[development-axapta] Bitmaps in pdf files

[Allan Ørum]

Hi,
I have a problem with pdf files.
When I print to screen (eg a confirmation), my bitmaps comes out fine and
scaled.
But when I print to a pdf file, the bitmaps are placed funny, and are no
longer scaled.

Anyone with experience in this area?

Regards Allan









  
  
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SV: [development-axapta] Type Casting in Axapta Urgent Please

[Allan Ørum]

Str s;

;

s = enum2Str(TableGroupAll::All);

 

Regards

 

Allan



Fra: development-axapta@yahoogroups.com [mailto:[EMAIL PROTECTED] På vegne af maltmega
Sendt: 15. februar 2006 13:16
Til: development-axapta@yahoogroups.com
Emne: [development-axapta] Type Casting in Axapta Urgent Please

 

Hi,

Actually I want to compare these two fields

inventtable.ItemId==routeopr.ItemCode

Inventtable.ItemId is of string type and routeopr.ItemCode is of 
baseenum type.

When i do compare it gives this error message

"Operand types are not compatible with the operator."

What do i have to do? How can i do type casting?

Help needed urgent please...

Regards,

Malters.








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SV: [development-axapta] Can anybody explain me this syntax

[Allan Ørum]

Hi Thomas

If you dont pass a parameter n to this method, n will get the value from the
tablebuffer _emp.name.
If you do pass a value, n will have this value.

The body, simply gives _emp.name the value n, and returns it.

Regards
Allan

-Oprindelig meddelelse-
Fra: development-axapta@yahoogroups.com
[mailto:[EMAIL PROTECTED] På vegne af Thomas
Sendt: 26. juli 2005 15:09
Til: development-axapta@yahoogroups.com
Emne: [development-axapta] Can anybody explain me this syntax

Hello,
I am used to programming Java and C#. But for some reason I have 
problems understanding this syntax:

EmplName name(EmplName n = _emp.name)
{
    _emp.name = n;
    return n;
}

I understand the following:
the method name returns an EmplName. when calling the method you do it 
with a parameter n of the type EmplName. But what dows the n = 
_emp.name do? and what goes on in the method body?







 
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