deducing function/delegate in template method

2013-05-24 Thread Luís.Marques

In this code:

   // accepts a list of handlers, for the respective types
void addHandlers(T...)(T handlers)
{
foreach(handler; handlers)
{
addHandler(handler);
}
}

// accepts one handler, for type T
void addHandler(T)(void delegate (T) handler)
{
...
}

...

foo.addHandler((int x) { /* always deduced as delegate */ });
foo.addHandlers(delegate (int x) { /* if no scope access 
deduction fails */ });


If I call addHandler with a function/delegate literal then DMD 
deduces that the literal has to be a delegate, but if I call 
addHandlers then I have to explicitly mark my function/delegate 
literal as a delegate, otherwise the template match will fail if 
the function/delegate literal does not access something from its 
scope. Couldn't DMD also deduce this correctly in this case?


Also, how can I change addHandler to accept delegates with 
heterogeneous varargs? Something like:


void addHandler(T...)(void delegate (T...) handler);

so that I can do:

foo.addHandler((int x, float y) { });


Re: deducing function/delegate in template method

2013-05-24 Thread Luís.Marques

On Friday, 24 May 2013 at 22:37:49 UTC, Luís Marques wrote:
foo.addHandlers(delegate (int x) { /* if no scope access 
deduction fails */ });


(I meant that deduction would fail if the literal was not marked 
as a delegate)