Re: not= counterintuitive?
The clojure.contrib.combinatorics/combinations does do exactly what I was trying to do, although I was doing the problem as an exercise in how to do it, and not in really needing combinations for something else. The combinatorics library certainly does it in a more generic way. Since I knew that I was dealing with numbers as input, I actually ended up using (> m n o) as my test condition, which has the same effect of guaranteeing all the numbers are distinct. I was looking for unique sets where order didn't matter. Thanks for the input, all! -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: not= counterintuitive?
On Sat, Sep 3, 2011 at 1:30 PM, Despite wrote: > So, you want to make sure each value in the vector is unique? My > first thought was to put them into a set, then see if the set was > equal to the vector, but clojure's equality doesn't allow for that. > And if you put the set back into a vector, you've changed the order. Just see if the set is the same *size* as the vector. If there were duplicates, it will be smaller instead. -- Protege: What is this seething mass of parentheses?! Master: Your father's Lisp REPL. This is the language of a true hacker. Not as clumsy or random as C++; a language for a more civilized age. -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: not= counterintuitive?
(= (seq v) (distinct v)) will short-circuit as soon as an inequality is found. On Sep 3, 12:47 pm, Meikel Brandmeyer wrote: > Hi, > > Am 03.09.2011 um 19:30 schrieb Despite: > > > So, you want to make sure each value in the vector is unique? My > > first thought was to put them into a set, then see if the set was > > equal to the vector, but clojure's equality doesn't allow for that. > > And if you put the set back into a vector, you've changed the order. > > You can check (= (count v) (count (set v))) whether there are no duplicates. > > Sincerley > Meikel -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: not= counterintuitive?
Hi, Am 03.09.2011 um 19:30 schrieb Despite: > So, you want to make sure each value in the vector is unique? My > first thought was to put them into a set, then see if the set was > equal to the vector, but clojure's equality doesn't allow for that. > And if you put the set back into a vector, you've changed the order. You can check (= (count v) (count (set v))) whether there are no duplicates. Sincerley Meikel -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: not= counterintuitive?
On Sep 2, 4:48 pm, ax2groin wrote: > That's what I get for posting a question while feeding a 1-year-old > child and getting ready to leave for lunch. > > I was trying to put together a (for) construct to output the > combinations of a set, and my logic was flawed. > > Here's what I really wanted [for sets of 3]: > > (for [m x n x o x :while (and (not= m n) (not= m o) (not= n o))] [m n > o]) > > Maybe not the most efficient, but the smallest construct I've come up > with, but it isn't generic enough for me yet. > > I'll keep working on it. So, you want to make sure each value in the vector is unique? My first thought was to put them into a set, then see if the set was equal to the vector, but clojure's equality doesn't allow for that. And if you put the set back into a vector, you've changed the order. Now I think you might be asking for the permutations. clojure.contrib.combinatorics as a permutations function: user=> (clojure.contrib.combinatorics/permutations [1 2 3]) ((1 2 3) (1 3 2) (2 1 3) (2 3 1) (3 1 2) (3 2 1)) -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: not= counterintuitive?
On Sat, Sep 3, 2011 at 10:59 AM, Alex Baranosky
wrote:
> Sounds like you want a function such as:
>
> none=
...which could be written as #(not-any? #{1} [1 2 3])
--Chouser
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Re: not= counterintuitive?
Sounds like you want a function such as: none= On Sep 3, 2011 4:30 AM, "Vijay Lakshminarayanan" wrote: > ax2groin writes: > >> This code doesn't return the value I intuitively expect: >> >> user=> (not= 1 2 1) >> true >> >> When I write that, I was expecting the equivalent of (and (= 1 2) (= 1 >> 1)), but the macro expansion is essentially (not (= 1 2 1)). > > If you were expecting (not (and (= 1 2) (= 1 1))) then it would match > your expectations. > > -- > Cheers > ~vijay > > -- > You received this message because you are subscribed to the Google > Groups "Clojure" group. > To post to this group, send email to clojure@googlegroups.com > Note that posts from new members are moderated - please be patient with your first post. > To unsubscribe from this group, send email to > clojure+unsubscr...@googlegroups.com > For more options, visit this group at > http://groups.google.com/group/clojure?hl=en -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: not= counterintuitive?
ax2groin writes: > This code doesn't return the value I intuitively expect: > > user=> (not= 1 2 1) > true > > When I write that, I was expecting the equivalent of (and (= 1 2) (= 1 > 1)), but the macro expansion is essentially (not (= 1 2 1)). If you were expecting (not (and (= 1 2) (= 1 1))) then it would match your expectations. -- Cheers ~vijay -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: not= counterintuitive?
That's what I get for posting a question while feeding a 1-year-old child and getting ready to leave for lunch. I was trying to put together a (for) construct to output the combinations of a set, and my logic was flawed. Here's what I really wanted [for sets of 3]: (for [m x n x o x :while (and (not= m n) (not= m o) (not= n o))] [m n o]) Maybe not the most efficient, but the smallest construct I've come up with, but it isn't generic enough for me yet. I'll keep working on it. -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: not= counterintuitive?
On Sep 2, 11:14 am, ax2groin wrote: > This code doesn't return the value I intuitively expect: > > user=> (not= 1 2 1) > true > > When I write that, I was expecting the equivalent of (and (= 1 2) (= 1 > 1)), but the macro expansion is essentially (not (= 1 2 1)). This is not a macro. -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: not= counterintuitive?
2011/9/2 Mark Engelberg > > On Fri, Sep 2, 2011 at 11:14 AM, ax2groin wrote: > >> This code doesn't return the value I intuitively expect: >> >> user=> (not= 1 2 1) >> true >> >> This is exactly what I expect. Those values are not all equal. > same for me > -- > You received this message because you are subscribed to the Google > Groups "Clojure" group. > To post to this group, send email to clojure@googlegroups.com > Note that posts from new members are moderated - please be patient with > your first post. > To unsubscribe from this group, send email to > clojure+unsubscr...@googlegroups.com > For more options, visit this group at > http://groups.google.com/group/clojure?hl=en > -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: not= counterintuitive?
On Fri, Sep 2, 2011 at 11:14 AM, ax2groin wrote: > This code doesn't return the value I intuitively expect: > > user=> (not= 1 2 1) > true > > This is exactly what I expect. Those values are not all equal. -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
not= counterintuitive?
This code doesn't return the value I intuitively expect: user=> (not= 1 2 1) true When I write that, I was expecting the equivalent of (and (= 1 2) (= 1 1)), but the macro expansion is essentially (not (= 1 2 1)). Note: This came out of the :while condition of a (for) expression not returning what I expected on three separate values, where (= x z). I can work around it to get what I want, but I was curious if perhaps the (not=) was not in the spirit it was intended. -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
