Re: [jQuery] Newbie Alert: Problem with Ajax

2007-02-27 Thread Matias Oberg 

Think I've found the solution myself.

In the return data from my phpscript I have a couple of javascripts.
I placed this in the wrong section of the phpfile which caused the
javascript to be written over and over again.

The sample script was this.

Re: [jQuery] Newbie Alert: Problem with Ajax

2007-02-27 Thread Matias Oberg 

Thanks Edwin,

it still don't think it's my PHP that's causing the problems.
The code is inside a php-script so all variables gets replaced at runtime.
But replacing the phpvariables with hardcoded values causes the same
problem.

$(document).ready(function(){
 $("a#cat_1").click(function(){
$("#ajaxloadimage").ajaxStart(function(){
$(this).show();
});
$.ajax({
type: "POST",
processData: true,
dataType: "html",
url: "getallfromcategory.php",
data: "uid='. $cat_result['uid'] .'",
success: function(txt){$("#show_cat_1").append(txt);}
});
$("#ajaxloadimage").ajaxStop(function(){
$(this).hide();
});
$("#show_cat_1").ajaxSuccess(function(){
$(this).slideDown("slow");
});
});
});

Are there any limitations on how much data Firefox can handle when updating
via JS? Do I have to divide the data into smaller chunks?

Thanks!

- Matias Oberg



Edwin Martin wrote:
> 
> Matias Oberg wrote:
>> Could this be it and are there any ways to avoid it?
>>   
>>> success: function(txt){$("#show_'. $catid 
>>> .'").append(txt);}
>>> 
> 
> Look at the contents of the string  "#show_'. $catid .'". I don't think 
> you want to use this as a selector.
> 
> I guess you want to paste in the value of a PHP-variable, so your 
> problem is in your PHP-code.
> 
> Edwin Martin
> 

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Re: [jQuery] Newbie Alert: Problem with Ajax

2007-02-27 Thread Edwin Martin 
Matias Oberg wrote:
> Could this be it and are there any ways to avoid it?
>   
>>  success: function(txt){$("#show_'. $catid 
>> .'").append(txt);}
>> 

Look at the contents of the string  "#show_'. $catid .'". I don't think 
you want to use this as a selector.

I guess you want to paste in the value of a PHP-variable, so your 
problem is in your PHP-code.

Edwin Martin



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Re: [jQuery] Newbie Alert: Problem with Ajax

2007-02-27 Thread Matias Oberg 

I've done some more testing.

When I change the success-line to...
success: function(txt){alert(txt);}
it works brilliantly without any hickups.
This makes me feel like it's not the AJAX causing the troubles rather the
append of data.

Could this be it and are there any ways to avoid it?

- Matias Oberg


Matias Oberg wrote:
> 
> Hi,
> 
> Please excuse my ignorance. I'm totally new to this.
> I'm trying to get some data from a PHP-script via AJAX.
> 
> $(document).ready(function(){
>$("a#'. $catid .'").click(function(){
>   $("#ajaxloadimage").ajaxStart(function(){
>   $(this).show();
>   });
>   $.ajax({
>   type: "POST",
>   processData: true,
>   dataType: "html",
>   url: "getallfromcategory.php",
>   data: "uid='. $cat_result['uid'] .'",
>   success: function(txt){$("#show_'. $catid 
> .'").append(txt);}
>   });
>   $("#ajaxloadimage").ajaxStop(function(){
>   $(this).hide();
>   });
>   $("#show_'. $catid .'").ajaxSuccess(function(){
>   $(this).slideDown("slow");
>   });
>   });
> });
> 
> It works nicely in IE.
> When I try in FF it works kinda.
> When the PHP-Script only returns a small amount of data it's fine.
> But when larger amounts of data gets retreived FF just hangs indefinite.
> 
> What am I doing wrong?
> Could someone please advice on what I should do?
> 

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[jQuery] Newbie Alert: Problem with Ajax

2007-02-26 Thread qsec 

Hi,

Please excuse my ignorance. I'm totally new to this.
I'm trying to get some data from a PHP-script via AJAX.

$(document).ready(function(){
 $("a#'. $catid .'").click(function(){
$("#ajaxloadimage").ajaxStart(function(){
$(this).show();
});
$.ajax({
type: "POST",
processData: true,
dataType: "html",
url: "getallfromcategory.php",
data: "uid='. $cat_result['uid'] .'",
success: function(txt){$("#show_'. $catid 
.'").append(txt);}
});
$("#ajaxloadimage").ajaxStop(function(){
$(this).hide();
});
$("#show_'. $catid .'").ajaxSuccess(function(){
$(this).slideDown("slow");
});
});
});

It works nicely in IE.
When I try in FF it works kinda.
When the PHP-Script only returns a small amount of data it's fine.
But when larger amounts of data gets retreived FF just hangs indefinite.

What am I doing wrong?
Could someone please advice on what I should do?
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