separate files are the Spring DSL

[newbiee]

I have an XML file with the following route: (I have tested it and it works
fine)


   
   
   
   ${header.CamelFileName}
regex '^.*xml$'
   
   
   
   ${header.CamelFileName}
regex '^.*(csv|csl)$'
   
   
   
   
   
   
   
  

Now I want to define the route in a separate XML file using routeContext and
access it in the main xml file using routeContextRef. I havee created the
route as 

  http://camel.apache.org/schema/spring";>

   
   
   
   ${header.CamelFileName}
regex '^.*xml$'
   
   
   
   ${header.CamelFileName}
regex '^.*(csv|csl)$'
   
   
   
   
   
   
   
  


If I save it as ftpToJms.xml then how can I refer to it using
routeContextRef?

I did follwoing but it is failing:

http://camel.apache.org/schema/spring";>
 


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Re: separate files are the Spring DSL

[newbiee]

Thank you for the reply.

I folllowed FAQ given at
http://camel.apache.org/how-do-i-import-routes-from-other-xml-files.html

Here is the route that I want to import:

http://www.springframework.org/schema/beans";
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";
   xsi:schemaLocation="
   http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
   http://camel.apache.org/schema/spring
http://camel.apache.org/schema/spring/camel-spring.xsd
">
 
 http://camel.apache.org/schema/spring";>

   
   
   
   ${header.CamelFileName}
regex '^.*xml$'
   
   
   
   ${header.CamelFileName}
regex '^.*(csv|csl)$'
   
   
   
   
   
   
   
  


  

and here is the XML file where I want to import the above route:

http://www.springframework.org/schema/beans";
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";
   xsi:schemaLocation="
   http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
   http://camel.apache.org/schema/spring
http://camel.apache.org/schema/spring/camel-spring.xsd
 ">

 
 


http://camel.apache.org/schema/spring";>

 



I am getting following error: (please tell me what is going wrong)
  


karaf@root> Exception in thread "SpringOsgiExtenderThread-21"
java.lang.IllegalStateException: BeanFactory not initialized or already
closed - call 'r
efresh' before accessing beans via the ApplicationContext
at
org.springframework.context.support.AbstractRefreshableApplicationContext.getBeanFactory(AbstractRefreshableApplicationContext.java:171)
at
org.springframework.osgi.extender.internal.dependencies.startup.DependencyWaiterApplicationContextExecutor.close(DependencyWaiterApplicatio
nContextExecutor.java:345)
at
org.springframework.osgi.extender.internal.dependencies.startup.DependencyWaiterApplicationContextExecutor.fail(DependencyWaiterApplication
ContextExecutor.java:401)
at
org.springframework.osgi.extender.internal.dependencies.startup.DependencyWaiterApplicationContextExecutor.stageOne(DependencyWaiterApplica
tionContextExecutor.java:287)
at
org.springframework.osgi.extender.internal.dependencies.startup.DependencyWaiterApplicationContextExecutor.refresh(DependencyWaiterApplicat
ionContextExecutor.java:175)
at
org.springframework.osgi.context.support.AbstractDelegatedExecutionApplicationContext.refresh(AbstractDelegatedExecutionApplicationContext.
java:175)
at
org.springframework.osgi.extender.internal.activator.ContextLoaderListener$2.run(ContextLoaderListener.java:718)
at java.lang.Thread.run(Thread.java:662)

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reading Message for content based routing

[newbiee]

Suppose I have following two messages:


Message 1:




Message 2:




I want to route message to queue "application A" or to queue "application B"
based on the application value in the message. How can I get to the
application value in the message?

Thank you

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