Re: [Django] Error occured while saving a form created through model formset factory
Hi,
Plz check about:
HttpResponseRedirect('/gspapp/ModelGSPRequestList')
On Sat, Feb 15, 2020, 13:15 Dilipkumar Noone wrote:
> Hi Maninder,
>
> This error seems because i used choice field which actually use names as
> values but django expects the id.
>
> As Django automatically creates a ModelChoicefield for a Foreign Key which
> use the correct values,i modified the code as below in forms.py.
>
> I have a requirement to populate only unique values for registered_model
> from the values returned from ModelRegister .
>
> I modified the code as below and now i am able to get the unique values .
>
>
>
> def unique_values():
> return
> [("","---")]+list(ModelRegister.objects.values_list('model_name','model_name').order_by('model_name').distinct())
>
> registered_model = forms.ChoiceField(required=False,choices=unique_values)
>
>
>
> registered_model =
> forms.ModelChoiceField(queryset=ModelRegister.objects.values_list('model_name',flat=True).order_by('model_name').distinct())
>
>
>
>
> Error is resolved now.
>
>
>
>But once i fill all the values in formset and submit the form.
>
>Not able to redirect to List View. Even if i click on submit button it
>stays on the same page.Anything needs to be taken care during POST request
>to save the created model formsets in the database.in the
>-
>
>
>-
>
>*def create_model_gsp_request_form(request,id=None):
>print("Inside create_model_gsp_request_form")
>template_name = "ModelGSPRequest.html"
>heading_message = "ModelGSPRequest"
>
>if id:
>action = 'edit'
>model = get_object_or_404(ModelGSPRequest, pk=id)
>else:
>action = 'submit'
>model = ModelGSPRequest()
>
>message = ""
>
>if request.method == 'GET':
>print("Get request in create_model_gsp_request_form")
># we don't want to display the already saved model instances
>#formset =
> ModelGSPRequestFormSet(queryset=ModelGSPRequest.objects.none(),instance=model)
>formset = ModelGSPRequestFormSet()
>#registered_model_details = serializers.serialize("json",
> ModelRegister.objects.all())
>#print("registered_model_details:", registered_model_details)
>elif request.method == 'POST':
>print("post request in create_model_gsp_request_form")
>formset = ModelGSPRequestFormSet(request.POST,request.FILES)
>if formset.is_valid():
>for form in formset:
># only save if name is present
>#if form.cleaned_data.get('name'):
>
>new_form = form.save(commit=False)
>new_form.model_gsp_requester = request.user.username
>new_form.save()
>formset.save_m2m()
>#return redirect('ModelGSPRequestList')
>return HttpResponseRedirect('/gspapp/ModelGSPRequestList')
>return render(request, template_name, {
>'formset': formset,
>'heading': heading_message,
>#'registered_model_data': registered_model_details,
>'action':action
>})*
>
>-
>
>
>
>
> Regards,
> N.Dilip Kumar.
>
>
> On Monday, February 10, 2020 at 12:11:42 AM UTC+5:30, Dilipkumar Noone
> wrote:
>>
>> I am a Django learner.
>>
>> 1.I have a requirement to create the multiple forms in a single page for
>> a model.
>> 2.So i created the formset using modelformset_factory.
>> 3.I have 2 models.
>> a)ModelRegister b)ModelGSPRequest. 4.ModelGSPRequest has a field named
>> registered_model which is a foreignKey to ModelRegister. 5.But after i
>> input all the fields for a modelformset and click on submit to save. I am
>> facing below error with the foreign key field.
>>
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>
> .
>
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Re: [Django] Error occured while saving a form created through model formset factory
Hi Maninder,
This error seems because i used choice field which actually use names as
values but django expects the id.
As Django automatically creates a ModelChoicefield for a Foreign Key which
use the correct values,i modified the code as below in forms.py.
I have a requirement to populate only unique values for registered_model
from the values returned from ModelRegister .
I modified the code as below and now i am able to get the unique values .
def unique_values():
return
[("","---")]+list(ModelRegister.objects.values_list('model_name','model_name').order_by('model_name').distinct())
registered_model = forms.ChoiceField(required=False,choices=unique_values)
registered_model =
forms.ModelChoiceField(queryset=ModelRegister.objects.values_list('model_name',flat=True).order_by('model_name').distinct())
Error is resolved now.
But once i fill all the values in formset and submit the form.
Not able to redirect to List View. Even if i click on submit button it
stays on the same page.Anything needs to be taken care during POST request
to save the created model formsets in the database.in the
-
-
*def create_model_gsp_request_form(request,id=None):
print("Inside create_model_gsp_request_form")
template_name = "ModelGSPRequest.html"
heading_message = "ModelGSPRequest"
if id:
action = 'edit'
model = get_object_or_404(ModelGSPRequest, pk=id)
else:
action = 'submit'
model = ModelGSPRequest()
message = ""
if request.method == 'GET':
print("Get request in create_model_gsp_request_form")
# we don't want to display the already saved model instances
#formset =
ModelGSPRequestFormSet(queryset=ModelGSPRequest.objects.none(),instance=model)
formset = ModelGSPRequestFormSet()
#registered_model_details = serializers.serialize("json",
ModelRegister.objects.all())
#print("registered_model_details:", registered_model_details)
elif request.method == 'POST':
print("post request in create_model_gsp_request_form")
formset = ModelGSPRequestFormSet(request.POST,request.FILES)
if formset.is_valid():
for form in formset:
# only save if name is present
#if form.cleaned_data.get('name'):
new_form = form.save(commit=False)
new_form.model_gsp_requester = request.user.username
new_form.save()
formset.save_m2m()
#return redirect('ModelGSPRequestList')
return HttpResponseRedirect('/gspapp/ModelGSPRequestList')
return render(request, template_name, {
'formset': formset,
'heading': heading_message,
#'registered_model_data': registered_model_details,
'action':action
})*
-
Regards,
N.Dilip Kumar.
On Monday, February 10, 2020 at 12:11:42 AM UTC+5:30, Dilipkumar Noone
wrote:
>
> I am a Django learner.
>
> 1.I have a requirement to create the multiple forms in a single page for a
> model.
> 2.So i created the formset using modelformset_factory.
> 3.I have 2 models.
> a)ModelRegister b)ModelGSPRequest. 4.ModelGSPRequest has a field named
> registered_model which is a foreignKey to ModelRegister. 5.But after i
> input all the fields for a modelformset and click on submit to save. I am
> facing below error with the foreign key field.
>
--
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https://groups.google.com/d/msgid/django-users/9d67053f-c0e1-4f68-b875-7886b62ea5fd%40googlegroups.com.
[Django] Error occured while saving a form created through model formset factory
I am a Django learner. 1.I have a requirement to create the multiple forms in a single page for a model. 2.So i created the formset using modelformset_factory. 3.I have 2 models. a)ModelRegister b)ModelGSPRequest. 4.ModelGSPRequest has a field named registered_model which is a foreignKey to ModelRegister. 5.But after i input all the fields for a modelformset and click on submit to save. I am facing below error with the foreign key field. -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/84953e1b-a2e0-490e-a646-2fade661e6de%40googlegroups.com.
