Re: Some help on Mixin Template at Class level.
On 5/23/11, Matthew Ong wrote:
> Someone also pointed out:
>
> template mydef(string name){
> }
>
> mixin(mydef!("abc"));
>
> The above are NOT shown up left hand side of that when we click on
> Language Reference
You're probably looking for this:
http://www.digitalmars.com/d/2.0/mixin.html
Re: Some help on Mixin Template at Class level.
On 5/23/2011 2:17 AM, Simen Kjaeraas wrote:
On Sat, 21 May 2011 11:40:22 +0200, Matthew Ong wrote:
Using your code I have this error:
src\Sample.d(16): Error: undefined identifier btype, did you mean
template AType(string name,U,alias V)?
src\Sample.d(16): Error: mixin AType!("ClassB",string,_error_) does
not match template declaration AType(string name,U,alias V)
Could you please ensure it is compilable code and so that I can test
the template shown by you.
Sorry about that.
string ATypeGenerator( string name ) {
return "class " ~ name ~ " : ClassC {
private:
U value;
public:
this(){}
void print(){}
mixin V;
}";
}
mixin template AType( string name, U, alias V ) {
mixin( ATypeGenerator( name ) );
}
class ClassC {}
mixin template btype() {
void someFunction() {}; // Content of a class.
}
mixin AType!("ClassB", string, btype);
void main() {
ClassC r = new ClassB();
}
Thanks simen. I have solve that issue.
Someone also pointed out:
template mydef(string name){
}
mixin(mydef!("abc"));
The above are NOT shown up left hand side of that when we click on
Language Reference
http://www.digitalmars.com/d/2.0/lex.html
And also here.
http://www.digitalmars.com/d/2.0/comparison.html
not the same as:
mixin template mydeff(T){
...
}
mixin mydeff!(string);
Some centralized documentation is needed for D.
--
Matthew Ong
email: on...@yahoo.com
Re: Some help on Mixin Template at Class level.
On Sat, 21 May 2011 11:40:22 +0200, Matthew Ong wrote:
Using your code I have this error:
src\Sample.d(16): Error: undefined identifier btype, did you mean
template AType(string name,U,alias V)?
src\Sample.d(16): Error: mixin AType!("ClassB",string,_error_) does not
match template declaration AType(string name,U,alias V)
Could you please ensure it is compilable code and so that I can test the
template shown by you.
Sorry about that.
string ATypeGenerator( string name ) {
return "class " ~ name ~ " : ClassC {
private:
U value;
public:
this(){}
void print(){}
mixin V;
}";
}
mixin template AType( string name, U, alias V ) {
mixin( ATypeGenerator( name ) );
}
class ClassC {}
mixin template btype() {
void someFunction() {}; // Content of a class.
}
mixin AType!("ClassB", string, btype);
void main() {
ClassC r = new ClassB();
}
--
Simen
Re: Some help on Mixin Template at Class level.
On 5/21/2011 5:12 PM, Simen Kjaeraas wrote:
On Sat, 21 May 2011 10:54:54 +0200, Matthew Ong wrote:
mixin template AType(alias T, U, alias V){
class T : ClassC { // Class level Template
This gives you a class called T. You seem to want it to have the name
you pass as a string, in which case you have to use string mixins.
private:
U value;
public:
this(){}
void print(){}
mixin V;
} // End Class
}
class ClassC {}
mixin template btype() {
void someFunction() {}; // Content of a class.
}
mixin AType!("ClassB", string, btype);
void main() {
ClassC r = new ClassB();
}
As mentioned above, in order to use the name from the template parameter
you need to use string mixins. Here is how I would do it:
string ATypeGenerator( string name ) {
return "class " ~ name ~ " : ClassC {
private:
U value;
public:
this(){}
void print(){}
mixin V;
}";
}
mixin template AType( string name, U, alias V ) {
mixin( ATypeGenerator( name ) );
}
mixin AType!("ClassB", string, btype);
void main() {
ClassC r = new ClassB();
}
Hi, Thanks for the respond.
I am really new to D.
Using your code I have this error:
src\Sample.d(16): Error: undefined identifier btype, did you mean
template AType(string name,U,alias V)?
src\Sample.d(16): Error: mixin AType!("ClassB",string,_error_) does not
match template declaration AType(string name,U,alias V)
Could you please ensure it is compilable code and so that I can test the
template shown by you.
--
Matthew Ong
email: on...@yahoo.com
Re: Some help on Mixin Template at Class level.
On Sat, 21 May 2011 10:54:54 +0200, Matthew Ong wrote:
mixin template AType(alias T, U, alias V){
class T : ClassC { // Class level Template
This gives you a class called T. You seem to want it to have the name
you pass as a string, in which case you have to use string mixins.
private:
U value;
public:
this(){}
void print(){}
mixin V;
} // End Class
}
class ClassC {}
mixin template btype() {
void someFunction() {}; // Content of a class.
}
mixin AType!("ClassB", string, btype);
void main() {
ClassC r = new ClassB();
}
As mentioned above, in order to use the name from the template parameter
you need to use string mixins. Here is how I would do it:
string ATypeGenerator( string name ) {
return "class " ~ name ~ " : ClassC {
private:
U value;
public:
this(){}
void print(){}
mixin V;
}";
}
mixin template AType( string name, U, alias V ) {
mixin( ATypeGenerator( name ) );
}
mixin AType!("ClassB", string, btype);
void main() {
ClassC r = new ClassB();
}
--
Simen
