Re: How to generate a hash map from a list
On Aug 23, 2009, at 8:21 PM, Stan Dyck wrote:
I'm still new to this so bear with me.
Welcome.
I'm trying to apply a function to a seq-able thing to produce a
hashmap. So for instance say the function is (inc 3).
I'd like to write a function that does
[1 2 3] -- {1 4, 2 5, 3 6}
Can someone help me?
Here's one way:
user= (into {} (for [i [1 2 3]] [i (+ 3 i)]))
{1 4, 2 5, 3 6}
--Steve
smime.p7s
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Re: How to generate a hash map from a list
(def a [1 2 3])
; zipmap takes two collections and makes a hash-map
user= (zipmap a (map #(+ 3 %) a))
{3 6, 2 5, 1 4}
; another way is to build up a map starting with empty {} and
associating key values
user= (reduce #(assoc %1 %2 (+ 3 %2)) {} a)
{3 6, 2 5, 1 4}
; hash-map constructs a map for a list of values (use flatten from
contrib/seq-utils to be more concise)
user= (apply hash-map (filter (complement sequential?) (rest (tree-
seq sequential? seq (for [i a] [i (+ 3 i)])
{1 4, 2 5, 3 6}
; into constructs a hashmap from a sequence of key/value pairs
; which is convenient to use with the for list comprehension
user= (into {} (for [i a] [i (+ 3 i)]))
{3 6, 2 5, 1 4}
Regards,
Tim
On Aug 24, 10:21 am, Stan Dyck stan.d...@gmail.com wrote:
I'm still new to this so bear with me.
I'm trying to apply a function to a seq-able thing to produce a hashmap. So
for instance say the function is (inc 3).
I'd like to write a function that does
[1 2 3] -- {1 4, 2 5, 3 6}
Can someone help me?
StanD.
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Re: How to generate a hash map from a list
Welcome again.
Here's another way. Not sure if it's any more or less efficient, but it's
the way my brain works.
= (defn map-hashmap [coll f]
(apply hash-map (interleave coll (map f coll
#'user/map-hashmap
= (map-hashmap [1 2 3] #(+ % 3))
{1 4, 2 5, 3 6}
On Mon, Aug 24, 2009 at 2:18 AM, Stephen C. Gilardi squee...@mac.comwrote:
On Aug 23, 2009, at 8:21 PM, Stan Dyck wrote:
I'm still new to this so bear with me.
Welcome.
I'm trying to apply a function to a seq-able thing to produce a hashmap.
So for instance say the function is (inc 3).
I'd like to write a function that does
[1 2 3] -- {1 4, 2 5, 3 6}
Can someone help me?
Here's one way:
user= (into {} (for [i [1 2 3]] [i (+ 3 i)]))
{1 4, 2 5, 3 6}
--Steve
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Re: How to generate a hash map from a list
On Aug 23, 5:21 pm, Stan Dyck stan.d...@gmail.com wrote:
I'm still new to this so bear with me.
I'm trying to apply a function to a seq-able thing to produce a hashmap. So
for instance say the function is (inc 3).
I'd like to write a function that does
[1 2 3] -- {1 4, 2 5, 3 6}
Can someone help me?
StanD.
There may be a cleaner solution, but this works:
(defn build-map [s fun]
(apply hash-map (interleave s (map fun s
= (build-map [1 2 3] inc)
{1 2, 2 3, 3 4}
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Re: How to generate a hash map from a list
(zipmap coll1 coll2) should be faster than (apply hash-map (interleave
coll1 coll2)) and the doc description hints that's what it was made
for.
On Aug 24, 8:25 am, Garth Sheldon-Coulson g...@mit.edu wrote:
Welcome again.
Here's another way. Not sure if it's any more or less efficient, but it's
the way my brain works.
= (defn map-hashmap [coll f]
(apply hash-map (interleave coll (map f coll
#'user/map-hashmap
= (map-hashmap [1 2 3] #(+ % 3))
{1 4, 2 5, 3 6}
On Mon, Aug 24, 2009 at 2:18 AM, Stephen C. Gilardi squee...@mac.comwrote:
On Aug 23, 2009, at 8:21 PM, Stan Dyck wrote:
I'm still new to this so bear with me.
Welcome.
I'm trying to apply a function to a seq-able thing to produce a hashmap.
So for instance say the function is (inc 3).
I'd like to write a function that does
[1 2 3] -- {1 4, 2 5, 3 6}
Can someone help me?
Here's one way:
user= (into {} (for [i [1 2 3]] [i (+ 3 i)]))
{1 4, 2 5, 3 6}
--Steve
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To post to this group, send email to clojure@googlegroups.com
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Re: How to generate a hash map from a list
Wonderful; I totally didn't know about zipmap. I've been using into
and map this whole time. Was it added right before Clojure 1.0? It
seems to be a lot faster than using into:
Clojure 1.0.0-
user= (time (into {} (for [i [1 2 3]] [i (+ 3 i)])) )
Elapsed time: 0.705 msecs
{3 6, 2 5, 1 4}
user= (time (zipmap [1 2 3] (map #(+ 3 %) [1 2 3])))
Elapsed time: 0.25 msecs
{3 6, 2 5, 1 4}
On Aug 24, 9:15 am, Dragan Djuric draga...@gmail.com wrote:
(zipmap coll1 coll2) should be faster than (apply hash-map (interleave
coll1 coll2)) and the doc description hints that's what it was made
for.
On Aug 24, 8:25 am, Garth Sheldon-Coulson g...@mit.edu wrote:
Welcome again.
Here's another way. Not sure if it's any more or less efficient, but it's
the way my brain works.
= (defn map-hashmap [coll f]
(apply hash-map (interleave coll (map f coll
#'user/map-hashmap
= (map-hashmap [1 2 3] #(+ % 3))
{1 4, 2 5, 3 6}
On Mon, Aug 24, 2009 at 2:18 AM, Stephen C. Gilardi squee...@mac.comwrote:
On Aug 23, 2009, at 8:21 PM, Stan Dyck wrote:
I'm still new to this so bear with me.
Welcome.
I'm trying to apply a function to a seq-able thing to produce a hashmap.
So for instance say the function is (inc 3).
I'd like to write a function that does
[1 2 3] -- {1 4, 2 5, 3 6}
Can someone help me?
Here's one way:
user= (into {} (for [i [1 2 3]] [i (+ 3 i)]))
{1 4, 2 5, 3 6}
--Steve
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Re: How to generate a hash map from a list
For completeness we should include a loop/recur pattern;
(defn fzipmap [f col]
Takes a col, applies f to each element and generates a
hash map keyed on each element of col.
(loop [col (seq col) mp {}]
(if col (recur (next col) (assoc mp (first col) (f (first col
mp)))
user= (fzipmap #(+ % 3) [1 2 3])
{3 6, 2 5, 1 4}
Regards, Adrian.
On Mon, Aug 24, 2009 at 6:43 PM, samppirbysam...@gmail.com wrote:
Wonderful; I totally didn't know about zipmap. I've been using into
and map this whole time. Was it added right before Clojure 1.0? It
seems to be a lot faster than using into:
Clojure 1.0.0-
user= (time (into {} (for [i [1 2 3]] [i (+ 3 i)])) )
Elapsed time: 0.705 msecs
{3 6, 2 5, 1 4}
user= (time (zipmap [1 2 3] (map #(+ 3 %) [1 2 3])))
Elapsed time: 0.25 msecs
{3 6, 2 5, 1 4}
On Aug 24, 9:15 am, Dragan Djuric draga...@gmail.com wrote:
(zipmap coll1 coll2) should be faster than (apply hash-map (interleave
coll1 coll2)) and the doc description hints that's what it was made
for.
On Aug 24, 8:25 am, Garth Sheldon-Coulson g...@mit.edu wrote:
Welcome again.
Here's another way. Not sure if it's any more or less efficient, but it's
the way my brain works.
= (defn map-hashmap [coll f]
(apply hash-map (interleave coll (map f coll
#'user/map-hashmap
= (map-hashmap [1 2 3] #(+ % 3))
{1 4, 2 5, 3 6}
On Mon, Aug 24, 2009 at 2:18 AM, Stephen C. Gilardi
squee...@mac.comwrote:
On Aug 23, 2009, at 8:21 PM, Stan Dyck wrote:
I'm still new to this so bear with me.
Welcome.
I'm trying to apply a function to a seq-able thing to produce a hashmap.
So for instance say the function is (inc 3).
I'd like to write a function that does
[1 2 3] -- {1 4, 2 5, 3 6}
Can someone help me?
Here's one way:
user= (into {} (for [i [1 2 3]] [i (+ 3 i)]))
{1 4, 2 5, 3 6}
--Steve
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Re: How to generate a hash map from a list
(defn fzipmap [f col]
Takes a col, applies f to each element and generates a
Note that the args should have come after the doc string!
On Tue, Aug 25, 2009 at 6:20 AM, Adrian
Cuthbertsonadrian.cuthbert...@gmail.com wrote:
For completeness we should include a loop/recur pattern;
(defn fzipmap [f col]
Takes a col, applies f to each element and generates a
hash map keyed on each element of col.
(loop [col (seq col) mp {}]
(if col (recur (next col) (assoc mp (first col) (f (first col
mp)))
user= (fzipmap #(+ % 3) [1 2 3])
{3 6, 2 5, 1 4}
Regards, Adrian.
On Mon, Aug 24, 2009 at 6:43 PM, samppirbysam...@gmail.com wrote:
Wonderful; I totally didn't know about zipmap. I've been using into
and map this whole time. Was it added right before Clojure 1.0? It
seems to be a lot faster than using into:
Clojure 1.0.0-
user= (time (into {} (for [i [1 2 3]] [i (+ 3 i)])) )
Elapsed time: 0.705 msecs
{3 6, 2 5, 1 4}
user= (time (zipmap [1 2 3] (map #(+ 3 %) [1 2 3])))
Elapsed time: 0.25 msecs
{3 6, 2 5, 1 4}
On Aug 24, 9:15 am, Dragan Djuric draga...@gmail.com wrote:
(zipmap coll1 coll2) should be faster than (apply hash-map (interleave
coll1 coll2)) and the doc description hints that's what it was made
for.
On Aug 24, 8:25 am, Garth Sheldon-Coulson g...@mit.edu wrote:
Welcome again.
Here's another way. Not sure if it's any more or less efficient, but it's
the way my brain works.
= (defn map-hashmap [coll f]
(apply hash-map (interleave coll (map f coll
#'user/map-hashmap
= (map-hashmap [1 2 3] #(+ % 3))
{1 4, 2 5, 3 6}
On Mon, Aug 24, 2009 at 2:18 AM, Stephen C. Gilardi
squee...@mac.comwrote:
On Aug 23, 2009, at 8:21 PM, Stan Dyck wrote:
I'm still new to this so bear with me.
Welcome.
I'm trying to apply a function to a seq-able thing to produce a
hashmap.
So for instance say the function is (inc 3).
I'd like to write a function that does
[1 2 3] -- {1 4, 2 5, 3 6}
Can someone help me?
Here's one way:
user= (into {} (for [i [1 2 3]] [i (+ 3 i)]))
{1 4, 2 5, 3 6}
--Steve
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