Re: How to ensure template function can be processed during compile time
On Wednesday, 8 July 2020 at 20:11:05 UTC, IGotD- wrote: int v; enum sz = mySize!int // works, returns 46 enum sz2 = mySize(v) // doesn't work. Error: variable v cannot be read at compile time Here we have a difference between C++ and D as C++ was able infer the size of v during compile time. To add to other respondents' replies, you can pass something that is known at compile time, for example the .init value: int v; enum sz2 = mySize(v.init); static assert(sz2 == 46); This way the compiler is able to evaluate `mySize` at compile time. Or use an alias template argument: auto mySize(alias v)() { return v.sizeof + 42; } int v; enum sz = mySize!int; enum sz2 = mySize!v; static assert(sz == sz2); static assert(sz == 46);
Re: How to ensure template function can be processed during compile time
On Wednesday, 8 July 2020 at 20:11:05 UTC, IGotD- wrote: Now since mySize is a template, shouldn't this work mySize!v, but it doesn't? What essential understanding have I missed here? You are trying to use a run-time value of v at compile-time, which is not possible. If you want the modified size of the type of a variable, you can pass the variable to the compile-time function by alias: enum mySize(alias e) = e.sizeof + 42; int v; enum size = mySize!v; pragma(msg, size); // 46LU If you want to the size of the type of a run-time expression, you will have to use typeof: static assert(mySize!(typeof(v + 1)) == 46);
Re: How to ensure template function can be processed during compile time
On Wed, Jul 08, 2020 at 08:11:05PM +, IGotD- via Digitalmars-d-learn wrote: [...] > Doing the same in D, would with my lack of knowledge look like this. > > > size_t mySize(T)() > { > return T.sizeof + 42; > } What you want is: enum mySize(T) = T.sizeof + 42; And there is no need for a const overload. [...] > int v; > > enum sz = mySize!int // works, returns 46 > enum sz2 = mySize(v) // doesn't work. Error: variable v cannot be read at > compile time Yes, because you're trying to pass the value of a variable to mySize, and that variable doesn't have a value until runtime. > Here we have a difference between C++ and D as C++ was able infer the > size of v during compile time. > > Now since mySize is a template, shouldn't this work mySize!v, but it > doesn't? What essential understanding have I missed here? https://wiki.dlang.org/User:Quickfur/Compile-time_vs._compile-time T -- The diminished 7th chord is the most flexible and fear-instilling chord. Use it often, use it unsparingly, to subdue your listeners into submission!
How to ensure template function can be processed during compile time
I have the following functions in C++ template inline constexpr size_t mySize(const T ) { return sizeof(v) + 42; } template inline constexpr size_t mySize() { return sizeof(T) + 42; } The constexpr ensures that it will be calculated to a compile time constant otherwise the build will fail. In this case C++ can handle that I feed these functions with both a type and a variable which it can solve during compile time. int v; constexpr size_t sz = mySize(v); // works, returns 46 constexpr size_t sz2 = mySize(); // works, returns 46 Doing the same in D, would with my lack of knowledge look like this. size_t mySize(T)() { return T.sizeof + 42; } size_t mySize(T)(const T t) { return T.sizeof + 42; } int v; enum sz = mySize!int // works, returns 46 enum sz2 = mySize(v) // doesn't work. Error: variable v cannot be read at compile time Here we have a difference between C++ and D as C++ was able infer the size of v during compile time. Now since mySize is a template, shouldn't this work mySize!v, but it doesn't? What essential understanding have I missed here?