Re: Can I count the of enum's fields at compile time?
On Thursday, 23 November 2017 at 01:34:54 UTC, Ali Çehreli wrote:
On 11/22/2017 05:21 PM, Marc wrote:
On Thursday, 23 November 2017 at 01:04:29 UTC, Jonathan M
Davis wrote:
On Thursday, November 23, 2017 00:58:21 Marc via
Digitalmars-d-learn wrote:
[...]
import std.traits;
enum countOfA = EnumMembers!A.length;
- Jonathna M Davis
This sounds more readable. I was going to write a "function
extension" to enum but I think it isn't really needed. Thank
you too.
As an eponymous template:
enum One { a }
enum Three { a, b, c }
import std.range : EnumMembers;
enum countOf(E) = EnumMembers!E.length;
unittest {
static assert(countOf!One == 1);
static assert(countOf!Three == 3);
}
void main() {
}
Ali
whoa, this is so easy and elegant. I'm falling in love with D.
Thank you too!
Re: Can I count the of enum's fields at compile time?
On 11/22/2017 05:21 PM, Marc wrote:
On Thursday, 23 November 2017 at 01:04:29 UTC, Jonathan M Davis wrote:
On Thursday, November 23, 2017 00:58:21 Marc via Digitalmars-d-learn
wrote:
for example:
enum A { a = -10, b = -11, c = -12, d = -13, e = -34}
enum int countOfA = coutOfFields(A); // 5 fields
import std.traits;
enum countOfA = EnumMembers!A.length;
- Jonathna M Davis
This sounds more readable. I was going to write a "function extension"
to enum but I think it isn't really needed. Thank you too.
As an eponymous template:
enum One { a }
enum Three { a, b, c }
import std.range : EnumMembers;
enum countOf(E) = EnumMembers!E.length;
unittest {
static assert(countOf!One == 1);
static assert(countOf!Three == 3);
}
void main() {
}
Ali
Re: Can I count the of enum's fields at compile time?
On Thursday, 23 November 2017 at 01:04:29 UTC, Jonathan M Davis
wrote:
On Thursday, November 23, 2017 00:58:21 Marc via
Digitalmars-d-learn wrote:
for example:
enum A { a = -10, b = -11, c = -12, d = -13, e = -34}
enum int countOfA = coutOfFields(A); // 5 fields
import std.traits;
enum countOfA = EnumMembers!A.length;
- Jonathna M Davis
This sounds more readable. I was going to write a "function
extension" to enum but I think it isn't really needed. Thank you
too.
Re: Can I count the of enum's fields at compile time?
On Thursday, November 23, 2017 00:58:21 Marc via Digitalmars-d-learn wrote:
> for example:
>
> enum A { a = -10, b = -11, c = -12, d = -13, e = -34}
>
> enum int countOfA = coutOfFields(A); // 5 fields
import std.traits;
enum countOfA = EnumMembers!A.length;
- Jonathna M Davis
Re: Can I count the of enum's fields at compile time?
On Thursday, 23 November 2017 at 01:01:42 UTC, Michael V.
Franklin wrote:
On Thursday, 23 November 2017 at 00:58:21 UTC, Marc wrote:
for example:
enum A { a = -10, b = -11, c = -12, d = -13, e = -34}
enum int countOfA = coutOfFields(A); // 5 fields
https://dlang.org/spec/traits.html#allMembers
enum A { a = -10, b = -11, c = -12, d = -13, e = -34}
enum int countOfA = __traits(allMembers, A).length; // 5 fields
static assert(countOfA == 5);
Mike
This was fast! Thanks
Re: Can I count the of enum's fields at compile time?
On Thursday, 23 November 2017 at 00:58:21 UTC, Marc wrote:
for example:
enum A { a = -10, b = -11, c = -12, d = -13, e = -34}
enum int countOfA = coutOfFields(A); // 5 fields
https://dlang.org/spec/traits.html#allMembers
enum A { a = -10, b = -11, c = -12, d = -13, e = -34}
enum int countOfA = __traits(allMembers, A).length; // 5 fields
static assert(countOfA == 5);
Mike
Can I count the of enum's fields at compile time?
for example:
enum A { a = -10, b = -11, c = -12, d = -13, e = -34}
enum int countOfA = coutOfFields(A); // 5 fields
