Re: Q about wizard.form.forms
Babatunde wrote: It is satisfied when the step contains a formset -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To post to this group, send email to django-users@googlegroups.com. Visit this group at http://groups.google.com/group/django-users?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
Q about wizard.form.forms
Hi,
Django’s documentation shows a sample form wizard template.
In that template there is a conditional tag: {% if wizard.form.forms %}{%
else %}
I can’t figure out when this condition will ever by met.
Does sombody have a clue?
Cheers and happy coding,
Rob
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problems getting the development version running on Leopard
I followed all instructions regarding the intallation of the development version of Django on Leopard. I’ve created the symbolic links but I keep getting two error messages: The first one trying to rum django-admin.py command not found The seccond trying to import django in the python shell No module named django.core I can see the symbolic links in finder and the show the content the should give. Some time ago I used exactly the same procedure on FreeBSD and all went fine. Do I have to something special to get this running on Leopard? Cheers, Rob -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: object and related object on one form (newforms)
Hi Thomas,
Thank you. I managed to get 2 forms in a view but I dont know how to
provide some 'default' data to some fields in the related form.
I'll give you some code:
class Infocard(models.Model):
from django.conf import settings
content_type = models.ForeignKey(ContentType, limit_choices_to =
{'id__in': settings.CARD_ITEMS})
object_id = models.PositiveIntegerField('item')
content_object = generic.GenericForeignKey()
photo = models.ForeignKey(Photo, related_name='infocards',
blank=True, null=True, unique=True)
text = models.TextField()
description = models.TextField(maxlength=300)
tag_field = TagField(verbose_name='Keyword(s)')
pubdate = models.DateTimeField(auto_now_add=True, editable=False)
moddate = models.DateTimeField(auto_now=True, editable=False)
publish = models.BooleanField(default=True)
author = models.ForeignKey(User, blank=True, null=True)
allow_comment = models.BooleanField()
class Sectie(models.Model):
viewname = models.CharField('url', maxlength=50, unique=True,
db_index=True, choices=settings.VIEW_CHOICES,)
name = models.CharField(maxlength=70, unique=True, db_index=True)
parent = models.ForeignKey('self', blank=True, null=True,
verbose_name="parent section", related_name='child_set',)
infocard = generic.GenericRelation(Infocard)
As you can see, I use an infocard to attach extended information to a
section. I can also attach cards to other kind of objects.
While adding, or editing a section I want to provide the form for an
infocard on the same page.
section = get_section_by_viewname_or_none(viewname)
SectionForm = forms.models.form_for_instance(section)
try:
infocard = section.infocard.all()[0:1].get()
InfocardForm = forms.models.form_for_instance(infocard)
except Infocard.DoesNotExist:
InfocardForm = forms.models.form_for_model(Infocard)
sform = SectionForm()
iform = InfokaartForm()
# and now I lost my way
In above example I expect a section to exist so I'll get it using a
custom function. For the given section I'll call a form.
If the section has a card it is fetched and a form is called.
Otherwise I call an empty form for it.
My question is about the last part, the empty infocard form. Doe you
know how to handle it a field value for the content_type and object_id
of the given section?
Rob
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object and related object on one form (newforms)
Can someone please explain to me how to create a form which provides not only the fields for the object but also the fiels for a related object (foreign key) and the best method to validate and save the data? Thanks in advance, Rob --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: pattern question
Hi Malcolm, SMART Thanks Rob --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
pattern question
I want to create a pattern to get one or more occurences of, let's
say, slug.
/bla/
/bla/blob/
/bla/blob/blebber/
/bla/blob/blebber/and_a_lot_more
etc.
I get it working for up to two slugs with
('^([^/]+)/([^/]+)/$', 'page'),
def page(request, *slugs):
slug_list = []
for slug in slugs:
slug_list.append(slug)
return render_to_response('platte_pagina.html', {
'slug_list' : slug_list,
}, context_instance=RequestContext(request))
I studied some regex tutorials but I still can't figure out how to fix
repetition in the pattern.
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Re: Custom validation for models in admin
Hi Mike, I have the same problem with my model. (Link below) Reading your "points to a .validate() on the model" raises the following question. Have you tried it? http://groups.google.com/group/django-users/browse_thread/thread/bd2b2c24f3879690 --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Please help with extra validation in admin
Addition: > This is my model and I use a custom save to prevent the creation of a > category with a parent_id which is the same a the current_id (child of > itself) When an error occurs an ugly error message apears so I tried to create a custom validator. Custom validator didn't work because of "no object_id to check upon". Creating a Custom manipulator doesn't seem to work in admin. Can someone show me a solution to get the validation done in admin? Thanks --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Is there a {% if_less_than %} template tag
Hi Greg: Just started using it yesterday :-) http://code.google.com/p/django-template-utils/ --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Please help with extra validation in admin
This is my model and I use a custom save to prevent the creation of a
category with a parent_id which is the same a the current_id (child of
itself)
class Category(models.Model):
name = models.CharField(maxlength=70, unique=True)
slug = models.SlugField(maxlength=50, unique=True,
prepopulate_from=('naam',))
parent = models.ForeignKey('self', blank=True, null=True,
limit_choices_to = {'parent__isnull': True})
def save(self):
try:
cur_id = int(self.id)
except:
cur_id = None
if cur_id and self.parent_id:
if int(self.parent_id) == cur_id:
raise validators.ValidationError("Same parent and child ")
super(Categorie, self).save()
I tried everything but I can't find a better approach than to use the
save method.
Custom validator: no object_id to check upon.
Custom manipulator: doesn't seem to work in admin.
So I cry for help on this one...
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Getting an object's meta value
For a class method I want to use the value of the Model>Meta>verbose_name. Can someone tell me how to get this value? Thanks, Rob --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
parent child question
class Category(models.Model):
name = models.CharField(maxlength=70)
parent = models.ForeignKey('self', blank=True, null=True,
limit_choices_to = {'parent__isnull': True})
I dont want to be able to select a parent which is actualy the
category currently edited.
I tried a custom validator but I dont have access to the category_id.
So I tried a custom manipulator but I couldn't fix it to work in admin
The only possible solution I have now is the raise an error in the
custom save method, which is a terrible ugly solution.
Does anyone have a pointer to a simple method to extend the automatic
manipulator???
Thanks,
Rob
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best alternative for subclassing
For a model I need subclassing which is work on progres. Falling back
to a OneToOne approach seems tricky because "the semantics of one-to-
one relationships will be changing soon". I'm wondering now what to
do. Here's my model in the OneToOne approach.
class Cropcat(models.Model):
parent = models.ForeignKey('self', blank=True, null=True,
related_name='child_set')
name = models.CharField(maxlength=70)
slug = models.SlugField(unique=True, prepopulate_from=('name',))
text = models.TextField()
class Cropdescription(models.Model):
name = models.CharField(maxlength=70)
history = models.TextField()
etc.
class Crop(models.Model):
cropcat = models.ForeignKey(Cropcat, blank=True, null=True,
limit_choices_to = {'parent__isnull': False})
cropdescription = models.OneToOneField(Cropdescription)
class Cropvar(models.Model):
parent = models.ForeignKey(Crop)
cropdescription = models.OneToOneField(Cropdescription)
As you can see, all common fiels for Crop and Cropvar live in
Cropdescription. Crop has an extra field for Cropcat. Cropvar has an
extra field for patent which is a Crop.
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site/section/app
I'm trying to implement a kind of model but I'm stuck. Maybe someone outhere can give me some help? This is what I'm thinking about: A site can have sections and a section can have apps. Also a site can have apps. For example: Site: gardening.org app: news sections: garden/kitchen garden apps: news/crop/tips kitchen apps: news/recipes/tips Site: canoein.org app: news sections: workshop/on the water workshop apps: news/tools/tips on the water apps: news/events/routes I know I can create two sites (projects) but I'm thinking about some database solution: One project and the abillity to add apps to sites and/or site-sections. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
menu application
For a given django site there are many urls.py's. The system also knows what apps are installed. Wouldn't it be nice to make an app that uses this knowledge and add some extra functionality to manage a website menu? At the moment I have no idea how to implement it but it should be something website editors can use to organize their menutree (order/ label/etc.) I have seen samples for platpages, generic relations... but none of these used the systems 'knowledge'. Maybe we can start a discussion about this? My thoughts: A system wide menu app for managing a kind of main menu. A menu functionality within the apps to manage the submenu's Making use of installed apps and urls.py's --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Unicode question
After moving to the latest version of Django one of the functions I
wrote fails to work.
I'll drop the code...
def year_cal(sectie, req_year = None, req_month=None):
cur_year= str(datetime.datetime.now().year)
cur_month= datetime.datetime.now().strftime("%b")
all_month_list = ['jan', 'feb', 'maa', 'apr', 'mei', 'jun', 'jul',
'aug', 'sep', 'okt', 'nov', 'dec']
month_list = []
if req_year is None:
req_year = cur_year
req_month= cur_month
else:
if int(req_year) > int(cur_year):
req_year = cur_year
if req_month is None:
req_month = trans_month('jan')
else:
req_month = trans_month(req_month)
prev_year_url = sectie.get_absolute_url() + str(int(req_year) - 1)
+ '/' + req_month
next_year_url = sectie.get_absolute_url() + str(int(req_year) + 1)
+ '/' + req_month
if int(req_year) == int(cur_year):
next_year_url = False
toggle_latest = False
for month in all_month_list:
if trans_month(month) == str.lower(req_month):
current = True
else:
current = False
if trans_month(month) == str.lower(cur_month):
url = sectie.get_absolute_url() + str(req_year) + '/' +
month
toggle_latest = True
else:
if(toggle_latest):
url = False
else:
url = sectie.get_absolute_url() + str(req_year) + '/' +
month
month_dict = {
'url' : url,
'caption' : month,
'current' : current,
}
month_list.append(month_dict)
else:
for month in all_month_list:
url = sectie.get_absolute_url() + str(req_year) + '/' + month
if trans_month(month) == str.lower(req_month):
current = True
else:
current = False
month_dict = {
'url' : url,
'caption' : month,
'current' : current,
}
month_list.append(month_dict)
return {'prev_year_url': prev_year_url, 'req_year': req_year,
'next_year_url': next_year_url, 'month_list': month_list }
register.inclusion_tag('year_cal.html')(year_cal)
The first error I get is about the line
str.lower(cur_month)
because str expects a str but gets a unicode.
Can some of you please give some simple tricks about moving from str
to unicode?
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ifchanged
Within a template I want to use the folowing construction.
{% for item in object_list reversed %}
{% ifchanged %}
{% if not forloop.first %}{% endif %}
{{ item.pub_date|
date:"F" }}
{% endifchanged %}
{{ item.title }}
{% if forloop.last %}{% endif %}
{% endfor %}
It will generate
2007
march
february
2006
december etc
I run in to problems because of the "if" statement within the
ifchanged tag.
Any ideas
Rob
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Re: Installation Question
Also beware that mod_php can give you session troubles on some systems. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
When to restart Apache?
When running Django using mod_python you have to restart Apache whenever you make changes to your code. Some changes don't require a restart so I wonder which changes trigger mod_python to reload and which don't. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: fiter for week
For those interested:
### INIT ###
import datetime, time
from django.http import Http404
def trans_month(month):
"""Vertaald de locale maandweergave naar globale"""
if month == "maa": month = "mar"
elif month == "mei": month = "may"
elif month == "okt": month = "oct"
return month
def get_week_range(year=None, week=None):
"""Geeft de begin en einddatum voor een optioneel meegegeven
week"""
if year is None:
year= str(datetime.datetime.now().year)
if week is None:
week= datetime.datetime.now().strftime("%W")
try:
start_date = datetime.date(*time.strptime(year + '-1-' + week,
'%Y-%w-%W')[:3])
except ValueError:
raise Http404
end_date = start_date + datetime.timedelta(days=7)
return [ start_date, end_date ]
def get_month_range(year=None, month=None):
"""Geeft de begin en einddatum voor een optioneel meegegeven
week"""
if year is None:
year= str(datetime.datetime.now().year)
if month is None:
month= datetime.datetime.now().strftime("%b")
else:
month = trans_month(month)
try:
date = datetime.date(*time.strptime(year+month, '%Y%b')[:3])
except ValueError:
raise Http404
first_day = date.replace(day=1)
if first_day.month == 12:
last_day = first_day.replace(year=first_day.year + 1, month=1)
else:
last_day = first_day.replace(month=first_day.month + 1)
return [ first_day, last_day ]
### VIEW ###
def sectie_intro(request, sectie_slug):
now = datetime.datetime.now()
sectie = get_sectie_by_slug_or_404(sectie_slug)
sectie_sjabloon = sectie.get_template()
sectie_periode = sectie.get_periode()
berichten_relevant = Bericht.objects.filter(sectie__id__exact =
sectie.id).exclude(publiceren=False).order_by('publicatiedatum')
if(sectie_periode == 'day'):
subtitel = "vandaag"
lookup_kwargs = {
'publicatiedatum__range' : (datetime.datetime.combine(now,
datetime.time.min), datetime.datetime.combine(now,
datetime.time.max)),
}
elif(sectie_periode == 'week'):
subtitel = "deze week"
range = get_week_range()
start_date = range[0]
end_date = range[1]
lookup_kwargs = {'publicatiedatum__range': (start_date,
end_date)}
if end_date >= now.date():
lookup_kwargs['publicatiedatum__lte'] = now
elif(sectie_periode == 'month'):
subtitel = "deze maand"
lookup_kwargs = {'publicatiedatum__month': now.month,
'publicatiedatum__year' : now.year}
else:
subtitel = "dit jaar"
lookup_kwargs['publicatiedatum__year'] = now.year
sectie_periodiek = sectie.periodiek_set.filter(**lookup_kwargs)
berichten_nieuw = berichten_relevant.filter(**lookup_kwargs)
return render_to_response(sectie_sjabloon, {
'sectie' : sectie,
'subtitel' : subtitel, ## voor in sjabloon achter de titel
'sectie_periodiek' : sectie_periodiek,
'berichten_nieuw' : berichten_nieuw,
'kruimelprefix' : '',
}, context_instance=RequestContext(request))
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Re: block.super
Sorry that isn't working (at least not in my template ) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Filtering foreign items in admin
For a several models I use a FK to photos. The drop down in admin to choose from lists all photos. Can this list be filtered so I can restrict the available photos for some models? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
fiter for week
Before re-inventing, I want to ask if there is some build-in for getting objects for [a || this] week. Something like: objects.filter(pubdate__week=now.week) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
block.super
On my base template I have a block, say X
One level down there is a section template (extending base)
overwriting block X
Further down there are templates (extending section). On these
templates I want to be able to get the original value of X.
I tried
{{ block.super }}
{{ block.super.super }}
{{ block.super.block.super }}
But none of these are doing the right thing. Is there a way to call
the parents parent blocks?
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Re: define odd, even in a loop
This is working great, thanks!! While on it, there are more filter like solutions for instance ADD. Is there also something like DIVIDE, MULTIPLY etc? Or can these be custom made? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
define odd, even in a loop
{% ifequal forloop.counter 1 %}odd{% endifequal %}
{% ifequal forloop.counter 3 %}odd{% endifequal %}
{% ifequal forloop.counter 5 %}odd{% endifequal %}
Is there a way to calculate this kind of thing, something like:
{% ifodd forloop.counter %}I am very odd{% endifodd %}
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slicing an loops
Kamil Wdowicz wrote regarding to handling loops:
{% for a in list|slice:"1" %}
{{ something }}
{% endfor %}
{% for a in list|slice:"1:3" %}
{{ something }}
{% endfor %}
{% for a in list|slice:"3:" %}
{{ something }}
{% endfor %}
What can be done to fill a table with a given list?
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ImageField Question
"Like FileField, but validates that the uploaded object is a valid
image. Has two extra optional arguments, height_field and width_field,
which, if set, will be auto-populated with the height and width of the
image each time a model instance is saved."
So I made this model:
class Foto(models.Model):
# import os, os.path, Image
PhotoFile = models.ImageField(upload_to= PH_FOLDER + "/%Y/%m/%d/",
height_field="H", width_field="W")
titel = models.CharField(maxlength=80)
I tried to get the dimension of the imageobject in my template using
{{ object.W }}
{{ object.width }}
{{ object.width_field }}
Without succes. After adding the fields to the model I got an error
because I had to fill the fields. No auto population!!
How does this work?
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Custom manipulator, default form?
For one of my models I need to do some extra validation. Because of what I want it isn't possible to just rely on a validator, I need a manipulator to get a request object. The manipulator only has to add an extra validator to one field. This validator validates using the database. No custom form is needed. The manipulator will be used within Django's admin. I searched and red and searched and red again but I couldn't find an answer on this one: How to add a custom manipulator, extending the default one, to a model using the default form? -- Robert Slotboom --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: admin > custom error message
Hi James et all, Because of what I want it isn't possible to just rely on a validator, I need a manipulator to get a request object. The manipulator only has to add an extra validator to one field. This validator validates using the database. No custom form is needed. The manipulator will be used within Django's admin. I searched and red and searched and red again but I couldn't find an answer on this one: How to add a custom manipulator, extending the default one, to a model using the default form? -- Robert Slotboom --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: sorting the results of a queryset
And of course a new kind of sorting function. Thank's to you :-) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: sorting the results of a queryset
Sorted works great but I have problems using it im my custom manager. I'm trying and trying but I can't figure out how to handle the following situation. class SortedTestcatManager(models.Manager): def get_query_set(self): QS = super(SortedTestcatManager, self).get_query_set() SQS = sorted(QS, key=self.model.get_absolute_url) return SQS >> sorted = Testcat.sorted_objects.all() >> sorted [] >> sorted.filte(title="nope") AttrbuteError: 'list' object has no attribute 'filter' Because I cant handle my prefered sorting in a query, I need to sort the result afterward. I could define some other functions in the custom manager to handle all and filter But this isn't a solution: allcats = Cat.sorted_objects.all() allcats.filter(var='val') << Isn't there a way to grap the result from the QS, sort it and place it back? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
sorting the results of a queryset
My model uses a single table parent-child relationship. I got the parent representation working but I isn't sorted right. So I tried to sort the list of objects, returned by objects.all() in the model class: def __cmp__(self, other): return cmp(self.get_absolute_url, other.get_absolute_url) In a function: cat_list = [] for cat in Category.objects.all(): cat_list.append(cat) cat_list.sort() No errors, no sorting??? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: admin > custom error message
Hmm,
I wrote this in my models.py. Errors rased are just for debugging.
class HasUniquePath(object):
def __init__(self, cat_obj, error_message=gettext_lazy("No unique
path!")):
self.cur_cat = cat_obj
self.error_message = error_message
self.always_test = True
def __call__(self, field_data, all_data):
if not field_data:
# check for unique foldername
folder = all_data.get('folder')
raise validators.ValidationError("Only a folder %s no path") %
folder
else:
parent = field_data
folder = all_data.get('folder')
raise validators.ValidationError("A folder %s and a path %s")
% (folder, parent)
class Testcat(models.Model):
title = models.CharField()
folder = models.SlugField(prepopulate_from=('title',))
parent = models.ForeignKey('self', blank=True, null=True,
related_name='child_set', validator_list=[HasUniquePath(self)])
Of course this wil not work because class "HasUniquePath" isn't a
manupulator.
I dont know however how to extend the object's manipulators.
Can yoy please give me a hint?
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Re: admin > custom error message
Thanks James,
I'll try this one
def IsUniqueForPath():
...
class Category(models.Model):
...
parent = models.ForeignKey('self', blank=True, null=True,
related_name='child_set', validator_list=[IsUniqueForPath])
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Re: admin > custom error message
Hi James, When I write a custom validator like: isValidCategory() I need a manipulator, validator and a form. Is there a way to use the 'current' ones and to expand these or do I need to create them from scratch? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
admin > custom error message
Given this save function in one of my models, I want to display an
error message in admin instead of a errorpage.
def save(self):
try:
cur_id = int(self.id)
except:
cur_id = 0
p_list = self._recurse_for_parents(self)
cats = Category.objects.filter(folder__exact=self.folder)
for cat in cats:
catp_list = cat._recurse_for_parents(cat)
if(cat.id != int(cur_id) and p_list == catp_list):
raise validators.ValidationError("This category already
exists within this path!")
super(Category, self).save()
Is there a way to do this?
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special characters in model
In my model I need a special character for the verbose_name_plural. I need an ë but admin gives a questionmark. What do I need to do? The folowing things don't work. verbose_name_plural = 'categoriën' verbose_name_plural = 'categoriën' verbose_name_plural = 'categori%sn' % chr(235) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
including a template in itself
I've a template which will be included. Within the template I want to
include it again if needed.
child_list.html
{% if categorie %}
{{ categorie.title }}
{% if categorie.child_set.all %}
{% for categorie in categorie.child_set.all %}
{% include "child_list.html" %}
{% endfor %}
{% endif %}
{% endif %}
When I do this Django crashes
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Re: custom manipulator in admin
Hello Aidas, Exactly. You answered your question yourself. Seems I'm on the right way then :-) Thanks for anwering, I'll give it a try. Regards, Rob --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: custom manipulator in admin
On 20 dec, 10:54, "patrick k." <[EMAIL PROTECTED]> wrote:
do it like in any other application:
custom view, custom template, change urls
Hi Patrick,
That's exactely what I wanted to know for one exception.
How to call the custom view when using admin.?
By overriding the 'default' call:
(r'^admin/mine/', include('mysite.admin.urls')),
(r'^admin/', include('django.contrib.admin.urls')),
Rob
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custom manipulator in admin
For a model I want to add a custom manipulator which can be used in the admin. With this manipulator I want to be able to add an extra formfield for displaying some additional data from a related object. There is no need for database storage. In this group I red that it isn't possible to extend manipulators in admin so the first question is if it is possible to replace the 'default' manipulator by providing a custom one? The next question is how to feed the form? From a custom template I suppose. Cheers, Rob --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Reverse ForeignKey lookups
Hi Cathy, Chris is right. User in entrystatus is a relation to User. This isnt't the same as a 'normal' field like Name or Title. Look at these: Entry.objects.filter(blog__id__exact=3) # Explicit form Entry.objects.filter(blog__id=3) # __exact is implied Entry.objects.filter(blog__pk=3) # __pk implies __id__exact This are simple relations from one table to another. Your filter is spanning three tables acualy Entry.objects.filter(entrystatus__user=3) << what about the user, his/her name, his/her e-mail? That's why you need to specify some extra argument like firstname, name, etc or of course id or pk. Thanks, I learned a lot myself by this question :-) Rob --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: generic relation | contenttypes issue
Please provide your model. Something is wrong with the tags attribute. Rob --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
extra field in edit_inline
This is my model and it works in Admin due to the efforts of Antoni.
(see link at the bottom)
What I want to do is to add a collumn to the inline editing list
representing some field from the related content_object. Is there an
easy way to do this?
class Category(models.Model):
name = models.CharField(maxlength=20)
parent = models.ForeignKey('self', blank=True, null=True,
related_name='child_set')
def __str__(self):
return self.name
def get_absolute_url(self):
return "./%i/" % self.id
def admin_links(self):
return 'edit | view | delete' % (self.id, self.get_absolute_url(),
self.id)
admin_links.allow_tags = True
admin_links.short_description = 'Actions'
class Admin:
pass
class CatItem(models.Model):
category = models.ForeignKey(Category, edit_inline=models.TABULAR,
num_in_admin=3)
content_type = models.ForeignKey(ContentType)
object_id = models.PositiveIntegerField(db_index=True, blank=True,
null=True,core=True,)
content_object = models.GenericForeignKey()
###
http://net-x.org/weblog/2006/nov/29/django-generic-relations-made-easier/
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Re: OneToOneField and edit_inline
Maybe we should create some kind of pressure group for this :-) I don't have any idea who can be consulted for this subject, do you? Cheers, Rob --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: urls question django_website
> I still can't figure out however how the flatfiles are loaded? Or maybe the homepage template from flatfiles is used, without using the content for the flatpage at all. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: urls question django_website
> The 'homepage' is a flatpage with an address of '/'. Hi Kwe, Great help!!! I still can't figure out however how the flatfiles are loaded? For example: http://code.djangoproject.com/browser/djangoproject.com/django_website/templates/flatfiles/homepage.html --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: OneToOneField and edit_inline
> I'd like to be able to edit Project and News separately with Content inline > instead. Do you know what i mean? Hi Dirk, I get the point though I think this will not work. I've tried similar things when creating a menu, where a menu "one to oned" to a poll item or blog entry. I gave up. In the meanwhile there is a discussion going on about generic relations, these will solve this kind of problems. Actualy generic relations already are available..but the do not (yet) work in the admin (p) Please have a look at djangoproject and search for generic relations. My guess is to sit and wait. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
urls question django_website
When I look at the urls.py file belonging to django_website I can't
figure out how the website handles the pattern for
www.djangoproject.com/
The only option seems to be the included flatpages.urls but this one
needs a pattern for an url.
Does anybody have a clue?
Here is the code:
urlpatterns = patterns('',
(r'^weblog/', include('django_website.apps.blog.urls')),
(r'^documentation/', include('django_website.apps.docs.urls')),
(r'^comments/$', 'django.views.generic.list_detail.object_list',
comments_info_dict),
(r'^comments/', include('django.contrib.comments.urls.comments')),
(r'^community/$', 'django.views.generic.list_detail.object_list',
aggregator_info_dict),
(r'^rss/(?P.*)/$', 'django.contrib.syndication.views.feed',
{'feed_dict': feeds}),
(r'^password_reset/',
include('django.conf.urls.admin_password_reset')),
(r'^r/', include('django.conf.urls.shortcut')),
(r'^sitemap.xml$', cache_page(sitemap_views.sitemap, 60 * 60 * 6),
{'sitemaps': sitemaps}),
(r'^admin/', include('django.contrib.admin.urls')),
(r'', include('django.contrib.flatpages.urls')),
)
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Re: Would Django be a good framework for developing and engineering/science application
> I guess the next thing for me to do is to spend alot of > time with the documentation and built a couple of simple apps/tutorials > to flush out my understanding of how Django will work. > Hi Thomas, And don't forget to look at the http://www.djangobook.com/ Rob --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Why does Django think my browser isn't accepting cookies?
Try to delete your cookies. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: OneToOneField and edit_inline
Hi Dirk,
I think it's the other way around, try this
class Content(models.Model):
title = models.CharField('Title', maxlength=255, core=True)
body = models.TextField('Body text')
class Admin:
fields = (
(None, {'fields': ('title','body',)}),
)
list_display = ('title')
list_filter = ['title'] ## optional
search_fields = ['title'] ## optional
date_hierarchy = 'title' ## optional
pass
class Project(models.Model):
content = models.OneToOneField(Content,
edit_inline=models.TABULAR, num_in_admin=1, core=True,
related_name='project_content')
subtitle = models.CharField('Subtitle', maxlength=255, core=True)
def __str__(self):
return self.Subtitle
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HttpResponseRedirect
For my project I created a templatetag which handles login, logout, get
profile etc. This way I can show a login/out box on every page by
including the tag in the main template.
There is one problem.
After logging out I want to redirect the user so the cookies etc, are
gone.
This is what I did (without success) because the result is passed over
to the template I suppose
### snippet ###
if current_user.is_authenticated():
if current_action == "logout":
try:
del request.session['member_id']
except KeyError:
pass
logout(request)
return HttpResponseRedirect("http://www.google.com";) << just
to test
elif current_action == "get_profile":
.
elif current_action == "change_password":
.
### end snip ###
Is there a way to pass the command to the correct handler???
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Re: help with tagging app
> tagging app from Luke Plant > zyons > the tagging app that jay parlar developed It seems that more and more tagging apps appear while using generic relations in admin will be available in a future Django. The last few days I've been strugling to create a menusystem. A kind of tag system but using a one to one relation. The model is as follows: Menuitem caption parent (self may be null) linked object The model and the idea is really very very simple but implementing it isn't. Should I wait till Django does support the generic relation in admin? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: GenericForeignKey
> paulh, take a look at > thishttp://net-x.org/weblog/2006/nov/29/django-generic-relations-made-eas... Hi Antoni, Seems interesting but the code isn't yet available I suppose... Rob --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: help with tagging app
> >That's easy. Hi Timm, Okay, this is a very simple example :-) But Luke Plant's Tagging App modell is realy a bit more comple. See>> http://groups-beta.google.com/group/django-users/browse_frm/thread/a7cbd4fd843583be/5ef4a59b78dbb2e1?lnk=gst&rnum=1&hl=nl#5ef4a59b78dbb2e1 --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: alternatives to edit_inline
Hi Milan, > Is there a workaround for that? Sorry I don't know. >I'll write my own views. Maybe you can expand the admin using your own views. Take a look at the next app for some ideas: http://trac.dedhost-sil-076.sil.at/trac/filebrowser/wiki Success. Rob --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: alternatives to edit_inline
Hi Milan, > Is there a workaround for that? Sorry I don't know. >I'll write my own views. Maybe you can expand the admin using your own views. Take a look at the next app for some ideas: http://trac.dedhost-sil-076.sil.at/trac/filebrowser/wiki Success. Rob --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: alternatives to edit_inline
Maybe this may be of any help. In the model you can add adminlinks like
this:
class Admin:
fields = (
)
list_display = ('name', 'admin_links')
def admin_links(self):
return 'edit | view | delete' % (self.id, self.get_absolute_url(),
self.id)
admin_links.allow_tags = True
admin_links.short_description = 'Actions'
Mind the indentation :-)
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help with tagging app
I installed Luke Plant's Tagging App and started reading the README file and the comments provided in the source. Compared to the marvelous Django Book and -tutorial this reading isn't very funny :-) Has someone a simple example for how to include a tag in another model, say Poll or Article? And now I'm on it: can related tags for a given model be used in the admin app? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: changing values just before saving
> Your solution seems to be some misunderstanding :) > If you set a foreign key to ContentType, then it already gets the > choices from the relation. Dear Aidas, I know, I know. The point is that I want to be able to use the damn generic relation in admin. I abuse the given field to collect real content items (poll, page etc) in the val:val form. With the selected value I want to set the appropriate fields using split. This way it may be possible to create menuitems for the various content. Cheers, Rob --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
changing values just before saving
In a model I feed a contenttype form field some initial data to choose
from.
class MenuItem(models.Model):
CONTENT_TYPE_CHOICES = tuple(get_available_content())
content_type = models.ForeignKey(ContentType,
choices=CONTENT_TYPE_CHOICES)
The data is provided using the folowing function which returns a tuple
for every stored (in this case) Poll in the form of 13:xxx where xxx is
the poll_id. Just before saving the data I split the two parts in
content_type_id and content_id. Then I want to hand them over to the
corresponding values. This way it must be possible to add some kind of
menu_app to django which works within the admin interface.
def get_available_content():
available_content_list = [('13','testpoll')]
from mysite.polls.models import Poll
polls_list = Poll.objects.all().order_by('-question')
for poll in polls_list:
key = '13:%s' % poll.id
caption = poll.question
poll_tup = ( key, caption )
available_content_list.append(poll_tup)
return available_content_list
The only thing I can't get working is setting the new value befor
saving
content_type_id, object_id = self.content_type_id.split(':', 1)
self.content_type.id = int(content_type_id)
self.object_id = int(object_id)
Maybe someone has an idea???
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Re: Cannot resolve keyword 'caption' into field
On 10 dec, 17:42, "[EMAIL PROTECTED]" <[EMAIL PROTECTED]> wrote: > What is the error you are getting? It's the 'subject' Cannot resolve keyword 'caption' into field --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
model problem "matching query does not exist"
After solving a problem described at:
http://groups-beta.google.com/group/django-users/browse_frm/thread/b453f0c91e29cc04?hl=nl
I continued developping my model. Unfortunately a new problem arose.
Given the following model, I get an error message in admin after
successfully saving an article and then selecting it.
MenuItem matching query does not exist.
The model describes an article 1to1 to menuitem
and a menuitem Mt1 to itself.
This way I try to get some kind of menustructure.
What causes the problem?
# model #
from django.db import models
from django.core import validators
class Article(models.Model):
headline = models.CharField(maxlength=200)
body = models.TextField()
art_image = models.CharField(maxlength=200, help_text="FileBrowser:
/", blank=True, null=True)
pub_date = models.DateTimeField('date published')
published = models.BooleanField()
def __str__(self):
return self.headline
class Admin:
fields = (
(None, {'fields': ('headline','body','art_image')}),
('Publication information', {'fields':
('pub_date','published'), 'classes': 'collapse'}),
)
date_hierarchy = 'pub_date'
list_filter = ['pub_date']
search_fields = ['headine']
js = (
'js/tiny_mce/tiny_mce.js',
'js/textareas.js',
'js/AddFileBrowser.js',
)
class MenuItem (models.Model):
article = models.OneToOneField(Article, edit_inline=models.TABULAR,
num_in_admin=1)
caption = models.CharField(maxlength=40, db_index=True, core=True)
parent = models.ForeignKey('self', blank=True, null=True,
related_name='child', core=True)
def __str__(self):
return self.caption
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Re: Cannot resolve keyword 'caption' into field
After many many trail and error I maybe found a 'bug'.
I simplefied the above model till it worked again. Then I added the
next field option and the error arose.
"unique=True" in MenuItem > name
Complete simplefied model with error:
###
from django.db import models
class Article(models.Model):
headline = models.CharField(maxlength=200)
body = models.TextField()
pub_date = models.DateTimeField('date published')
published = models.BooleanField()
def __str__(self):
return self.headline
class Admin:
pass
class MenuItem (models.Model):
article = models.OneToOneField(Article, edit_inline=models.TABULAR,
num_in_admin=1)
naam = models.CharField(maxlength=200, unique=True, core=True)
def __str__(self):
return self.caption
replace
naam = models.CharField(maxlength=200, unique=True, core=True)
with
naam = models.CharField(maxlength=200, core=True)
and it works again.
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Cannot resolve keyword 'caption' into field
I get this error in admin when saving a new article.
Can someone please help me?
Complete model...
from django.db import models
from django.core import validators
class Article(models.Model):
pub_date = models.DateTimeField('date published')
published = models.BooleanField()
headline = models.CharField(maxlength=200)
article = models.TextField()
art_image = models.CharField(maxlength=200, help_text="FileBrowser:
/", blank=True, null=True)
# reporter = models.ForeignKey(Reporter)
def __str__(self):
return self.headline
class Admin:
fields = (
(None, {'fields': ('headline','article','art_image',)}),
('Publication information', {'fields':
('pub_date','published'), 'classes': 'collapse'}),
)
date_hierarchy = 'pub_date'
list_filter = ['pub_date']
search_fields = ['headine']
js = (
'js/tiny_mce/tiny_mce.js',
'js/textareas.js',
'js/AddFileBrowser.js',
)
class MenuItem (models.Model):
article = models.OneToOneField(Article, edit_inline=models.TABULAR,
num_in_admin=1)
caption = models.CharField(maxlength=40, unique=True, db_index=True,
core=True)
parent = models.ForeignKey('self', blank=True, null=True,
related_name='child_set', core=True)
def __str__(self):
p_list = self._recurse_for_parents(self)
p_list.append(self.caption)
return self.get_separator().join(p_list)
def _recurse_for_parents(self, cat_obj):
p_list = []
if cat_obj.parent_id:
p = cat_obj.parent
p_list.append(p.caption)
more = self._recurse_for_parents(p)
p_list.extend(more)
if cat_obj == self and p_list:
p_list.reverse()
return p_list
def get_separator(self):
return ' :: '
def _parents_repr(self):
p_list = self._recurse_for_parents(self)
return self.get_separator().join(p_list)
_parents_repr.short_description = "Item parents"
def save(self):
p_list = self._recurse_for_parents(self)
if self.caption in p_list:
raise validators.ValidationError("U kunt geen menuiten in
zichzelf opslaan!")
super(MenuItem, self).save()
"""
class Admin:
list_display = ('caption', '_parents_repr')
pass
"""
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model field question
For a model I have defined two table fields. To fill those fields in admin I want to provide an extra dropdown field. Is it possible to add an extra field to the model without creating a corresponding database field? The use: field1 = content_type_id field2 = content_item_id Extra dropdown field = "id1 id2", "id1 id2","id1 id2","id1 id2", Befor saving I grap the values using split. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
cursor.fetchall() attribute error
In a models.py I have created the folowing function. Top level, not in
a class.
def get_unvoted_polls_for_voter_ip(ip):
from django.db import connection
cursor = connection.cursor()
sql = """SELECT polls_poll.* FROM polls_poll
LEFT OUTER JOIN polls_vote ON polls_poll.id = polls_vote.poll_id
WHERE polls_vote.voter_ip <> '%s' OR polls_vote.voter_ip IS
NULL;""" % ip
cursor.execute(sql)
return [Poll.__class__(*row) for row in cursor.fetchall()]
This is the Poll object
class Poll(models.Model):
question = models.CharField('vraag', maxlength=200)
pub_date = models.DateTimeField('publicatie datum')
I've tested the function using a "bare" list as result.
Trying to store the resulting data in poll entities using the above
construction raised an error:
'datetime.datetime' object has no attribute 'pop'.
Can someone tell me how to solve this?
### DEBUG SNIPPET ###
/usr/local/lib/python2.4/site-packages/Django-0.95-py2.4.egg/django/db/models/base.py
in __new__
"Metaclass for all models"
def __new__(cls, name, bases, attrs):
# If this isn't a subclass of Model, don't do anything special.
if not bases or bases == (object,):
return type.__new__(cls, name, bases, attrs)
# Create the class.
new_class = type.__new__(cls, name, bases, {'__module__':
attrs.pop('__module__')}) ...
new_class.add_to_class('_meta', Options(attrs.pop('Meta',
None)))
new_class.add_to_class('DoesNotExist',
types.ClassType('DoesNotExist', (ObjectDoesNotExist,), {}))
# Build complete list of parents
for base in bases:
# TODO: Checking for the presence of '_meta' is hackish.
▼ Local vars
VariableValue
attrs datetime.datetime(2006, 10, 23, 12, 4)
bases 'Wat is Django?'
cls
name2
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cursor.fetchall() attribute error
In a models.py I have created the folowing function. Top level, not in
a class.
def get_unvoted_polls_for_voter_ip(ip):
from django.db import connection
cursor = connection.cursor()
sql = """SELECT polls_poll.* FROM polls_poll
LEFT OUTER JOIN polls_vote ON polls_poll.id = polls_vote.poll_id
WHERE polls_vote.voter_ip <> '%s' OR polls_vote.voter_ip IS
NULL;""" % ip
cursor.execute(sql)
return [Poll.__class__(*row) for row in cursor.fetchall()]
This is the Poll object
class Poll(models.Model):
question = models.CharField('vraag', maxlength=200)
pub_date = models.DateTimeField('publicatie datum')
I've tested the function using a "bare" list as result.
Trying to store the resulting data in poll entities using the above
construction raised an error:
'datetime.datetime' object has no attribute 'pop'.
Can someone tell me how to solve this?
### DEBUG SNIPPET ###
/usr/local/lib/python2.4/site-packages/Django-0.95-py2.4.egg/django/db/models/base.py
in __new__
"Metaclass for all models"
def __new__(cls, name, bases, attrs):
# If this isn't a subclass of Model, don't do anything special.
if not bases or bases == (object,):
return type.__new__(cls, name, bases, attrs)
# Create the class.
new_class = type.__new__(cls, name, bases, {'__module__':
attrs.pop('__module__')}) ...
new_class.add_to_class('_meta', Options(attrs.pop('Meta',
None)))
new_class.add_to_class('DoesNotExist',
types.ClassType('DoesNotExist', (ObjectDoesNotExist,), {}))
# Build complete list of parents
for base in bases:
# TODO: Checking for the presence of '_meta' is hackish.
▼ Local vars
VariableValue
attrs datetime.datetime(2006, 10, 23, 12, 4)
bases 'Wat is Django?'
cls
name2
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Re: model question
Thank you guys. Without a poll_id in vote it isn't possible to check integrity in the database so I keep it :-) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: model question
Rob Hudson schreef: > I'd kind of think that in Vote you don't need the poll FK, just the > choice since the choice then maps to a particular poll. But how do I prevent a voter to vote more than once on a poll? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
model question
I'm trying to get a very simple relationship to work but I can't figure
ou how to do this in Django.
This is what I want.
Poll ---<< question
Poll ---<< vote
A user can vote a poll just once. I check this using a function which
gets the remote ip.
This is the models.py snippet
class Poll(models.Model):
question = models.CharField('vraag', maxlength=200)
pub_date = models.DateTimeField('publicatie datum')
def has_remote_addr_voted(self, ip):
result = False
if (self.vote_set.filter(voter_ip = ip).count() > 0):
result = True
return result
class Admin:
fields = (
(None, {'fields': ('question','pub_date',)}),
)
pass
class Choice(models.Model):
poll = models.ForeignKey(Poll, edit_inline=models.TABULAR,
num_in_admin=3)
choice = models.CharField(maxlength=200, core=True)
votes = models.IntegerField(core=True)
class Vote(models.Model):
poll = models.ForeignKey(Poll, edit_inline=models.TABULAR,
num_in_admin=3)
voter_ip = models.IPAddressField(core=True)
choice = models.ForeignKey(Choice, edit_inline=models.TABULAR,
num_in_admin=3)
class Meta:
unique_together = (("poll", "voter_ip"),)
The model is correct but the problem occurs in admin.
Editing a poll you get the related choices and votes. For a vote you
can select a choice from a list which contains all choices, not the
choices for the current poll.
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Re: What's the best way to make a custom publishing workflow?
Hi Kevn, May be of interest: http://www.b-list.org/weblog/2006/09/02/django-tips-user-registration http://www.b-list.org/weblog/2006/06/06/django-tips-extending-user-model --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
setting and using an object variable without using a field
To be able to control a template output based on a current remote
address, I created this model.
class Poll(models.Model):
question = models.CharField('vraag', maxlength=200)
pub_date = models.DateTimeField('publicatie datum')
voted_by_remote_addr = False
def set_voted_by_remote_addr(self, ip):
if (self.vote_set.filter(voter_ip = ip).count() > 0):
self.voted_by_remote_addr = True
I use the model in a view like this:
def list(request):
poll_list = Poll.objects.all().order_by('-pub_date')
for poll in poll_list:
poll.set_voted_by_remote_addr(request.META["REMOTE_ADDR"])
return render_to_response('polls_list.html', {
'object_list': poll_list,
'title': 'List of polls',
}, context_instance=RequestContext(request))
The template contains:
{% if object_list %}
{% for poll in object_list %}
{{ poll.question
}} {{ poll.voted_by_remote_addr }}
{% endfor %}
{% else %}
No polls are available.
{% endif %}
And. it's working.
Just one question: Is this the right way to do such things?
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Re: custom or build in register/login/logout
Sorry, I should have searched smarter before posting. Found the anwers at http://www.b-list.org/weblog/2006/09/02/django-tips-user-registration --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users -~--~~~~--~~--~--~---
custom or build in register/login/logout
For a project I need to record customer information such as name, address etc. I doubt about the best approach to create this functionality. Shall I use the user class in contrib.auth and extend it or shall I create an independent customer class/app? The first approach serves me the default authentication. The second brings me an app wich I can comprehend. Or, can I use the second and still use the basic authentication? Please advise.. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users -~--~~~~--~~--~--~---
Re: include tag and urls
> Can you give some more details, please? I cannot puzzle out what you are
> currently doing here.
Hello Malcolm,
It's about in the template.
Here come the details...
### mysite/polls/templatetags/poll_tags.py
from django import template
from mysite.polls.models import Poll
register = template.Library()
def show_latest_polls(count=5):
latest_polls = Poll.objects.all().order_by('-pub_date')[:count]
return {'latest_polls' : latest_polls}
register.inclusion_tag('latest_polls.html')(show_latest_polls)
### mysite/polls/templates/latest_polls.html
{% for poll in latest_polls %}
{{ poll.question }}
{% endfor %}
### mysite/templates/index.html
...
{% load poll_tags %}
{% show_latest_polls 10 %}
...
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include tag and urls
Using an inlude tag on my homepage to get a list of current polls
requires a template. This template lists the polls and provides a link
for the details. I need to give an url including the modulename:
(a href="/polls/5")
I don't like this approach so I want to ask if it is possible to use
an object variable to get the right prefix?
Futhermore, I also want to keep the tag templates within the
templatetags directory. I tried this using
register.inclusion_tag('/dirto/template.html')(...) but that doesn't
work out. Is it possible (without the use of settings.py)?
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Re: Template question
Thank you, I'll have a look. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users -~--~~~~--~~--~--~---
Re: Template question
Hi Malcolm,
{{forloop.counter|add:offset}} works fine.
Thanks,
Rob
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Re: Breaking up long lists
I don't know. I'll have a look. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users -~--~~~~--~~--~--~---
Breaking up long lists
I've added an example view and template at: http://code.djangoproject.com/wiki/CookBookViews Good luck. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users -~--~~~~--~~--~--~---
Template question
Is it possible to add some initial value to a forloop.counter?
This would be handy when using limit and offset.
More general, is is possible to use template vars as values for
calculations:
{{ var1 }} + {{ var 2 }}
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Re: stringformat in template
Dear Geert,
I entered {{ total_amount|stringformat:".2f" }} and it realy worked :-)
Actualy I red the STRINGFORMAT docu but I didn't get the clue. Now I
do...
Thanks.
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Getting an object' content_type_id
Is there a way to get an object's content_type_id? I need it to store an object's id and content_type_id in another table. Currently I solved this by using an sql-statement but maybe there is some 'hidden' property or function like: self.content_type or self.get_content_type --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users -~--~~~~--~~--~--~---
stringformat in template
I tried to use stringformat within a template but without success. This is what I want in 'normal' syntax': return "%.2f" % total_amount It returns a two decimal value. But how to use it in the template??? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users -~--~~~~--~~--~--~---
getting a model's content_type_id
Is there a way to get a model's content_type_id? I need it to store an object's id and content_type_id in another table. Currently I solved this by using an sql-statement but maybe there is some 'hidden' property or function like: self.content_type or self.get_content_type --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users -~--~~~~--~~--~--~---
Re: Creating a menu structure
To create hierarchical menu's, the first thing I thought about was some kind of parent child relation on just one table but then you have to submit many queries. A better approach wil be the Modified Preorder Tree Traversal. See: http://www.sitepoint.com/print/hierarchical-data-database On the Django site you can find an example at: http://code.djangoproject.com/wiki/ModifiedPreorderTreeTraversal I'm still experimenting but I use one table to store some kind of collection (id, content_type, object_id) so I can relate to different types of content (tables) After saving content -say a book- I run _post_save to add the book to the collection. For the menu itself I create a table, containing the collection_id and the fields for ordering (lft, rgt) This is just a startingpoint but I hope it will help you on the run. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users -~--~~~~--~~--~--~---
admin > site
Hi guys, Can someone please tell me what can be done with the site feature in admin? And now I'm on it: from the ducumentation I understand that it is possible to use admin interface parts in your own apps by calling classes. Am I correct? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users -~--~~~~--~~--~--~---
