my first (public) app: django-requires_js_css

[Jason Persampieri]

http://github.com/pappy74/django-requires_js_css

Howdy folks,

I was hoping to get some feedback on my first public app, django-
requires_js_css.  The app's purpose is to allow 'sane' JavaScript and
CSS requirements.  That is, require from within templates, but still
load using 'best practices'.

Definitely a work in progress, although we are using it at our
startup.  My questions to you:
- Is there another app that does this?
- Do other devs find this worthwhile?
- What's missing?
- I currently use a fairly gnarly hack to make this all work
(embedding tokens in the response content, then post-processing those
tokens using middleware).  Is there a better way?

_jason

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Re: /admin list help ASAP

[Steve Holden]

On 10/20/2010 11:55 PM, Mike Dewhirst wrote:
> On 21/10/2010 1:24pm, Bobby Roberts wrote:
>> hi all.  I have two models setup let's call them
>>
>> Gallery
>> Photos
>>
>> photos has a field as such:
>>
>> GalleryId = models.ForeignKey('Gallery', verbose_name=_('Gallery Id'),
>> related_name='Gallery_Id',blank=False, null=False, help_text=_("Please
>> choose the gallery to which you wish to associate this photo."))
>>
>> Ok now here's the question.
>>
>> In the listing page for my photos, I want to print Gallery.Title
>>
>> the two models are related on Photos.GalleryId=Gallery.Id
>>
>> How do I return Gallery title in the listing page in /admin?
>>
> 
> You can write a function in __unicode__() to display the two ...
> 
> def getGallery(self):
> pass # not sure how to get the Gallery title
> 
> def __unicode__(self):
> return u'%s: %s' % (self.getGallery,
> self.title)
> 
Shouldn't that be

def __unicode__(self):
return u'%s: %s' % (self.getGallery(),
self.title)

You actually have to _call_ the getGallery method.

Note that the __unicode__ and getGallery methods Mike describes should
be methods of your photos model.

regards
 Steve
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Re: /admin list help ASAP

[Mike Dewhirst]

On 21/10/2010 1:24pm, Bobby Roberts wrote:

hi all.  I have two models setup let's call them

Gallery
Photos

photos has a field as such:

GalleryId = models.ForeignKey('Gallery', verbose_name=_('Gallery Id'),
related_name='Gallery_Id',blank=False, null=False, help_text=_("Please
choose the gallery to which you wish to associate this photo."))

Ok now here's the question.

In the listing page for my photos, I want to print Gallery.Title

the two models are related on Photos.GalleryId=Gallery.Id

How do I return Gallery title in the listing page in /admin?



You can write a function in __unicode__() to display the two ...

def getGallery(self):
pass # not sure how to get the Gallery title

def __unicode__(self):
return u'%s: %s' % (self.getGallery,
self.title)

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/admin list help ASAP

[Bobby Roberts]

hi all.  I have two models setup let's call them

Gallery
Photos

photos has a field as such:

GalleryId = models.ForeignKey('Gallery', verbose_name=_('Gallery Id'),
related_name='Gallery_Id',blank=False, null=False, help_text=_("Please
choose the gallery to which you wish to associate this photo."))

Ok now here's the question.

In the listing page for my photos, I want to print Gallery.Title

the two models are related on Photos.GalleryId=Gallery.Id

How do I return Gallery title in the listing page in /admin?

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Re: dump sqlite to file when testing

[Russell Keith-Magee]

On Wed, Oct 20, 2010 at 10:33 PM, Miguel Araujo  wrote:
> Hi everyone,
> Is there any way to force sqlite3 to use a file instead of RAM when running
> tests? I would like to access the DB somehow to check some fields. This is
> the only DB engine I have in this machine.

Yes - set the TEST_NAME (or DATABASE_TEST_NAME if you're using pre 1.2
style database settings) to a specific file name [1]. This will
override the default behavior of using :memory: as the test database
name.

[1] http://docs.djangoproject.com/en/dev/ref/settings/#test-name

Yours,
Russ Magee %-)

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call more than one view action from an uri path?

[Phlip]

Djangoistas:

We want to call this URL:

   http://www.server.com/nest/5/pest/6/rest/7

We want each handler to call, with its argument, in order:

  def nest(request, x):
  ...
  def pest(request, y):
  ...
  def rest(request, z):
  ...

(Internally, at rest() time, we want x and y to be available on some
session or file-scope variable.)

How to write an url() call in urls.py that handles part of a path, and
then dispatches to the next part of the path, if any?

--
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  http://bit.ly/ZeekLand

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checkboxes disappearing in the admin panel?

[Yo'av Moshe]

Hey,
I'm seeing some very odd behavior in Django's admin panel.

I'm using the admin panel to list about 3500 objects of "people". The
list view shows about 17 fields.
I'm using the checkboxes to perform certain admin actions I wrote.

This all works great, usually.

Sometimes, when I'm looking at the list, there are no checkboxes,
which means I can't select anything to perform any action.
The only way I found to restore the checkboxes is by restarting the
Django process.

Did anyone see this odd behavior? Is there any reason Django is not
showing my checkboxes?

Thank you.

Yo'av

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Re: about site price

[Steve Holden]

On 10/20/2010 4:17 PM, Lic. José M. Rodriguez Bacallao wrote:
> hi folks, I have a client that need to develop a bet site like this:
> http://www.webapuestas.com/
> the problem is that I am new in the business and I don't know how much
> money can I ask for a
> this work, can someone help me and take a look to the site and give me
> an approximate cost for
> a site like this?
> 
> PS: sorry for my English, it's not so good.
> 
This really is a dangerous question.

First, you have to ask what it will cost you to develop. Do you have any
clear idea of that cost?

Next you have to ask yourself what it's worth to the customer.

If the second figure is lower than the first, stop right there.

I would seriously advise you not to undertake a large paid gig such as
building a betting site without first getting enough industry experience
and learning a lot more about building web sites than you apparently do
at the moment.

If you don't gain the experience, you risk exposing yourself to large
liabilities.

regards
 Steve
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Re: Problems displaying image objects in a Django template using a custom template tag? (coding included)

[werefr0g]

Hello,

I think you should use something like alt="{{ object.title }}" /> in your template: you want to output images' 
url in your template, not the "object" itself. You'll find explanations 
in [1] and [2].


Regards

[1] 
http://docs.djangoproject.com/en/dev/ref/models/fields/#django.db.models.FileField.storage

[2] http://docs.djangoproject.com/en/dev/ref/files/file/#the-file-object

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about site price

[Lic . José M . Rodriguez Bacallao]

hi folks, I have a client that need to develop a bet site like this:
http://www.webapuestas.com/
the problem is that I am new in the business and I don't know how much
money can I ask for a
this work, can someone help me and take a look to the site and give me
an approximate cost for
a site like this?

PS: sorry for my English, it's not so good.

-- 
Lic. José M. Rodriguez Bacallao
Centro de Biofisica Medica
-
Todos somos muy ignorantes, lo que ocurre es que no todos ignoramos lo mismo.

Recuerda: El arca de Noe fue construida por aficionados, el titanic
por profesionales
-

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Re: Heriter charField

[abdou diagne]

merci beaucoup ,
 mais mon probleme est le mot de passe  ne doit pas etre en claire dans la
base .Aussi je peux pas utiliser les hash parceque ya une autre application
, java meme , qui accéde a la base de donnee

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Re: call shell script from Django web service

[Elie Zedeck RANDRIAMIANDRIRAY]

If I were you, I would first investigate why is the script failing. Then,
when you know why it's failing, you could make a workaround.

It is normally possible to run external apps from Django, because it's just
Python. You simply need to give your script the correct set of environment
for it to work properly.

Most of the time, lack of some directives in the environments is the cause
of external apps not running.

On Wed, Oct 20, 2010 at 9:47 PM, jintao  wrote:

> Hi all,
>
> I implemented some web service with Django framework.  I need this
> service to execute some shell script on the server.
>
> I have already tried os.system(), which works in python terminal, but
> doesn't work in Django framework.
>
> Anyone could show some guidance here?
>
> Thanks tons!
>
> jintao
>
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call shell script from Django web service

[jintao]

Hi all,

I implemented some web service with Django framework.  I need this
service to execute some shell script on the server.

I have already tried os.system(), which works in python terminal, but
doesn't work in Django framework.

Anyone could show some guidance here?

Thanks tons!

jintao

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Re: Oracle Database Other User Tables/Views

[Ian]

On Oct 20, 8:20 am, "Christopher Conover" 
wrote:
> Hello,
>
> I am using Django's multiple database support to connect to an existing 
> Oracle database (10g). I do not have control of the schema nor do I have any 
> other privileges beyond SELECT. Further, the tables and views that I have 
> access to are owned by a different user. Because of this I'm having to refer 
> to these tables in queries using the other_user.table syntax.
>
> This issue is that Django's Oracle backend wants to quote all table names. 
> This does not work for the other_user.table syntax. To get this working for 
> the moment, I have patched the quote_name method on line 192 of 
> django/db/backends/oracle/base.py to forego the quoting.
>
> Does anyone have any suggestions of how to work around this without modifying 
> the Django source?

Alternate schema support is the subject of ticket #6148 in the Django
ticket tracker.  When that finally lands, it will be as simple as
setting the db_schema Meta option.

In the meantime, the recommended workaround for Oracle is to create
synonyms within the Django schema for the external tables and views,
e.g.:

CREATE SYNONYM MY_SCHEMA.SOME_TABLE FOR OTHER_SCHEMA.SOME_TABLE;

This only requires the rather innocuous CREATE SYNONYM system
privilege.  If the DBA won't even let you have that, you can fall back
on specifying the schema and table in the db_table option with the
proper interior quoting, e.g.:

db_table = 'other_schema"."some_table'

This is sufficient to trick Django into doing the right thing in most
cases.

Cheers,
Ian

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Re: Heriter charField

[Elie Zedeck RANDRIAMIANDRIRAY]

Je suis un débutant en Django, mais je pense que tu doit utiliser un autre
widget pour ton mot de passe. Par exemple:

password = CharField(widget=PasswordInput)

D'autres widget ici: http://docs.djangoproject.com/en/dev/ref/forms/widgets/

2010/10/20 updo 

> Bonjour à tout le monde
> Je voudrai creer une classe passwordField qui va heriter de la classe
> charField afin de crypter les mots dans la base de donnée , je
> voudrai  savoir quelles sont les méthodes de la classe faudra
> redéfinir pour que quand je cree une instance de la classe
> passwordField , il prend en parametre le mot de passe en clair , le
> crype et le sauve dans la bdd .De même quand j'affiche un objet un
> objet passwordField ,il recupere le mot de passe crypte au niveau de
> la base , le decrypte et me l'affiche en claire . j'ai deja mes
> methodes  pour crypter et  decrypter du texte
>
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>
>

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Re: Heriter charField

[Daniel Roseman]

On Oct 20, 6:40 pm, updo  wrote:
> Bonjour à tout le monde
> Je voudrai creer une classe passwordField qui va heriter de la classe
> charField afin de crypter les mots dans la base de donnée , je
> voudrai  savoir quelles sont les méthodes de la classe faudra
> redéfinir pour que quand je cree une instance de la classe
> passwordField , il prend en parametre le mot de passe en clair , le
> crype et le sauve dans la bdd .De même quand j'affiche un objet un
> objet passwordField ,il recupere le mot de passe crypte au niveau de
> la base , le decrypte et me l'affiche en claire . j'ai deja mes
> methodes  pour crypter et  decrypter du texte

Bonjour,

tu devrais savoir que la langue habituelle de ce groupe est l'anglais
- il y en a parmi nous qui comprendent le français, mais tu auras plus
de chance si tu posais la question en anglais.

De toute façon, cela n'est pas un méthode très sur de sauver un mot de
passe. Le methode qu'utilise Django est d'employer une fonction
"hash", qui marche dans une direction seulement - c'est à dire, il est
possible de crypter, mais non pas de decrypter. Quand quelqu'un donne
son mot de passe pour accéder au site, on crypte le mot qu'il a donné,
et va voir si les deux sont pareils.

Cependeant, si tu est certain, il faut voir les docus qui décrivent
comment écrire un champ customisé: 
http://docs.djangoproject.com/en/1.2/howto/custom-model-fields/

[To the group: the OP wanted to know what methods he should use for
writing a passwordfield which automatically encrypted and decrypted a
password when it was saved to/read from the database. I suggested that
wasn't a very secure way of doing it, but pointed him to the custom
field documentation. And for those whose French is better than mine, I
apologise for the many errors above.]
--
DR.

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Heriter charField

[updo]

Bonjour à tout le monde
Je voudrai creer une classe passwordField qui va heriter de la classe
charField afin de crypter les mots dans la base de donnée , je
voudrai  savoir quelles sont les méthodes de la classe faudra
redéfinir pour que quand je cree une instance de la classe
passwordField , il prend en parametre le mot de passe en clair , le
crype et le sauve dans la bdd .De même quand j'affiche un objet un
objet passwordField ,il recupere le mot de passe crypte au niveau de
la base , le decrypte et me l'affiche en claire . j'ai deja mes
methodes  pour crypter et  decrypter du texte

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Re: "No module named copycompat" error

[mathphreak]

That worked.  Thanks!

On Oct 19, 4:05 pm, timc3  wrote:
> From a python prompt can you do:
>
> from django.utils import copycompat
>
> If not, Django might not be imported properly. Also check your
> PYTHONPATH.
>
> On Oct 18, 10:57 pm, mathphreak  wrote:
>
>
>
> > I just upgraded my computer to Ubuntu 10.10, and now running "python
> > manage.py runserver" gives me "Error: No module named copycompat".
> > I've probably also upgraded Django from 1.1.x to 1.2.x, which might be
> > the problem too.  Which upgrade broke manage.py, and how can I fix
> > this?

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What is the difference between MEDIA_ROOT and STATICFILES_ROOT in Django1.3?

[P.R.]

.. and why staticfiles doesn't work? :-)

# django.contrib.staticfiles
...
if settings.DEBUG:
raise ImproperlyConfigured("The view to serve static files can
only "
   "be used if the DEBUG setting is
True")


It should be "if not settings.DEBUG" I think.


regards.

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Re: Manual ordering

[Nick]

Worked like a charm. This was a limited case so I won't be needing any
checks to ensure that the ID's are all in the queryset since there are
only 5 or 6. Thanks again.

On Oct 20, 10:44 am, Shawn Milochik  wrote:
> Given a tuple/list of primary keys named ordered_ids and a queryset named 
> records:
>
> results = [records.get(pk = x) for x in ordered_ids]
>
> This is a naive example, as it assumes that ordered_ids will never have IDs 
> which don't exist in the queryset, but it gives a simple way to do what 
> you're asking for.
>
> Shawn

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Re: Newbie question: How should I structure my very simple project / app?

[wawa wawawa]

Just a quick response to thank everyone for the suggestions.

I'll let you all know how I get on.

;-)

(Actually, you'll probably guess from the quality or absurdity of my
questions that may come up over the coming days / weeks)

WZ

On 20 October 2010 00:01, timc3  wrote:

> Take a look at:
>
> http://lincolnloop.com/django-best-practices/projects/layout.html
>
> After you have done the tutorials and stuff.
>
> Tim.

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Re: Manual ordering

[Shawn Milochik]

Given a tuple/list of primary keys named ordered_ids and a queryset named 
records:

results = [records.get(pk = x) for x in ordered_ids]

This is a naive example, as it assumes that ordered_ids will never have IDs 
which don't exist in the queryset, but it gives a simple way to do what you're 
asking for.

Shawn


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Re: Multi-user environment where users can add/edit/delete only their own posts

[Shawn Milochik]

Your post model should have a foreign key to user, perhaps named "creator" or 
"owner."

Then ensure that the edit and delete views in your application can only modify 
or delete posts where the owner is request.user.

Shawn


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Manual ordering

[Nick]

I am working on the output for some data and I would like to manually
assign the order as there is no field that I can order by that will
give me the desired output. Is there a way to manually declare the
order of output based on the PKs of an entry?

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Multi-user environment where users can add/edit/delete only their own posts

[piousbox]

hello all,

I'm considering Django for one of my projects but I run into an issue.
Suppose I have a multi-user environment (like craigslist) where users
can register and, let's say, write posts and create photo galleries. I
want a user to be able to edit his or her own posts and galleries. I
want all posts and galleries to be viewable by all. How would I do
that in Django?

In another framework, I'd have User hasMany Post, Post belongsTo User,
and then in the controller in action Post/edit/post_id, I'd compare
Post.user_id to that from the session of the authenticated user, and
kick him out if his id doesn't match. But in Django I'm not sure how
to do that.

Your help is much appreciated.

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Re: login_required and new class based views

[Harro]

Let me add that the decorator_from_middleware call all the middleware
process_* functions if available but these will ofcourse be called at
a whole different point in time then the actual middleware.
Normally middleware is woven through the whole dispatch process, as a
decorator it's wrapped around the view.

On Oct 20, 1:12 pm, Russell Keith-Magee 
wrote:
> 2010/10/20 Łukasz Rekucki :
>
> > On 19 October 2010 19:06, Valentin Golev  wrote:
> >> Hello,
>
> > 2) decorate the dispatch method. You need to turn login_required into
> > a method decorator first (Django should probably provide a tool for
> > this).
>
> Django does :-) It's called method_decorator.
>
> from django.utils.decorators import method_decorator
>
> class MyDecoratedView(MyView):
>
>     @method_decorator(login_required)
>     def dispatch(self, *args, **kwargs):
>         #...
>
> This works for any method on any class, that you want to decorate with
> any function-based decorator.
>
> As a point of interest, the django.utils.decorators module has a
> couple of other useful utilities in this vein, such as
> decorator_from_middleware (which, predictably, enables you to turn any
> middleware into a decorator that wraps a single view).
>
> Yours,
> Russ Magee %-)

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django.contrib.auth password reset reveals the user id

[Yaniv Aknin]

Hi,

I'd like to use contrib.auth's password reset feature, but wouldn't
like to expose my user id. Since user ids (even if they start at an
arbitrary number) can be used to deduce the size of the userbase and
growth rate, I think it's easy enough to justify this at least as an
option.

To fix this, I'd like to suggest the token generator (see
django.contrib.auth.tokens) be made in charge of creating a single
token of whatever form it wishes, and the token would be the only
information revealed to the user. The token generator will also be
incharge of receiving the token, and returning a user object if the
token is valid. If you will look at
django.contrib.auth.forms.PasswordResetForm, you will see it sends the
user both the uid (encoded to base36) and the token, and the token
generator expects to be fed the user object from the outside.

Does this make sense? I don't mind submitting a patch, but it will
break custom token generators' APIs (or we add a somewhat ugly
backwards-compatibility check). At the moment, I believe I'm forced to
replace the whole form and the token generator, as well as wrap the
view.

 - Yaniv

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Problems displaying image objects in a Django template using a custom template tag? (coding included)

[tricks...@googlemail.com]

I have the following code that fails to display object images. But
displays normal images fine.

My Model

class News(models.Model):
title---
image = models.ImageField(upload_to='images')
body

Template tag coding

from django import template
register = template.Library()
from .models import ---

def funct(num):
myobjects = News.objects.all()[:num]
return {'objects': myobjects}
register.inclusion_tag('news/template.html')(funct)

template coding

{% for object in objects %}
{{ object.title }}

{{ object.body }}
{% endfor %}

This code outputs all the variable information such as title and body
in a list however it does not display the associated image. I have
tried numerous variations on this code with no success. This is
strange because when an image is called from the image folder in the
following manner



Everything works fine. The problems occur when its a model image being
called. Any help fixing this issue is much appreciated

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dump sqlite to file when testing

[Miguel Araujo]

Hi everyone,

Is there any way to force sqlite3 to use a file instead of RAM when running
tests? I would like to access the DB somehow to check some fields. This is
the only DB engine I have in this machine.

Thanks, Best regards
Miguel Araujo

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Oracle Database Other User Tables/Views

[Christopher Conover]

Hello,

I am using Django's multiple database support to connect to an existing Oracle 
database (10g). I do not have control of the schema nor do I have any other 
privileges beyond SELECT. Further, the tables and views that I have access to 
are owned by a different user. Because of this I'm having to refer to these 
tables in queries using the other_user.table syntax. 

This issue is that Django's Oracle backend wants to quote all table names. This 
does not work for the other_user.table syntax. To get this working for the 
moment, I have patched the quote_name method on line 192 of 
django/db/backends/oracle/base.py to forego the quoting. 

Does anyone have any suggestions of how to work around this without modifying 
the Django source? 

Thanks,
Chris

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Re: Updating a video rating using AJAX

[Nicolas R]

When you change data on your database ALWAYS use the http POST method.

So your view should check if request.method == 'POST' and then proceed
to change the rating. It should also check if the user is
authenticated and if she already voted.

As for the ajax part have a look at the jQuery javascript library. You
could do something like this:

$('#my_form').live('submit',function(){
var self = $this;
$.post( self.attr('action'), function(r){
self.replaceWith( $(r).find('#my_form') );
});
return false;
});

The javascript code you should write depends on how your app and views
work. The above snippet assumes that the url where the form submits
will return the form (even if there is an error).




On Oct 20, 4:23 pm, Sithembewena Lloyd Dube  wrote:
> Hi all,
>
> I have a page where users can rate a video, and in models.py I have a video
> model with a 'rating' property. I wish to find out how I can AJAXify the
> rating button on the page, so that if a user clicks on it, the button can
> call a custom function and pass the video id (cannot call a view as that
> would return an entire response). Am thinking of a function roughly as
> follows:
>
> from myproject.myapp.models import Video
>
> def save_rating(video_id, rating):
>     video = Video.objects.filter(pk=video_id)
>     video.rating += rating
>     video.save()
>     return video.rating #* The rating label on the page would then be
> updated with the returned rating.*
>
> I would like to do this without using a view or doing a form POST or GET of
> any kind. Any pointers?
>
> Thanks.
>
> --
> Regards,
> Sithembewena Lloyd Dubehttp://www.lloyddube.com

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Re: Expense of django query

[Ed]

Brilliant.  Thanks!

On Oct 20, 9:41 am, Javier Guerra Giraldez  wrote:
> On Wed, Oct 20, 2010 at 7:59 AM, Ed  wrote:
> > what is the purpose of ifchanged?
>
> since the images are sorted by film, if you just show the film for
> every image it would be repeated.  with {% ifchanged %} it's only
> shown before all the images for this film, so the result is like this:
>
> film A
> image a.1
> image a.2
> film B
> image b.1
> image b.2
> image b.3
> film C
> 
>
> without {% ifchanged %} you would get:
> film A
> image a.1
> film A
> image a.2
> film B
> image b.1
> film B
> image b.2
> film B
> image b.3
> film C
> ...
>
> --
> Javier

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Re: rake routes

[esatterwh...@wi.rr.com]

There is also a very useful project out there called django-command-
extensions
http://code.google.com/p/django-command-extensions/

you can install that. Along with a gaggle of things you will have a
show_urls command

python manage.py show_urls

will print out all of the urls from all of the apps in your installed
apps

On Oct 19, 8:20 pm, Phlip  wrote:
> A web platform which I will refer to as "Rails" lets you print out all
> the equivalents of the matchers and modules in the tree of urls.py
> files using "rake routes".
>
> Does Django have such a command? Or how could one be written?
>
> --
>   Phlip
>  http://bit.ly/ZeekLand

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Re: Updating a video rating using AJAX

[brad]

Also, if you DO choose to pass JSON back to your client, you should
serialize it first.  See this:

http://docs.djangoproject.com/en/dev/topics/serialization/

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Re: Updating a video rating using AJAX

[Brian Neal]

On Oct 20, 8:23 am, Sithembewena Lloyd Dube  wrote:
> Hi all,
>
> I have a page where users can rate a video, and in models.py I have a video
> model with a 'rating' property. I wish to find out how I can AJAXify the
> rating button on the page, so that if a user clicks on it, the button can
> call a custom function and pass the video id (cannot call a view as that
> would return an entire response). Am thinking of a function roughly as
> follows:
>
> from myproject.myapp.models import Video
>
> def save_rating(video_id, rating):
>     video = Video.objects.filter(pk=video_id)
>     video.rating += rating
>     video.save()
>     return video.rating #* The rating label on the page would then be
> updated with the returned rating.*
>
> I would like to do this without using a view or doing a form POST or GET of
> any kind. Any pointers?

AJAX does in fact do a POST or GET. So you do need to make a view
function that your javascript can issue a POST to update the rating.
Your javascript will need to pass the video ID to the view somehow,
either as part of the URL or as a POST parameter. Your view then needs
to return a response to the javascript, and you can do this as either
plain old text, JSON, XML, or HTML, depending on what makes the most
sense for you. I'd recommend you use a javascript library like jQuery,
simply because these libraries hide some of the very tedious things
you have to do if you were to code the request by hand.

I'd suggest you take a look at some jQuery AJAX tutorials on the web.

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Re: Updating a video rating using AJAX

[brad]

> I would like to do this without using a view or doing a form POST or GET of
> any kind. Any pointers?

Why?  If you're building a web app, you should use HTTP to for the
client to communicate with the app (AJAX is just another form of that
communication).

You're almost there, though, because your function is pretty close to
a view:

def save_rating(request, video_id, rating):
if request.is_ajax():
# the rest of your code...

json_content = '{"rating":"%s"}' % video.rating
return HttpResponse(json_content, mimetype='application/json')

Just be sure to return some sort of data that your client-side
javascript can interpret, such as JSON (of which I've given you an
untested example).

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Re: Expense of django query

[Javier Guerra Giraldez]

On Wed, Oct 20, 2010 at 7:59 AM, Ed  wrote:
> what is the purpose of ifchanged?

since the images are sorted by film, if you just show the film for
every image it would be repeated.  with {% ifchanged %} it's only
shown before all the images for this film, so the result is like this:

film A
image a.1
image a.2
film B
image b.1
image b.2
image b.3
film C


without {% ifchanged %} you would get:
film A
image a.1
film A
image a.2
film B
image b.1
film B
image b.2
film B
image b.3
film C
...


-- 
Javier

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Re: DRY forms

[skyjur]

Does your form look like:

MyForm (ModelForm):
Meta:
fields: ['one', 'second']

it updates only those fields listed in meta tag. Other fields aren't
touched.

On Oct 20, 9:16 am, simonty  wrote:
> Hello,
> I have a database table with about 100 fields.
> I have a number of forms with only a few  fields in each form based on
> the fields in the table.
> If I create one massive django model to represent the table and a
> number of modelforms based on
> the django model, this becomes inefficent because every time I update
> one of my small modelforms (
> which contain only a few fields), all fields in the table will get
> updated. I can see this when I inspect the
> sql query.
> Alternatively I can create small django models and base my modelforms
> on those but this isn't very DRY.
> Its a alot of work.
> Ideally, when I call save() on my modelform, I only want the fields on
> my form to be updated. This makes sense because I am saving the
> information in the form, not the entire model.
> Could anyone make any suggestions for the above scenario?
> Many thanks.

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Registering a ModelAdmin, but with a different URL

[Elie]

Hey guys,

This is my first post in here, and I'm also rather new to Django and a
lot of things are still new to me. I'm also very confused going around
the documentation, so I'd like to ask directly what should I do.

Basically, what I want to do is very very simple really, but I can't
exactly find in the documentation what to do.

First, for the scope of my question, I have 2 models, "Response" and
"Request". A Request object can have multiple Responses. In the
"Response" model.

Secondly, what I'm trying to achieve is to register both models in the
Admin form. But with an exception: that the "Response" model doesn't
show-up in the list of models that the admin backend can manage, but
show it within /admin/my_app/request/1/response/ ...

That is, the list of response can only be related to the give
request ... in the example above, I would like to show a list of
Responses that are belonging to Response with pk=1.

The problem that I'm facing is that if I register the Response
(admin.site.register(Response)) then the Request and Response would be
shown in the main admin page, which is not I'm looking for.
Now, I'm not sure how would I go about displaying the Responses in
that /admin/my_app/request/1/response/ and have it use the default
admin interface (look and feel, links, add button, ...) but only
relevant to the Request that is being worked on.

Thanks for any response,
Elie

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Updating a video rating using AJAX

[Sithembewena Lloyd Dube]

Hi all,

I have a page where users can rate a video, and in models.py I have a video
model with a 'rating' property. I wish to find out how I can AJAXify the
rating button on the page, so that if a user clicks on it, the button can
call a custom function and pass the video id (cannot call a view as that
would return an entire response). Am thinking of a function roughly as
follows:

from myproject.myapp.models import Video

def save_rating(video_id, rating):
video = Video.objects.filter(pk=video_id)
video.rating += rating
video.save()
return video.rating #* The rating label on the page would then be
updated with the returned rating.*

I would like to do this without using a view or doing a form POST or GET of
any kind. Any pointers?

Thanks.

-- 
Regards,
Sithembewena Lloyd Dube
http://www.lloyddube.com

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Re: Displaying a template table using a query set

[Casey S. Greene]

Hi Pranav,

I think what Steve was saying is that if you go back to your original 
template and view:



{% for row in table_data %}

{% for value in row %}

{{ row }}

{% endfor %}

{% endfor %}


and you know, for instance, what fields you want to display and how 
(like your id field) that you don't need to first go to a list (this is 
assuming the view you first posted, not the one that goes to a list):



{% for row in table_data %}

 {{ row.id }} 

{% endfor %}


which is how you proposed to fix the list based situation the second 
time (i.e. how you are thinking it should work is how django actually 
works if you don't force it to go through the list step).


Hope this helps,
-- Casey

On 10/20/2010 09:07 AM, Pranav wrote:



On Oct 20, 5:24 pm, Steve Holden  wrote:

On 10/20/2010 7:58 AM, Pranav wrote:






On Oct 20, 4:13 pm, Daniel Roseman  wrote:

On Oct 20, 8:29 am, Pranav  wrote:



I'm trying to display a table in template using the result retrieved
from a query set, but i get problem when i try to display the table
iterating through each row'' and column''



view file:
from django.shortcuts import get_object_or_404, render_to_response
from models import Organization



def startpage(request):
 table_data = Organization.objects.all()
 return render_to_response('display_table.html', {'table_data':
table_data})



display_table template file:
   
 {% for row in table_data %}
 
 {% for value in row %}
 
 {{ row }}
 
 {% endfor %}
 
 {% endfor %}
 



when i try to run this i get an error saying the object is not
itreable for the second for loop. please provide a solution to this
issue...



Thanks and Regards
Pranav



`value` is an Organisation instance, and model instances are not
iterable, as you could see by trying it in the shell.



You could try passing a values_list instead of a queryset:
 table_data = Organization.objects.all().values_list()
as these are iterable.
--
DR.



Hi Dan,
 Thanks for the fix it worked.
I guess Organization.objects.all().values_list() returns a list.
But what if i want to refer to a particular field say Organization.id
inside my template?



like:

{% for row in table_data %}
   
   
   {{ row.Organization.id }}
   
   
<% endfor %}




I guess I'll have to pass another query set object to do this,
will this have any effect on the throughput of the database?
Is it possible to access cached result of the query set inside the
template?


The point is that normally you don't just want to iterate over the
columns of a retrieved row, since they have differences in meaning that
normally require differences in display formatting and the like as well.

Therefore the solution you offer above is more or less what you actually
do.

regards
  Steve
--
DjangoCon US 2010 September 7-9http://djangocon.us/


Hi Steve,
 I know its a bit odd to display only a column of a table, but
thats the only way i can display a href list and a full fledged table
next to each other.
I guess I'll just have to go with passing 2 query set objects



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Re: Displaying a template table using a query set

[Pranav]

On Oct 20, 5:24 pm, Steve Holden  wrote:
> On 10/20/2010 7:58 AM, Pranav wrote:
>
>
>
>
>
> > On Oct 20, 4:13 pm, Daniel Roseman  wrote:
> >> On Oct 20, 8:29 am, Pranav  wrote:
>
> >>> I'm trying to display a table in template using the result retrieved
> >>> from a query set, but i get problem when i try to display the table
> >>> iterating through each row'' and column''
>
> >>> view file:
> >>> from django.shortcuts import get_object_or_404, render_to_response
> >>> from models import Organization
>
> >>> def startpage(request):
> >>>     table_data = Organization.objects.all()
> >>>     return render_to_response('display_table.html', {'table_data':
> >>> table_data})
>
> >>> display_table template file:
> >>>   
> >>>         {% for row in table_data %}
> >>>             
> >>>             {% for value in row %}
> >>>                 
> >>>                     {{ row }}
> >>>                 
> >>>             {% endfor %}
> >>>             
> >>>         {% endfor %}
> >>>     
>
> >>> when i try to run this i get an error saying the object is not
> >>> itreable for the second for loop. please provide a solution to this
> >>> issue...
>
> >>> Thanks and Regards
> >>> Pranav
>
> >> `value` is an Organisation instance, and model instances are not
> >> iterable, as you could see by trying it in the shell.
>
> >> You could try passing a values_list instead of a queryset:
> >>     table_data = Organization.objects.all().values_list()
> >> as these are iterable.
> >> --
> >> DR.
>
> > Hi Dan,
> >     Thanks for the fix it worked.
> > I guess Organization.objects.all().values_list() returns a list.
> > But what if i want to refer to a particular field say Organization.id
> > inside my template?
>
> > like:
> > 
> > {% for row in table_data %}
> >   
> >   
> >      {{ row.Organization.id }} 
> >   
> >   
> > <% endfor %}
> > 
>
> > I guess I'll have to pass another query set object to do this,
> > will this have any effect on the throughput of the database?
> > Is it possible to access cached result of the query set inside the
> > template?
>
> The point is that normally you don't just want to iterate over the
> columns of a retrieved row, since they have differences in meaning that
> normally require differences in display formatting and the like as well.
>
> Therefore the solution you offer above is more or less what you actually
> do.
>
> regards
>  Steve
> --
> DjangoCon US 2010 September 7-9http://djangocon.us/

Hi Steve,
I know its a bit odd to display only a column of a table, but
thats the only way i can display a href list and a full fledged table
next to each other.
I guess I'll just have to go with passing 2 query set objects

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Re: Expense of django query

[Ed]

Thanks for the suggestion.  Javier's was exactly what I needed.  The
one question I have is why what is the purpose of ifchanged?  I'm
aware of the command but I don't see the purpose of it within a loop.


On Oct 20, 5:18 am, Daniel Roseman  wrote:
> On Oct 19, 9:46 pm, Ed  wrote:
>
>
>
>
>
> > Thanks for the answers.  I thought that the view was already pulling
> > the data.  I didn't realize it gets pulled when called in the
> > template.  I was able to rewrite the view to provide the data more
> > efficiently.
>
> > I have another related question on the topic of query expense.  What
> > is the best practice as far as database table design?
>
> > I have 3 tables: studio, film, images.  If film has a foreign key to
> > studio, and images has a foreign key to film.  If I wanted to pull all
> > of the images for a particular studio, it would be more expensive to
> > pull:
>
> > all films (given studio), and then films.images_set
>
> > as opposed to:
>
> > including the studio in the image table and then pulling all images
> > (given studio).
>
> > But there is some data replication here.  Technically, I can discover
> > studio by following the link from image to film to studio.  But it I
> > need less queries given this particular need.  What is the best
> > practice in a scenario like this?
>
> Well, as you've realised, iterating through each film to get its
> images will fire off one query per film. But how to do it efficiently
> depends on what you're doing with the data. If you just need all
> images for one studio, and don't care about the films, then one query
> will suffice:
>
>     Image.objects.filter(film__studio=mystudio)
>
> If you need all studios and their related images, it's a bit more
> difficult. One way of doing it would be to use the queryset `extra`
> clause to add a studio ID to each image, group them by that ID, then
> studios appending the image list to each one. I can post some code if
> that's the sort of thing you need to do.
> --
> DR.

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Re: DRY forms

[S Basl]

Apologies, I seem to have misunderstood the situation in my haste to be of
assistance.  I admit I'm no Django/Python whiz, more of a talented(?)
dabbler.  Maybe someone else can correct me, but it seems that save() will
always hit the entire row if you use a single model. Does save(f

It seems a bit hacky, but what about creating a method to parse the
modelform's inner Meta.fields then generate and execute a custom UPDATE
statement? This might be a bit more difficult if you're using exclude rather
than fields. To keep it DRY attach this method to a subclass of modelform
then make your existing modelforms subclasses of this.

This seems like a lot more work than aught be necessary, so you may be best
off waiting for someone more knowledgeable than me to chime in.



On Wed, Oct 20, 2010 at 3:34 AM, simonty  wrote:

> I can't change the database design. Even if I could, that would still
> mean I would have to define a model and a modelform for each table,
> no?
>
> On Oct 20, 6:13 pm, srb...@gmail.com wrote:
> > Can you just break the table up into several tables connected with
> one-to-one relations? Maybe look at the model forms you're using the most as
> a guide for which fields to include in the new tables?
> > Sent from my Verizon Wireless BlackBerry
> >
> > -Original Message-
> > From: simonty 
> >
> > Sender: django-users@googlegroups.com
> > Date: Tue, 19 Oct 2010 23:16:38
> > To: Django users
> > Reply-To: django-users@googlegroups.com
> > Subject: DRY forms
> >
> > Hello,
> > I have a database table with about 100 fields.
> > I have a number of forms with only a few  fields in each form based on
> > the fields in the table.
> > If I create one massive django model to represent the table and a
> > number of modelforms based on
> > the django model, this becomes inefficent because every time I update
> > one of my small modelforms (
> > which contain only a few fields), all fields in the table will get
> > updated. I can see this when I inspect the
> > sql query.
> > Alternatively I can create small django models and base my modelforms
> > on those but this isn't very DRY.
> > Its a alot of work.
> > Ideally, when I call save() on my modelform, I only want the fields on
> > my form to be updated. This makes sense because I am saving the
> > information in the form, not the entire model.
> > Could anyone make any suggestions for the above scenario?
> > Many thanks.
> >
> > --
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Re: Displaying a template table using a query set

[Steve Holden]

On 10/20/2010 7:58 AM, Pranav wrote:
> 
> 
> On Oct 20, 4:13 pm, Daniel Roseman  wrote:
>> On Oct 20, 8:29 am, Pranav  wrote:
>>
>>
>>
>>
>>
>>> I'm trying to display a table in template using the result retrieved
>>> from a query set, but i get problem when i try to display the table
>>> iterating through each row'' and column''
>>
>>> view file:
>>> from django.shortcuts import get_object_or_404, render_to_response
>>> from models import Organization
>>
>>> def startpage(request):
>>> table_data = Organization.objects.all()
>>> return render_to_response('display_table.html', {'table_data':
>>> table_data})
>>
>>> display_table template file:
>>>   
>>> {% for row in table_data %}
>>> 
>>> {% for value in row %}
>>> 
>>> {{ row }}
>>> 
>>> {% endfor %}
>>> 
>>> {% endfor %}
>>> 
>>
>>> when i try to run this i get an error saying the object is not
>>> itreable for the second for loop. please provide a solution to this
>>> issue...
>>
>>> Thanks and Regards
>>> Pranav
>>
>> `value` is an Organisation instance, and model instances are not
>> iterable, as you could see by trying it in the shell.
>>
>> You could try passing a values_list instead of a queryset:
>> table_data = Organization.objects.all().values_list()
>> as these are iterable.
>> --
>> DR.
> 
> Hi Dan,
> Thanks for the fix it worked.
> I guess Organization.objects.all().values_list() returns a list.
> But what if i want to refer to a particular field say Organization.id
> inside my template?
> 
> like:
> 
> {% for row in table_data %}
>   
>   
>  {{ row.Organization.id }} 
>   
>   
> <% endfor %}
> 
> 
> I guess I'll have to pass another query set object to do this,
> will this have any effect on the throughput of the database?
> Is it possible to access cached result of the query set inside the
> template?
> 
The point is that normally you don't just want to iterate over the
columns of a retrieved row, since they have differences in meaning that
normally require differences in display formatting and the like as well.

Therefore the solution you offer above is more or less what you actually
do.

regards
 Steve
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Re: Different logins in same browser session and login_required

[PyMan]

>
> > It shouldn't happen, but it could. It's an office or it's a warehouse,
> > people could work with the same user and/or (above all) people may
> > work on the same machine...so they should pay attention on what they
> > do...but even no.
>
> > Just an example when the problem can occurs:
> > The djangoapp has more users, some of these have privileges to access
> > the django-admin to change some user permissions
>
> > With just one opened browser window the user U1 (not superuser/staff)
> > is logged on, then going on the django-admin (in a new window because
> > the link opened there, or jsut the user opened a new window by himself
> > or whatever) a login is required. Logging on with a different user,
> > the first window still seems (especially when the whole application is
> > ajax based) to use the U1 user and something of not expected (to the
> > user) may occurs.
>
> > I understand it's normal, the end-user may not.
>
> In which case the solution is to instruct them not to share logins,
> which they would have to do to experience those problems.
>
> I agree it can be a pain when they do that, but if they are so
> unsophisticated that they let two different users interact with the
> system through a single login account they must expect trouble with
> authenticated systems.
>
> As is so often the case, education is the answer. And, as is so often
> the case, the users would rather sacrifice security for convenience
> (then make it the system designer's fault when they realize they can't
> have both).
>
> regards
>  Steve
>
> --
> DjangoCon US 2010 September 7-9http://djangocon.us/

100% agree! If it were for me the thing would have already been
stopped here! :D

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Re: Displaying a template table using a query set

[Pranav]

On Oct 20, 4:13 pm, Daniel Roseman  wrote:
> On Oct 20, 8:29 am, Pranav  wrote:
>
>
>
>
>
> > I'm trying to display a table in template using the result retrieved
> > from a query set, but i get problem when i try to display the table
> > iterating through each row'' and column''
>
> > view file:
> > from django.shortcuts import get_object_or_404, render_to_response
> > from models import Organization
>
> > def startpage(request):
> >     table_data = Organization.objects.all()
> >     return render_to_response('display_table.html', {'table_data':
> > table_data})
>
> > display_table template file:
> >   
> >         {% for row in table_data %}
> >             
> >             {% for value in row %}
> >                 
> >                     {{ row }}
> >                 
> >             {% endfor %}
> >             
> >         {% endfor %}
> >     
>
> > when i try to run this i get an error saying the object is not
> > itreable for the second for loop. please provide a solution to this
> > issue...
>
> > Thanks and Regards
> > Pranav
>
> `value` is an Organisation instance, and model instances are not
> iterable, as you could see by trying it in the shell.
>
> You could try passing a values_list instead of a queryset:
>     table_data = Organization.objects.all().values_list()
> as these are iterable.
> --
> DR.

Hi Dan,
Thanks for the fix it worked.
I guess Organization.objects.all().values_list() returns a list.
But what if i want to refer to a particular field say Organization.id
inside my template?

like:

{% for row in table_data %}
  
  
 {{ row.Organization.id }} 
  
  
<% endfor %}


I guess I'll have to pass another query set object to do this,
will this have any effect on the throughput of the database?
Is it possible to access cached result of the query set inside the
template?

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Re: Different logins in same browser session and login_required

[Steve Holden]

On 10/20/2010 5:20 AM, PyMan wrote:
> 
> 
> On 20 Ott, 10:28, Daniel Roseman  wrote:
>> On Oct 20, 8:11 am, PyMan  wrote:
>>
 Firefox has long had its "profile" functionality.
>>
 firefox -no-remote -ProfileManager
>>
 You can create multiple firefox profiles, then run multiple instances of
 firefox at once - so long as you use different profiles for them.  A bit
 fiddly, but obviously useful for development/testing.
>>
>>> First of all thanks for your answers to both of you :)
>>
>>> Yeah, I know about FX profiles and I already knew it was a working
>>> solution, but it's not a good solution. I mean we're speaking about
>>> users that don't even know what a browser is. Telling them to do that
>>> is just mess.
>>
>> What's your case for getting end users to log in as two separate
>> profiles? If they're non-technical, they shouldn't have to be worrying
>> about this level of detail in any case. It's going to be confusing for
>> them no matter what you do.
>> --
>> DR.
> 
> It shouldn't happen, but it could. It's an office or it's a warehouse,
> people could work with the same user and/or (above all) people may
> work on the same machine...so they should pay attention on what they
> do...but even no.
> 
> Just an example when the problem can occurs:
> The djangoapp has more users, some of these have privileges to access
> the django-admin to change some user permissions
> 
> With just one opened browser window the user U1 (not superuser/staff)
> is logged on, then going on the django-admin (in a new window because
> the link opened there, or jsut the user opened a new window by himself
> or whatever) a login is required. Logging on with a different user,
> the first window still seems (especially when the whole application is
> ajax based) to use the U1 user and something of not expected (to the
> user) may occurs.
> 
> I understand it's normal, the end-user may not.
> 
In which case the solution is to instruct them not to share logins,
which they would have to do to experience those problems.

I agree it can be a pain when they do that, but if they are so
unsophisticated that they let two different users interact with the
system through a single login account they must expect trouble with
authenticated systems.

As is so often the case, education is the answer. And, as is so often
the case, the users would rather sacrifice security for convenience
(then make it the system designer's fault when they realize they can't
have both).

regards
 Steve

-- 
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Re: Displaying a template table using a query set

[Daniel Roseman]

On Oct 20, 8:29 am, Pranav  wrote:
> I'm trying to display a table in template using the result retrieved
> from a query set, but i get problem when i try to display the table
> iterating through each row'' and column''
>
> view file:
> from django.shortcuts import get_object_or_404, render_to_response
> from models import Organization
>
> def startpage(request):
>     table_data = Organization.objects.all()
>     return render_to_response('display_table.html', {'table_data':
> table_data})
>
> display_table template file:
>   
>         {% for row in table_data %}
>             
>             {% for value in row %}
>                 
>                     {{ row }}
>                 
>             {% endfor %}
>             
>         {% endfor %}
>     
>
> when i try to run this i get an error saying the object is not
> itreable for the second for loop. please provide a solution to this
> issue...
>
> Thanks and Regards
> Pranav

`value` is an Organisation instance, and model instances are not
iterable, as you could see by trying it in the shell.

You could try passing a values_list instead of a queryset:
table_data = Organization.objects.all().values_list()
as these are iterable.
--
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Re: login_required and new class based views

[Russell Keith-Magee]

2010/10/20 Łukasz Rekucki :
> On 19 October 2010 19:06, Valentin Golev  wrote:
>> Hello,
>>
> 2) decorate the dispatch method. You need to turn login_required into
> a method decorator first (Django should probably provide a tool for
> this).

Django does :-) It's called method_decorator.

from django.utils.decorators import method_decorator

class MyDecoratedView(MyView):

@method_decorator(login_required)
def dispatch(self, *args, **kwargs):
#...

This works for any method on any class, that you want to decorate with
any function-based decorator.

As a point of interest, the django.utils.decorators module has a
couple of other useful utilities in this vein, such as
decorator_from_middleware (which, predictably, enables you to turn any
middleware into a decorator that wraps a single view).

Yours,
Russ Magee %-)

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BrightonPy event: The Why and How of Automated Testing with Python and Django

[Jamie Matthews]

Hi all, I thought our next BrightonPy meeting might be of interest to
this list:

The Why and How of Automated Testing with Python and Django

Jim Purbrick, Tuesday October 26, 2010, 19:30 at The Skiff

http://brightonpy.org/meetings/2010-10-26/

Why do we write tests? How do we write them? What kinds of tests are
valuable? Learn and share your experiences of how to do Test Driven
Development in Python and Django. The evening will start with a talk
by agile software veteran Jim Purbrick followed by a hands-on
practical session led by Alan McNeil Jackson, CTO of Aptivate. Bring a
laptop if you want to code along.

Please sign up on Upcoming or Lanyrd if you will be attending:
http://upcoming.yahoo.com/event/7193208/
http://lanyrd.com/2010/brightonpy-october/

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Displaying a template table using a query set

[Pranav]

I'm trying to display a table in template using the result retrieved
from a query set, but i get problem when i try to display the table
iterating through each row'' and column''

view file:
from django.shortcuts import get_object_or_404, render_to_response
from models import Organization

def startpage(request):
table_data = Organization.objects.all()
return render_to_response('display_table.html', {'table_data':
table_data})

display_table template file:
  
{% for row in table_data %}

{% for value in row %}

{{ row }}

{% endfor %}

{% endfor %}


when i try to run this i get an error saying the object is not
itreable for the second for loop. please provide a solution to this
issue...

Thanks and Regards
Pranav

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distinct in autocomplete

[alecx]

Hello,

how do I get only distinct values of that query in the autocomplete
field:

def autocomplete_techlastname(request):
if request.GET.has_key('q'):
tags = 
Item.objects.filter(techlastname__icontains=request.GET['q'])
[:5]
return HttpResponse('\n'.join(tag.techlastname for tag in tags))
return HttpResponse()

appending distinct seems not to work.

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Re: Different logins in same browser session and login_required

[PyMan]

On 20 Ott, 10:28, Daniel Roseman  wrote:
> On Oct 20, 8:11 am, PyMan  wrote:
>
> > > Firefox has long had its "profile" functionality.
>
> > > firefox -no-remote -ProfileManager
>
> > > You can create multiple firefox profiles, then run multiple instances of
> > > firefox at once - so long as you use different profiles for them.  A bit
> > > fiddly, but obviously useful for development/testing.
>
> > First of all thanks for your answers to both of you :)
>
> > Yeah, I know about FX profiles and I already knew it was a working
> > solution, but it's not a good solution. I mean we're speaking about
> > users that don't even know what a browser is. Telling them to do that
> > is just mess.
>
> What's your case for getting end users to log in as two separate
> profiles? If they're non-technical, they shouldn't have to be worrying
> about this level of detail in any case. It's going to be confusing for
> them no matter what you do.
> --
> DR.

It shouldn't happen, but it could. It's an office or it's a warehouse,
people could work with the same user and/or (above all) people may
work on the same machine...so they should pay attention on what they
do...but even no.

Just an example when the problem can occurs:
The djangoapp has more users, some of these have privileges to access
the django-admin to change some user permissions

With just one opened browser window the user U1 (not superuser/staff)
is logged on, then going on the django-admin (in a new window because
the link opened there, or jsut the user opened a new window by himself
or whatever) a login is required. Logging on with a different user,
the first window still seems (especially when the whole application is
ajax based) to use the U1 user and something of not expected (to the
user) may occurs.

I understand it's normal, the end-user may not.

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Re: Expense of django query

[Daniel Roseman]

On Oct 19, 9:46 pm, Ed  wrote:
> Thanks for the answers.  I thought that the view was already pulling
> the data.  I didn't realize it gets pulled when called in the
> template.  I was able to rewrite the view to provide the data more
> efficiently.
>
> I have another related question on the topic of query expense.  What
> is the best practice as far as database table design?
>
> I have 3 tables: studio, film, images.  If film has a foreign key to
> studio, and images has a foreign key to film.  If I wanted to pull all
> of the images for a particular studio, it would be more expensive to
> pull:
>
> all films (given studio), and then films.images_set
>
> as opposed to:
>
> including the studio in the image table and then pulling all images
> (given studio).
>
> But there is some data replication here.  Technically, I can discover
> studio by following the link from image to film to studio.  But it I
> need less queries given this particular need.  What is the best
> practice in a scenario like this?

Well, as you've realised, iterating through each film to get its
images will fire off one query per film. But how to do it efficiently
depends on what you're doing with the data. If you just need all
images for one studio, and don't care about the films, then one query
will suffice:

Image.objects.filter(film__studio=mystudio)

If you need all studios and their related images, it's a bit more
difficult. One way of doing it would be to use the queryset `extra`
clause to add a studio ID to each image, group them by that ID, then
studios appending the image list to each one. I can post some code if
that's the sort of thing you need to do.
--
DR.

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Re: Different logins in same browser session and login_required

[Daniel Roseman]

On Oct 20, 8:11 am, PyMan  wrote:
> > Firefox has long had its "profile" functionality.
>
> > firefox -no-remote -ProfileManager
>
> > You can create multiple firefox profiles, then run multiple instances of
> > firefox at once - so long as you use different profiles for them.  A bit
> > fiddly, but obviously useful for development/testing.
>
> First of all thanks for your answers to both of you :)
>
> Yeah, I know about FX profiles and I already knew it was a working
> solution, but it's not a good solution. I mean we're speaking about
> users that don't even know what a browser is. Telling them to do that
> is just mess.

What's your case for getting end users to log in as two separate
profiles? If they're non-technical, they shouldn't have to be worrying
about this level of detail in any case. It's going to be confusing for
them no matter what you do.
--
DR.

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Re: DRY forms

[simonty]

I can't change the database design. Even if I could, that would still
mean I would have to define a model and a modelform for each table,
no?

On Oct 20, 6:13 pm, srb...@gmail.com wrote:
> Can you just break the table up into several tables connected with one-to-one 
> relations? Maybe look at the model forms you're using the most as a guide for 
> which fields to include in the new tables?
> Sent from my Verizon Wireless BlackBerry
>
> -Original Message-
> From: simonty 
>
> Sender: django-users@googlegroups.com
> Date: Tue, 19 Oct 2010 23:16:38
> To: Django users
> Reply-To: django-users@googlegroups.com
> Subject: DRY forms
>
> Hello,
> I have a database table with about 100 fields.
> I have a number of forms with only a few  fields in each form based on
> the fields in the table.
> If I create one massive django model to represent the table and a
> number of modelforms based on
> the django model, this becomes inefficent because every time I update
> one of my small modelforms (
> which contain only a few fields), all fields in the table will get
> updated. I can see this when I inspect the
> sql query.
> Alternatively I can create small django models and base my modelforms
> on those but this isn't very DRY.
> Its a alot of work.
> Ideally, when I call save() on my modelform, I only want the fields on
> my form to be updated. This makes sense because I am saving the
> information in the form, not the entire model.
> Could anyone make any suggestions for the above scenario?
> Many thanks.
>
> --
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Re: DRY forms

[srbasl]

Can you just break the table up into several tables connected with one-to-one 
relations? Maybe look at the model forms you're using the most as a guide for 
which fields to include in the new tables?
Sent from my Verizon Wireless BlackBerry

-Original Message-
From: simonty 
Sender: django-users@googlegroups.com
Date: Tue, 19 Oct 2010 23:16:38 
To: Django users
Reply-To: django-users@googlegroups.com
Subject: DRY forms

Hello,
I have a database table with about 100 fields.
I have a number of forms with only a few  fields in each form based on
the fields in the table.
If I create one massive django model to represent the table and a
number of modelforms based on
the django model, this becomes inefficent because every time I update
one of my small modelforms (
which contain only a few fields), all fields in the table will get
updated. I can see this when I inspect the
sql query.
Alternatively I can create small django models and base my modelforms
on those but this isn't very DRY.
Its a alot of work.
Ideally, when I call save() on my modelform, I only want the fields on
my form to be updated. This makes sense because I am saving the
information in the form, not the entire model.
Could anyone make any suggestions for the above scenario?
Many thanks.

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Re: Different logins in same browser session and login_required

[PyMan]

>
> Firefox has long had its "profile" functionality.
>
> firefox -no-remote -ProfileManager
>
> You can create multiple firefox profiles, then run multiple instances of
> firefox at once - so long as you use different profiles for them.  A bit
> fiddly, but obviously useful for development/testing.

First of all thanks for your answers to both of you :)

Yeah, I know about FX profiles and I already knew it was a working
solution, but it's not a good solution. I mean we're speaking about
users that don't even know what a browser is. Telling them to do that
is just mess.

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DRY forms

[simonty]

Hello,
I have a database table with about 100 fields.
I have a number of forms with only a few  fields in each form based on
the fields in the table.
If I create one massive django model to represent the table and a
number of modelforms based on
the django model, this becomes inefficent because every time I update
one of my small modelforms (
which contain only a few fields), all fields in the table will get
updated. I can see this when I inspect the
sql query.
Alternatively I can create small django models and base my modelforms
on those but this isn't very DRY.
Its a alot of work.
Ideally, when I call save() on my modelform, I only want the fields on
my form to be updated. This makes sense because I am saving the
information in the form, not the entire model.
Could anyone make any suggestions for the above scenario?
Many thanks.

-- 
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