Re: Recursive anonymous functions in the call position
Thanks !!! It's wonderful how much time can be wasted because a bad copy&paste :-) Juan Manuel On Friday, March 16, 2012 9:39:09 AM UTC+1, Meikel Brandmeyer (kotarak) wrote: > > Hi, > > there is no 6th element in your example. That's why you get nil. > > Clojure 1.3.0 > user=> ((fn [[f & r] n] (if (zero? n) f (recur r (dec n [4 5 6 7 8 9] > 2) > 6 > > Sincerely > Meikel > > -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: Recursive anonymous functions in the call position
Hi, there is no 6th element in your example. That's why you get nil. Clojure 1.3.0 user=> ((fn [[f & r] n] (if (zero? n) f (recur r (dec n [4 5 6 7 8 9] 2) 6 Sincerely Meikel -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Recursive anonymous functions in the call position
Problem 21 is: Write a function which returns the Nth element from a sequence. My solution is: (fn [[f & r] n] (if (zero? n) f (recur r (dec n) but it is marked as incorrect. Opening a REPL, and defining it with defn: (defn mynth [[f & r] n] (if (zero? n) f (recur r (dec n user=> (mynth '(4 5 6 7 8) 2) 6 And using def + fn: (def mynth-anon (fn [[f & r] n] (if (zero? n) f (recur r (dec n)) user=> #'user/mynth-anon user=> (mynth-anon '(4 5 6 7 8) 2) 6 But (it id this result which I can't understand and the reason 4clojure does not like my solution) : user=> ((fn [[f & r] n] (if (zero? n) f (recur r (dec n '(4 5 6 7 8 9) 6) nil user=> It seems I can't use an explicit anonymous recursive function in the call position. Is this so? Why? Is it a bug? Thanks, Juan Manuel -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
