.

Matt 

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Re: Regular Expression help

2008-10-31 Thread Jason Fisher
Forgot about Ryan Swanson's slick little tool.  It certainly validates and 
picks up the middle 'kiss' in his validator, using either '\W' or '^a-zA-Z0-9_' 
as the filter:

http://ryanswanson.com/regexp/#start 

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Re: Regular Expression help

2008-10-31 Thread Matthew Friedman
Figured out the issue, this works great.

Thank you, thank you, thank you 

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Re: Regular Expression help

2008-10-31 Thread Matthew Friedman
I just found an issue with this regexp

cfif REFindnocase(([^a-zA-Z0-9_]#badword#[^a-zA-Z0-9_]),clean_skills)

this works great if it is not the first word or only word in the string.

what do I need to do to update the regexp to pick up the bad word it is the 
first last or only word in the string also.

Thank you again for all of your help.

Matt 

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Re: Regular Expression help

2008-10-31 Thread Sonny Savage
Typo: cfif REFindnocase(((^|\W)#badword#(\W|$)),clean_skills)


On Fri, Oct 31, 2008 at 1:09 PM, Sonny Savage [EMAIL PROTECTED] wrote:

 cfif REFindnocase(((^|\W)#badword#(\W|$),clean_skills)



 On Fri, Oct 31, 2008 at 1:04 PM, Matthew Friedman [EMAIL PROTECTED]wrote:

 I just found an issue with this regexp

 cfif REFindnocase(([^a-zA-Z0-9_]#badword#[^a-zA-Z0-9_]),clean_skills)

 this works great if it is not the first word or only word in the string.

 what do I need to do to update the regexp to pick up the bad word it is
 the first last or only word in the string also.

 Thank you again for all of your help.

 Matt

 

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Re: Regular Expression help

2008-10-31 Thread Jason Fisher
Good call.  Try this, seems to work in initial testing:

cfif REFindnocase(((^|[^a-zA-Z0-9_])#badword#([^a-zA-Z0-9_]|$)), 
clean_skills)



 I just found an issue with this regexp
 
 cfif REFindnocase(([^a-zA-Z0-9_]#badword#[^a-zA-Z0-9_]),
 clean_skills)
 
 this works great if it is not the first word or only word in the 
 string.
 
 what do I need to do to update the regexp to pick up the bad word it 
 is the first last or only word in the string also.
 
 Thank you again for all of your help.
 
 Matt 


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Re: Regular Expression help

2008-10-31 Thread Sonny Savage
cfif REFindnocase(((^|\W)#badword#(\W|$),clean_skills)


On Fri, Oct 31, 2008 at 1:04 PM, Matthew Friedman [EMAIL PROTECTED] wrote:

 I just found an issue with this regexp

 cfif REFindnocase(([^a-zA-Z0-9_]#badword#[^a-zA-Z0-9_]),clean_skills)

 this works great if it is not the first word or only word in the string.

 what do I need to do to update the regexp to pick up the bad word it is the
 first last or only word in the string also.

 Thank you again for all of your help.

 Matt

 

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Re: Regular Expression Help on Email Addresses

2007-02-21 Thread Eric Haskins
I am working on a variable mask version as I have time. This one will
atleast mask the domain for now.

Eric

On 2/20/07, Eric Haskins [EMAIL PROTECTED] wrote:

 cfset email = ReReplaceNocase(email,
 ([a-zA-Z0-9_\-\.]+)@((([a-zA-Z0-9\-]+\.)+))([a-zA-Z]{2,4}|[0-9]{1,3}),
 [EMAIL PROTECTED])/


 Try this one

 Eric




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Re: Regular Expression Help on Email Addresses

2007-02-21 Thread Eric Haskins
cfset variables.domainlen = Len(ReReplaceNocase(attributes.email,
([a-zA-Z0-9_\-\.]+)@((([a-zA-Z0-9\-]+\.)+))([a-zA-Z]{2,4}|[0-9]{1,3}),
\2)) - 1
cfset variables.mask = 
cfloop from=1 to=#variables.domainlen# index=i
 cfset variables.mask = variables.mask  *
/cfloop
cfset variables.email = ReReplaceNocase(attributes.email,
([a-zA-Z0-9_\-\.]+)@((([a-zA-Z0-9\-]+\.)+))([a-zA-Z]{2,4}|[0-9]{1,3}),
[EMAIL PROTECTED])/


Kind of a hack Im sure it can be done better but this works. Im still
learning :)

-- 
~Eric


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Regular Expression Help on Email Addresses

2007-02-20 Thread K Simanonok
I would like to use a regular expression to camouflage email addresses in a 
forum I'm building.  I'd like to replace just the domain name (not the .com or 
.net or other extension though) with x's:

FROM THIS:  [EMAIL PROTECTED]
TO THIS:[EMAIL PROTECTED]

Where the number of x's exactly matches the number of characters replaced.  
Make sense?  It should work with kludgy domain names having dashes in them too 
(are there any other characters allowed?  I don't think so) like so:

FROM THIS: [EMAIL PROTECTED]
TO THIS:   [EMAIL PROTECTED]

Can anyone help me out with this?  TIA

Karl S.

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Regular Expression Help on Email Addresses

2007-02-20 Thread K Simanonok
I would like to use a regular expression to camouflage email addresses in a 
forum I'm building.  I'd like to replace just the domain name (not the .com or 
.net or other extension though) with x's:

FROM THIS:  [EMAIL PROTECTED]
TO THIS:[EMAIL PROTECTED]

Where the number of x's exactly matches the number of characters replaced.  
Make sense?  It should work with kludgy domain names having dashes in them too 
(are there any other characters allowed?  I don't think so) like so:

FROM THIS: [EMAIL PROTECTED]
TO THIS:   [EMAIL PROTECTED]

Can anyone help me out with this?  TIA

Karl S.

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Re: Regular Expression Help on Email Addresses

2007-02-20 Thread Eric Haskins
cfset email = ReReplaceNocase(email,
([a-zA-Z0-9_\-\.]+)@((([a-zA-Z0-9\-]+\.)+))([a-zA-Z]{2,4}|[0-9]{1,3}),
[EMAIL PROTECTED])/


Try this one

Eric


On 2/20/07, K Simanonok [EMAIL PROTECTED] wrote:

 I would like to use a regular expression to camouflage email addresses in
 a forum I'm building.  I'd like to replace just the domain name (not the
 .com or .net or other extension though) with x's:

 FROM THIS:  [EMAIL PROTECTED]
 TO THIS:[EMAIL PROTECTED]

 Where the number of x's exactly matches the number of characters
 replaced.  Make sense?  It should work with kludgy domain names having
 dashes in them too (are there any other characters allowed?  I don't think
 so) like so:

 FROM THIS: [EMAIL PROTECTED]
 TO THIS:   [EMAIL PROTECTED]

 Can anyone help me out with this?  TIA

 Karl S.

 

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Regular Expression Help on Email Addresses

2007-02-20 Thread K Simanonok
I would like to use a regular expression to camouflage email addresses in a 
forum I'm building.  I'd like to replace just the domain name (not the .com or 
.net or other extension though) with x's:

FROM THIS:  [EMAIL PROTECTED]
TO THIS:[EMAIL PROTECTED]

Where the number of x's exactly matches the number of characters replaced.  
Make sense?  It should work with kludgy domain names having dashes in them too 
(are there any other characters allowed?  I don't think so) like so:

FROM THIS: [EMAIL PROTECTED]
TO THIS:   [EMAIL PROTECTED]

Can anyone help me out with this?  TIA

Karl S.

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Re: Regular Expression Help on Email Addresses

2007-02-20 Thread Ben Doom
Offhand, I think your best bet is to use a regex to identify everything 
from the @ to the TLD, then use the len returned by refind to do a 
replace of it.  There are a number of really good regexes for 
finding/dissecting emails out there.  CFLib.org is a good place to start.

--Ben Doom

K Simanonok wrote:
 I would like to use a regular expression to camouflage email addresses in a 
 forum I'm building.  I'd like to replace just the domain name (not the .com 
 or .net or other extension though) with x's:
 
 FROM THIS:  [EMAIL PROTECTED]
 TO THIS:[EMAIL PROTECTED]
 
 Where the number of x's exactly matches the number of characters replaced.  
 Make sense?  It should work with kludgy domain names having dashes in them 
 too (are there any other characters allowed?  I don't think so) like so:
 
 FROM THIS: [EMAIL PROTECTED]
 TO THIS:   [EMAIL PROTECTED]
 
 Can anyone help me out with this?  TIA
 
 Karl S.
 
 

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Regular Expression Help

2007-01-29 Thread Lee.S.Surma
How would you do numbers under one hundred with a limit of 7 decimals?

 

Lee Surma

Applications Systems Engineer

Wells Fargo Corporate Trust

[EMAIL PROTECTED]

612-667-4066

 



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RE: Regular Expression Help

2007-01-29 Thread Ben Nadel
Not really sure what exactly you are looking to do, but the regular
expression pattern for numbers under 100 with 7 decimals would be:

\d{2}(\.\d{1,7})?

This makes the decimal optional (with 1 to 7 decimal places). Of course,
this does not protect AGAINST numbers over one hundred. For that you
would need to use a java-style negative look behind (not available in
standard CF RE functions):

(?!\d{1})\d{2}(\.\d{1,7})?(?!\d{1})

This should make sure you only find the valid numbers ( I think ).


..
Ben Nadel
Certified Advanced ColdFusion MX7 Developer
www.bennadel.com
 
Need ColdFusion Help?
www.bennadel.com/ask-ben/

-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] 
Sent: Monday, January 29, 2007 10:06 AM
To: CF-Talk
Subject: Regular Expression Help

How would you do numbers under one hundred with a limit of 7 decimals?

 

Lee Surma

Applications Systems Engineer

Wells Fargo Corporate Trust

[EMAIL PROTECTED]

612-667-4066

 





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Re: Regular Expression Help

2007-01-29 Thread Ben Doom
Ben Nadel wrote:
 Not really sure what exactly you are looking to do, but the regular
 expression pattern for numbers under 100 with 7 decimals would be:
 
 \d{2}(\.\d{1,7})?

I'd anchor it, assuming that this is supposed to be the whole string:

^\d{2}(\.\d{1,7})?$

--Ben Doom

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RE: Regular Expression Help

2007-01-29 Thread Ben Nadel
Well played. 


..
Ben Nadel
Certified Advanced ColdFusion MX7 Developer
www.bennadel.com
 
Need ColdFusion Help?
www.bennadel.com/ask-ben/

-Original Message-
From: Ben Doom [mailto:[EMAIL PROTECTED] 
Sent: Monday, January 29, 2007 11:22 AM
To: CF-Talk
Subject: Re: Regular Expression Help

Ben Nadel wrote:
 Not really sure what exactly you are looking to do, but the regular 
 expression pattern for numbers under 100 with 7 decimals would be:
 
 \d{2}(\.\d{1,7})?

I'd anchor it, assuming that this is supposed to be the whole string:

^\d{2}(\.\d{1,7})?$

--Ben Doom



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RE: Regular Expression Help

2007-01-29 Thread Bobby Hartsfield
That would not match 0 through 9.999 unless they were formatted into 2
digit numbers like 00, 01, etc... 09.999 It also wouldn’t match anything
between 1 and 0 like .999 unless it was formatted like 00.999

Try this one: ^\d{0,2}(\.\d{1,7})?$

I don’t know what you are using it for but there is also the possibility of
negative numbers. The above will not match them either. You could say ... if
(regex matches number OR number LT 100) to get the negatives if it matters.

cheers

-- 
No virus found in this outgoing message.
Checked by AVG Free Edition.
Version: 7.5.432 / Virus Database: 268.17.14/657 - Release Date: 1/29/2007
9:04 AM
 



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RE: Regular Expression Help....

2007-01-24 Thread Ben Nadel
Dave,

While you probably don't need this anymore, I thought I would post it up
here as your question inspired my blog post:

http://www.bennadel.com/blog/487-Using-Verbose-Regular-Expressions-To-Ex
plain-Url-Auto-Linking-In-ColdFusion.htm
[ OR http://bennadel.com/index.cfm?dax=blog:486.view ]

Cheers.


..
Ben Nadel
Certified Advanced ColdFusion MX7 Developer
www.bennadel.com
 
Need ColdFusion Help?
www.bennadel.com/ask-ben/

-Original Message-
From: Dave Phillips [mailto:[EMAIL PROTECTED] 
Sent: Tuesday, January 23, 2007 9:36 AM
To: CF-Talk
Subject: Regular Expression Help

Hi,

RegExp's are not my forte and I need to create a function that will
extract URL's from a body of text and return it in a list.

I have a function that extracts the anchor tags from a document, but I
need to acurately extract the URL from that anchor tag.  I can do a find
for 'href' and so on, but the RIGHT regular expression would make sure
all possibilities are covered like href=, href=' or href= or href = and
so on.

Can anyone help please?

Thanks!

Dave



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RE: Regular Expression Help....

2007-01-24 Thread Dave Phillips
Here's what I ended up using:

https?:)\/\/))[-[:alnum:]\?%,\.\/##!@:=\+~_]+[A-Za-z0-9\/])

Thanks to Bobby Hartsfield for that!

It seems to get everything I need and nothing I don't.  Here's the whole
function in case anyone wants it:

function extractURLs(inputString) {

var nPos=0;
var lsURLs = ;
var sDelimiter = chr(9);
var nEndPos = ;
var sLink = ;
var sRegExp =
https?:)\/\/))[-[:alnum:]\?%,\.\/##!@:=\+~_]+[A-Za-z0-9\/]);

if(arrayLen(arguments) eq 2) {
sDelimiter = arguments[2];
}
nPos = reFindNoCase(sRegExp,inputString);
while(nPos) {
inputString =
mid(inputString,nPos,len(inputString));
nEndPos = reFind(['#chr(34)# ],inputString);
sLink = left(inputString,nEndPos-1);
// Remove trailing slash if it exists so we don't
end up with duplicates.
if(right(sLink,1) EQ /) {
sLink = left(sLink,len(sLink)-1);
}
if( NOT listFindNoCase(lsURLs, sLink,
sDelimiter)) {
lsURLs = listAppend(lsURLs, sLink,
sDelimiter);
}
nEndPos = findNoCase(/a,inputString);
inputString =
mid(inputString,nEndPos+4,len(inputString));
nPos = reFindNoCase(sRegExp,inputString);
}

return lsURLs;
}



-Original Message-
From: Eric Haskins [mailto:[EMAIL PROTECTED] 
Sent: Tuesday, January 23, 2007 11:31 PM
To: CF-Talk
Subject: Re: Regular Expression Help


Dave how did it turn out??

~Eric




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Regular Expression Help....

2007-01-23 Thread Dave Phillips
Hi,

RegExp's are not my forte and I need to create a function that will extract 
URL's from a body of text and return it in a list.

I have a function that extracts the anchor tags from a document, but I need to 
acurately extract the URL from that anchor tag.  I can do a find for 'href' and 
so on, but the RIGHT regular expression would make sure all possibilities are 
covered like href=, href=' or href= or href = and so on.

Can anyone help please?

Thanks!

Dave

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RE: Regular Expression Help....

2007-01-23 Thread Andy Matthews
This page might get you pointed in the right direction.

http://foad.org/~abigail/Perl/url2.html
 

-Original Message-
From: Dave Phillips [mailto:[EMAIL PROTECTED] 
Sent: Tuesday, January 23, 2007 8:36 AM
To: CF-Talk
Subject: Regular Expression Help

Hi,

RegExp's are not my forte and I need to create a function that will extract
URL's from a body of text and return it in a list.

I have a function that extracts the anchor tags from a document, but I need
to acurately extract the URL from that anchor tag.  I can do a find for
'href' and so on, but the RIGHT regular expression would make sure all
possibilities are covered like href=, href=' or href= or href = and so on.

Can anyone help please?

Thanks!

Dave



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RE: Regular Expression Help....

2007-01-23 Thread Andy Matthews
This one might be better:
http://www.manamplified.org/archives/000318.html 

-Original Message-
From: Andy Matthews [mailto:[EMAIL PROTECTED] 
Sent: Tuesday, January 23, 2007 9:50 AM
To: CF-Talk
Subject: RE: Regular Expression Help

This page might get you pointed in the right direction.

http://foad.org/~abigail/Perl/url2.html
 

-Original Message-
From: Dave Phillips [mailto:[EMAIL PROTECTED]
Sent: Tuesday, January 23, 2007 8:36 AM
To: CF-Talk
Subject: Regular Expression Help

Hi,

RegExp's are not my forte and I need to create a function that will extract
URL's from a body of text and return it in a list.

I have a function that extracts the anchor tags from a document, but I need
to acurately extract the URL from that anchor tag.  I can do a find for
'href' and so on, but the RIGHT regular expression would make sure all
possibilities are covered like href=, href=' or href= or href = and so on.

Can anyone help please?

Thanks!

Dave





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Re: Regular Expression Help....

2007-01-23 Thread Dave Phillips
Thanks, I'm working on something with that now, but does anyone know if there 
is a function or tag out there someone has already written that does this?  It 
seems that I should not be the first person who needs to feed a function a body 
of text and get back a list of the URL's in that text.

Thanks,

Dave

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Re: Regular Expression Help.... (Solution?)

2007-01-23 Thread Dave Phillips
I think I have a solution, but if a few of you could review and see if it can 
be any faster or more efficient (or if I'm missing something) I'd appreciate 
it.  To find the end of the URL I'm looking for a single quote, double quote or 
space.

function extractURLs(inputString) {

var nPos=0;
var lsURLs = ;
var sDelimiter = chr(9);
var nEndPos = ;
var sLink = ;
var sRegExp = 
([A-Za-z][A-Za-z0-9+.-]{1,120}:[A-Za-z0-9/](([A-Za-z0-9$_.+!*,;/?:@~=-])|%[A-Fa-f0-9]{2}){1,333}(##([a-zA-Z0-9][a-zA-Z0-9$_.+!*,;/?:@~=%-]{0,1000}))?);

if(arrayLen(arguments) eq 2) {
sDelimiter = arguments[2];
}
nPos = reFindNoCase(sRegExp,inputString);
while(nPos) {
inputString = mid(inputString,nPos,len(inputString));
nEndPos = reFind(['#chr(34)# ],inputString);
sLink = left(inputString,nEndPos-1);
if(NOT listFindNoCase(lsURLs,sLink,sDelimiter)) {
lsURLs = listAppend(lsURLs, sLink, sDelimiter);
}
inputString = mid(inputString,nEndPos,len(inputString));
nPos = reFindNoCase(sRegExp,inputString);
}

return lsURLs;
}

Thanks!

Dave

 Hi,
 
 RegExp's are not my forte and I need to create a function that will 
 extract URL's from a body of text and return it in a list.
 
 I have a function that extracts the anchor tags from a document, but I 
 need to acurately extract the URL from that anchor tag.  I can do a 
 find for 'href' and so on, but the RIGHT regular expression would make 
 sure all possibilities are covered like href=, href=' or href= or 
 href = and so on.
 
 Can anyone help please?
 
 Thanks!
 
Dave

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RE: Regular Expression Help....

2007-01-23 Thread Ben Nadel
Dave,

This snippet takes your regular expression and returns all matches in an
array:

http://www.bennadel.com/index.cfm?dax=snippets:11.view

You can then take that and convert it to a list (but I would guess
keeping it in an array is the way to go). 

After that, all you need is a good RegExp, which it looks like other
people have already provided.

Keep in mind, this snippet is for use with JAVA regular expression,
which are slightly different but same idea.


..
Ben Nadel
Certified Advanced ColdFusion MX7 Developer
www.bennadel.com
 
Need ColdFusion Help?
www.bennadel.com/ask-ben/

-Original Message-
From: Dave Phillips [mailto:[EMAIL PROTECTED] 
Sent: Tuesday, January 23, 2007 9:55 AM
To: CF-Talk
Subject: Re: Regular Expression Help

Thanks, I'm working on something with that now, but does anyone know if
there is a function or tag out there someone has already written that
does this?  It seems that I should not be the first person who needs to
feed a function a body of text and get back a list of the URL's in that
text.

Thanks,

Dave



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RE: Regular Expression Help.... (Solution?)

2007-01-23 Thread Ben Nadel
Oh sorry, I didn't see the Solution email before I posted my last
snippet. What you are doing below is fine. I cannot attest to the RegEx.
You might want to try grabbing something of of RegExLib.com if you are
unsure. I do know you should probably check for period . to end a URL,
but do not confuse with file extension. URLs are a tricky beast. 


..
Ben Nadel
Certified Advanced ColdFusion MX7 Developer
www.bennadel.com
 
Need ColdFusion Help?
www.bennadel.com/ask-ben/

-Original Message-
From: Dave Phillips [mailto:[EMAIL PROTECTED] 
Sent: Tuesday, January 23, 2007 10:25 AM
To: CF-Talk
Subject: Re: Regular Expression Help (Solution?)

I think I have a solution, but if a few of you could review and see if
it can be any faster or more efficient (or if I'm missing something) I'd
appreciate it.  To find the end of the URL I'm looking for a single
quote, double quote or space.

function extractURLs(inputString) {

var nPos=0;
var lsURLs = ;
var sDelimiter = chr(9);
var nEndPos = ;
var sLink = ;
var sRegExp =
([A-Za-z][A-Za-z0-9+.-]{1,120}:[A-Za-z0-9/](([A-Za-z0-9$_.+!*,;/?:@~=-
])|%[A-Fa-f0-9]{2}){1,333}(##([a-zA-Z0-9][a-zA-Z0-9$_.+!*,;/?:@~=%-]{0,
1000}))?);

if(arrayLen(arguments) eq 2) {
sDelimiter = arguments[2];
}
nPos = reFindNoCase(sRegExp,inputString);
while(nPos) {
inputString = mid(inputString,nPos,len(inputString));
nEndPos = reFind(['#chr(34)# ],inputString);
sLink = left(inputString,nEndPos-1);
if(NOT listFindNoCase(lsURLs,sLink,sDelimiter)) {
lsURLs = listAppend(lsURLs, sLink, sDelimiter);
}
inputString = mid(inputString,nEndPos,len(inputString));
nPos = reFindNoCase(sRegExp,inputString);
}

return lsURLs;
}

Thanks!

Dave

 Hi,
 
 RegExp's are not my forte and I need to create a function that will 
 extract URL's from a body of text and return it in a list.
 
 I have a function that extracts the anchor tags from a document, but I

 need to acurately extract the URL from that anchor tag.  I can do a 
 find for 'href' and so on, but the RIGHT regular expression would make

 sure all possibilities are covered like href=, href=' or href= or 
 href = and so on.
 
 Can anyone help please?
 
 Thanks!
 
Dave



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Re: Regular Expression Help....

2007-01-23 Thread Dave Phillips
Hi,

The RegExp below is giving me more than I want.  It is returning things that I 
don't want:

mailto:
urn:schemas-microsoft-com:office:office

and others.  I want to chnage it to only return url's starting with http: or 
https:.  Here's what I currently have:

([A-Za-z][A-Za-z0-9+.-]{1,120}:[A-Za-z0-9/](([A-Za-z0-9$_.+!*,;/?:@~=-])|%[A-Fa-f0-9]{2}){1,333}(##([a-zA-Z0-9][a-zA-Z0-9$_.+!*,;/?:@~=%-]{0,1000}))?)

I think I want something like this, but it doesn't seem to be working right:

([http|https]:[A-Za-z0-9/](([A-Za-z0-9$_.+!*,;/?:@~=-])|%[A-Fa-f0-9]{2}){1,333}(##([a-zA-Z0-9][a-zA-Z0-9$_.+!*,;/?:@~=%-]{0,1000}))?)

Can someone clear this up for me please?

Thanks,

Dave

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Re: Regular Expression Help....

2007-01-23 Thread Eric Haskins
When I test it tells me not enough (

I am troubleshooting it now  out sick today but list draws me back
everytime lol

Eric


On 1/23/07, Dave Phillips [EMAIL PROTECTED] wrote:

 Hi,

 The RegExp below is giving me more than I want.  It is returning things
 that I don't want:

 mailto:
 urn:schemas-microsoft-com:office:office

 and others.  I want to chnage it to only return url's starting with http:
 or https:.  Here's what I currently have:


 ([A-Za-z][A-Za-z0-9+.-]{1,120}:[A-Za-z0-9/](([A-Za-z0-9$_.+!*,;/?:@~=-])|%[A-Fa-f0-9]{2}){1,333}(##([a-zA-Z0-9][a-zA-Z0-9$_.+!*,;/?:@~=%-]{0,1000}))?)

 I think I want something like this, but it doesn't seem to be working
 right:


 ([http|https]:[A-Za-z0-9/](([A-Za-z0-9$_.+!*,;/?:@~=-])|%[A-Fa-f0-9]{2}){1,333}(##([a-zA-Z0-9][a-zA-Z0-9$_.+!*,;/?:@~=%-]{0,1000}))?)

 Can someone clear this up for me please?

 Thanks,

 Dave

 

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RE: Regular Expression Help....

2007-01-23 Thread Bobby Hartsfield
Try this one

https?:)\/\/)|(www\.|ftp\.))[-[:alnum:]\?%,\.\/##!@:=\+~_]+[A-Za-z0-9\/
])



-Original Message-
From: Dave Phillips [mailto:[EMAIL PROTECTED] 
Sent: Tuesday, January 23, 2007 2:03 PM
To: CF-Talk
Subject: Re: Regular Expression Help

Hi,

The RegExp below is giving me more than I want.  It is returning things that
I don't want:

mailto:
urn:schemas-microsoft-com:office:office

and others.  I want to chnage it to only return url's starting with http: or
https:.  Here's what I currently have:

([A-Za-z][A-Za-z0-9+.-]{1,120}:[A-Za-z0-9/](([A-Za-z0-9$_.+!*,;/?:@~=-])|%[
A-Fa-f0-9]{2}){1,333}(##([a-zA-Z0-9][a-zA-Z0-9$_.+!*,;/?:@~=%-]{0,1000}))?)

I think I want something like this, but it doesn't seem to be working right:

([http|https]:[A-Za-z0-9/](([A-Za-z0-9$_.+!*,;/?:@~=-])|%[A-Fa-f0-9]{2}){1,
333}(##([a-zA-Z0-9][a-zA-Z0-9$_.+!*,;/?:@~=%-]{0,1000}))?)

Can someone clear this up for me please?

Thanks,

Dave



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Re: Regular Expression Help....

2007-01-23 Thread Eric Haskins
(?:href=|href=|href=')((?:http|https)://(.+))(?:|'|)

Does this help at all??? This will find all http or https links??

Eric

On 1/23/07, Eric Haskins [EMAIL PROTECTED] wrote:

 When I test it tells me not enough (

 I am troubleshooting it now  out sick today but list draws me back
 everytime lol

 Eric


  On 1/23/07, Dave Phillips [EMAIL PROTECTED] wrote:
 
  Hi,
 
  The RegExp below is giving me more than I want.  It is returning things
  that I don't want:
 
  mailto:
  urn:schemas-microsoft-com:office:office
 
  and others.  I want to chnage it to only return url's starting with
  http: or https:.  Here's what I currently have:
 
  ([A-Za-z][A-Za-z0-9+.-]{1,120}:[A-Za-z0-9/](([A-Za-z0-9$_.+!*,;/?:@~=-])|%[A-Fa-f0-9]{2}){1,333}(##([a-zA-Z0-9][a-zA-Z0-9$_.+!*,;/?:@~=%-]{0,1000}))?)
 
 
  I think I want something like this, but it doesn't seem to be working
  right:
 
  ([http|https]:[A-Za-z0-9/](([A-Za-z0-9$_.+!*,;/?:@~=-])|%[A-Fa-f0-9]{2}){1,333}(##([a-zA-Z0-9][a-zA-Z0-9$_.+!*,;/?:@~=%-]{0,1000}))?)
 
 
  Can someone clear this up for me please?
 
  Thanks,
 
  Dave
 
  

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RE: Regular Expression Help....

2007-01-23 Thread Bobby Hartsfield
Oops, that had ftp in it...

Try this... I took out the www since you apparently only wanted links that
started with http:// and https://

https?:)\/\/))[-[:alnum:]\?%,\.\/##!@:=\+~_]+[A-Za-z0-9\/])

-Original Message-
From: Dave Phillips [mailto:[EMAIL PROTECTED] 
Sent: Tuesday, January 23, 2007 2:03 PM
To: CF-Talk
Subject: Re: Regular Expression Help

Hi,

The RegExp below is giving me more than I want.  It is returning things that
I don't want:

mailto:
urn:schemas-microsoft-com:office:office

and others.  I want to chnage it to only return url's starting with http: or
https:.  Here's what I currently have:

([A-Za-z][A-Za-z0-9+.-]{1,120}:[A-Za-z0-9/](([A-Za-z0-9$_.+!*,;/?:@~=-])|%[
A-Fa-f0-9]{2}){1,333}(##([a-zA-Z0-9][a-zA-Z0-9$_.+!*,;/?:@~=%-]{0,1000}))?)

I think I want something like this, but it doesn't seem to be working right:

([http|https]:[A-Za-z0-9/](([A-Za-z0-9$_.+!*,;/?:@~=-])|%[A-Fa-f0-9]{2}){1,
333}(##([a-zA-Z0-9][a-zA-Z0-9$_.+!*,;/?:@~=%-]{0,1000}))?)

Can someone clear this up for me please?

Thanks,

Dave



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Re: Regular Expression Help....

2007-01-23 Thread Eric Haskins
Dave how did it turn out??

~Eric


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Regular Expression Help

2006-04-13 Thread cf coder
Hello Everybody,

I'm having problems writing a regular expression. I'm trying to pass a string 
to flash and want to strip off and replace the html tags with a br tag but 
also leave any b, span, i, strong, div, br, and p tags. 

This is what I've done so far:

cfscript
function StripHTML(str) {
return REReplaceNoCase(str,[^]*,br,ALL);
}
/cfscript

cfse logtext = tabletrtdpThis is not real text/p/td/tr
trtdbFriday 17 march, 2006/b/td/tr/table

cfset str = StripHTML(logtext)

The above function strips out any html tag and replaces it with a br tag. 
This is fine but I want to keep the span, i, b, strong, div, br, 
p tags and dont know how to tell it to ignore these tags and replace 
everything else with a  and  angle brackets.

Can someone please help me with this. I am just not good at this sort of things.

Thanks,
cfcoder

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Regular expression help

2005-08-10 Thread John Munyan
Hi, I have an url such as
http://www.blah.com/something/somethingelse/default.cfm stored in a
database. I wish to use this information as links to others site which
have similar reviews.   I would like to parse down the full url to on
the domain i.e. http://www.blah.com http://www.blah.com/  - for
display purposes.  I have searched around trying to find an example and
have been unsuccessful.  Does anyone have any pointers to how to parse
the domain out of the url?  The nearest I have found is
#REReplace(getsimilarlinks.linkurl,\?.*$,)#.  

 

Thanks,

 

John

 

Interested in Hiking in Washington State?  Check out
http://www.attrition.ws http://www.attrition.ws/ 

 

 



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RE: Regular expression help

2005-08-10 Thread Jim Davis
 -Original Message-
 From: John Munyan [mailto:[EMAIL PROTECTED]
 Sent: Wednesday, August 10, 2005 3:03 AM
 To: CF-Talk
 Subject: Regular expression help
 
 Hi, I have an url such as
 http://www.blah.com/something/somethingelse/default.cfm stored in a
 database. I wish to use this information as links to others site which
 have similar reviews.   I would like to parse down the full url to on
 the domain i.e. http://www.blah.com http://www.blah.com/  - for
 display purposes.  I have searched around trying to find an example and
 have been unsuccessful.  Does anyone have any pointers to how to parse
 the domain out of the url?  The nearest I have found is
 #REReplace(getsimilarlinks.linkurl,\?.*$,)#.

If all of your links are fully formed like that you don't need regexs at all
- just treat the URL as a list delimited by a forward slash (/).

Since CF condenses multiple delimiters I think this will give you your URL:

cfset Link = http://www.blah.com/something/somethingelse/default.cfm  /

cfset JustDomainLink = ListGetAt(Link, 1, /)  //  ListGetAt(Link, 2,
/) /

Using the ListGetAt() for the first part (the protocol) is important to
catch none http links like https: and ftp:.

Jim Davis




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Regular Expression help

2005-05-31 Thread Rey Bango
Guys,

I have the following email check but it won't accept a .info email 
address. I'm not a regular expression expert and was hoping someone 
could help me out with this. How could I update the following script to 
accept domain suffixes other than .com, .net  .org?

function isEmail(str) {
   // are regular expressions supported?
   var supported = 0;
   if (window.RegExp) {
 var tempStr = a;
 var tempReg = new RegExp(tempStr);
 if (tempReg.test(tempStr)) supported = 1;
   }
   if (!supported)
 return (str.indexOf(.)  2)  (str.indexOf(@)  0);
   var r1 = new RegExp((@.*@)|(\\.\\.)|(@\\.)|(^\\.));
   var r2 = new 
RegExp(^.+\\@(\\[?)[a-zA-Z0-9\\-\\.]+\\.([a-zA-Z]{2,3}|[0-9]{1,3})(\\]?)$);
   return (!r1.test(str)  r2.test(str));
   }

Rey...

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Re: Regular Expression help

2005-05-31 Thread Rey Bango
I found the fix guys!!! Amazing what a little Googling will do. :P

Rey...

Rey Bango wrote:
 Guys,
 
 I have the following email check but it won't accept a .info email 
 address. I'm not a regular expression expert and was hoping someone 
 could help me out with this. How could I update the following script to 
 accept domain suffixes other than .com, .net  .org?
 
 function isEmail(str) {
// are regular expressions supported?
var supported = 0;
if (window.RegExp) {
  var tempStr = a;
  var tempReg = new RegExp(tempStr);
  if (tempReg.test(tempStr)) supported = 1;
}
if (!supported)
  return (str.indexOf(.)  2)  (str.indexOf(@)  0);
var r1 = new RegExp((@.*@)|(\\.\\.)|(@\\.)|(^\\.));
var r2 = new 
 RegExp(^.+\\@(\\[?)[a-zA-Z0-9\\-\\.]+\\.([a-zA-Z]{2,3}|[0-9]{1,3})(\\]?)$);
return (!r1.test(str)  r2.test(str));
}
 
 Rey...
 
 

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Regular Expression Help

2004-11-05 Thread Daniel Farmer
I'm searching a long string and looking for the value

input type=hidden name=BV_SessionID value=any value here

what kind of syntax would I use to grab the value of the above tag.

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RE: Regular Expression Help

2004-11-05 Thread Pascal Peters
REReplaceNoCase(text,'^.*input type=hidden name=BV_SessionID
value=([^]*).*$',\1)

Pascal

 -Original Message-
 From: Daniel Farmer [mailto:[EMAIL PROTECTED]
 Sent: 05 November 2004 10:24
 To: CF-Talk
 Subject: Regular Expression Help
 
 I'm searching a long string and looking for the value
 
 input type=hidden name=BV_SessionID value=any value here
 
 what kind of syntax would I use to grab the value of the above tag.
 
 

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Re: Regular Expression Help

2004-11-05 Thread Daniel Farmer
Thanks Pascal... but I am having problems implementing

cfset theval = #REFind('^.*input type=hidden name=BV_SessionID 
value=([^]*).*$',\1,)#, cfhttp.filecontent, startpos )#  

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RE: Regular Expression Help

2004-11-05 Thread Gavin Brook
Pascal,

  Would it be possible for you to explain a bit more about what each part of
the RegEx is doing? I'm trying to do something similar and I'm having no end
of trouble getting the RegEx right. MM documentation is pretty thin on more
advanced matching.

Thanks,

Gavin

-Original Message-
From: Pascal Peters [mailto:[EMAIL PROTECTED] 
Sent: 05 November 2004 10:43
To: CF-Talk
Subject: RE: Regular Expression Help


REReplaceNoCase(text,'^.*input type=hidden name=BV_SessionID
value=([^]*).*$',\1)

Pascal

 -Original Message-
 From: Daniel Farmer [mailto:[EMAIL PROTECTED]
 Sent: 05 November 2004 10:24
 To: CF-Talk
 Subject: Regular Expression Help
 
 I'm searching a long string and looking for the value
 
 input type=hidden name=BV_SessionID value=any value here
 
 what kind of syntax would I use to grab the value of the above tag.
 
 



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RE: Regular Expression Help

2004-11-05 Thread Pascal Peters
cfset theval = REReplaceNoCase(cfhttp.filecontent,'^.*input
type=hidden name=BV_SessionID value=([^]*).*$',\1)

Pascal

 -Original Message-
 From: Daniel Farmer [mailto:[EMAIL PROTECTED]
 Sent: 05 November 2004 11:10
 To: CF-Talk
 Subject: Re: Regular Expression Help
 
 Thanks Pascal... but I am having problems implementing
 
 cfset theval = #REFind('^.*input type=hidden name=BV_SessionID
 value=([^]*).*$',\1,)#, cfhttp.filecontent, startpos )# 
 
 

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RE: Regular Expression Help

2004-11-05 Thread Pascal Peters
^ beginning of string
.* any character, any number of times
... literal string
([^]*) any character except , any number of times (grouped for
backreferencing)
.* see above
$ end of string

The \1 matches the first group saved for backreferencing. I forgot the
quotes in my original post.

If you are looking for resources:
Printed: 
- Ben Forta's book is very good for beginners
- Mastering Regular Expressions frm O'Reilly (the regexp bible, more
advanced)
Online: http://www.regular-expressions.info/

Pascal

 -Original Message-
 From: Gavin Brook [mailto:[EMAIL PROTECTED]
 Sent: 05 November 2004 12:11
 To: CF-Talk
 Subject: RE: Regular Expression Help
 
 Pascal,
 
   Would it be possible for you to explain a bit more about what each
part
 of
 the RegEx is doing? I'm trying to do something similar and I'm having
no
 end
 of trouble getting the RegEx right. MM documentation is pretty thin on
 more
 advanced matching.
 
 Thanks,
 
 Gavin
 
 -Original Message-
 From: Pascal Peters [mailto:[EMAIL PROTECTED]
 Sent: 05 November 2004 10:43
 To: CF-Talk
 Subject: RE: Regular Expression Help
 
 
 REReplaceNoCase(text,'^.*input type=hidden name=BV_SessionID
 value=([^]*).*$',\1)
 
 Pascal
 
  -Original Message-
  From: Daniel Farmer [mailto:[EMAIL PROTECTED]
  Sent: 05 November 2004 10:24
  To: CF-Talk
  Subject: Regular Expression Help
 
  I'm searching a long string and looking for the value
 
  input type=hidden name=BV_SessionID value=any value here
 
  what kind of syntax would I use to grab the value of the above tag.
 
 
 
 
 
 

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Regular expression help with dictionary definitions

2004-07-13 Thread Paul Vernon
Ok,

This one is killing me.. And my CFMX server...

Currently I'm using the following code to parse some text:

cfset teststr = definition
cfset st = ReFindNoCase({[^}]*}, teststr,
1, true)
cfloop condition=st.pos[1] GT 0
	cfset replaceme = mid(teststr,
st.pos[1], st.len[1])
	cfset theword = mid(replaceme, 2,
len(replaceme)-2)
	cfset teststr =
ReplaceNoCase(teststr, replaceme, a
href="">
heword#/a, all)
	cfset st = ReFindNoCase({[^}]*},
teststr, 1, true)
/cfloop

The text usually resembles something like the first example below and by the
time the parser has run, everything inside the parentheses are turned into
hyperlinks..

Fungi \Fungi\, n. pl. (Bot.)
A group of thallophytic plants of low organization, destitute
of chlorophyll, in which reproduction is mainly accomplished
by means of asexual spores, which are produced in a great
variety of ways, though sexual reproduction is known to occur
in certain {Phycomycetes}, or so-called algal fungi.

Note: The Fungi appear to have originated by degeneration
from various alg[ae], losing their chlorophyll on
assuming a parasitic or saprophytic life. By some they
are divided into the subclasses {Phycomycetes}, the
lower or algal fungi; the {Mesomycetes}, or
intermediate fungi; and the {Mycomycetes}, or the
higher fungi; by others into the {Phycomycetes}; the
{Ascomycetes}, or sac-spore fungi; and the
{Basidiomycetes}, or basidial-spore fungi.

My problem is that I have just discovered is that of nested parentheses...
Using the code above the process goes into an infinite loop and eats all
available RAM in about 30 seconds

The following text kills my algorithm!

Cryptogamia \Cryp`to*gami*a\ (kr?p`t?-g?m?-?), n.; pl.
{Cryptogami[ae]} (-?). [NL., fr. Gr. krypto`s hidden, secret
+ ga`mos marriage.] (Bot.)
The series or division of flowerless plants, or those never
having true stamens and pistils, but propagated by spores of
various kinds.

Note: The subdivisions have been variously arranged. The
following arrangement recognizes four classes: -- I.
{{Pteridophyta}, or {Vascular Acrogens}.} These include
Ferns, {Equiseta} or Scouring rushes, {Lycopodiace[ae]}
or Club mosses, {Selaginelle[ae]}, and several other
smaller orders. Here belonged also the extinct coal
plants called {Lepidodendron}, {Sigillaria}, and
{Calamites}. II. {{Bryophita}, or {Cellular Acrogens}}.
These include {Musci}, or Mosses, {Hepatic[ae]}, or
Scale mosses and Liverworts, and possibly
{Charace[ae]}, the Stoneworts. III. {{Alg[ae]}}, which
are divided into {Floride[ae]}, the Red Seaweeds, and
the orders {Dictyote[ae]}, {O[o]spore[ae]},
{Zo[o]spore[ae]}, {Conjugat[ae]}, {Diatomace[ae]}, and
{Cryptophyce[ae]}. IV. {{Fungi}}. The molds, mildews,
mushrooms, puffballs, etc., which are variously grouped
into several subclasses and many orders. The {Lichenes}
or Lichens are now considered to be of a mixed nature,
each plant partly a Fungus and partly an Alga.

One solution would be to repeatedly pre-parse the text to remove or escape
the extra parentheses but I'm not inclined to do this as I believe I should
be able to fix my regular _expression_ which is currently {[^}]*}.

Does anyone have any suggestions???

Thanks in advance

Paul
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RE: Regular expression help with dictionary definitions

2004-07-13 Thread Pascal Peters
If this is the actual code you are using, you are creating an infinite
loop because you always start looking at the start position 1 in your
REFind. It will keep matching the first {}.

It really depends what you are trying to grab. If you are trying to get
only the inner parentheses it is not too hard. Now for the solution:

teststr = REReplaceNoCase(teststr,\{([^{}]+)\},{a
href="">
},all);

Not tested, but it should work.

Pascal

 -Original Message-
 From: Paul Vernon [mailto:[EMAIL PROTECTED]
 Sent: 13 July 2004 18:17
 To: CF-Talk
 Subject: Regular _expression_ help with dictionary definitions
 
 Ok,
 
 This one is killing me.. And my CFMX server...
 
 Currently I'm using the following code to parse some text:
 
 cfset teststr = definition
 cfset st = ReFindNoCase({[^}]*},
teststr,
 1, true)
 cfloop condition=st.pos[1] GT 0
 	cfset replaceme = mid(teststr,
 st.pos[1], st.len[1])
 	cfset theword = mid(replaceme,
2,
 len(replaceme)-2)
 	cfset teststr =
 ReplaceNoCase(teststr, replaceme, a

href="">

 #t
 heword#/a, all)
 	cfset st =
ReFindNoCase({[^}]*},
 teststr, 1, true)
 /cfloop

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RE: FIXED - Regular expression help with dictionary definitions

2004-07-13 Thread Paul Vernon
Sorry for the original and long post... I fixed it...

The regular _expression_ changed to {[^{^}]*} and I changed the startpos for
the next REFindNoCase so it skipped the nesting issues...

cfset st = ReFindNoCase({[^{^}]*},
teststr, 1, true)
cfloop condition=st.pos[1] GT 0
	cfset replaceme = mid(teststr,
st.pos[1], st.len[1])
	cfset theword = mid(replaceme, 2,
len(replaceme)-2)
	
	cfset replacestr = a
href="">
heword#/a
	cfset teststr =
ReplaceNoCase(teststr, replaceme, replacestr, all)
	cfset st =
ReFindNoCase({[^{^}]*}, teststr, st.pos[1]+len(replacestr), true)
/cfloop

Paul
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RE: FIXED - Regular expression help with dictionary definitions

2004-07-13 Thread Pascal Peters
This is not exactly what you are trying to say: 

[^{^}] == anything but { or } or ^
Correct: [^{}]

Pascal

PS Give the REReplace with the backreferencing (see my previous post) a
shot. It is only 1 line to do the same thing.

 -Original Message-
 From: Paul Vernon [mailto:[EMAIL PROTECTED]
 Sent: 13 July 2004 18:45
 To: CF-Talk
 Subject: RE: FIXED - Regular _expression_ help with dictionary
definitions
 
 Sorry for the original and long post... I fixed it...
 
 The regular _expression_ changed to {[^{^}]*} and I changed the startpos
for
 the next REFindNoCase so it skipped the nesting issues...

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RE: FIXED - Regular expression help with dictionary definitions

2004-07-13 Thread Paul Vernon
 PS Give the REReplace with the backreferencing (see my previous post) a
 shot. It is only 1 line to do the same thing.

Pascal, you are a STAR!

 
The backreferencing wasn't quite there as I wanted to remove all of the
extra parentheses also but a simple replacelist wrapped around your elegant
solution fixed that...

 
The results can be seen at
http://www.web-architect.co.uk/cfx_dict.cfm?dictionary=web1913
http://www.web-architect.co.uk/cfx_dict.cfm?dictionary=web1913phrase=Fungi
 phrase=Fungi

 
Thanks again

 
Paul
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RE: FIXED - Regular expression help with dictionary definitions

2004-07-13 Thread Pascal Peters
Don't do the replace, just don't include the {} in the REreplace.
Although I may have overlooked something: You really should do a
URLEncodedFormat() of the word (which doesn't work with the
backreferencing). 

function MakeLinks(text,dictionary){
	var st = StructNew();
	var start = 1;
	var word = ;
	var link = ;
	while(true){
		st = REFind(\{([^{}]+)\},text,start,true);
		if(st.pos[1] IS 0) break;
		word = Mid(text,st.pos[2],st.len[2]);
		text = RemoveChars(text,st.pos[1],st.len[1]);
		link = a
href="">
dFormat(word)##word#/a
;
		text = Insert(link,text,st.pos[1]-1);
		start = st.pos[1] + Len(link);
	}
	return text;
}

Pascal

 -Original Message-
 From: Paul Vernon [mailto:[EMAIL PROTECTED]
 Sent: 13 July 2004 19:06
 To: CF-Talk
 Subject: RE: FIXED - Regular _expression_ help with dictionary
definitions
 
  PS Give the REReplace with the backreferencing (see my previous
post) a
  shot. It is only 1 line to do the same thing.
 
 Pascal, you are a STAR!
 
 The backreferencing wasn't quite there as I wanted to remove all of
the
 extra parentheses also but a simple replacelist wrapped around your
 elegant
 solution fixed that...
 
 The results can be seen at
 http://www.web-architect.co.uk/cfx_dict.cfm?dictionary=web1913
 http://www.web-
 architect.co.uk/cfx_dict.cfm?dictionary=web1913phrase=Fungi
  phrase=Fungi
 
 Thanks again
 
 Paul
 
 
 
 

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RE: Regular Expression Help

2004-05-18 Thread Pascal Peters
On CFMX 

stTmp = REFindNoCase('msg:(.*?);',str,1,true);
if(stTmp.pos[1]){
	message = Mid(str,stTmp.pos[2],stTmp.len[2]);
}
else {
	message = ;
}

ON CF5

stTmp = REFindNoCase('msg:(([^]|[^;])*);',str,1,true);
if(stTmp.pos[1]){
	message = Mid(str,stTmp.pos[2],stTmp.len[2]);
}
else {
	message = ;
}

 -Original Message-
 From: Ian [mailto:[EMAIL PROTECTED] 
 Sent: maandag 17 mei 2004 22:39
 To: CF-Talk
 Subject: Regular _expression_ Help
 
 I'm trying to parse a string and pluck a bit of text, but my 
 regex isn't working :( Here's a sample string:
 
 (msg:My Message Here; content:My Content Here;)
 
 I want to return My Message Here.
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Regular Expression Help

2004-05-17 Thread Ian
I'm trying to parse a string and pluck a bit of text, but my regex
isn't working :( Here's a sample string:

(msg:My Message Here; content:My Content Here;)

I want to return My Message Here.

And here's my regex:

refindnocase(msg:[[:print:]]+;, mystring)

I'm using print as mystring may contain any printable characters.

This returns 0 as the position. Any ideas?

Ian
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RE: Regular Expression Help

2004-05-17 Thread Marlon Moyer
This should work.

cfset test = (msg:My Message Here; content:My Content Here;)

cfset temp = refindnocase(msg:([^;]*),test,1,yes)

cfloop from=1 to=#arraylen(temp.pos)# index=i
	cfoutput#mid(test,temp.pos[i],temp.len[i])#br/cfoutput
/cfloop

-- 
Marlon Moyer, Sr. Internet Developer
American Contractors Insurance Group
phone: 972.687.9445
fax: 972.687.0607
mailto:[EMAIL PROTECTED]
www.acig.com

 -Original Message-
 From: Ian [mailto:[EMAIL PROTECTED]
 Sent: Monday, May 17, 2004 3:39 PM
 To: CF-Talk
 Subject: Regular _expression_ Help
 
 I'm trying to parse a string and pluck a bit of text, but my regex
 isn't working :( Here's a sample string:
 
 (msg:My Message Here; content:My Content Here;)
 
 I want to return My Message Here.
 
 And here's my regex:
 
 refindnocase(msg:[[:print:]]+;, mystring)
 
 I'm using print as mystring may contain any printable characters.
 
 This returns 0 as the position. Any ideas?
 
 Ian
 
 
 

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RE: Regular expression help

2004-02-17 Thread Pascal Peters
cfscript
regexp = ##[[:space:]]*([0-9]{2-3});
stTmp = REFindNoCase(regexp,str,1,true);
if(stTmp.pos[1])
	result = Mid(str,stTmp.pos[2],stTmp.len[2]);
else
	result = ;
/cfscript

If you need to find all, you do it in a loop: 

cfscript
regexp = ##[[:space:]]*([0-9]{2-3});
results = ArrayNew(1);
start = 1;
while(true){
	stTmp = REFindNoCase(regexp,str,start,true);
	if(stTmp.pos[1]){
		ArrayAppend(results,Mid(str,stTmp.pos[2],stTmp.len[2]));
		start = stTmp.pos[1] + stTmp.len[1];
	}
	else break;
}
/cfscript

Probably you want to make sure that the character after the 2-3 digits
is not a digit. If so, modify the regexp to
regexp = ##[[:space:]]*([0-9]{2-3})([^0-9]|$);

On CFMX you could use negative lookahead:
regexp = ##\s*(\d{2,3})(?!\d);

Pascal

 -Original Message-
 From: Andy Ousterhout [mailto:[EMAIL PROTECTED] 
 Sent: dinsdag 17 februari 2004 0:05
 To: CF-Talk
 Subject: Regular _expression_ help
 
 What regular _expression_ would find a # followed by any 
 number of blanks, followed by 2-3 numbers
 
 For example, I want to return 45 from this string:
 
 Testing this string # 45 to 46
 
 Andy
 
 

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Regular expression help

2004-02-16 Thread Andy Ousterhout
What regular _expression_ would find a # followed by any number of blanks,
followed by 2-3 numbers

For example, I want to return 45 from this string:

Testing this string # 45 to 46

Andy
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RE: Regular expression help

2004-02-16 Thread Matthew Walker
How about this?

cfset result = reFind(##[[:space:]]*([[:digit:]]+), myString, 1, true)

cfif result.pos[1]

cfoutput#mid(myString, result.pos[2],
result.len[2])#/cfoutput

/cfif

-Original Message-
From: Andy Ousterhout [mailto:[EMAIL PROTECTED] 
Sent: Tuesday, 17 February 2004 11:05 a.m.
To: CF-Talk
Subject: Regular _expression_ help

What regular _expression_ would find a # followed by any number of blanks,
followed by 2-3 numbers

For example, I want to return 45 from this string:

Testing this string # 45 to 46

Andy

_
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I'm gonna need some regular expression help here...

2003-10-13 Thread Jeff
Got a cfinput, it's required, and the validation is a regular _expression_.

The Problem: The regular _expression_ isn't allowing a capital letter after
the '@'. I'm sure there are other faults with this regular _expression_, but
you see...I'm just not there yet when it comes to troubleshooting these
things, so I thought I'd paste the relevant portion here hoping for some,
miracle regular _expression_ person to jump in and gimme a hand.

Ready?

Here it is:

validate=regular_expression
pattern=^[_a-z0-9-]+(\.[_a-z0-9-]+)[EMAIL PROTECTED](\.[a-z0-9-]+)*\.(([a-z]{2,3
})|(aero|coop|info|museum|name))$

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RE: I'm gonna need some regular expression help here...

2003-10-13 Thread Bosky, Dave
Here's a nice little _expression_ I use.
var chkEmail=
/^([\w-]+(?:\.[\w-]+)*)@((?:[\w-]+\.)*\w[\w-]{0,66})\.([a-z]{2,6}(?:\.[a-z]{
2})?)$/i;

 
if ((form.Email.value.length  6 ) || (chkEmail.test(form.Email.value) ==
false)) {
var msg= Email address entry error!\n\nPlease a valid email
address!\n\nClick OK to continue.;
alert (msg);
form.Email.focus();
return false;
 }

 
~Dave

-Original Message-
From: Jeff [mailto:[EMAIL PROTECTED] 
Sent: Monday, October 13, 2003 11:42 AM
To: CF-Talk
Subject: I'm gonna need some regular _expression_ help here...

Got a cfinput, it's required, and the validation is a regular _expression_.

The Problem: The regular _expression_ isn't allowing a capital letter after
the '@'. I'm sure there are other faults with this regular _expression_, but
you see...I'm just not there yet when it comes to troubleshooting these
things, so I thought I'd paste the relevant portion here hoping for some,
miracle regular _expression_ person to jump in and gimme a hand.

Ready?

Here it is:

validate=regular_expression
pattern=^[_a-z0-9-]+(\.[_a-z0-9-]+)[EMAIL PROTECTED](\.[a-z0-9-]+)*\.(([a-z]{2,3
})|(aero|coop|info|museum|name))$

_


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Re: I'm gonna need some regular expression help here...

2003-10-13 Thread Ben Doom
This regex was intended to be used with a case-insensitive regular 
_expression_ checker.To make it case insensitive, there are two things 
you'll have to do.

replace a-z in brackets with a-zA-Z

replace each of aero, coop, info, museum, and name with EVERYPOSSIBLE 
CAPITALIZATION POSSIBILITY.

If I were you, I would probably do my email format validation on the 
backend.

--Ben Doom

Jeff wrote:

 Got a cfinput, it's required, and the validation is a regular _expression_.
 
 The Problem: The regular _expression_ isn't allowing a capital letter after
 the '@'. I'm sure there are other faults with this regular _expression_, but
 you see...I'm just not there yet when it comes to troubleshooting these
 things, so I thought I'd paste the relevant portion here hoping for some,
 miracle regular _expression_ person to jump in and gimme a hand.
 
 Ready?
 
 Here it is:
 
 validate=regular_expression
 pattern=^[_a-z0-9-]+(\.[_a-z0-9-]+)[EMAIL PROTECTED](\.[a-z0-9-]+)*\.(([a-z]{2,3
 })|(aero|coop|info|museum|name))$
 
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Re: I'm gonna need some regular expression help here...

2003-10-13 Thread Thomas Chiverton
On Monday 13 Oct 2003 17:01 pm, Ben Doom wrote:
 replace each of aero, coop, info, museum, and name with EVERYPOSSIBLE
 CAPITALIZATION POSSIBILITY.

Or alternatively, don't bother checking the TLD against a static list, because 
eventualy a new one will crop up, and you'll wind people up who have one.
There are still sites I can't use with my .info address.

-- 
Tom Chiverton 
Advanced ColdFusion Programmer

Tel: +44(0)1749 834997
email: [EMAIL PROTECTED]
BlueFinger Limited
Underwood Business Park
Wookey Hole Road, WELLS. BA5 1AF
Tel: +44 (0)1749 834900
Fax: +44 (0)1749 834901
web: www.bluefinger.com
Company Reg No: 4209395 Registered Office: 2 Temple Back East, Temple
Quay, BRISTOL. BS1 6EG.
*** This E-mail contains confidential information for the addressee
only. If you are not the intended recipient, please notify us
immediately. You should not use, disclose, distribute or copy this
communication if received in error. No binding contract will result from
this e-mail until such time as a written document is signed on behalf of
the company. BlueFinger Limited cannot accept responsibility for the
completeness or accuracy of this message as it has been transmitted over
public networks.***

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Re: I'm gonna need some regular expression help here...

2003-10-13 Thread Ben Doom
I use:
^[a-zA-Z]([.]?([[:alnum:]_-]+[.]?)*[[:alnum:]_-])?@([[:alnum:]\-_]+\.)+[a-zA-Z]{2,4}$
which, admittedly, won't allow .museum addresses, but will match most 
common emails.

--Ben Doom

Thomas Chiverton wrote:

 On Monday 13 Oct 2003 17:01 pm, Ben Doom wrote:
 replace each of aero, coop, info, museum, and name with EVERYPOSSIBLE
 CAPITALIZATION POSSIBILITY.
 
 Or alternatively, don't bother checking the TLD against a static list, 
 because
 eventualy a new one will crop up, and you'll wind people up who have one.
 There are still sites I can't use with my .info address.
 
 -- 
 Tom Chiverton
 Advanced ColdFusion Programmer
 
 Tel: +44(0)1749 834997
 email: [EMAIL PROTECTED]
 BlueFinger Limited
 Underwood Business Park
 Wookey Hole Road, WELLS. BA5 1AF
 Tel: +44 (0)1749 834900
 Fax: +44 (0)1749 834901
 web: www.bluefinger.com
 Company Reg No: 4209395 Registered Office: 2 Temple Back East, Temple
 Quay, BRISTOL. BS1 6EG.
 *** This E-mail contains confidential information for the addressee
 only. If you are not the intended recipient, please notify us
 immediately. You should not use, disclose, distribute or copy this
 communication if received in error. No binding contract will result from
 this e-mail until such time as a written document is signed on behalf of
 the company. BlueFinger Limited cannot accept responsibility for the
 completeness or accuracy of this message as it has been transmitted over
 public networks.***
 
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Regular Expression Help

2003-09-26 Thread kelly
 Ok I suck at reg expressions.Basically I have some data and within the data there is some stuff I want to remove.Example text text a href="" href="http://www.blah.comblah">http://www.blah.comblah blah blah blah/a text text Ok basically I want to remove everything from a href through /a although it will be different on every line. So I need code that will look for a href and the ending of /a and remove all text inbetween (including the a href and /a of course.) leaving just text text text text.(note text is simply an example the verbiage will differ everytime, the only consistency is the a href etc. SUggestions? Kelly
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Re: Regular Expression Help

2003-09-26 Thread Ben Doom
What version of CF?--Ben the RegEx Ninja Doomkelly wrote:Ok I suck at reg expressions.Basically I have some data and within the data there is some stuff I want to remove.Example  text text a href="" href="http://www.blah.comblah">http://www.blah.comblah http://www.blah.comblah  blah blah blah/a text text  Ok basically I want to remove everything from a href through /a although it will be different on every line. So I need code that will look for a href and the ending of /a and remove all text inbetween (including the a href and /a of course.) leaving just text text text text.(note text is simply an example the verbiage will differ everytime, the only consistency is the a href etc.  SUggestions? Kelly 
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Re: Regular Expression Help

2003-09-26 Thread Claude Schneegans
Ok basically I want to remove everything from a href through /a althoughit will be different on every line.This is tipically the situation why I developed CF_REextract (seehttp://www.contentbox.com/claude/customtags/tagstore.cfm?p=hf(see specs and examples)The tag will find all occurences, and return then in a query.You can then loop in the query and rebuild the string with the parts you want simply using the mid() function.The tag will even get your file from disk or HTTP the page for you if you want.
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Repost: Regular Expression Help

2003-08-14 Thread Patricia G . L . Hall
I tried to post this yesterday from the archives and I screwed it up.  
So.. reposting.

I am dealing with a site that has been ripped apart by search and 
replace
in Homesite+.  Tags that used to look like:

td
 select name=sel_costarts size=20 
class=formSelectColumnsLarge

td width=60nbsp;/td

td colspan=3img src=images/main_header.jpg width=371
height=148/td

Have had the  stripped off of the td and now look like this:

td
 select name=sel_costarts size=20 
class=formSelectColumnsLarge

td width=60nbsp;/td

td colspan=3img src=images/main_header.jpg width=371
height=148/td

I need a regular expression that I can use in Homesite+ to locate all
victims.  I found a regex that I tried to hack and modify, but I only
barely know regex.  The hack has found a bunch, but I'd like more expert
help if I could.  This is the regex I used (which located all of the
examples above).

td[a-zA-Z0-9]* [^]*

Can anyone help me do better?

Thanks - Patti

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Re: Repost: Regular Expression Help

2003-08-12 Thread Patricia G . L . Hall
Thanks... it did.  I'm going to bang on it for a while, and if the  
weekend doesn't go well, then I'll pop over to the regex list...

-Patti

On Friday, August 8, 2003, at 05:29  PM, Ben Doom wrote:

 Well, there are some things you can do here, but nothing's going to be
 perfect.

 Let me restate:  it would be more work to create a regex to handle  
 every
 case than to just to a find  replace on things.

 Start with the most complicated common case.  Let's say it's a td with  
 a
 width.  Your regex might look something like this:
 td width=([[:digit:]]+%?)
 and your replace would look like this:
 td width=\1

 The problem is that there's no really good way for you to define how  
 much
 the regex should match, since there are a really wide variety of  
 things you
 can stick in a td, both legally and otherwise.

 Anyway, I'd start with your most complicated case and work back down  
 to a
 plain td.  From there, you ought to (hopefully) be able to tweak it by  
 hand
 fairly easily.

 If not, or you want to explore this more thoroughly, or just want a  
 better
 explanation of how the regex works or whatnot, I'd point you to the  
 CF-RegEx
 list, where Ninjas are standing by.  Seriously, there are several guys  
 over
 there who, between us, generally can take on just about anything:
 http://www.houseoffusion.com/cf_lists/ 
 index.cfm?method=threadsforumid=21

 HTH.


 --  Ben Doom
 Programmer  General Lackey
 Moonbow Software, Inc

 : -Original Message-
 : From: Patricia G. L. Hall [mailto:[EMAIL PROTECTED]
 : Sent: Friday, August 08, 2003 8:41 AM
 : To: CF-Talk
 : Subject: Repost: Regular Expression Help
 :
 :
 : I tried to post this yesterday from the archives and I screwed it up.
 : So.. reposting.
 :
 : I am dealing with a site that has been ripped apart by search and
 : replace
 : in Homesite+.  Tags that used to look like:
 :
 : td
 :  select name=sel_costarts size=20
 : class=formSelectColumnsLarge
 :
 : td width=60nbsp;/td
 :
 : td colspan=3img src=images/main_header.jpg width=371
 : height=148/td
 :
 : Have had the  stripped off of the td and now look like this:
 :
 : td
 :  select name=sel_costarts size=20
 : class=formSelectColumnsLarge
 :
 : td width=60nbsp;/td
 :
 : td colspan=3img src=images/main_header.jpg width=371
 : height=148/td
 :
 : I need a regular expression that I can use in Homesite+ to locate all
 : victims.  I found a regex that I tried to hack and modify, but I only
 : barely know regex.  The hack has found a bunch, but I'd like more  
 expert
 : help if I could.  This is the regex I used (which located all of the
 : examples above).
 :
 : td[a-zA-Z0-9]* [^]*
 :
 : Can anyone help me do better?
 :
 : Thanks - Patti
 :
 :
 
~|
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RE: Repost: Regular Expression Help

2003-08-09 Thread Ben Doom
Well, there are some things you can do here, but nothing's going to be
perfect.

Let me restate:  it would be more work to create a regex to handle every
case than to just to a find  replace on things.

Start with the most complicated common case.  Let's say it's a td with a
width.  Your regex might look something like this:
td width=([[:digit:]]+%?)
and your replace would look like this:
td width=\1

The problem is that there's no really good way for you to define how much
the regex should match, since there are a really wide variety of things you
can stick in a td, both legally and otherwise.

Anyway, I'd start with your most complicated case and work back down to a
plain td.  From there, you ought to (hopefully) be able to tweak it by hand
fairly easily.

If not, or you want to explore this more thoroughly, or just want a better
explanation of how the regex works or whatnot, I'd point you to the CF-RegEx
list, where Ninjas are standing by.  Seriously, there are several guys over
there who, between us, generally can take on just about anything:
http://www.houseoffusion.com/cf_lists/index.cfm?method=threadsforumid=21

HTH.


--  Ben Doom
Programmer  General Lackey
Moonbow Software, Inc

: -Original Message-
: From: Patricia G. L. Hall [mailto:[EMAIL PROTECTED]
: Sent: Friday, August 08, 2003 8:41 AM
: To: CF-Talk
: Subject: Repost: Regular Expression Help
:
:
: I tried to post this yesterday from the archives and I screwed it up.
: So.. reposting.
:
: I am dealing with a site that has been ripped apart by search and
: replace
: in Homesite+.  Tags that used to look like:
:
: td
:  select name=sel_costarts size=20
: class=formSelectColumnsLarge
:
: td width=60nbsp;/td
:
: td colspan=3img src=images/main_header.jpg width=371
: height=148/td
:
: Have had the  stripped off of the td and now look like this:
:
: td
:  select name=sel_costarts size=20
: class=formSelectColumnsLarge
:
: td width=60nbsp;/td
:
: td colspan=3img src=images/main_header.jpg width=371
: height=148/td
:
: I need a regular expression that I can use in Homesite+ to locate all
: victims.  I found a regex that I tried to hack and modify, but I only
: barely know regex.  The hack has found a bunch, but I'd like more expert
: help if I could.  This is the regex I used (which located all of the
: examples above).
:
: td[a-zA-Z0-9]* [^]*
:
: Can anyone help me do better?
:
: Thanks - Patti
:
: 
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Regular Expression Help

2002-12-06 Thread Jeff D. Chastain
I am trying to use a regular expression to change all possible special
characters in a string to underscores because I am trying to use the
string as a variable name.

Regular expressions are not my specialty and I am running into problems
using some characters in my reReplace function.

Could somebody offer some suggestions on making this work?

I am needing to replace !@#$%^*()-+={[}]|\:;',.?/ plus a blank
space, all with the _ character.

Thanks
-- Jeff

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RE: Regular Expression Help

2002-12-06 Thread Joshua Miller
 ReReplaceNoCase(string,[[:punct:]],_,ALL)

Joshua Miller
Head Programmer / IT Manager
Garrison Enterprises Inc.
www.garrisonenterprises.net
[EMAIL PROTECTED]
(704) 569-9044 ext. 254
 

*
Any views expressed in this message are those of the individual sender,
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This e-mail is intended only for the individual or entity to which it is
addressed and contains information that is private and confidential. If
you are not the intended recipient you are hereby notified that any
dissemination, distribution or copying is strictly prohibited. If you 
have received this e-mail in error please delete it immediately and
advise us by return e-mail to [EMAIL PROTECTED]

*


-Original Message-
From: Jeff D. Chastain [mailto:[EMAIL PROTECTED]] 
Sent: Friday, December 06, 2002 12:31 PM
To: CF-Talk
Subject: Regular Expression Help


I am trying to use a regular expression to change all possible special
characters in a string to underscores because I am trying to use the
string as a variable name.

Regular expressions are not my specialty and I am running into problems
using some characters in my reReplace function.

Could somebody offer some suggestions on making this work?

I am needing to replace !@#$%^*()-+={[}]|\:;',.?/ plus a blank
space, all with the _ character.

Thanks
-- Jeff


~|
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RE: Regular Expression Help

2002-12-06 Thread Joshua Miller
Oh, forgot the space  use [[:punct:]]||[[:space:]] as the RegEX

Joshua Miller
Head Programmer / IT Manager
Garrison Enterprises Inc.
www.garrisonenterprises.net
[EMAIL PROTECTED]
(704) 569-9044 ext. 254
 

*
Any views expressed in this message are those of the individual sender,
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Garrison Enterprises Inc.
 
This e-mail is intended only for the individual or entity to which it is
addressed and contains information that is private and confidential. If
you are not the intended recipient you are hereby notified that any
dissemination, distribution or copying is strictly prohibited. If you 
have received this e-mail in error please delete it immediately and
advise us by return e-mail to [EMAIL PROTECTED]

*


-Original Message-
From: Jeff D. Chastain [mailto:[EMAIL PROTECTED]] 
Sent: Friday, December 06, 2002 12:31 PM
To: CF-Talk
Subject: Regular Expression Help


I am trying to use a regular expression to change all possible special
characters in a string to underscores because I am trying to use the
string as a variable name.

Regular expressions are not my specialty and I am running into problems
using some characters in my reReplace function.

Could somebody offer some suggestions on making this work?

I am needing to replace !@#$%^*()-+={[}]|\:;',.?/ plus a blank
space, all with the _ character.

Thanks
-- Jeff


~|
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RE: Regular Expression Help

2002-12-06 Thread Mike Townend
Something like

CFSET sNewString = REReplace(sOldString, [[:punct:][:space:]], ,
ALL)

HTH



-Original Message-
From: Jeff D. Chastain [mailto:[EMAIL PROTECTED]] 
Sent: Friday, December 6, 2002 17:31
To: CF-Talk
Subject: Regular Expression Help


I am trying to use a regular expression to change all possible special
characters in a string to underscores because I am trying to use the string
as a variable name.

Regular expressions are not my specialty and I am running into problems
using some characters in my reReplace function.

Could somebody offer some suggestions on making this work?

I am needing to replace !@#$%^*()-+={[}]|\:;',.?/ plus a blank space,
all with the _ character.

Thanks
-- Jeff


~|
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RE: Regular Expression Help

2002-12-06 Thread Raymond Camden
It's as simple as:

cfset str =
reReplace(!@##\$%\^\*()-+={[}]|\\:;',\.\?/,_,all)

Notice I had to escape out the # and  for CF and a few character that
regex use like . and *. It's possible I may have missed one though.

===
Raymond Camden, ColdFusion Jedi Master for Mindseye, Inc

Email: [EMAIL PROTECTED]
WWW  : www.camdenfamily.com/morpheus
Yahoo IM : morpheus

My ally is the Force, and a powerful ally it is. - Yoda 

 -Original Message-
 From: Jeff D. Chastain [mailto:[EMAIL PROTECTED]] 
 Sent: Friday, December 06, 2002 11:31 AM
 To: CF-Talk
 Subject: Regular Expression Help
 
 
 I am trying to use a regular expression to change all 
 possible special characters in a string to underscores 
 because I am trying to use the string as a variable name.
 
 Regular expressions are not my specialty and I am running 
 into problems using some characters in my reReplace function.
 
 Could somebody offer some suggestions on making this work?
 
 I am needing to replace !@#$%^*()-+={[}]|\:;',.?/ plus a 
 blank space, all with the _ character.
 
 Thanks
 -- Jeff
 
 
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RE: Regular Expression Help

2002-12-06 Thread Jeff D. Chastain
That was what I was looking for, I just had not found it yet.

Thanks

-Original Message-
From: Joshua Miller [mailto:[EMAIL PROTECTED]] 
Sent: Friday, December 06, 2002 11:42 AM
To: CF-Talk
Subject: RE: Regular Expression Help


 ReReplaceNoCase(string,[[:punct:]],_,ALL)

Joshua Miller
Head Programmer / IT Manager
Garrison Enterprises Inc.
www.garrisonenterprises.net [EMAIL PROTECTED]
(704) 569-9044 ext. 254
 

*
Any views expressed in this message are those of the individual sender,
except where the sender states them to be the views of 
Garrison Enterprises Inc.
 
This e-mail is intended only for the individual or entity to which it is
addressed and contains information that is private and confidential. If
you are not the intended recipient you are hereby notified that any
dissemination, distribution or copying is strictly prohibited. If you 
have received this e-mail in error please delete it immediately and
advise us by return e-mail to [EMAIL PROTECTED]

*


-Original Message-
From: Jeff D. Chastain [mailto:[EMAIL PROTECTED]] 
Sent: Friday, December 06, 2002 12:31 PM
To: CF-Talk
Subject: Regular Expression Help


I am trying to use a regular expression to change all possible special
characters in a string to underscores because I am trying to use the
string as a variable name.

Regular expressions are not my specialty and I am running into problems
using some characters in my reReplace function.

Could somebody offer some suggestions on making this work?

I am needing to replace !@#$%^*()-+={[}]|\:;',.?/ plus a blank
space, all with the _ character.

Thanks
-- Jeff



~|
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RE: Regular Expression Help

2002-12-06 Thread Raymond Camden
Jeff, definetly use Josh's code - just make sure that the chars you want
match the [[:punct:]] char class - from the docs:

Matches any punctuation character, that is, one of ! ' # S %  ` ( ) * +
, - . / : ;  =  ? @ [ / ] ^ _ { | } ~

===
Raymond Camden, ColdFusion Jedi Master for Mindseye, Inc

Email: [EMAIL PROTECTED]
WWW  : www.camdenfamily.com/morpheus
Yahoo IM : morpheus

My ally is the Force, and a powerful ally it is. - Yoda 

 -Original Message-
 From: Joshua Miller [mailto:[EMAIL PROTECTED]] 
 Sent: Friday, December 06, 2002 11:43 AM
 To: CF-Talk
 Subject: RE: Regular Expression Help
 
 
 Oh, forgot the space  use [[:punct:]]||[[:space:]] as the RegEX
 
 Joshua Miller
 Head Programmer / IT Manager
 Garrison Enterprises Inc.
 www.garrisonenterprises.net [EMAIL PROTECTED]
 (704) 569-9044 ext. 254
  

 
 
 -Original Message-
 From: Jeff D. Chastain [mailto:[EMAIL PROTECTED]] 
 Sent: Friday, December 06, 2002 12:31 PM
 To: CF-Talk
 Subject: Regular Expression Help
 
 
 I am trying to use a regular expression to change all 
 possible special characters in a string to underscores 
 because I am trying to use the string as a variable name.
 
 Regular expressions are not my specialty and I am running 
 into problems using some characters in my reReplace function.
 
 Could somebody offer some suggestions on making this work?
 
 I am needing to replace !@#$%^*()-+={[}]|\:;',.?/ plus a 
 blank space, all with the _ character.
 
 Thanks
 -- Jeff
 

~|
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RE: Regular Expression Help

2002-12-06 Thread Jeff D. Chastain
How do you not replace a non-existent space before and after the string?
Everything else works great.

Thanks

-Original Message-
From: Joshua Miller [mailto:[EMAIL PROTECTED]] 
Sent: Friday, December 06, 2002 11:43 AM
To: CF-Talk
Subject: RE: Regular Expression Help


Oh, forgot the space  use [[:punct:]]||[[:space:]] as the RegEX

Joshua Miller
Head Programmer / IT Manager
Garrison Enterprises Inc.
www.garrisonenterprises.net [EMAIL PROTECTED]
(704) 569-9044 ext. 254
 

*
Any views expressed in this message are those of the individual sender,
except where the sender states them to be the views of 
Garrison Enterprises Inc.
 
This e-mail is intended only for the individual or entity to which it is
addressed and contains information that is private and confidential. If
you are not the intended recipient you are hereby notified that any
dissemination, distribution or copying is strictly prohibited. If you 
have received this e-mail in error please delete it immediately and
advise us by return e-mail to [EMAIL PROTECTED]

*


-Original Message-
From: Jeff D. Chastain [mailto:[EMAIL PROTECTED]] 
Sent: Friday, December 06, 2002 12:31 PM
To: CF-Talk
Subject: Regular Expression Help


I am trying to use a regular expression to change all possible special
characters in a string to underscores because I am trying to use the
string as a variable name.

Regular expressions are not my specialty and I am running into problems
using some characters in my reReplace function.

Could somebody offer some suggestions on making this work?

I am needing to replace !@#$%^*()-+={[}]|\:;',.?/ plus a blank
space, all with the _ character.

Thanks
-- Jeff



~|
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RE: Regular Expression Help

2002-12-06 Thread Teel, C. Doug
I think you accidentally doubled the pipes between the punct and space.   It
should be:
[[:punct:]]|[[:space:]]

Thanks,
Doug
-Original Message-
From: Joshua Miller [mailto:[EMAIL PROTECTED]]
Sent: Friday, December 06, 2002 11:43 AM
To: CF-Talk
Subject: RE: Regular Expression Help


Oh, forgot the space  use [[:punct:]]||[[:space:]] as the RegEX

Joshua Miller
Head Programmer / IT Manager
Garrison Enterprises Inc.
www.garrisonenterprises.net
[EMAIL PROTECTED]
(704) 569-9044 ext. 254
 

*
Any views expressed in this message are those of the individual sender,
except where the sender states them to be the views of 
Garrison Enterprises Inc.
 
This e-mail is intended only for the individual or entity to which it is
addressed and contains information that is private and confidential. If
you are not the intended recipient you are hereby notified that any
dissemination, distribution or copying is strictly prohibited. If you 
have received this e-mail in error please delete it immediately and
advise us by return e-mail to [EMAIL PROTECTED]

*


-Original Message-
From: Jeff D. Chastain [mailto:[EMAIL PROTECTED]] 
Sent: Friday, December 06, 2002 12:31 PM
To: CF-Talk
Subject: Regular Expression Help


I am trying to use a regular expression to change all possible special
characters in a string to underscores because I am trying to use the
string as a variable name.

Regular expressions are not my specialty and I am running into problems
using some characters in my reReplace function.

Could somebody offer some suggestions on making this work?

I am needing to replace !@#$%^*()-+={[}]|\:;',.?/ plus a blank
space, all with the _ character.

Thanks
-- Jeff



~|
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RE: Regular Expression Help

2002-12-06 Thread Rob Rohan
lastly, you could think backwards [^A-Za-z0-9]

Rob

http://treebeard.sourceforge.net
http://ruinworld.sourceforge.net
Scientia Est Potentia

-Original Message-
From: Raymond Camden [mailto:[EMAIL PROTECTED]]
Sent: Friday, December 06, 2002 9:47 AM
To: CF-Talk
Subject: RE: Regular Expression Help


Jeff, definetly use Josh's code - just make sure that the chars you want
match the [[:punct:]] char class - from the docs:

Matches any punctuation character, that is, one of ! ' # S %  ` ( ) * +
, - . / : ;  =  ? @ [ / ] ^ _ { | } ~

===
Raymond Camden, ColdFusion Jedi Master for Mindseye, Inc

Email: [EMAIL PROTECTED]
WWW  : www.camdenfamily.com/morpheus
Yahoo IM : morpheus

My ally is the Force, and a powerful ally it is. - Yoda

 -Original Message-
 From: Joshua Miller [mailto:[EMAIL PROTECTED]]
 Sent: Friday, December 06, 2002 11:43 AM
 To: CF-Talk
 Subject: RE: Regular Expression Help


 Oh, forgot the space  use [[:punct:]]||[[:space:]] as the RegEX

 Joshua Miller
 Head Programmer / IT Manager
 Garrison Enterprises Inc.
 www.garrisonenterprises.net [EMAIL PROTECTED]
 (704) 569-9044 ext. 254




 -Original Message-
 From: Jeff D. Chastain [mailto:[EMAIL PROTECTED]]
 Sent: Friday, December 06, 2002 12:31 PM
 To: CF-Talk
 Subject: Regular Expression Help


 I am trying to use a regular expression to change all
 possible special characters in a string to underscores
 because I am trying to use the string as a variable name.

 Regular expressions are not my specialty and I am running
 into problems using some characters in my reReplace function.

 Could somebody offer some suggestions on making this work?

 I am needing to replace !@#$%^*()-+={[}]|\:;',.?/ plus a
 blank space, all with the _ character.

 Thanks
 -- Jeff



~|
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RE: Regular Expression Help

2002-12-06 Thread Raymond Camden
What is a non-existent space? How could a regex remove a character not
there?

===
Raymond Camden, ColdFusion Jedi Master for Mindseye, Inc

Email: [EMAIL PROTECTED]
WWW  : www.camdenfamily.com/morpheus
Yahoo IM : morpheus

My ally is the Force, and a powerful ally it is. - Yoda 

 -Original Message-
 From: Jeff D. Chastain [mailto:[EMAIL PROTECTED]] 
 Sent: Friday, December 06, 2002 11:53 AM
 To: CF-Talk
 Subject: RE: Regular Expression Help
 
 
 How do you not replace a non-existent space before and after 
 the string? Everything else works great.
 
 Thanks
 
 -Original Message-
 From: Joshua Miller [mailto:[EMAIL PROTECTED]] 
 Sent: Friday, December 06, 2002 11:43 AM
 To: CF-Talk
 Subject: RE: Regular Expression Help
 
 
 Oh, forgot the space  use [[:punct:]]||[[:space:]] as the RegEX
 

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RE: Regular Expression Help

2002-12-06 Thread Joshua Miller
Yeah, that's probably the safest method - anything that's NOT a letter
or number. Good call.

Joshua Miller
Head Programmer / IT Manager
Garrison Enterprises Inc.
www.garrisonenterprises.net
[EMAIL PROTECTED]
(704) 569-9044 ext. 254
 

*
Any views expressed in this message are those of the individual sender,
except where the sender states them to be the views of 
Garrison Enterprises Inc.
 
This e-mail is intended only for the individual or entity to which it is
addressed and contains information that is private and confidential. If
you are not the intended recipient you are hereby notified that any
dissemination, distribution or copying is strictly prohibited. If you 
have received this e-mail in error please delete it immediately and
advise us by return e-mail to [EMAIL PROTECTED]

*


-Original Message-
From: Rob Rohan [mailto:[EMAIL PROTECTED]] 
Sent: Friday, December 06, 2002 12:54 PM
To: CF-Talk
Subject: RE: Regular Expression Help


lastly, you could think backwards [^A-Za-z0-9]

Rob

http://treebeard.sourceforge.net http://ruinworld.sourceforge.net
Scientia Est Potentia

-Original Message-
From: Raymond Camden [mailto:[EMAIL PROTECTED]]
Sent: Friday, December 06, 2002 9:47 AM
To: CF-Talk
Subject: RE: Regular Expression Help


Jeff, definetly use Josh's code - just make sure that the chars you want
match the [[:punct:]] char class - from the docs:

Matches any punctuation character, that is, one of ! ' # S %  ` ( ) * +
, - . / : ;  =  ? @ [ / ] ^ _ { | } ~

===
Raymond Camden, ColdFusion Jedi Master for Mindseye, Inc

Email: [EMAIL PROTECTED]
WWW  : www.camdenfamily.com/morpheus
Yahoo IM : morpheus

My ally is the Force, and a powerful ally it is. - Yoda

 -Original Message-
 From: Joshua Miller [mailto:[EMAIL PROTECTED]]
 Sent: Friday, December 06, 2002 11:43 AM
 To: CF-Talk
 Subject: RE: Regular Expression Help


 Oh, forgot the space  use [[:punct:]]||[[:space:]] as the RegEX

 Joshua Miller
 Head Programmer / IT Manager
 Garrison Enterprises Inc.
 www.garrisonenterprises.net [EMAIL PROTECTED]
 (704) 569-9044 ext. 254




 -Original Message-
 From: Jeff D. Chastain [mailto:[EMAIL PROTECTED]]
 Sent: Friday, December 06, 2002 12:31 PM
 To: CF-Talk
 Subject: Regular Expression Help


 I am trying to use a regular expression to change all possible special

 characters in a string to underscores because I am trying to use the 
 string as a variable name.

 Regular expressions are not my specialty and I am running into 
 problems using some characters in my reReplace function.

 Could somebody offer some suggestions on making this work?

 I am needing to replace !@#$%^*()-+={[}]|\:;',.?/ plus a blank 
 space, all with the _ character.

 Thanks
 -- Jeff




~|
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RE: Regular Expression Help

2002-12-06 Thread Jeff D. Chastain
When I use your before mention snippet, I am getting an underscore
character tacked onto the beginning and ending of each word.  There is
no space or any other character their, but after executing the regex
statement, I have underscores before and after.

[[:punct:]]|[[:space:]] on 'some phrase' returns '_some_phrase_' instead
of 'some_phrase' which is what I was looking for.

Thanks

-Original Message-
From: Raymond Camden [mailto:[EMAIL PROTECTED]] 
Sent: Friday, December 06, 2002 11:54 AM
To: CF-Talk
Subject: RE: Regular Expression Help


What is a non-existent space? How could a regex remove a character not
there?

===
Raymond Camden, ColdFusion Jedi Master for Mindseye, Inc

Email: [EMAIL PROTECTED]
WWW  : www.camdenfamily.com/morpheus
Yahoo IM : morpheus

My ally is the Force, and a powerful ally it is. - Yoda 

 -Original Message-
 From: Jeff D. Chastain [mailto:[EMAIL PROTECTED]]
 Sent: Friday, December 06, 2002 11:53 AM
 To: CF-Talk
 Subject: RE: Regular Expression Help
 
 
 How do you not replace a non-existent space before and after
 the string? Everything else works great.
 
 Thanks
 
 -Original Message-
 From: Joshua Miller [mailto:[EMAIL PROTECTED]]
 Sent: Friday, December 06, 2002 11:43 AM
 To: CF-Talk
 Subject: RE: Regular Expression Help
 
 
 Oh, forgot the space  use [[:punct:]]||[[:space:]] as the RegEX
 


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RE: Regular Expression Help

2002-12-06 Thread Jeff D. Chastain
Yep, this is probably the safest bet and produces the expected result.

Thanks


-Original Message-
From: Rob Rohan [mailto:[EMAIL PROTECTED]] 
Sent: Friday, December 06, 2002 11:54 AM
To: CF-Talk
Subject: RE: Regular Expression Help


lastly, you could think backwards [^A-Za-z0-9]

Rob

http://treebeard.sourceforge.net http://ruinworld.sourceforge.net
Scientia Est Potentia

-Original Message-
From: Raymond Camden [mailto:[EMAIL PROTECTED]]
Sent: Friday, December 06, 2002 9:47 AM
To: CF-Talk
Subject: RE: Regular Expression Help


Jeff, definetly use Josh's code - just make sure that the chars you want
match the [[:punct:]] char class - from the docs:

Matches any punctuation character, that is, one of ! ' # S %  ` ( ) * +
, - . / : ;  =  ? @ [ / ] ^ _ { | } ~

===
Raymond Camden, ColdFusion Jedi Master for Mindseye, Inc

Email: [EMAIL PROTECTED]
WWW  : www.camdenfamily.com/morpheus
Yahoo IM : morpheus

My ally is the Force, and a powerful ally it is. - Yoda

 -Original Message-
 From: Joshua Miller [mailto:[EMAIL PROTECTED]]
 Sent: Friday, December 06, 2002 11:43 AM
 To: CF-Talk
 Subject: RE: Regular Expression Help


 Oh, forgot the space  use [[:punct:]]||[[:space:]] as the RegEX

 Joshua Miller
 Head Programmer / IT Manager
 Garrison Enterprises Inc.
 www.garrisonenterprises.net [EMAIL PROTECTED]
 (704) 569-9044 ext. 254




 -Original Message-
 From: Jeff D. Chastain [mailto:[EMAIL PROTECTED]]
 Sent: Friday, December 06, 2002 12:31 PM
 To: CF-Talk
 Subject: Regular Expression Help


 I am trying to use a regular expression to change all possible special

 characters in a string to underscores because I am trying to use the 
 string as a variable name.

 Regular expressions are not my specialty and I am running into 
 problems using some characters in my reReplace function.

 Could somebody offer some suggestions on making this work?

 I am needing to replace !@#$%^*()-+={[}]|\:;',.?/ plus a blank 
 space, all with the _ character.

 Thanks
 -- Jeff




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RE: Regular Expression Help

2002-12-06 Thread Joshua Miller
Did you TRIM the variable first? That may help ... Perhaps there's
whitespace surrounding the text.

Try: ReReplaceNoCase(trim(variable),[^A-Za-z0-9],_,ALL)

Joshua Miller
Head Programmer / IT Manager
Garrison Enterprises Inc.
www.garrisonenterprises.net
[EMAIL PROTECTED]
(704) 569-9044 ext. 254
 

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-Original Message-
From: Jeff D. Chastain [mailto:[EMAIL PROTECTED]] 
Sent: Friday, December 06, 2002 1:03 PM
To: CF-Talk
Subject: RE: Regular Expression Help


When I use your before mention snippet, I am getting an underscore
character tacked onto the beginning and ending of each word.  There is
no space or any other character their, but after executing the regex
statement, I have underscores before and after.

[[:punct:]]|[[:space:]] on 'some phrase' returns '_some_phrase_' instead
of 'some_phrase' which is what I was looking for.

Thanks

-Original Message-
From: Raymond Camden [mailto:[EMAIL PROTECTED]] 
Sent: Friday, December 06, 2002 11:54 AM
To: CF-Talk
Subject: RE: Regular Expression Help


What is a non-existent space? How could a regex remove a character not
there?

===
Raymond Camden, ColdFusion Jedi Master for Mindseye, Inc

Email: [EMAIL PROTECTED]
WWW  : www.camdenfamily.com/morpheus
Yahoo IM : morpheus

My ally is the Force, and a powerful ally it is. - Yoda 

 -Original Message-
 From: Jeff D. Chastain [mailto:[EMAIL PROTECTED]]
 Sent: Friday, December 06, 2002 11:53 AM
 To: CF-Talk
 Subject: RE: Regular Expression Help
 
 
 How do you not replace a non-existent space before and after the 
 string? Everything else works great.
 
 Thanks
 
 -Original Message-
 From: Joshua Miller [mailto:[EMAIL PROTECTED]]
 Sent: Friday, December 06, 2002 11:43 AM
 To: CF-Talk
 Subject: RE: Regular Expression Help
 
 
 Oh, forgot the space  use [[:punct:]]||[[:space:]] as the RegEX
 



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RE: Regular Expression Help

2002-12-06 Thread Jeff D. Chastain
reReplace(string, [^A-Za-z0-9], _, ALL) on 'some phrase' returns
'some_phrase' as expected.

reReplace(string, [[:punct:]]|[[:space:]], _ ALL) on 'some phrase'
returns '_some_phrase_' which was not expected.  The string 'some
phrase' really is just that without any extra spaces.

Either way, the first method works just fine and is probably safer.


-Original Message-
From: Joshua Miller [mailto:[EMAIL PROTECTED]] 
Sent: Friday, December 06, 2002 12:30 PM
To: CF-Talk
Subject: RE: Regular Expression Help


Did you TRIM the variable first? That may help ... Perhaps there's
whitespace surrounding the text.

Try: ReReplaceNoCase(trim(variable),[^A-Za-z0-9],_,ALL)

Joshua Miller
Head Programmer / IT Manager
Garrison Enterprises Inc.
www.garrisonenterprises.net [EMAIL PROTECTED]
(704) 569-9044 ext. 254
 

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RE: Regular Expression Help

2002-12-06 Thread Ben Doom
I'd use
[[:punct:] ]
as the class if you only need to check spaces -- if you need vertical tabs,
carriage returns, tabs, etc. use
[[:punct:][:space:]]
which should give you something like
newstring = rereplace(string, [[:punct:][:space:]], _, all);

Of course, it might be easier (as Rob suggested) to think about what
characters you want to allow instead of disallow:

newstring = rereplace(string, [^a-zA-Z0-9_], _, all);

would only keep letters, numbers, and underscores.

As always, the plug for the RegEx list:
http://www.houseoffusion.com/cf_lists/index.cfm?method=threadsforumid=21
Read, Post to, or Join the list here for all your RegEx needs.  :-)


  --Ben Doom
Programmer  General Lackey
Moonbow Software

: -Original Message-
: From: Joshua Miller [mailto:[EMAIL PROTECTED]]
: Sent: Friday, December 06, 2002 12:43 PM
: To: CF-Talk
: Subject: RE: Regular Expression Help
:
:
: Oh, forgot the space  use [[:punct:]]||[[:space:]] as the RegEX
:
: Joshua Miller
: Head Programmer / IT Manager
: Garrison Enterprises Inc.
: www.garrisonenterprises.net
: [EMAIL PROTECTED]
: (704) 569-9044 ext. 254
:
: 
: *
: Any views expressed in this message are those of the individual sender,
: except where the sender states them to be the views of
: Garrison Enterprises Inc.
:
: This e-mail is intended only for the individual or entity to which it is
: addressed and contains information that is private and confidential. If
: you are not the intended recipient you are hereby notified that any
: dissemination, distribution or copying is strictly prohibited. If you
: have received this e-mail in error please delete it immediately and
: advise us by return e-mail to [EMAIL PROTECTED]
: 
: *
:
:
: -Original Message-
: From: Jeff D. Chastain [mailto:[EMAIL PROTECTED]]
: Sent: Friday, December 06, 2002 12:31 PM
: To: CF-Talk
: Subject: Regular Expression Help
:
:
: I am trying to use a regular expression to change all possible special
: characters in a string to underscores because I am trying to use the
: string as a variable name.
:
: Regular expressions are not my specialty and I am running into problems
: using some characters in my reReplace function.
:
: Could somebody offer some suggestions on making this work?
:
: I am needing to replace !@#$%^*()-+={[}]|\:;',.?/ plus a blank
: space, all with the _ character.
:
: Thanks
: -- Jeff
:
:
: 
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regular expression help

2002-07-09 Thread Mark Warrick

Hello,

I've got a form field in which I want to allow people to enter HTML tags
(formatted stories for the web), but only a limited set of them such as
heading, bold, and italic tags so that they don't mess up the overall
formatting of the page.

What I'd like to do is automatically strip out any other HTML tag (or
JavaScript, CSS, DHTML, etc.) from the submission but leave the safe tags.
I'm thinking that using a regular expression string to do this would be the
way to go, however there is something to consider about that idea.  The data
ends up in an NTEXT field in the SQL database which is capable of storing a
lot of data and I suspect people might be typing as much as a few pages of
text into this field.  So I'm worried that a regular expression might take
too long to parse through all the entered text.

Perhaps I'm missing something obvious here.  Anyone have any suggestions?

---mark


Mark Warrick ([EMAIL PROTECTED])
Founder, Fusioneers.com / CTO, ZapConnect.com
Phone: 714-547-5386 / 714-667-0203 / Efax: 801-730-7289
http://www.warrick.net / http://www.fusioneers.com
http://www.zapconnect.com
ICQ: 125160 AIM: markwarric Yahoo: Serengeti



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RE: regular expression help

2002-07-09 Thread Tangorre, Michael

Mark,

I am fairly new to RegEx, but I can tell you we did this on our University's site when 
I was in college.
We allowed the different departments to submit formatted text using an assortment of 
HTML tags that we specified.
We used RegEx to do this, and did not notice a performace hit at all.

For what that's worth...

Mike


-Original Message-
From: Mark Warrick [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, July 09, 2002 3:50 PM
To: CF-Talk
Subject: regular expression help


Hello,

I've got a form field in which I want to allow people to enter HTML tags
(formatted stories for the web), but only a limited set of them such as
heading, bold, and italic tags so that they don't mess up the overall
formatting of the page.

What I'd like to do is automatically strip out any other HTML tag (or
JavaScript, CSS, DHTML, etc.) from the submission but leave the safe tags.
I'm thinking that using a regular expression string to do this would be the
way to go, however there is something to consider about that idea.  The data
ends up in an NTEXT field in the SQL database which is capable of storing a
lot of data and I suspect people might be typing as much as a few pages of
text into this field.  So I'm worried that a regular expression might take
too long to parse through all the entered text.

Perhaps I'm missing something obvious here.  Anyone have any suggestions?

---mark


Mark Warrick ([EMAIL PROTECTED])
Founder, Fusioneers.com / CTO, ZapConnect.com
Phone: 714-547-5386 / 714-667-0203 / Efax: 801-730-7289
http://www.warrick.net / http://www.fusioneers.com
http://www.zapconnect.com
ICQ: 125160 AIM: markwarric Yahoo: Serengeti




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Re: regular expression help

2002-07-09 Thread Michael Dinowitz

If you have a limited range of accepted tags then the following will probably be your 
best bet. 
1. find all of the tags you want to allow. 
2. replace their brackets with some non-standard character (like a yen symbol). 
3. remove all other tags that exist.
4. replace your yen with brackets again.



 Hello,
 
 I've got a form field in which I want to allow people to enter HTML tags
 (formatted stories for the web), but only a limited set of them such as
 heading, bold, and italic tags so that they don't mess up the overall
 formatting of the page.
 
 What I'd like to do is automatically strip out any other HTML tag (or
 JavaScript, CSS, DHTML, etc.) from the submission but leave the safe tags.
 I'm thinking that using a regular expression string to do this would be the
 way to go, however there is something to consider about that idea.  The data
 ends up in an NTEXT field in the SQL database which is capable of storing a
 lot of data and I suspect people might be typing as much as a few pages of
 text into this field.  So I'm worried that a regular expression might take
 too long to parse through all the entered text.
 
 Perhaps I'm missing something obvious here.  Anyone have any suggestions?
 
 ---mark
 
 
 Mark Warrick ([EMAIL PROTECTED])
 Founder, Fusioneers.com / CTO, ZapConnect.com
 Phone: 714-547-5386 / 714-667-0203 / Efax: 801-730-7289
 http://www.warrick.net / http://www.fusioneers.com
 http://www.zapconnect.com
 ICQ: 125160 AIM: markwarric Yahoo: Serengeti
 
 
 
 
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RE: Regular Expression Help

2002-03-03 Thread Pascal Peters

lWordList = ArrayToList(myarray,|);
REReplaceNoCase(mystring,([^[:alnum]])(#lWordList#)([^[:alnum]]),\1\3
,ALL);

This will replace the words defined in myarray by empty strings.

-Original Message-
From: James Sleeman [mailto:[EMAIL PROTECTED]]
Sent: zaterdag 2 maart 2002 13:29
To: CF-Talk
Subject: Re: Regular Expression Help


On Sat, 2002-03-02 at 10:10, Jared Stark wrote:
 Hello all.  I am trying to write a simple search engine, and would 
like 
 to replace certain commonly used prepositions from the search string 
 such as 'a','the','for', etc...
 
 I have an array of the prepositions that I would like to remove, 
however 
 the problem I have is that it is removing them when they are subsets 
of 
 other words, for example 'them' would become 'm' when removing 'the', 
 'bag' would become 'bg' when removing 'a', etc...  
 
 I'm not an expert at regular expression, but I'm assuming it is 
possible 
 to remove only those instances where the prepositions are stand-alone 
 and not subsets of other words.  Could someone render me some 
 assistance?

If you want to use regular expressions to do it, easiest way would be to
use the character class for whitespace before and after your
preposition.

However don't underestimate the power of the CF list processing
functions, think of your search term as a list seperated by whitespace
and you can use any of the CF list functions.


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Re: Regular Expression Help

2002-03-02 Thread James Sleeman

On Sat, 2002-03-02 at 10:10, Jared Stark wrote:
 Hello all  I am trying to write a simple search engine, and would like 
 to replace certain commonly used prepositions from the search string 
 such as 'a','the','for', etc
 
 I have an array of the prepositions that I would like to remove, however 
 the problem I have is that it is removing them when they are subsets of 
 other words, for example 'them' would become 'm' when removing 'the', 
 'bag' would become 'bg' when removing 'a', etc  
 
 I'm not an expert at regular expression, but I'm assuming it is possible 
 to remove only those instances where the prepositions are stand-alone 
 and not subsets of other words  Could someone render me some 
 assistance?

If you want to use regular expressions to do it, easiest way would be to
use the character class for whitespace before and after your
preposition

However don't underestimate the power of the CF list processing
functions, think of your search term as a list seperated by whitespace
and you can use any of the CF list functions

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Re: Regular Expression Help

2002-03-02 Thread Douglas Brown

just do a udf and create your array and then check that the value of the 
words you are replacing (length). If they are less than 4 char then they 
should be removed. Hope that makes sense.



Success is a journey, not a destination!!



Doug Brown
- Original Message - 
From: James Sleeman [EMAIL PROTECTED]
To: CF-Talk [EMAIL PROTECTED]
Sent: Saturday, March 02, 2002 4:28 AM
Subject: Re: Regular Expression Help


 On Sat, 2002-03-02 at 10:10, Jared Stark wrote:
  Hello all.  I am trying to write a simple search engine, and would 
like 
  to replace certain commonly used prepositions from the search string 

  such as 'a','the','for', etc...
  
  I have an array of the prepositions that I would like to remove, 
however 
  the problem I have is that it is removing them when they are subsets 
of 
  other words, for example 'them' would become 'm' when removing 
'the', 
  'bag' would become 'bg' when removing 'a', etc...  
  
  I'm not an expert at regular expression, but I'm assuming it is 
possible 
  to remove only those instances where the prepositions are 
stand-alone 
  and not subsets of other words.  Could someone render me some 
  assistance?
 
 If you want to use regular expressions to do it, easiest way would be 
to
 use the character class for whitespace before and after your
 preposition.
 
 However don't underestimate the power of the CF list processing
 functions, think of your search term as a list seperated by whitespace
 and you can use any of the CF list functions.
 
 
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Regular Expression Help

2002-03-01 Thread Jared Stark

Hello all  I am trying to write a simple search engine, and would like 
to replace certain commonly used prepositions from the search string 
such as 'a','the','for', etc

I have an array of the prepositions that I would like to remove, however 
the problem I have is that it is removing them when they are subsets of 
other words, for example 'them' would become 'm' when removing 'the', 
'bag' would become 'bg' when removing 'a', etc  

I'm not an expert at regular expression, but I'm assuming it is possible 
to remove only those instances where the prepositions are stand-alone 
and not subsets of other words  Could someone render me some 
assistance?

Much thanks,
Jared

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