Re: Comparing arrays of floats?
On Friday, 9 October 2015 at 22:14:09 UTC, Straivers wrote: Forgive me if this has already been discussed, but how are arrays of floating point numbers compared in D? i.e. Is it a bit-by-bit comparison, is the std.math.approxEqual function get called for each element, or is it byte-by-byte across the entire array? -Straivers If you want to compare them with approxEqual, you can do: arr1.equal!approxEqual(arr2)
Re: Comparing arrays of floats?
On Saturday 10 October 2015 00:14, Straivers wrote: > Is it a bit-by-bit comparison, no > is the std.math.approxEqual function get called for > each element, no > or is it byte-by-byte across the entire array? no After comparing the lengths, the elements are checked for equality one by one, using the usual `==` operator. `==` is different from bitwise comparison. For example, -0f and +0f are `==` equal but have different bits, and NaNs are equal no nothing, not even themselves.
