How to use pmap over a partition-all list of list?

2013-02-02 Thread Leandro Moreira
Hi there,

I have this:

*user=* (partition-all 5 (range 1 20))
((1 2 3 4 5) (6 7 8 9 10) (11 12 13 14 15) (16 17 18 19))

And I would like to apply the *pmap* over the partitions, something like: 
(the line bellow doesn't work)
*user=* (pmap + (partition-all 5 (range 1 20)))

*I would like to have this (pmap + (1 2 3 4 5) (6 7 8 9 10) (11 12 13 14 
15) (16 17 18 19)) instead of this (pmap + ((1 2 3 4 5) (6 7 8 9 10) (11 12 
13 14 15) (16 17 18 19)))*

How can I apply pmap over a partition-all result?
If it's possible, by doing that am I distributing the load better than if I 
used the pmap with the whole list?

Thanks

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Re: How to use pmap over a partition-all list of list?

2013-02-02 Thread Jim - FooBar();

Use this:

(pmap #(reduce + %) (partition-all 5 (range 1 20)))

OR as you yourself said you can use 'apply' instead of reduce

Jim



On 02/02/13 12:31, Leandro Moreira wrote:

Hi there,

I have this:

*user=* (partition-all 5 (range 1 20))
((1 2 3 4 5) (6 7 8 9 10) (11 12 13 14 15) (16 17 18 19))

And I would like to apply the *pmap* over the partitions, something 
like: (the line bellow doesn't work)

*user=* (pmap + (partition-all 5 (range 1 20)))

/I would like to have this (pmap + (1 2 3 4 5) (6 7 8 9 10) (11 12 13 
14 15) (16 17 18 19)) instead of this (pmap + ((1 2 3 4 5) (6 7 8 9 
10) (11 12 13 14 15) (16 17 18 19)))/


How can I apply pmap over a partition-all result?
If it's possible, by doing that am I distributing the load better than 
if I used the pmap with the whole list?


Thanks
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Re: How to use pmap over a partition-all list of list?

2013-02-02 Thread Jim - FooBar();

aaa you want a scalar as the result? then use an outer reduce as well:

(reduce +
(pmap #(reduce + %) (partition-all 5 (range 1 20
=190

Jim


On 02/02/13 13:10, Jim - FooBar(); wrote:

Use this:

(pmap #(reduce + %) (partition-all 5 (range 1 20)))

OR as you yourself said you can use 'apply' instead of reduce

Jim



On 02/02/13 12:31, Leandro Moreira wrote:

Hi there,

I have this:

*user=* (partition-all 5 (range 1 20))
((1 2 3 4 5) (6 7 8 9 10) (11 12 13 14 15) (16 17 18 19))

And I would like to apply the *pmap* over the partitions, something 
like: (the line bellow doesn't work)

*user=* (pmap + (partition-all 5 (range 1 20)))

/I would like to have this (pmap + (1 2 3 4 5) (6 7 8 9 10) (11 12 13 
14 15) (16 17 18 19)) instead of this (pmap + ((1 2 3 4 5) (6 7 8 9 
10) (11 12 13 14 15) (16 17 18 19)))/


How can I apply pmap over a partition-all result?
If it's possible, by doing that am I distributing the load better 
than if I used the pmap with the whole list?


Thanks
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Re: How to use pmap over a partition-all list of list?

2013-02-02 Thread Leandro Moreira
Hi Jim,

Thanks for your help  time, how do I apply instead of reduce?

I was looking the documentation of pmap and it says

*(pmap fn coll  colls)*

So I think we can use pmap this way:

*(pmap + '(1 2 3) '(4 5 6) '(7 8 9) )*

Which gives us the result: *(12 15 18)*

My intention it's only to *use range and partition to substitute that*, but 
I think partition-all doesn't work like separated argument as list, 
instead. When we type:

(*partition-all 5 (range 1 20))*
Results in this:
*((1 2 3 4 5) (6 7 8 9 10) ...*

There is any way of *transforming* (maybe a macro or destruct way) this 
list in *several colls argument as expected by pmap* signature (fn coll  
colls)? 


On Saturday, February 2, 2013 11:10:35 AM UTC-2, Jim foo.bar wrote:

  Use this:

 (pmap #(reduce + %) (partition-all 5 (range 1 20)))

 OR as you yourself said you can use 'apply' instead of reduce

 Jim



 On 02/02/13 12:31, Leandro Moreira wrote:
  
 Hi there, 

  I have this:

  *user=* (partition-all 5 (range 1 20))
 ((1 2 3 4 5) (6 7 8 9 10) (11 12 13 14 15) (16 17 18 19))
  
  And I would like to apply the *pmap* over the partitions, something 
 like: (the line bellow doesn't work)
 *user=* (pmap + (partition-all 5 (range 1 20)))
  
  *I would like to have this (pmap + (1 2 3 4 5) (6 7 8 9 10) (11 12 13 14 
 15) (16 17 18 19)) instead of this (pmap + ((1 2 3 4 5) (6 7 8 9 10) (11 12 
 13 14 15) (16 17 18 19)))*

  How can I apply pmap over a partition-all result?
 If it's possible, by doing that am I distributing the load better than if 
 I used the pmap with the whole list?

  Thanks
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Re: How to use pmap over a partition-all list of list?

2013-02-02 Thread Leonardo Borges
this works:

(apply pmap + (partition-all 5 (range 1 20)))

And then reducing the overall result:

(reduce + (apply pmap + (partition-all 5 (range 1 20


Leonardo Borges
www.leonardoborges.com


On Sun, Feb 3, 2013 at 12:35 AM, Leandro Moreira
leandro.rhc...@gmail.com wrote:
 Hi Jim,

 Thanks for your help  time, how do I apply instead of reduce?

 I was looking the documentation of pmap and it says

 (pmap fn coll  colls)

 So I think we can use pmap this way:

 (pmap + '(1 2 3) '(4 5 6) '(7 8 9) )

 Which gives us the result: (12 15 18)

 My intention it's only to use range and partition to substitute that, but I
 think partition-all doesn't work like separated argument as list, instead.
 When we type:

 (partition-all 5 (range 1 20))
 Results in this:
 ((1 2 3 4 5) (6 7 8 9 10) ...

 There is any way of transforming (maybe a macro or destruct way) this list
 in several colls argument as expected by pmap signature (fn coll  colls)?


 On Saturday, February 2, 2013 11:10:35 AM UTC-2, Jim foo.bar wrote:

 Use this:

 (pmap #(reduce + %) (partition-all 5 (range 1 20)))

 OR as you yourself said you can use 'apply' instead of reduce

 Jim



 On 02/02/13 12:31, Leandro Moreira wrote:

 Hi there,

 I have this:

 user= (partition-all 5 (range 1 20))
 ((1 2 3 4 5) (6 7 8 9 10) (11 12 13 14 15) (16 17 18 19))

 And I would like to apply the pmap over the partitions, something like:
 (the line bellow doesn't work)
 user= (pmap + (partition-all 5 (range 1 20)))

 I would like to have this (pmap + (1 2 3 4 5) (6 7 8 9 10) (11 12 13 14
 15) (16 17 18 19)) instead of this (pmap + ((1 2 3 4 5) (6 7 8 9 10) (11 12
 13 14 15) (16 17 18 19)))

 How can I apply pmap over a partition-all result?
 If it's possible, by doing that am I distributing the load better than if
 I used the pmap with the whole list?

 Thanks
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Re: How to use pmap over a partition-all list of list?

2013-02-02 Thread Jim - FooBar();
apply does exactly what you're describing...it treats a collection as 
several arguments:


(apply + [1 2 3 4]) is equivalent to: (+ 1 2 3 4)
= 10

so (pmap + '(1 2 3) '(4 5 6) '(7 8 9) ) is equivalent to: (apply pmap + 
['(1 2 3) '(4 5 6) '(7 8 9)])


no need for macros and stuff...actually apply is a macro...

hope that helps

Jim

On 02/02/13 13:35, Leandro Moreira wrote:

Hi Jim,

Thanks for your help  time, how do I apply instead of reduce?

I was looking the documentation of pmap and it says

*(pmap fn coll  colls)*

So I think we can use pmap this way:

*(pmap + '(1 2 3) '(4 5 6) '(7 8 9) )*

Which gives us the result: *(12 15 18)*

My intention it's only to *use range and partition to substitute 
that*, but I think partition-all doesn't work like separated argument 
as list, instead. When we type:


(*partition-all 5 (range 1 20))*
Results in this:
*((1 2 3 4 5) (6 7 8 9 10) ...*

There is any way of *transforming* (maybe a macro or destruct way) 
this list in *several colls argument as expected by pmap* signature 
(fn coll  colls)?



On Saturday, February 2, 2013 11:10:35 AM UTC-2, Jim foo.bar wrote:

Use this:

(pmap #(reduce + %) (partition-all 5 (range 1 20)))

OR as you yourself said you can use 'apply' instead of reduce

Jim



On 02/02/13 12:31, Leandro Moreira wrote:

Hi there,

I have this:

*user=* (partition-all 5 (range 1 20))
((1 2 3 4 5) (6 7 8 9 10) (11 12 13 14 15) (16 17 18 19))

And I would like to apply the *pmap* over the partitions,
something like: (the line bellow doesn't work)
*user=* (pmap + (partition-all 5 (range 1 20)))

/I would like to have this (pmap + (1 2 3 4 5) (6 7 8 9 10) (11
12 13 14 15) (16 17 18 19)) instead of this (pmap + ((1 2 3 4 5)
(6 7 8 9 10) (11 12 13 14 15) (16 17 18 19)))/

How can I apply pmap over a partition-all result?
If it's possible, by doing that am I distributing the load better
than if I used the pmap with the whole list?

Thanks
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Re: How to use pmap over a partition-all list of list?

2013-02-02 Thread Marko Topolnik


 no need for macros and stuff...actually apply is a macro...


Not really, it's a function. But it does rely on the low-level IFn 
interface methods. 

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Re: How to use pmap over a partition-all list of list?

2013-02-02 Thread Leandro Moreira
Thanks all, you were really helpful ! 

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