Re: Overloading opEquals(T)(T y)

2011-02-08 Thread Steven Schveighoffer

On Tue, 08 Feb 2011 11:49:47 -0500, spir  wrote:


On 02/08/2011 05:17 PM, Steven Schveighoffer wrote:



What is the difference between:

bool opEquals(T)(T y) if (is(T == BigRational)) {...}

and

bool opEquals(T)(T y)
{
static if(is(T == BigRational)) {...}
else static assert(0, "invalid type");
}


Thank you very much, Steven.
I'd say: in the first case, there are as many functions as constraints  
variants (provided other variants are implemented, indeed) triggered by  
actual calls to opEquals.
Tell me if i'm right on this: In the second case, there is a single  
function generated, and branches of static if are inserted according to  
actual calls. Is that right? If yes then I don't really care of this use  
of static f (I'm aware there are other, maybe more relevant, use cases).


No, there are multiple functions generated, and in each function, the  
correct static if branch is compiled.  It's technically no different  
code-generation wise than the constraint version.


The difference comes in the compiler decision of whether to compile a  
function or not, and who is responsible for reporting the error (in the  
first, the compiler reports the error, in the second, you are responsible  
for reporting the error via static assert).


-Steve


Re: Overloading opEquals(T)(T y)

2011-02-08 Thread spir

On 02/08/2011 05:17 PM, Steven Schveighoffer wrote:

On Tue, 08 Feb 2011 10:52:35 -0500, spir  wrote:


On 02/08/2011 12:16 AM, bearophile wrote:

Charles McAnany:


Hi, all. So I'm trying to make a BigRational struct, to get more comfortable
with D.





I just thought at this alternative between a constraint and a static if a few
hours ago. In which case, and according to which reasoning, would one choose
one or the other? (I chose static if only for the very bad reason I can
hardly stand is().)


The point of constraints are to intercept the compilation earlier. For the
discussed example, it's not as important. Let's try a smaller example.

What is the difference between:

bool opEquals(T)(T y) if (is(T == BigRational)) {...}

and

bool opEquals(T)(T y)
{
static if(is(T == BigRational)) {...}
else static assert(0, "invalid type");
}


Thank you very much, Steven.
I'd say: in the first case, there are as many functions as constraints variants 
(provided other variants are implemented, indeed) triggered by actual calls to 
opEquals.
Tell me if i'm right on this: In the second case, there is a single function 
generated, and branches of static if are inserted according to actual calls. Is 
that right? If yes then I don't really care of this use of static f (I'm aware 
there are other, maybe more relevant, use cases).



With an example like myBigRational == 5?

The difference is, with the first, the compiler simply skips compiling that
function due to the constraint. With the second, the compiler still tries to
compile the opEquals. The difference is really in the error the compiler
generates. With the first, the error is "no function found", the second is
"function doesn't compile". This is all pretty much equivalent, until you want
to overload the template. Perhaps you want to overload it in different modules.
With the second method, this is impossible, all overloads must be in the single
definition. This also makes it somewhat less readable.

Plus, with the second, its really easy to forget that "else static assert",
meaning the function will compile, and simply do nothing (actually, it won't
compile because it doesn't return a value, but still, that error message is
going to be way more confusing than "no function found").


Right.


I'd say a rule of thumb is, if the entire function is going to be different
based on the types, you should use a constraint. If there is one small
difference in the function, then using the static if might be a better
approach, but you still might want to use the constraints to restrict to what
you expect.


Right again, makes full sense now.

Denis
--
_
vita es estrany
spir.wikidot.com



Re: Overloading opEquals(T)(T y)

2011-02-08 Thread Steven Schveighoffer

On Tue, 08 Feb 2011 10:52:35 -0500, spir  wrote:


On 02/08/2011 12:16 AM, bearophile wrote:

Charles McAnany:

Hi, all. So I'm trying to make a BigRational struct, to get more  
comfortable

with D.


I suggest to ask similar questions in the D.learn newsgroup.



bool opEquals(Tdummy = void)(BigRational y){
auto temp = this-y;
if (temp.numerator == 0)
return true;
return false;
}

bool opEquals(T)(T y){
return this == BigRational(y);
}

But this is an ambiguity error.


One possible solution:

bool opEquals(T)(T y) if (is(T == BigRational)) { ... }
bool opEquals(T)(T y) if (!is(T == BigRational)) { ... }


Another solution:

bool opEquals(T)(T y) {
 static if (is(T == BigRational)) {
 // ...
 } else {
 // ...
 }
}

Bye,
bearophile


I just thought at this alternative between a constraint and a static if  
a few hours ago. In which case, and according to which reasoning, would  
one choose one or the other? (I chose static if only for the very bad  
reason I can hardly stand is().)


The point of constraints are to intercept the compilation earlier.  For  
the discussed example, it's not as important.  Let's try a smaller example.


What is the difference between:

bool opEquals(T)(T y) if (is(T == BigRational)) {...}

and

bool opEquals(T)(T y)
{
   static if(is(T == BigRational)) {...}
   else static assert(0, "invalid type");
}

With an example like myBigRational == 5?

The difference is, with the first, the compiler simply skips compiling  
that function due to the constraint.  With the second, the compiler still  
tries to compile the opEquals.  The difference is really in the error the  
compiler generates.  With the first, the error is "no function found", the  
second is "function doesn't compile".  This is all pretty much equivalent,  
until you want to overload the template.  Perhaps you want to overload it  
in different modules.  With the second method, this is impossible, all  
overloads must be in the single definition.  This also makes it somewhat  
less readable.


Plus, with the second, its really easy to forget that "else static  
assert", meaning the function will compile, and simply do nothing  
(actually, it won't compile because it doesn't return a value, but still,  
that error message is going to be way more confusing than "no function  
found").


I'd say a rule of thumb is, if the entire function is going to be  
different based on the types, you should use a constraint.  If there is  
one small difference in the function, then using the static if might be a  
better approach, but you still might want to use the constraints to  
restrict to what you expect.


-Steve


Re: Overloading opEquals(T)(T y)

2011-02-08 Thread spir

On 02/08/2011 12:16 AM, bearophile wrote:

Charles McAnany:


Hi, all. So I'm trying to make a BigRational struct, to get more comfortable
with D.


I suggest to ask similar questions in the D.learn newsgroup.



bool opEquals(Tdummy = void)(BigRational y){
auto temp = this-y;
if (temp.numerator == 0)
return true;
return false;
}

bool opEquals(T)(T y){
return this == BigRational(y);
}

But this is an ambiguity error.


One possible solution:

bool opEquals(T)(T y) if (is(T == BigRational)) { ... }
bool opEquals(T)(T y) if (!is(T == BigRational)) { ... }


Another solution:

bool opEquals(T)(T y) {
 static if (is(T == BigRational)) {
 // ...
 } else {
 // ...
 }
}

Bye,
bearophile


I just thought at this alternative between a constraint and a static if a few 
hours ago. In which case, and according to which reasoning, would one choose 
one or the other? (I chose static if only for the very bad reason I can hardly 
stand is().)


Denis
--
_
vita es estrany
spir.wikidot.com



Re: Overloading opEquals(T)(T y)

2011-02-07 Thread bearophile
Charles McAnany:

> Hi, all. So I'm trying to make a BigRational struct, to get more comfortable
> with D.

I suggest to ask similar questions in the D.learn newsgroup.


> bool opEquals(Tdummy = void)(BigRational y){
>   auto temp = this-y;
>   if (temp.numerator == 0)
>   return true;
>   return false;
> }
> 
> bool opEquals(T)(T y){
>   return this == BigRational(y);
> }
> 
> But this is an ambiguity error.

One possible solution:

bool opEquals(T)(T y) if (is(T == BigRational)) { ... }
bool opEquals(T)(T y) if (!is(T == BigRational)) { ... }


Another solution:

bool opEquals(T)(T y) {
static if (is(T == BigRational)) {
// ...
} else {
// ...
}
}

Bye,
bearophile


Overloading opEquals(T)(T y)

2011-02-07 Thread Charles McAnany
Hi, all. So I'm trying to make a BigRational struct, to get more comfortable
with D. I'm working on the opEquals part now, and I'm having some difficulty.
I'd like to write an equality checker for two BigRationals, and have all other
comparisons make a BigRational of the rhs and then forward that to the first
equality checker.

bool opEquals(Tdummy = void)(BigRational y){
auto temp = this-y;
if (temp.numerator == 0)
return true;
return false;
}

bool opEquals(T)(T y){
return this == BigRational(y);
}

But this is an ambiguity error. Certainly, I could write opEquals(T: int)(T
y), opEquals(T:long)(T y), and so on and so on, but I feel there must be a
more elegant solution. Any ideas?
Thanks,
Charles