Re: Equivalent of C++ std::function
On Wednesday, 25 June 2014 at 05:13:00 UTC, Olivier Pisano wrote: On Wednesday, 25 June 2014 at 03:33:15 UTC, Yuushi wrote: Thanks a ton - I guess I need to do a fair bit more reading about alias. In this case, alias acts as typedef in C++. What is important here is the function pointers/delegates syntax. Yeah, I realised that when I went back and looked at what I'd tried: function string(string) transform; which should have been: string function(string) transform; which does work. Thanks for the clarification.
Re: Equivalent of C++ std::function
On 06/24/2014 08:33 PM, Yuushi wrote: I guess I need to do a fair bit more reading about alias. It is probably too basic for you but somebody else may find it useful: http://ddili.org/ders/d.en/lambda.html Ali
Re: Equivalent of C++ std::function
On 06/24/2014 11:23 PM, Yuushi wrote:
Yeah, I realised that when I went back and looked at what I'd tried:
function string(string) transform;
That gets me all the time! :-/ That is the long version of the function
literal syntax:
auto f = function string(string s) { return hello; };
which should have been:
string function(string) transform;
which does work.
Thanks for the clarification.
Ali
Re: Equivalent of C++ std::function
On 6/25/2014 10:10 AM, Yuushi wrote:
I was wondering if D had something akin to std::function in C++.
Say I have some functions in an associative array, for example:
auto mapping = ['!' : (string a) = toUpper!string(a), '^' :
(string a) = capitalize!string(a)];
What I want to do is basically declare something like:
function string(string) transform;
if(some condition) {
transform = mapping[lookup];
}
In C++, this could be done by declaring:
std::functionstring(string) transform;
Is there an equivalent D construct for this?
For function pointers (free functions or static class functions):
alias TransformFunc = string function( string );
TransformFunc transform;
if( foo ) transform = func;
For delegates (lambdas or pointers to class methods or inner functions):
alias TransformDg = string delegate( string );
TransformDG transform;
if( foo ) transform = bar.method;
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Re: Equivalent of C++ std::function
On Wednesday, 25 June 2014 at 01:47:13 UTC, Mike Parker wrote:
On 6/25/2014 10:45 AM, Mike Parker wrote:
On 6/25/2014 10:10 AM, Yuushi wrote:
I was wondering if D had something akin to std::function in
C++.
Say I have some functions in an associative array, for
example:
auto mapping = ['!' : (string a) = toUpper!string(a),
'^' :
(string a) = capitalize!string(a)];
What I want to do is basically declare something like:
function string(string) transform;
if(some condition) {
transform = mapping[lookup];
}
In C++, this could be done by declaring:
std::functionstring(string) transform;
Is there an equivalent D construct for this?
For function pointers (free functions or static class
functions):
alias TransformFunc = string function( string );
TransformFunc transform;
if( foo ) transform = func;
For delegates (lambdas or pointers to class methods or inner
functions):
alias TransformDg = string delegate( string );
TransformDG transform;
if( foo ) transform = bar.method;
And in this case you want the latter:
TransformDg transform = mapping[ '!' ];
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Thanks a ton - I guess I need to do a fair bit more reading about
alias.
Re: Equivalent of C++ std::function
On Wednesday, 25 June 2014 at 03:33:15 UTC, Yuushi wrote: Thanks a ton - I guess I need to do a fair bit more reading about alias. In this case, alias acts as typedef in C++. What is important here is the function pointers/delegates syntax.
