Re: main.d(61): Error: temp_[i_] isn't mutable
Hi Andrei, == Quote from Andrei Alexandrescu (seewebsiteforem...@erdani.org)'s article On 06/20/2010 12:56 PM, Ali Çehreli wrote: Ben Hanson wrote: == Quote from Justin Spahr-Summers (justin.spahrsumm...@gmail.com)'s string is actually an alias for immutable(char)[] (and similarly for the other string types), so its contents are not modifiable, though its length can be adjusted and contents appended. If you need to be able to modify the characters, just use char[] instead. You can then use the .idup property to get a string afterward. I'm converted temp_ to CharT[] as suggested, but the conversion back to a string is failing: _charset = temp_.idup; main.d(76): Error: cannot implicitly convert expression (_adDupT(( D58TypeInfo_AT4main14__T5regexTAyaZ18basic_string_token5CharT6__initZ),cast (string)temp_)) of type immutable(CharT)[] to string Would it work for you if the regex template took the character type instead of the string type? The relevant lines: template regex(CharT) { // ... alias CharT[] StringT; StringT _charset; enum size_t MAX_CHARS = CharT.max + 1; // ... _charset = squeeze(_charset.idup).dup; And then, in main: regex!(char).basic_string_token token_; Ali IMHO it's more general if the regexp took the string type as a parameter. This is because later that is easier generalizable to accepting a range that's different from an array. My dream: to have a compile-time-generated regex engine that can operate on any input stream. Andrei I'm currently using strings for the regex strings themselves. In lexertl, I use templated free functions what work with iterators, which means input can come from different sources. This sounds like the kind of thing you are talking about? Regards, Ben
Re: main.d(61): Error: temp_[i_] isn't mutable
On 06/21/2010 03:37 AM, Ben Hanson wrote: I'm currently using strings for the regex strings themselves. In lexertl, I use templated free functions what work with iterators, which means input can come from different sources. This sounds like the kind of thing you are talking about? Regards, Ben Sounds about right! Andrei
Re: main.d(61): Error: temp_[i_] isn't mutable
== Quote from Justin Spahr-Summers (justin.spahrsumm...@gmail.com)'s string is actually an alias for immutable(char)[] (and similarly for the other string types), so its contents are not modifiable, though its length can be adjusted and contents appended. If you need to be able to modify the characters, just use char[] instead. You can then use the .idup property to get a string afterward. I'm converted temp_ to CharT[] as suggested, but the conversion back to a string is failing: _charset = temp_.idup; main.d(76): Error: cannot implicitly convert expression (_adDupT(( D58TypeInfo_AT4main14__T5regexTAyaZ18basic_string_token5CharT6__initZ),cast (string)temp_)) of type immutable(CharT)[] to string
Re: main.d(61): Error: temp_[i_] isn't mutable
Ben Hanson wrote: == Quote from Justin Spahr-Summers (justin.spahrsumm...@gmail.com)'s string is actually an alias for immutable(char)[] (and similarly for the other string types), so its contents are not modifiable, though its length can be adjusted and contents appended. If you need to be able to modify the characters, just use char[] instead. You can then use the .idup property to get a string afterward. I'm converted temp_ to CharT[] as suggested, but the conversion back to a string is failing: _charset = temp_.idup; main.d(76): Error: cannot implicitly convert expression (_adDupT(( D58TypeInfo_AT4main14__T5regexTAyaZ18basic_string_token5CharT6__initZ),cast (string)temp_)) of type immutable(CharT)[] to string Would it work for you if the regex template took the character type instead of the string type? The relevant lines: template regex(CharT) { // ... alias CharT[] StringT; StringT _charset; enum size_t MAX_CHARS = CharT.max + 1; // ... _charset = squeeze(_charset.idup).dup; And then, in main: regex!(char).basic_string_token token_; Ali
Re: main.d(61): Error: temp_[i_] isn't mutable
On 06/20/2010 12:56 PM, Ali Çehreli wrote: Ben Hanson wrote: == Quote from Justin Spahr-Summers (justin.spahrsumm...@gmail.com)'s string is actually an alias for immutable(char)[] (and similarly for the other string types), so its contents are not modifiable, though its length can be adjusted and contents appended. If you need to be able to modify the characters, just use char[] instead. You can then use the .idup property to get a string afterward. I'm converted temp_ to CharT[] as suggested, but the conversion back to a string is failing: _charset = temp_.idup; main.d(76): Error: cannot implicitly convert expression (_adDupT(( D58TypeInfo_AT4main14__T5regexTAyaZ18basic_string_token5CharT6__initZ),cast (string)temp_)) of type immutable(CharT)[] to string Would it work for you if the regex template took the character type instead of the string type? The relevant lines: template regex(CharT) { // ... alias CharT[] StringT; StringT _charset; enum size_t MAX_CHARS = CharT.max + 1; // ... _charset = squeeze(_charset.idup).dup; And then, in main: regex!(char).basic_string_token token_; Ali IMHO it's more general if the regexp took the string type as a parameter. This is because later that is easier generalizable to accepting a range that's different from an array. My dream: to have a compile-time-generated regex engine that can operate on any input stream. Andrei
Re: main.d(61): Error: temp_[i_] isn't mutable
On Sun, 20 Jun 2010 12:01:31 + (UTC), Ben Hanson ben.han...@tfbplc.co.uk wrote: == Quote from Justin Spahr-Summers (justin.spahrsumm...@gmail.com)'s string is actually an alias for immutable(char)[] (and similarly for the other string types), so its contents are not modifiable, though its length can be adjusted and contents appended. If you need to be able to modify the characters, just use char[] instead. You can then use the .idup property to get a string afterward. I'm converted temp_ to CharT[] as suggested, but the conversion back to a string is failing: _charset = temp_.idup; main.d(76): Error: cannot implicitly convert expression (_adDupT(( D58TypeInfo_AT4main14__T5regexTAyaZ18basic_string_token5CharT6__initZ),cast (string)temp_)) of type immutable(CharT)[] to string Sorry I missed this on the first run through. Since you're using typedef to create your CharT type, it will create a type independent from all the others, meaning no implicit casts to or from it. alias is the equivalent to a C/C++ typedef, and that should fix the compilation error.
Re: main.d(61): Error: temp_[i_] isn't mutable
Andrei Alexandrescu wrote: IMHO it's more general if the regexp took the string type as a parameter. This is because later that is easier generalizable to accepting a range that's different from an array. Agreed. Given T which may be an immutable type, what is the cleanest way of creating a mutable copy of that type? typeof(array.dup) works on arrays but what if T is a value type or any type where .dup doesn't exist? Ali
Re: main.d(61): Error: temp_[i_] isn't mutable
On 06/20/2010 02:29 PM, Ali Çehreli wrote: Andrei Alexandrescu wrote: IMHO it's more general if the regexp took the string type as a parameter. This is because later that is easier generalizable to accepting a range that's different from an array. Agreed. Given T which may be an immutable type, what is the cleanest way of creating a mutable copy of that type? typeof(array.dup) works on arrays but what if T is a value type or any type where .dup doesn't exist? Ali std.conv.to should work with most sensible combinations. Andrei
main.d(61): Error: temp_[i_] isn't mutable
Hi there, I'm converting the following C++ function to D: void negate () { const std::size_t max_chars_ = sizeof (CharT) == 1 ? num_chars : num_wchar_ts; CharT curr_char_ = sizeof (CharT) == 1 ? -128 : 0; string temp_; const CharT *curr_ = _charset.c_str (); const CharT *chars_end_ = curr_ + _charset.size (); _negated = !_negated; temp_.resize (max_chars_ - _charset.size ()); CharT *ptr_ = const_castCharT * (temp_.c_str ()); std::size_t i_ = 0; while (curr_ chars_end_) { while (*curr_ curr_char_) { *ptr_ = curr_char_; ++ptr_; ++curr_char_; ++i_; } ++curr_char_; ++curr_; ++i_; } for (; i_ max_chars_; ++i_) { *ptr_ = curr_char_; ++ptr_; ++curr_char_; } _charset = temp_; } Here's the complete source: module main; import std.algorithm; import std.string; template regex(StringT) { struct basic_string_token { bool _negated = false; StringT _charset; typedef typeof(StringT.init[0]) CharT; enum size_t MAX_CHARS = CharT.max + 1; this(const bool negated_, ref StringT charset_) { _negated = negated_; _charset = charset_; } void remove_duplicates() { _charset.sort; _charset = squeeze(_charset); } void normalise() { if (_charset.length == MAX_CHARS) { _negated = !_negated; _charset.clear(); } else if (_charset.length MAX_CHARS / 2) { negate(); } } void negate() { CharT curr_char_ = MAX_CHARS == 256 ? 0x80 : 0; StringT temp_; size_t curr_ = 0; size_t end_ = _charset.length; size_t i_ = 0; _negated = !_negated; temp_.length = MAX_CHARS - end_; while (curr_ end_) { while (_charset[curr_] curr_char_) { temp_[i_] = curr_char_; ++curr_char_; ++i_; } ++curr_char_; ++curr_; ++i_; } for (; i_ MAX_CHARS; ++i_) { temp_ ~= curr_char_; ++curr_char_; } _charset = temp_; } }; } int main(char[][]argv) { regex!(string).basic_string_token token_; token_._charset = cccbba; token_.remove_duplicates(); token_.negate(); return 0; } Can anyone explain the error 'main.d(61): Error: temp_[i_] isn't mutable'? Can I use pointers instead like the C++ code? What's the best approach for maximum efficiency in D (pointers would make the conversion easier to, I guess). Thanks, Ben
Re: main.d(61): Error: temp_[i_] isn't mutable
On 06/19/2010 12:30 PM, Ben Hanson wrote: Hi there, I'm converting the following C++ function to D: void negate () { const std::size_t max_chars_ = sizeof (CharT) == 1 ? num_chars : num_wchar_ts; CharT curr_char_ = sizeof (CharT) == 1 ? -128 : 0; string temp_; const CharT *curr_ = _charset.c_str (); const CharT *chars_end_ = curr_ + _charset.size (); _negated = !_negated; temp_.resize (max_chars_ - _charset.size ()); CharT *ptr_ = const_castCharT * (temp_.c_str ()); std::size_t i_ = 0; while (curr_ chars_end_) { while (*curr_ curr_char_) { *ptr_ = curr_char_; ++ptr_; ++curr_char_; ++i_; } ++curr_char_; ++curr_; ++i_; } for (; i_ max_chars_; ++i_) { *ptr_ = curr_char_; ++ptr_; ++curr_char_; } _charset = temp_; } Here's the complete source: module main; import std.algorithm; import std.string; template regex(StringT) { struct basic_string_token { bool _negated = false; StringT _charset; typedef typeof(StringT.init[0]) CharT; enum size_t MAX_CHARS = CharT.max + 1; this(const bool negated_, ref StringT charset_) { _negated = negated_; _charset = charset_; } void remove_duplicates() { _charset.sort; _charset = squeeze(_charset); } void normalise() { if (_charset.length == MAX_CHARS) { _negated = !_negated; _charset.clear(); } else if (_charset.length MAX_CHARS / 2) { negate(); } } void negate() { CharT curr_char_ = MAX_CHARS == 256 ? 0x80 : 0; StringT temp_; size_t curr_ = 0; size_t end_ = _charset.length; size_t i_ = 0; _negated = !_negated; temp_.length = MAX_CHARS - end_; while (curr_ end_) { while (_charset[curr_] curr_char_) { temp_[i_] = curr_char_; ++curr_char_; ++i_; } ++curr_char_; ++curr_; ++i_; } for (; i_ MAX_CHARS; ++i_) { temp_ ~= curr_char_; ++curr_char_; } _charset = temp_; } }; } int main(char[][]argv) { regex!(string).basic_string_token token_; token_._charset = cccbba; token_.remove_duplicates(); token_.negate(); return 0; } Can anyone explain the error 'main.d(61): Error: temp_[i_] isn't mutable'? Can I use pointers instead like the C++ code? What's the best approach for maximum efficiency in D (pointers would make the conversion easier to, I guess). Thanks, Ben because strings aren't mutable. char[]'s on the other hand are, so you could just change temp_'s type to import std.traits; Unqual!(typeof(StringT.init[0]))[] temp_; or something like that.
Re: main.d(61): Error: temp_[i_] isn't mutable
On Sat, 19 Jun 2010 17:30:26 + (UTC), Ben Hanson ben.han...@tfbplc.co.uk wrote: Here's the complete source: module main; import std.algorithm; import std.string; template regex(StringT) { struct basic_string_token { bool _negated = false; StringT _charset; typedef typeof(StringT.init[0]) CharT; enum size_t MAX_CHARS = CharT.max + 1; this(const bool negated_, ref StringT charset_) { _negated = negated_; _charset = charset_; } void remove_duplicates() { _charset.sort; _charset = squeeze(_charset); } void normalise() { if (_charset.length == MAX_CHARS) { _negated = !_negated; _charset.clear(); } else if (_charset.length MAX_CHARS / 2) { negate(); } } void negate() { CharT curr_char_ = MAX_CHARS == 256 ? 0x80 : 0; StringT temp_; size_t curr_ = 0; size_t end_ = _charset.length; size_t i_ = 0; _negated = !_negated; temp_.length = MAX_CHARS - end_; while (curr_ end_) { while (_charset[curr_] curr_char_) { temp_[i_] = curr_char_; ++curr_char_; ++i_; } ++curr_char_; ++curr_; ++i_; } for (; i_ MAX_CHARS; ++i_) { temp_ ~= curr_char_; ++curr_char_; } _charset = temp_; } }; } int main(char[][]argv) { regex!(string).basic_string_token token_; token_._charset = cccbba; token_.remove_duplicates(); token_.negate(); return 0; } Can anyone explain the error 'main.d(61): Error: temp_[i_] isn't mutable'? Can I use pointers instead like the C++ code? What's the best approach for maximum efficiency in D (pointers would make the conversion easier to, I guess). Thanks, Ben string is actually an alias for immutable(char)[] (and similarly for the other string types), so its contents are not modifiable, though its length can be adjusted and contents appended. If you need to be able to modify the characters, just use char[] instead. You can then use the .idup property to get a string afterward.
Re: main.d(61): Error: temp_[i_] isn't mutable
Hi Justin, == Quote from Justin Spahr-Summers (justin.spahrsumm...@gmail.com)'s article string is actually an alias for immutable(char)[] (and similarly for the other string types), so its contents are not modifiable, though its length can be adjusted and contents appended. If you need to be able to modify the characters, just use char[] instead. You can then use the .idup property to get a string afterward. Thanks for the clarification! Regards, Ben