Re: core.logic - using membero to generate list?

2013-07-06 Thread Norman Richards
On Sat, Jul 6, 2013 at 3:16 PM, Adam Saleh  wrote:

>
> =>  (run 1 [q]
> #=>   (membero :a q))
> ((:a . _0))
>
> Unfortunately when I try to do something \w it, it throws exception
>
> => (first *1)
> (1 . _0)
> => (first *1)
> IllegalArgumentException Don't know how to create ISeq from:
> clojure.core.logic.LCons  clojure.lang.RT.seqFrom (RT.java:505)
>
> I guess I need to somehow convert the "logic-based" list to
> "clojure-based", how do I do it?
>

A cons cell doesn't really convert to a clojure list, especially when the
last item is fresh.  I guess the real question is: what result do you want
from Clojure?

If you just want to access the values you have now, you can get them with
lfirst/lnext (in clojure.core.logic.protocols) but maybe the better
question to ask is: what clojure result do you actually want?

If you want all the possible proper lists, then I'd suggest constraining it
to be such:

(defn listo [l]
  (conde [(emptyo l)]
 [(fresh [a d]
 (conso a d l)
 (listo d))]))


In my experience, calling core.logic from real application code works best
when you write programs that produce fully realized results without any
fresh values

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core.logic - using membero to generate list?

2013-07-06 Thread Adam Saleh
Hi,

I wanted to use featurec to generate hash-map, 
similarily to a way I use membero when generating lists.

i.e 
=>  (run 1 [q]
#=>   (membero :a q))
((:a . _0))

Unfortunately when I try to do something \w it, it throws exception

=> (first *1)
(1 . _0)
=> (first *1)
IllegalArgumentException Don't know how to create ISeq from: 
clojure.core.logic.LCons  clojure.lang.RT.seqFrom (RT.java:505)

I guess I need to somehow convert the "logic-based" list to 
"clojure-based", how do I do it?

Thanks!

Adam

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