Re: template problem in windows
yes thanks mike mostly i work in linux but i had to see some work on windows and this problem was little strange. but all well now. thanks again --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
template problem in windows
i have found this during working with django on windws. if i create folder like template, backup (start characters t, b etc) it wont work because template folder settings in the SETTINGS.py will be TEMPLATE_DIRS = ( 'c:\myproject\template', } it would not work because \t is tab character and it would render a tab in the path resulting in template not found exception. similarly other executable characters like \b for bell etc. would result in template not found exception. a solution for it can be escaping the executable character so instead of using \t using \\t would work TEMPLATE_DIRS = ( 'c:\myproject\\template', } it's not a problem at all in linux. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Data truncated for column 'text' at row 1
the problem seems to be your database installation. you can increase CharField length by installaing mysql version 5.xx. also check what database you are using and character set it supports. On Sep 25, 10:42 am, Sebastian Dahlgren <[EMAIL PROTECTED]> wrote: > Hi! > I have built my site on the Django dev server and everything works > fine there. But when I uploaded the project to a Apache + mod_python > server I got an error > > Data truncated for column 'text' at row 1 > > That is shown when I pass swedish chars like å ä and ö into a form, > which then POST's the form back to the same page. The whole warning- > message reads: > > Warning at / > Data truncated for column 'text' at row 1 > Request Method: POST > Request URL:http://sql.bidclub.se/ > Exception Type: Warning > Exception Value:Data truncated for column 'text' at row 1 > Exception Location: /usr/lib/python2.4/site-packages/MySQLdb/ > cursors.py in _warning_check, line 80 > Python Executable: /usr/bin/python > Python Version: 2.4.4 > > The POSTing works 'cause when I return to the site I can see the post. > I guess this has something to do with unicode or something, but I > don't really know where to look. > > Any hint is really appreciated! > > Thanks in advance --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: changing settings.py
you can try adding MaxRequestsPerChild 1 to your httpd.conf file and restart apache then i think you dont' need to restart apache every time. this is just for testing purpose, for more read documentation on it. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
run queries stored in database
can we save django ORM queries in database and execute them later. suppose i have class class queries(): qry=models.CharField(maxlength=200) and i save a query "test.objects.filter(id=5)" in qry now want to run query stored in qry field --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
problem organizing queries
hi i am having problem with relating objects. i have models as below
class support():
suptype = models.CharField(maxlength=255)
class DispMaster():
dmtype=models.ForeignKey(support)
class DataDispMaster():
ddmmaster=models.ForeignKey(Master)
class Master():
class DataMaster():
dmmaster = models.ForeignKey(Master)
i want to get one row from support table,
get its related entry from DispMaster table,
get multiple entries from DataDispMaster table related to DispMaster
table,
get multiple entries from Master table related to DataDispMaster
table,
finally get values from DataMaster table related to Master table
this is what i have done so far (i really don't think it is good
enough)
supid=support.objects.filter(suptype="Basic") #this will
return one row only
dispmid=DispMaster.objects.filter(dmtype=supid[0].id)#this also
will return only one row
mid = Master.objects.filter(datadispmaster__ddmmaster__exact =
dispmid[0].id) #this is where i am getting problems because i will
get multiple values from here which again will be used in the next
query to get further values.
now i want values from DataMaster table respective to the values i
have got in previous table.
i have also read the discussion going at
http://groups.google.co.in/group/django-users/browse_thread/thread/91985e7ca5ad7c8c?hl=en#
i still figuring it out if django ORM support this type of query. and
if not what is the best way to overcome this problem.
one way i think is to get the dictionary for mid object
(mid.values('id')) and convert the dictionary to list and use ORMs
IN function. but this, i dont' think, is good solution
if any body can help me to organize these queries
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Re: url config problem
i think you are using windows.
try adding "MaxRequestsPerChild 1" (without quotes) to
httpd.conf,
you can change this setting later after reading how apache handles
requests. i think that wouldn't be required for you now.
also put your application to the python path (you can try initial
application at "site-packages" folder inside python folder)
check your files for sample application
urls.py
(r'^mysite/admin/', include('django.contrib.admin.urls')),
notice "mysite/admin/"
where mysite is url you have defined at httpd.conf
notice "/mysite"you can
read further on it
SetEnv DJANGO_SETTINGS_MODULE mysite.settings
i have seen same problem on windows and following these steps, i have
eliminated the problem.
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Re: url config problem
which os you are using?? is your site-packages directory under system path?? and can you paste lines from httpd.conf, urls.py and settings.py where you have made modifications. On Sep 26, 6:49 pm, swati <[EMAIL PROTECTED]> wrote: > I have configured httpd.conf, you can look at it > athttp://82.165.180.35:8088/djproject/ > I can see the first django page. Could not run any application when I > try to do that by editing urls.py file. > > Thanks, > Swati > > On Sep 26, 1:27 pm, Dushyant Sharma <[EMAIL PROTECTED]> wrote: > > > i think you have not configured httpd.conf and this is why apache can > > not identify the request. > > > read this pagehttp://www.djangoproject.com/documentation/modpython/ > > > also make entry in httpd.conf > > LoadModule python_module /usr/local/apache2/modules/mod_python.so (for > > linux) > > for windows use your windows installation path --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: url config problem
i think you have not configured httpd.conf and this is why apache can not identify the request. read this page http://www.djangoproject.com/documentation/modpython/ also make entry in httpd.conf LoadModule python_module /usr/local/apache2/modules/mod_python.so (for linux) for windows use your windows installation path --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: response from another function
> function1(request): > return function2(request) no i just want that function2(request) call makes a permanent redirect (not HttpResponseRedirect, i dont want more burden on urls.py) to function2 and all the response should be sent from function2 only. it should never come back to function1 again. if it is possible --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
response from another function
is it possible to return HttpResponse from another function
like i have called a function say furnction1(request) and now is it
possible
function1(request):
#normal statements
#here i call another function
function2(request)
return HttpResponse('bye') #just for example not useful here
function2(request):
return HttpResponse('ok')
here it will return 'bye' but i want that the function call for
function2 should return 'ok' to the client browser
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Re: How to run server after install Django
dear Han you must add path of python.exe, django-admin.py and manage.py to your system path you should avoid copying system files here and there as it will cause problems. clean approach should be 1. install python (say installed at C:\python25) 2. set path for python.exe 3. install django (will be installed at c:\python25\lib\site-packages) 4. add django-admin.py and manage.py (complete path) to system path 5. create a new folder (just to manage your applications) (say c: \djangoapps) 6. inside c:\djangoapps use command django-admin.py startproject mysite 7. it will create new folder mysite inside c:\djangoapps 8. here you can run server manage.py runserver and you are ready to work --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
size of urls.py
is there any performance bottleneck when the size of urls.py goes large. if yes how to overcome that. also if we use same url for a particular group, based on some hidden action variable in htmls, would it improve performance. like i am using if request.method == 'POST': action = request.POST['act'] if action == '0001': call some function based on action 0001 --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: User session variable in view
use RequestContext
http://www.djangoproject.com/documentation/templates_python/#subclassing-context-requestcontext
pass request object to it
c= RequestContext(request, {other objects})
then you can use user.fieldname in your view
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Re: Uploading files
class ThingForm(forms.Form):
name = forms.CharField(max_length=30, required=True, label=_('Name
of the thing'))
photo = forms.Field(widget=forms.FileInput, required=False,
label=_('Photo'), help_text=_('Upload an image (max %s kilobytes)' %
settings.MAX_PHOTO_UPLOAD_SIZE))
def thing_add(request):
if request.method == 'POST':
new_data = request.POST.copy()
new_data.update(request.FILES)
form = ThingForm(new_data)
if form.is_valid():
clean_data = form.clean_data
t = Thing()
t.name = clean_data['name']
if clean_data['photo']:
photo = clean_data['photo']
t.save_photo_file(photo['filename'], photo['content'])
please also read
http://www.djangoproject.com/documentation/model-api/#filefield
and
http://batiste.dosimple.ch/blog/2007-05-13-1/
new forms have changed this binding and made things easy so you can
also check
http://www.djangoproject.com/documentation/newforms/#binding-uploaded-files-to-a-form
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Re: FileInput widget and FileField
here is model
class Thing(models.Model):
PID=models.ForeignKey(Property)
name = models.CharField(blank=False, null=False, maxlength=30)
photo = models.ImageField(upload_to='images/things/', blank=True,
null=True)
the form
class ThingForm(forms.Form):
name = forms.CharField(max_length=30, required=True, label=_('Name
of the thing'))
photo = forms.Field(widget=forms.FileInput, required=False,
label=_('Photo'))
html
save data
new_data = request.POST.copy() # these two lines
are
new_data.update(request.FILES) # very important
form = ThingForm(new_data)
if form.is_valid():
clean_data = form.clean_data
t = Thing()
t.name = clean_data['name']
if clean_data['photo']:
photo = clean_data['photo']
t.save_photo_file(photo['filename'],
photo['content'])
you can also eliminate model and save directly to some binary stream
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Re: php fsockopen equivalent in Django
may be you can use ajax for that. i have tried and it works wonders. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
log in without loggin in
hi it might sound strange but what i am thinking is to use two servers one for authentication only and one for serving normal content. authentication server can not come into direct contact with users. here how it goes. suppose we have user server USrv and authentication server ASrv. auth_user table is at ASrv only. request for log in from the user goes to USrv. Usrv sends it to ASrv for authentication. If ASrv says the user is authentic then USrv treat the user as logged in without actually calling authenticate() function for it. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Email problem
i think you should try port 25 at EMAIL_PORT after all you wont loss anything giving a try On Jun 14, 6:12 pm, Malcolm Tredinnick <[EMAIL PROTECTED]> wrote: > On Thu, 2007-06-14 at 05:35 -0700, Brij wrote: > > Hi, > > > I am using the django.core.mail for sending mail to users in my > > application...I have defined EMAIL_HOST but havenot defined EMAIL_PORT > > because my smtp server doesnt require a port number... > > All services require a port number. If you don't specify the EMAIL_PORT, > it will use the default (and standard value) of 25. That's fine; just > making you aware that it is using a port number even if you don't > specify it. > > > Following is the view function im using ::: > > > def send_email(request, sender, reciepient): > > subject = 'Test Mail from OST' > > message = 'Testing email from OST' > > from_email = '[EMAIL PROTECTED]' > > if subject and message and from_email: > >try: > >send_mail(subject, message, from_email, > > ['[EMAIL PROTECTED]']) > > [...] > > > The error which i m getting is ::: > > Exception Value: (10054, 'Connection reset by peer') > > Exception Location: C:\Python24\Lib\socket.py in readline, line 340 > > There's no way I can think of to tell what the problem is from this > information. All the error message is saying is that you made a > connection to a server (so something is listening on port 25 on the > machine you specified) and then it hung up on you at some later point. > > Debugging network transactions like this is difficult. Ideally, use a > network sniffer to see the traffic going back and forth between the > client and the server so that you can tell where the problem occurs > (since an email sending interaction is a series of requests and > responses, there are a number of places it can go wrong). If you have > access to the mail logs on the server, that is another way to determine > what is going wrong (not normally posssible in many environments, > though, so it's unlikely you'll be able to use this route). > > Check to see if you SMTP server requires using a TLS connection, rather > than just a plain connection (if so, use the TLS parameter from the > latest Django code -- this option won't be available in the 0.96 > release, however). > > There's not really much I can think to suggest short of finding a way to > watch the network traffic (with something like WireShark), since you > need to know what went wrong and when. At the moment, all you know is > that "it didn't work", which could mean any one of a hundred things. > > Some other respondents may have other ideas, though. > > Regards, > Malcolm --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: jsonrpc working example
here is what i am doing
server code
from jsonrpc import handleCGI, ServiceMethod
from django.core import serializers
@ServiceMethod
def hello(msg):
json = serializers.serialize("json",msg)# initially i tried
return(msg)only but i was getting error JSONDecodeException at /c/
testhello/
#Expected []{}," or Number, Null, False or True
return HttpResponse(json)
or
return (json)
or i can use
return HttpResponse(json,mimetype='application/javascript')
none of them works
at client side i use
def testhello(response):
s = ServiceProxy("http://localhost/s/hello";)
resp=s.hello('hello')# this is where i am doubtful
return HttpResponse(resp)
when calling it shows error
JSONDecodeException at /c/testhello/
Expected []{}," or Number, Null, False or True
what i am trying is creating two projects setup with apache virtual
host. one is interacting with user as we do normally. another is
serving the first project by taking requests and sending response to
the first without letting the user know anything.
On Jun 14, 5:39 pm, Kenneth Gonsalves <[EMAIL PROTECTED]> wrote:
> On 14-Jun-07, at 6:00 PM, Dushyant Sharma wrote:
>
> > has any body used jsonrpc with django if yes kindly help me
> > here is how to use it but i cant use it with django facing problems
>
> would be helpful if you stated what you tried and what the errors were
>
> --
>
> regards
> kghttp://lawgon.livejournal.comhttp://nrcfosshelpline.in/web/
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jsonrpc working example
has any body used jsonrpc with django if yes kindly help me here is how to use it but i cant use it with django facing problems http://json-rpc.org/wiki/python-json-rpc --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: session variable in template
how can i use it with HttpResponseRedirect()
like if i wish to use it as return HttpResponseRedirect('/someurl',
RequestContext(request))
is it possible
On Jun 13, 5:42 am, Malcolm Tredinnick <[EMAIL PROTECTED]>
wrote:
> On Tue, 2007-06-12 at 13:27 +0000, Dushyant Sharma wrote:
> > i am building single page for logged in users and anonymous users
> > where i can use uid for logged in users and show specific things to
> > them and for this i want to use session variable in template. i am
> > trying request.session.uid in template where uid is session
> > variable..
>
> Have a read
> ofhttp://www.djangoproject.com/documentation/authentication/#authentica
> That should explain what you need.
>
> Regards,
> Malcolm
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session variable in template
i am building single page for logged in users and anonymous users
where i can use uid for logged in users and show specific things to
them and for this i want to use session variable in template. i am
trying request.session.uid in template where uid is session
variable..
i have set request.session['uid']=str(user.id)
now i want to dothe following in template
{% if request.session.id %}
you are logged in
{% endif %}
but nothing is showing
here i am loggin user in
login(request, user)
request.session['uname']=username
uu=User.objects.get(username=username)
request.session['uid']=str(uu.id)
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Re: manipulator for auth.user
come on somebody pl. reply --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: manipulator for auth.user
if this is possible or not to apply manipulator on User and on two models. i have read previous posts in this regard sugggesting method what i have used but i am getting errors as above. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
manipulator for auth.user
i am trying to add manipulator on default User object. i am getting
name, email and address from the form and trying to fill date_joined
and last_login attributes myself as
user_data['date_joined_date']=datetime.date.today()
user_data['date_joined_time']=(datetime.time()
user_data['last_login_date']=datetime.date.today()
user_data['last_login_time']=datetime.time()
uerrors=umanipulator.get_validation_errors(user_data)
it shows
Exception Value:'datetime.date' object has no attribute 'decode'
if i convert all of them to string with strftime() as
user_data['date_joined_date']=datetime.datetime.now().strftime('%Y-%m-
%d')
user_data['date_joined_time']=datetime.datetime.now().strftime('%H:%M:
%S')
user_data['last_login_date']=datetime.datetime.now().strftime('%Y-%m-
%d')
user_data['last_login_time']=datetime.datetime.now().strftime('%H:%M:
%S')
it says
Exception Value: combine() argument 1 must be datetime.date, not str
what actually i am doing is i am trying to add manipulator on two
objects with
umanipulator = User.AddManipulator()
manipulator = Builder.AddManipulator()
user_data['date_joined_date']=datetime.date.today()
user_data['date_joined_time']=(datetime.time()
user_data['last_login_date']=datetime.date.today()
user_data['last_login_time']=datetime.time()
uerrors=umanipulator.get_validation_errors(user_data)
if not (uerrors):
new_user = umanipulator.save(user_data)
u=User.object.get(username__exact=user_data['id_username'])
and with u.id i ll save other object with same method
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Re: if 'photo' in request.FILES seems to be not working
i can not beleive this i had only to write enctype in capital ENCTYPE="multipart/form-data" i am sick --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Django Deployment Headache (Apache Permissions?)
i am having the same problem i tried adding mysite.pth to site- packages folder now i can see the path in python as /root/workspace/ and /root/workspace/mysite settings.py is in mysite directory at /root/workspace also i have __init_.py there it show the same error but if i put the directory mysite at site-packages it works just fine --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
if 'photo' in request.FILES seems to be not working
hi friends
i am trying to upload an image file but i am getting errors.
code is as follows
def thing_add(request):
if request.method == 'POST':
if 'photo' in request.FILES:
# it aint getting here just skip this section
try:
img = Image.open(StringIO(request.FILES['photo']
['content']))
request.FILES['photo']['dimensions'] = img.size
except:
request.FILES['photo']['error'] = True
new_data = request.POST.copy()
new_data.update(request.FILES)
form = ThingForm(new_data)
if form.is_valid():
clean_data = form.clean_data
t = Thing()
t.name = clean_data['name']
if clean_data['photo']:
photo = clean_data['photo']
t.save_photo_file(photo['filename'], photo['content'])
return HttpResponse('/some/where')
else:
form = ThingForm()
context = Context({'form': form})
return render_to_response('loadfiles.html', context)
with loadfiles having
i am having an exception
Exception Value:string indices must be integers
at line
t.save_photo_file(photo['filename'], photo['content'])
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Re: access user.id
hey thanks chrominance for real good helping stuff. i was not looking at the last line which clearly states that argument 1 must be string or read-only buffer, not long your return HttpResponse(str(uu.id))is really helpful and also thanks for get() and filter(). i'll keep that in mind --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
