Bug#711162: ssh-copy-id unexpected operator error

2013-06-05 Thread Andrey Rahmatullin 
Package: openssh-client
Version: 1:6.2p2-3
Severity: normal

When running ssh-copy-id with or without arguments I get a shell error:

/usr/bin/ssh-copy-id: 168: [: 0: unexpected operator

The script continues working after this though. The offending code: [ $# == 0
]. There is also [ $# != 1 ] in the next code block. POSIX test(1) doesn't
know == and applies != only to strings. Numbers should be compared with -eq
and -ne.



-- System Information:
Debian Release: jessie/sid
  APT prefers testing
  APT policy: (990, 'testing'), (500, 'unstable'), (1, 'experimental')
Architecture: amd64 (x86_64)
Foreign Architectures: i386

Kernel: Linux 3.8-2-amd64 (SMP w/4 CPU cores)
Locale: LANG=ru_RU.UTF-8, LC_CTYPE=ru_RU.UTF-8 (charmap=UTF-8)
Shell: /bin/sh linked to /bin/dash

Versions of packages openssh-client depends on:
ii  adduser   3.113+nmu3
ii  dpkg  1.16.10
ii  libc6 2.17-3
ii  libedit2  2.11-20080614-5
ii  libgssapi-krb5-2  1.10.1+dfsg-5
ii  libselinux1   2.1.13-2
ii  libssl1.0.0   1.0.1e-3
ii  passwd1:4.1.5.1-1
ii  zlib1g1:1.2.8.dfsg-1

Versions of packages openssh-client recommends:
ii  xauth  1:1.0.7-1

Versions of packages openssh-client suggests:
pn  keychain none
pn  libpam-ssh   none
pn  monkeysphere none
ii  openssh-blacklist0.4.1+nmu1
ii  openssh-blacklist-extra  0.4.1+nmu1
pn  ssh-askpass  none

-- no debconf information


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Bug#711162: ssh-copy-id unexpected operator error

2013-06-05 Thread Colin Watson 
Control: forwarded -1 https://bugzilla.mindrot.org/show_bug.cgi?id=2117
Control: tag -1 pending

On Wed, Jun 05, 2013 at 12:52:06PM +0600, Andrey Rahmatullin wrote:
 When running ssh-copy-id with or without arguments I get a shell error:
 
 /usr/bin/ssh-copy-id: 168: [: 0: unexpected operator
 
 The script continues working after this though. The offending code: [ $# == 0
 ]. There is also [ $# != 1 ] in the next code block. POSIX test(1) doesn't
 know == and applies != only to strings. Numbers should be compared with 
 -eq
 and -ne.

Actually it's fine to do equality comparisons on numbers with = and !=,
just not (portably) with ==.  For purposes as simple as this, numbers
can be treated as strings.

I have forwarded your comment upstream, and fixed the non-portability
for my next upload.

Thanks,

-- 
Colin Watson   [cjwat...@debian.org]


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