Re: AW: [development-axapta] operation from combination of enum
hi jesper,
thx for ur suggestion, ur solutions is most useful for me among all.i will only
need 2 "for loop" for 2 enum with 4 elements each. thx very much.
rgds,
daniel
[EMAIL PROTECTED] wrote:
Hi
You can loop over an enum like this
static void EnumTest(Args _args)
{
SysDictenum dictEnum;
Counter counter;
;
dictEnum = new SysDictEnum(EnumNum(ABC));
for (counter = 0; counter < dictEnum.values(); counter++)
{
print dictEnum.index2Name(counter);
}
pause;
}
Yf
jesper
Von: Hans-Walter Bous [mailto:[EMAIL PROTECTED]
Gesendet: Donnerstag, 17. März 2005 09:21
An: development-axapta@yahoogroups.com
Betreff: Re: [development-axapta] operation from combination of enum
Hi,
you can do something like this:
switch (enumA)
{
case(enumA::TypeA):
switch (enumB)
{
case(enumB::TypeA) :
do something;
break;
}
}
John
daniellim_yh <[EMAIL PROTECTED]> wrote:
hi all,
i have 2 enum type, 4 elements each, i wonder wat is the best way
for me to do
like this in axapta.
if (enum1::typeA && enum2::typeW)
Do something1
else
if (enum1::typeA && enum2::typeX)
Do something 2
else
if (enum1::typeA && enum2::typeY)
do something 3
.
.
.
.
if (enum1::typeD && enum2::Z)
do something 16
with 2 combinations of 2 enums i will have 16 combinations, any
better
way of it?using enum element position to do looping may be?but as
i know i cannot get enum position like container.
pls provide any idea. thx in advance.
rgds,
daniel
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AW: [development-axapta] operation from combination of enum
Hi
You can loop over an enum like this
static void EnumTest(Args _args)
{
SysDictenum dictEnum;
Counter counter;
;
dictEnum = new SysDictEnum(EnumNum(ABC));
for (counter = 0; counter < dictEnum.values(); counter++)
{
print dictEnum.index2Name(counter);
}
pause;
}
Yf
jesper
Von: Hans-Walter Bous [mailto:[EMAIL PROTECTED]
Gesendet: Donnerstag, 17. März 2005 09:21
An: development-axapta@yahoogroups.com
Betreff: Re: [development-axapta] operation from combination of enum
Hi,
you can do something like this:
switch (enumA)
{
case(enumA::TypeA) :
switch (enumB)
{
case(enumB::TypeA) :
do something;
break;
}
}
John
daniellim_yh <[EMAIL PROTECTED]> wrote:
hi all,
i have 2 enum type, 4 elements each, i wonder wat is the best way
for me to do
like this in axapta.
if (enum1::typeA && enum2::typeW)
Do something1
else
if (enum1::typeA && enum2::typeX)
Do something 2
else
if (enum1::typeA && enum2::typeY)
do something 3
.
.
.
.
if (enum1::typeD && enum2::Z)
do something 16
with 2 combinations of 2 enums i will have 16 combinations, any
better
way of it?using enum element position to do looping may be?but as
i know i cannot get enum position like container.
pls provide any idea. thx in advance.
rgds,
daniel
Yahoo! Groups SponsorADVERTISEMENT
-
Yahoo! Groups Links
To visit your group on the web, go to:
http://groups.yahoo.com/group/development-axapta/
To unsubscribe from this group, send an email to:
[EMAIL PROTECTED]
Your use of Yahoo! Groups is subject to the Yahoo! Terms of Service.
-
Gesendet von Yahoo! Mail - Jetzt mit 250MB kostenlosem Speicher
[Non-text portions of this message have been removed]
Yahoo! Groups Sponsor
ADVERTISEMENT
click here
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Yahoo! Groups Links
* To visit your group on the web, go to:
http://groups.yahoo.com/group/development-axapta/
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