[cfaussie] Re: outputting recordset
This is what I like about programming, even in parallel developing there is always more ways to skin the cat. On 4/5/07, Steve Onnis <[EMAIL PROTECTED]> wrote: > > > Ok > > thought I would put my 2cents in here. I figured if you wanted to adapt > it > for more than 3 columns or less than 3 columns it would be silly to be > hard > coding in cells so here you go. > > > listToArray("1,2,3,4,5,6,7,8,9,10,11")) /> > > > > > > > > > > >#query["column"][row + ((rows * cell))]# > > > > > > > > > > > > This will also fill any empty cells automatically > > Have fun > > Steve Onnis > --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "cfaussie" group. To post to this group, send email to cfaussie@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cfaussie?hl=en -~--~~~~--~~--~--~---
[cfaussie] Re: outputting recordset
Ok thought I would put my 2cents in here. I figured if you wanted to adapt it for more than 3 columns or less than 3 columns it would be silly to be hard coding in cells so here you go. #query["column"][row + ((rows * cell))]# This will also fill any empty cells automatically Have fun Steve Onnis From: cfaussie@googlegroups.com [mailto:[EMAIL PROTECTED] On Behalf Of Andrew Scott Sent: Thursday, 5 April 2007 6:12 PM To: cfaussie@googlegroups.com Subject: [cfaussie] Re: outputting recordset Yes they are very quick and it wouldn't make any perfomace issue one way or the other. On 4/5/07, Dale Fraser <[EMAIL PROTECTED]> wrote: Ahh, Picky, in my defence, array functions are very quick :P Regards Dale Fraser http://dale.fraser.id.au/blog -Original Message- From: cfaussie@googlegroups.com [mailto: cfaussie@googlegroups.com <mailto:cfaussie@googlegroups.com> ] On Behalf Of Scott Thornton Sent: Thursday, 5 April 2007 4:26 PM To: cfaussie@googlegroups.com Subject: [cfaussie] outputting recordset Hi, You probably don't want to calculate the length of the array within every iteration of the loop if it does not change. >>> "Dale Fraser" < [EMAIL PROTECTED]> 05/04/2007 3:29 pm >>> Working example. #data[i]# #data[i+rows*1]# #data[i+rows*2]# Regards Dale Fraser http://dale.fraser.id.au/blog _ From: cfaussie@googlegroups.com <mailto:cfaussie@googlegroups.com> [mailto:[EMAIL PROTECTED] On Behalf Of Taco Fleur Sent: Thursday, 5 April 2007 3:22 PM To: cfaussie@googlegroups.com <mailto:cfaussie@googlegroups.com> Subject: [cfaussie] Re: outputting recordset Hi Seona, that is it! Thanks. * count * count + divisor * count + (divisor * 2) On 4/5/07, Seona Bellamy < [EMAIL PROTECTED]> wrote: On 05/04/07, Dale Fraser < [EMAIL PROTECTED] <mailto:[EMAIL PROTECTED] > > wrote: So are you saying a fixed number of rows 6 Or a fixed number of columns 3? I believe the line in the original email was: I need to output a recordset in a table, infinite rows, and maximum 3 columns in width. I'm more interested in knowing if there was a reason for the number of empty cells in the third column. Because I'm pretty sure that the columns could have been closer to even in length, and that would be easier to do I think. The maths is making better sense in my head, anyway. Then again, knowing my history with maths, I'm not sure that's saying much... Basically, what I'm thinking is something along these lines: * Divide your number of records by 3 and round it off to an integer (I'll call this divisor). This is the number of records you will have in each of the first two (complete) columns. The third column may or may not have this many records. * Loop over your recordset this many times, with a counter of some sort to count the iterations. * In the loop, get the three cells as follows: * count * count + divisor * count + (divisor * 2) I haven't tested this, so it's purely theoretical and may or may not work. Oh, and you'd probably want to test if the value exists in the third column because that one may not be full. Cheers, Seona. We
[cfaussie] Re: outputting recordset
Ahh, Picky, in my defence, array functions are very quick :P Regards Dale Fraser http://dale.fraser.id.au/blog -Original Message- From: cfaussie@googlegroups.com [mailto:[EMAIL PROTECTED] On Behalf Of Scott Thornton Sent: Thursday, 5 April 2007 4:26 PM To: cfaussie@googlegroups.com Subject: [cfaussie] outputting recordset Hi, You probably don't want to calculate the length of the array within every iteration of the loop if it does not change. >>> "Dale Fraser" <[EMAIL PROTECTED]> 05/04/2007 3:29 pm >>> Working example. #data[i]# #data[i+rows*1]# #data[i+rows*2]# Regards Dale Fraser http://dale.fraser.id.au/blog _ From: cfaussie@googlegroups.com [mailto:[EMAIL PROTECTED] On Behalf Of Taco Fleur Sent: Thursday, 5 April 2007 3:22 PM To: cfaussie@googlegroups.com Subject: [cfaussie] Re: outputting recordset Hi Seona, that is it! Thanks. * count * count + divisor * count + (divisor * 2) On 4/5/07, Seona Bellamy <[EMAIL PROTECTED]> wrote: On 05/04/07, Dale Fraser < [EMAIL PROTECTED] <mailto:[EMAIL PROTECTED]> > wrote: So are you saying a fixed number of rows 6 Or a fixed number of columns 3? I believe the line in the original email was: I need to output a recordset in a table, infinite rows, and maximum 3 columns in width. I'm more interested in knowing if there was a reason for the number of empty cells in the third column. Because I'm pretty sure that the columns could have been closer to even in length, and that would be easier to do I think. The maths is making better sense in my head, anyway. Then again, knowing my history with maths, I'm not sure that's saying much... Basically, what I'm thinking is something along these lines: * Divide your number of records by 3 and round it off to an integer (I'll call this divisor). This is the number of records you will have in each of the first two (complete) columns. The third column may or may not have this many records. * Loop over your recordset this many times, with a counter of some sort to count the iterations. * In the loop, get the three cells as follows: * count * count + divisor * count + (divisor * 2) I haven't tested this, so it's purely theoretical and may or may not work. Oh, and you'd probably want to test if the value exists in the third column because that one may not be full. Cheers, Seona. Web Design, Web development, Graphic Design and Complete Internet Solutions an industry leader with commercial IT experience since 1994 . --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "cfaussie" group. To post to this group, send email to cfaussie@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cfaussie?hl=en -~--~~~~--~~--~--~---
[cfaussie] Re: outputting recordset
Yes they are very quick and it wouldn't make any perfomace issue one way or the other. On 4/5/07, Dale Fraser <[EMAIL PROTECTED]> wrote: > > > Ahh, > > Picky, in my defence, array functions are very quick :P > > Regards > Dale Fraser > > http://dale.fraser.id.au/blog > > > -Original Message- > From: cfaussie@googlegroups.com [mailto:[EMAIL PROTECTED] On > Behalf > Of Scott Thornton > Sent: Thursday, 5 April 2007 4:26 PM > To: cfaussie@googlegroups.com > Subject: [cfaussie] outputting recordset > > > Hi, > > You probably don't want to calculate the length of the array within every > iteration of the loop if it does not change. > > > > > > >>> "Dale Fraser" <[EMAIL PROTECTED]> 05/04/2007 3:29 pm >>> > Working example. > > > > > > > > > > > > > > > > > > > > #data[i]# > > arrayLen(data)>#data[i+rows*1]# > > arrayLen(data)>#data[i+rows*2]# > > > > > > > > > > > > Regards > > Dale Fraser > > > > http://dale.fraser.id.au/blog > > > > _ > > From: cfaussie@googlegroups.com [mailto:[EMAIL PROTECTED] On > Behalf > Of Taco Fleur > Sent: Thursday, 5 April 2007 3:22 PM > To: cfaussie@googlegroups.com > Subject: [cfaussie] Re: outputting recordset > > > > Hi Seona, > > > > that is it! Thanks. > > > > * count > * count + divisor > * count + (divisor * 2) > > > > On 4/5/07, Seona Bellamy <[EMAIL PROTECTED]> wrote: > > On 05/04/07, Dale Fraser < [EMAIL PROTECTED] <mailto:[EMAIL PROTECTED]> > > wrote: > > So are you saying a fixed number of rows 6 > > Or a fixed number of columns 3? > > > I believe the line in the original email was: > > > > > I need to output a recordset in a table, infinite rows, and maximum 3 > columns in width. > > > I'm more interested in knowing if there was a reason for the number of > empty > cells in the third column. Because I'm pretty sure that the columns could > have been closer to even in length, and that would be easier to do I > think. > The maths is making better sense in my head, anyway. Then again, knowing > my > history with maths, I'm not sure that's saying much... > > Basically, what I'm thinking is something along these lines: > > * Divide your number of records by 3 and round it off to an integer (I'll > call this divisor). This is the number of records you will have in each of > the first two (complete) columns. The third column may or may not have > this > many records. > > * Loop over your recordset this many times, with a counter of some sort to > count the iterations. > > * In the loop, get the three cells as follows: > * count > * count + divisor > * count + (divisor * 2) > > I haven't tested this, so it's purely theoretical and may or may not work. > Oh, and you'd probably want to test if the value exists in the third > column > because that one may not be full. > > > Cheers, > > Seona. > > > > Web Design, Web development, Graphic Design and Complete Internet > Solutions > an industry leader with commercial IT experience since 1994 . > > > > > > > > > > > > > > > -- Senior Coldfusion Developer Aegeon Pty. Ltd. www.aegeon.com.au Phone: +613 8676 4223 Mobile: 0404 998 273 --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "cfaussie" group. To post to this group, send email to cfaussie@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cfaussie?hl=en -~--~~~~--~~--~--~---
[cfaussie] Re: outputting recordset
Working example. #data[i]# #data[i+rows*1]# #data[i+rows*2]# Regards Dale Fraser http://dale.fraser.id.au/blog _ From: cfaussie@googlegroups.com [mailto:[EMAIL PROTECTED] On Behalf Of Taco Fleur Sent: Thursday, 5 April 2007 3:22 PM To: cfaussie@googlegroups.com Subject: [cfaussie] Re: outputting recordset Hi Seona, that is it! Thanks. * count * count + divisor * count + (divisor * 2) On 4/5/07, Seona Bellamy <[EMAIL PROTECTED]> wrote: On 05/04/07, Dale Fraser < [EMAIL PROTECTED] <mailto:[EMAIL PROTECTED]> > wrote: So are you saying a fixed number of rows 6 Or a fixed number of columns 3? I believe the line in the original email was: I need to output a recordset in a table, infinite rows, and maximum 3 columns in width. I'm more interested in knowing if there was a reason for the number of empty cells in the third column. Because I'm pretty sure that the columns could have been closer to even in length, and that would be easier to do I think. The maths is making better sense in my head, anyway. Then again, knowing my history with maths, I'm not sure that's saying much... Basically, what I'm thinking is something along these lines: * Divide your number of records by 3 and round it off to an integer (I'll call this divisor). This is the number of records you will have in each of the first two (complete) columns. The third column may or may not have this many records. * Loop over your recordset this many times, with a counter of some sort to count the iterations. * In the loop, get the three cells as follows: * count * count + divisor * count + (divisor * 2) I haven't tested this, so it's purely theoretical and may or may not work. Oh, and you'd probably want to test if the value exists in the third column because that one may not be full. Cheers, Seona. Web Design, Web development, Graphic Design and Complete Internet Solutions an industry leader with commercial IT experience since 1994 . --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "cfaussie" group. To post to this group, send email to cfaussie@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cfaussie?hl=en -~--~~~~--~~--~--~---
[cfaussie] Re: outputting recordset
this should helpremember a query can be treated as an array, so you'll be able to substitute your code into this without too many problems. #a[array_index]# On Apr 5, 1:03 pm, "Taco Fleur" <[EMAIL PROTECTED]> wrote: > fixed number of columns, i.e. 3 > > On 4/5/07, Dale Fraser <[EMAIL PROTECTED]> wrote: > > > > > > > > > So are you saying a fixed number of rows 6 > > > Or a fixed number of columns 3? > > > Regards > > > Dale Fraser > > >http://dale.fraser.id.au/blog > > > -- > > > *From:* cfaussie@googlegroups.com [mailto:[EMAIL PROTECTED] *On > > Behalf Of *Taco Fleur > > *Sent:* Thursday, 5 April 2007 2:33 PM > > *To:* cfaussie@googlegroups.com > > *Subject:* [cfaussie] outputting recordset > > > Hi all, > > > I have a problem I can't seem to get my head around, any help is > > appreciated. > > > I need to output a recordset in a table, infinite rows, and maximum 3 > > columns in width. > > > Output need to be as following though; > > > 1 - 7 - 13 > > > 2 - 8 - 14 > > > 3 - 9 - 15 > > > 4 - 10 - [] > > > 5 - 11 - [] > > > 6 - 12 - [] > > > -- > > Taco Fleur -http://www.pacificfox.com.au > > Web Design, Web development, Graphic Design and Complete Internet > > Solutions > > an industry leader with commercial IT experience since 1994 ... > > -- > Taco Fleur -http://www.pacificfox.com.au > Web Design, Web development, Graphic Design and Complete Internet Solutions > an industry leader with commercial IT experience since 1994 ...- Hide quoted > text - > > - Show quoted text - --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "cfaussie" group. To post to this group, send email to cfaussie@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cfaussie?hl=en -~--~~~~--~~--~--~---
[cfaussie] Re: outputting recordset
Hi Seona, that is it! Thanks. * count * count + divisor * count + (divisor * 2) On 4/5/07, Seona Bellamy <[EMAIL PROTECTED]> wrote: > > On 05/04/07, Dale Fraser <[EMAIL PROTECTED]> wrote: > > > > So are you saying a fixed number of rows 6 > > > > Or a fixed number of columns 3? > > > > I believe the line in the original email was: > > >I need to output a recordset in a table, infinite rows, and maximum 3 > > columns in width. > > > > I'm more interested in knowing if there was a reason for the number of > empty cells in the third column. Because I'm pretty sure that the columns > could have been closer to even in length, and that would be easier to do I > think. The maths is making better sense in my head, anyway. Then again, > knowing my history with maths, I'm not sure that's saying much... > > Basically, what I'm thinking is something along these lines: > > * Divide your number of records by 3 and round it off to an integer (I'll > call this divisor). This is the number of records you will have in each of > the first two (complete) columns. The third column may or may not have this > many records. > > * Loop over your recordset this many times, with a counter of some sort to > count the iterations. > > * In the loop, get the three cells as follows: > * count > * count + divisor > * count + (divisor * 2) > > I haven't tested this, so it's purely theoretical and may or may not work. > Oh, and you'd probably want to test if the value exists in the third column > because that one may not be full. > > > Cheers, > > Seona. > > > > -- Taco Fleur - http://www.pacificfox.com.au Web Design, Web development, Graphic Design and Complete Internet Solutions an industry leader with commercial IT experience since 1994 --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "cfaussie" group. To post to this group, send email to cfaussie@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cfaussie?hl=en -~--~~~~--~~--~--~---
[cfaussie] Re: outputting recordset
this is what I currently have, which is not what I am after as it produces 1 2 3 4 5 6 7 8 9 10 11 12 etc variables.column = 3; variables.row = ceiling( rsSubCategory.recordCount / variables.column ); #rsCategory.title# variables.index = ( variables.i * variables.column ) + variables.j; #variables.index# On 4/5/07, Seona Bellamy <[EMAIL PROTECTED]> wrote: > > On 05/04/07, Dale Fraser <[EMAIL PROTECTED]> wrote: > > > > > > > --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "cfaussie" group. To post to this group, send email to cfaussie@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cfaussie?hl=en -~--~~~~--~~--~--~---
[cfaussie] Re: outputting recordset
Taco, Doesn't Mod 3 work for you? Andrew Scott Senior Coldfusion Developer Aegeon Pty. Ltd. www.aegeon.com.au Phone: +613 8676 4223 Mobile: 0404 998 273 From: cfaussie@googlegroups.com [mailto:[EMAIL PROTECTED] On Behalf Of Taco Fleur Sent: Thursday, 5 April 2007 3:03 PM To: cfaussie@googlegroups.com Subject: [cfaussie] Re: outputting recordset fixed number of columns, i.e. 3 On 4/5/07, Dale Fraser <[EMAIL PROTECTED]> wrote: So are you saying a fixed number of rows 6 Or a fixed number of columns 3? Regards Dale Fraser http://dale.fraser.id.au/blog _ From: cfaussie@googlegroups.com [mailto:[EMAIL PROTECTED] On Behalf Of Taco Fleur Sent: Thursday, 5 April 2007 2:33 PM To: cfaussie@googlegroups.com Subject: [cfaussie] outputting recordset Hi all, I have a problem I can't seem to get my head around, any help is appreciated. I need to output a recordset in a table, infinite rows, and maximum 3 columns in width. Output need to be as following though; 1 - 7 - 13 2 - 8 - 14 3 - 9 - 15 4 - 10 - [] 5 - 11 - [] 6 - 12 - [] -- Taco Fleur - http://www.pacificfox.com.au <http://www.pacificfox.com.au/> Web Design, Web development, Graphic Design and Complete Internet Solutions an industry leader with commercial IT experience since 1994 . http://www.pacificfox.com.au Web Design, Web development, Graphic Design and Complete Internet Solutions an industry leader with commercial IT experience since 1994 . --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "cfaussie" group. To post to this group, send email to cfaussie@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cfaussie?hl=en -~--~~~~--~~--~--~---
[cfaussie] Re: outputting recordset
wouldnt that be 1 - 6 - 11 2 - 7 - 12 3 - 8 - 13 4 - 9 - 14 5 - 10 - 15 ? _ From: cfaussie@googlegroups.com [mailto:[EMAIL PROTECTED] On Behalf Of Taco Fleur Sent: Thursday, 5 April 2007 2:33 PM To: cfaussie@googlegroups.com Subject: [cfaussie] outputting recordset Hi all, I have a problem I can't seem to get my head around, any help is appreciated. I need to output a recordset in a table, infinite rows, and maximum 3 columns in width. Output need to be as following though; 1 - 7 - 13 2 - 8 - 14 3 - 9 - 15 4 - 10 - [] 5 - 11 - [] 6 - 12 - [] -- Taco Fleur - http://www.pacificfox.com.au Web Design, Web development, Graphic Design and Complete Internet Solutions an industry leader with commercial IT experience since 1994 . --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "cfaussie" group. To post to this group, send email to cfaussie@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cfaussie?hl=en -~--~~~~--~~--~--~---
[cfaussie] Re: outputting recordset
That would be, but trying to get a point across. 1 - 7 - 13 2 - 8 - 14 3 - 9 - 15 4 - 10 - 16 5 - 11 - 17 6 - 12 - [] On 4/5/07, Steve Onnis <[EMAIL PROTECTED]> wrote: > > wouldnt that be > > 1 - 6 - 11 > 2 - 7 - 12 > 3 - 8 - 13 > 4 - 9 - 14 > 5 - 10 - 15 > > ? > > -- > *From:* cfaussie@googlegroups.com [mailto:[EMAIL PROTECTED] *On > Behalf Of *Taco Fleur > *Sent:* Thursday, 5 April 2007 2:33 PM > *To:* cfaussie@googlegroups.com > *Subject:* [cfaussie] outputting recordset > > > Hi all, > > I have a problem I can't seem to get my head around, any help is > appreciated. > > I need to output a recordset in a table, infinite rows, and maximum 3 > columns in width. > Output need to be as following though; > > 1 - 7 - 13 > 2 - 8 - 14 > 3 - 9 - 15 > 4 - 10 - [] > 5 - 11 - [] > 6 - 12 - [] > > -- > Taco Fleur - http://www.pacificfox.com.au > Web Design, Web development, Graphic Design and Complete Internet > Solutions > an industry leader with commercial IT experience since 1994 > > > > > -- Taco Fleur - http://www.pacificfox.com.au Web Design, Web development, Graphic Design and Complete Internet Solutions an industry leader with commercial IT experience since 1994 --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "cfaussie" group. To post to this group, send email to cfaussie@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cfaussie?hl=en -~--~~~~--~~--~--~---
[cfaussie] Re: outputting recordset
fixed number of columns, i.e. 3 On 4/5/07, Dale Fraser <[EMAIL PROTECTED]> wrote: > > So are you saying a fixed number of rows 6 > > > > Or a fixed number of columns 3? > > > > Regards > > Dale Fraser > > > > http://dale.fraser.id.au/blog > > > -- > > *From:* cfaussie@googlegroups.com [mailto:[EMAIL PROTECTED] *On > Behalf Of *Taco Fleur > *Sent:* Thursday, 5 April 2007 2:33 PM > *To:* cfaussie@googlegroups.com > *Subject:* [cfaussie] outputting recordset > > > > Hi all, > > > > I have a problem I can't seem to get my head around, any help is > appreciated. > > > > I need to output a recordset in a table, infinite rows, and maximum 3 > columns in width. > > Output need to be as following though; > > > > 1 - 7 - 13 > > 2 - 8 - 14 > > 3 - 9 - 15 > > 4 - 10 - [] > > 5 - 11 - [] > > 6 - 12 - [] > > -- > Taco Fleur - http://www.pacificfox.com.au > Web Design, Web development, Graphic Design and Complete Internet > Solutions > an industry leader with commercial IT experience since 1994 > > > > > > -- Taco Fleur - http://www.pacificfox.com.au Web Design, Web development, Graphic Design and Complete Internet Solutions an industry leader with commercial IT experience since 1994 --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "cfaussie" group. To post to this group, send email to cfaussie@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cfaussie?hl=en -~--~~~~--~~--~--~---
[cfaussie] Re: outputting recordset
On 05/04/07, Dale Fraser <[EMAIL PROTECTED]> wrote: > > So are you saying a fixed number of rows 6 > > Or a fixed number of columns 3? > I believe the line in the original email was: I need to output a recordset in a table, infinite rows, and maximum 3 > columns in width. > I'm more interested in knowing if there was a reason for the number of empty cells in the third column. Because I'm pretty sure that the columns could have been closer to even in length, and that would be easier to do I think. The maths is making better sense in my head, anyway. Then again, knowing my history with maths, I'm not sure that's saying much... Basically, what I'm thinking is something along these lines: * Divide your number of records by 3 and round it off to an integer (I'll call this divisor). This is the number of records you will have in each of the first two (complete) columns. The third column may or may not have this many records. * Loop over your recordset this many times, with a counter of some sort to count the iterations. * In the loop, get the three cells as follows: * count * count + divisor * count + (divisor * 2) I haven't tested this, so it's purely theoretical and may or may not work. Oh, and you'd probably want to test if the value exists in the third column because that one may not be full. Cheers, Seona. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "cfaussie" group. To post to this group, send email to cfaussie@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cfaussie?hl=en -~--~~~~--~~--~--~---
[cfaussie] Re: outputting recordset
So are you saying a fixed number of rows 6 Or a fixed number of columns 3? Regards Dale Fraser http://dale.fraser.id.au/blog _ From: cfaussie@googlegroups.com [mailto:[EMAIL PROTECTED] On Behalf Of Taco Fleur Sent: Thursday, 5 April 2007 2:33 PM To: cfaussie@googlegroups.com Subject: [cfaussie] outputting recordset Hi all, I have a problem I can't seem to get my head around, any help is appreciated. I need to output a recordset in a table, infinite rows, and maximum 3 columns in width. Output need to be as following though; 1 - 7 - 13 2 - 8 - 14 3 - 9 - 15 4 - 10 - [] 5 - 11 - [] 6 - 12 - [] -- Taco Fleur - http://www.pacificfox.com.au Web Design, Web development, Graphic Design and Complete Internet Solutions an industry leader with commercial IT experience since 1994 . --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "cfaussie" group. To post to this group, send email to cfaussie@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cfaussie?hl=en -~--~~~~--~~--~--~---