Re: union initalization
Am Fri, 22 Jul 2016 01:48:52 + schrieb Rufus Smith: > I would like to combine two types > > > template Foo(A, B = 4) > { > union > { > byte b = B; > int a = A << 8; > } > } > > > I get an error about overlapping default initialization. They > don't actually overlap in this case because of the shift. To be pedantic about this: The initializers actually do overlap. As A << 8 shifts in zeroes, these bits are initialized as well. I think there's no idiomatic way to initialize only part of an integer.
Re: union initalization
On 07/21/2016 08:00 PM, Rufus Smith wrote: >> Bitfields may actually be useful in this case: >> >> https://dlang.org/phobos/std_bitmanip.html#.bitfields >> > > They don't allow default assignment though? A factory function can help: import std.bitmanip; struct S(int a_init, byte b_init) { mixin (bitfields!(int, "a", 24, byte, "b", 8)); @disable this(); } auto makeS(int a_init, byte b_init = 4)() { auto s = S!(a_init, b_init).init; s.a = a_init; s.b = b_init; return s; } void main() { const s = makeS!42(); assert(s.a == 42); assert(s.b == 4); } >> The following at least compiles: >> >> struct Foo(int A, byte B = 4) >> { >> union >> { >> byte b = void; >> int a = void; >> uint __both = (A << 8) | B; >> } >> } >> >> void main() { >> auto f = Foo!(42)(); >> } >> >> Ali > > Maybe... I don't like extra member. Me neither. Besides, 'b' coincides with a different part of 'a' depending on the endianness of the system. Ali
Re: union initalization
On Friday, 22 July 2016 at 02:08:06 UTC, Ali Çehreli wrote: On 07/21/2016 06:48 PM, Rufus Smith wrote: > I would like to combine two types > > > template Foo(A, B = 4) > { > union > { > byte b = B; > int a = A << 8; > } > } > > This packs a and b together in to an int bytes, saving an int(rather > than storing a and b in an int each) and makes it easier to access. Bitfields may actually be useful in this case: https://dlang.org/phobos/std_bitmanip.html#.bitfields They don't allow default assignment though? > I get an error about overlapping default initialization. They don't > actually overlap in this case because of the shift. The following at least compiles: struct Foo(int A, byte B = 4) { union { byte b = void; int a = void; uint __both = (A << 8) | B; } } void main() { auto f = Foo!(42)(); } Ali Maybe... I don't like extra member. Bitfields seem like it would be the best way but I require default initialization. I want to hide as details of the work on unpacking as possible.
Re: union initalization
On 07/21/2016 06:48 PM, Rufus Smith wrote: > I would like to combine two types > > > template Foo(A, B = 4) > { > union > { > byte b = B; > int a = A << 8; > } > } > > This packs a and b together in to an int bytes, saving an int(rather > than storing a and b in an int each) and makes it easier to access. Bitfields may actually be useful in this case: https://dlang.org/phobos/std_bitmanip.html#.bitfields > I get an error about overlapping default initialization. They don't > actually overlap in this case because of the shift. The following at least compiles: struct Foo(int A, byte B = 4) { union { byte b = void; int a = void; uint __both = (A << 8) | B; } } void main() { auto f = Foo!(42)(); } Ali
union initalization
I would like to combine two types template Foo(A, B = 4) { union { byte b = B; int a = A << 8; } } This packs a and b together in to an int bytes, saving an int(rather than storing a and b in an int each) and makes it easier to access. I get an error about overlapping default initialization. They don't actually overlap in this case because of the shift.