Re: Application design question
Thanks Alex, that was exactly what I was looking for. On Jan 31, 8:06 pm, "alex.gay...@gmail.com" wrote: > On Jan 31, 8:04 pm, eddie wrote: > > > > > Hey guys & girls, > > > I've just started playing with django, and am not sure of the best way > > to do something. > > > I've got a basic site, where page a displays model a, page b displays > > model b, etc. Every model has it's own view function and template, > > all extending a base template with a header, footer, etc. In every > > page's footer, I would like to add a parsed RSS feed (just an ul of > > links). > > > I don't want to repeat code, so I don't feel like calculating it and > > sending it to every render_to_response that I've got (I'll worry about > > caching later, by the way). So I wonder if there is a way that I > > could give every template access to this object without adding it to > > my views... though this seems like a kind of "global variable" type > > situation that I'm a little wary of too. > > > How would you proceed? > > > Thanks! > > -e > > Take a look at implementing a template context processor. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Application design question
On Jan 31, 8:04 pm, eddie wrote: > Hey guys & girls, > > I've just started playing with django, and am not sure of the best way > to do something. > > I've got a basic site, where page a displays model a, page b displays > model b, etc. Every model has it's own view function and template, > all extending a base template with a header, footer, etc. In every > page's footer, I would like to add a parsed RSS feed (just an ul of > links). > > I don't want to repeat code, so I don't feel like calculating it and > sending it to every render_to_response that I've got (I'll worry about > caching later, by the way). So I wonder if there is a way that I > could give every template access to this object without adding it to > my views... though this seems like a kind of "global variable" type > situation that I'm a little wary of too. > > How would you proceed? > > Thanks! > -e Take a look at implementing a template context processor. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Application design question
Hey guys & girls, I've just started playing with django, and am not sure of the best way to do something. I've got a basic site, where page a displays model a, page b displays model b, etc. Every model has it's own view function and template, all extending a base template with a header, footer, etc. In every page's footer, I would like to add a parsed RSS feed (just an ul of links). I don't want to repeat code, so I don't feel like calculating it and sending it to every render_to_response that I've got (I'll worry about caching later, by the way). So I wonder if there is a way that I could give every template access to this object without adding it to my views... though this seems like a kind of "global variable" type situation that I'm a little wary of too. How would you proceed? Thanks! -e --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
