Re: Django URL routing
Hi Roseman,
Your comment pointed me to the right direction.
I have finally cracked the mystery!
Thanks so much!
On Thursday, May 7, 2020 at 5:17:22 PM UTC+3, Ronald Kamulegeya wrote:
>
> Here is my attempt at creating unique path:
> Still i get page not found error. The index page is not opening too.
> urlpatterns = [
> path("tenants/", views.TenantsListView.as_view(), name="index"),
> path("tenants/details",views.TenantDetailView.as_view(),name="detail"
> ),
> path("tenants/add",views.createTenant, name='createTenant'),
> path("tenants/edit//",views.TenantUpdateView.as_view(), name=
> 'edit'),
> path("tenants/delete//",views.delete, name='delete'),
>
> ]
> urlpatterns = [
> path('', include('rentals.urls',namespace='rentals')),
> path('admin/', admin.site.urls),
>
> On Thursday, May 7, 2020 at 3:53:44 PM UTC+3, Ronald Kamulegeya wrote:
>>
>> Hello Roseman,
>> Please suggest how i can code the different Urls.
>>
>>
>> On Thursday, May 7, 2020 at 3:24:28 PM UTC+3, Daniel Roseman wrote:
>>>
>>> You have multiple URLs that are the same path. That can't work. One URL
>>> maps to one view.
>>> --
>>> DR.
>>>
>>> On Thursday, 7 May 2020 11:40:09 UTC+1, Ronald Kamulegeya wrote:
I am learning Django and progressing well but i am stuck on how to
configure the different urls to view functions.
I have gone through tutorials and URL routing seems pretty
straight forward but i cant make it work in my apps.
I am almost hitting a brick wall. I dont see anything wrong i have done.
What happens is that the index view and admin interface opens.
But connecting from the index view to other pages raises the 404 error.
[image: project-s.png]
I created a project TenancyMGt and added app rentals as shown above.
I have created several views in the module views.py Two are relevant
here:
def createTenant(request):
form = TenantsForm
context = {'form': form}
html_form = render_to_string('rentals/partial_tenant_create.html',
context,
request=request,
)
return JsonResponse({'html_form': html_form})class
TenantsListView(ListView):
model = Tenants
context_object_name = 'tenant_list'
template_name = 'rentals/tenants_list.html'
paginate_by = 5
def get_queryset(self):
return Tenants.objects.all()
Now i created a file urls.py under the app rentals:
from . import viewsfrom django.urls import path
app_name='rentals'
urlpatterns = [
path("", views.TenantsListView.as_view(), name="index"),
path("",views.TenantDetailView.as_view,name="detail"),
path("",views.createTenant, name='createTenant'),
path("/",views.TenantUpdateView.as_view, name='edit'),
path("/",views.delete, name='delete'),
]
under TenancyMgr/urls, i add the following:
from django.contrib import adminfrom django.urls import path,includefrom
rentals import views
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('rentals.urls')),
]
When i run the server, the index view opens successfully! From the index,
i want to open the createTenant view as below.
>>> data-url="{% url 'rentals:createTenant' %}>
New Tenant
When the button is clicked, i get the urls below:
http://127.0.0.1:8000/rentals/createTenant/
Then i get the response is 404,page not found error.
But this opens admin page:
http://127.0.0.1:8000/admin/
So far i have failed to crack the secret of how the Urls work. I have gone
through several tutorials and i see the same set up as mine.
I am requesting for guidance on how to crack the puzzle i.e make the other
urls work.
Ronald
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Re: Django URL routing
Here is my attempt at creating unique path:
Still i get page not found error. The index page is not opening too.
urlpatterns = [
path("tenants/", views.TenantsListView.as_view(), name="index"),
path("tenants/details",views.TenantDetailView.as_view(),name="detail"),
path("tenants/add",views.createTenant, name='createTenant'),
path("tenants/edit//",views.TenantUpdateView.as_view(), name=
'edit'),
path("tenants/delete//",views.delete, name='delete'),
]
urlpatterns = [
path('', include('rentals.urls',namespace='rentals')),
path('admin/', admin.site.urls),
On Thursday, May 7, 2020 at 3:53:44 PM UTC+3, Ronald Kamulegeya wrote:
>
> Hello Roseman,
> Please suggest how i can code the different Urls.
>
>
> On Thursday, May 7, 2020 at 3:24:28 PM UTC+3, Daniel Roseman wrote:
>>
>> You have multiple URLs that are the same path. That can't work. One URL
>> maps to one view.
>> --
>> DR.
>>
>> On Thursday, 7 May 2020 11:40:09 UTC+1, Ronald Kamulegeya wrote:
>>>
>>> I am learning Django and progressing well but i am stuck on how to
>>> configure the different urls to view functions.
>>> I have gone through tutorials and URL routing seems pretty
>>> straight forward but i cant make it work in my apps.
>>>
>>> I am almost hitting a brick wall. I dont see anything wrong i have done.
>>>
>>> What happens is that the index view and admin interface opens.
>>>
>>> But connecting from the index view to other pages raises the 404 error.
>>>
>>> [image: project-s.png]
>>> I created a project TenancyMGt and added app rentals as shown above.
>>> I have created several views in the module views.py Two are relevant
>>> here:
>>>
>>> def createTenant(request):
>>> form = TenantsForm
>>> context = {'form': form}
>>> html_form = render_to_string('rentals/partial_tenant_create.html',
>>> context,
>>> request=request,
>>> )
>>> return JsonResponse({'html_form': html_form})class
>>> TenantsListView(ListView):
>>> model = Tenants
>>> context_object_name = 'tenant_list'
>>> template_name = 'rentals/tenants_list.html'
>>> paginate_by = 5
>>> def get_queryset(self):
>>> return Tenants.objects.all()
>>>
>>> Now i created a file urls.py under the app rentals:
>>>
>>> from . import viewsfrom django.urls import path
>>> app_name='rentals'
>>> urlpatterns = [
>>> path("", views.TenantsListView.as_view(), name="index"),
>>> path("",views.TenantDetailView.as_view,name="detail"),
>>> path("",views.createTenant, name='createTenant'),
>>> path("/",views.TenantUpdateView.as_view, name='edit'),
>>> path("/",views.delete, name='delete'),
>>> ]
>>>
>>> under TenancyMgr/urls, i add the following:
>>>
>>> from django.contrib import adminfrom django.urls import path,includefrom
>>> rentals import views
>>>
>>> urlpatterns = [
>>> path('admin/', admin.site.urls),
>>> path('', include('rentals.urls')),
>>> ]
>>>
>>> When i run the server, the index view opens successfully! From the index, i
>>> want to open the createTenant view as below.
>>>
>>>
>>> New Tenant
>>>
>>>
>>> When the button is clicked, i get the urls below:
>>>
>>> http://127.0.0.1:8000/rentals/createTenant/
>>>
>>> Then i get the response is 404,page not found error.
>>>
>>> But this opens admin page:
>>>
>>> http://127.0.0.1:8000/admin/
>>>
>>> So far i have failed to crack the secret of how the Urls work. I have gone
>>> through several tutorials and i see the same set up as mine.
>>>
>>> I am requesting for guidance on how to crack the puzzle i.e make the other
>>> urls work.
>>>
>>> Ronald
>>>
>>>
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Re: Django URL routing
Hello Roseman,
Please suggest how i can code the different Urls.
On Thursday, May 7, 2020 at 3:24:28 PM UTC+3, Daniel Roseman wrote:
>
> You have multiple URLs that are the same path. That can't work. One URL
> maps to one view.
> --
> DR.
>
> On Thursday, 7 May 2020 11:40:09 UTC+1, Ronald Kamulegeya wrote:
>>
>> I am learning Django and progressing well but i am stuck on how to
>> configure the different urls to view functions.
>> I have gone through tutorials and URL routing seems pretty
>> straight forward but i cant make it work in my apps.
>>
>> I am almost hitting a brick wall. I dont see anything wrong i have done.
>>
>> What happens is that the index view and admin interface opens.
>>
>> But connecting from the index view to other pages raises the 404 error.
>>
>> [image: project-s.png]
>> I created a project TenancyMGt and added app rentals as shown above.
>> I have created several views in the module views.py Two are relevant here:
>>
>> def createTenant(request):
>> form = TenantsForm
>> context = {'form': form}
>> html_form = render_to_string('rentals/partial_tenant_create.html',
>> context,
>> request=request,
>> )
>> return JsonResponse({'html_form': html_form})class
>> TenantsListView(ListView):
>> model = Tenants
>> context_object_name = 'tenant_list'
>> template_name = 'rentals/tenants_list.html'
>> paginate_by = 5
>> def get_queryset(self):
>> return Tenants.objects.all()
>>
>> Now i created a file urls.py under the app rentals:
>>
>> from . import viewsfrom django.urls import path
>> app_name='rentals'
>> urlpatterns = [
>> path("", views.TenantsListView.as_view(), name="index"),
>> path("",views.TenantDetailView.as_view,name="detail"),
>> path("",views.createTenant, name='createTenant'),
>> path("/",views.TenantUpdateView.as_view, name='edit'),
>> path("/",views.delete, name='delete'),
>> ]
>>
>> under TenancyMgr/urls, i add the following:
>>
>> from django.contrib import adminfrom django.urls import path,includefrom
>> rentals import views
>>
>> urlpatterns = [
>> path('admin/', admin.site.urls),
>> path('', include('rentals.urls')),
>> ]
>>
>> When i run the server, the index view opens successfully! From the index, i
>> want to open the createTenant view as below.
>>
>>
>> New Tenant
>>
>>
>> When the button is clicked, i get the urls below:
>>
>> http://127.0.0.1:8000/rentals/createTenant/
>>
>> Then i get the response is 404,page not found error.
>>
>> But this opens admin page:
>>
>> http://127.0.0.1:8000/admin/
>>
>> So far i have failed to crack the secret of how the Urls work. I have gone
>> through several tutorials and i see the same set up as mine.
>>
>> I am requesting for guidance on how to crack the puzzle i.e make the other
>> urls work.
>>
>> Ronald
>>
>>
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Re: Django URL routing
Yaaahhh
On Thu, 7 May 2020, 15:24 Daniel Roseman, wrote:
> You have multiple URLs that are the same path. That can't work. One URL
> maps to one view.
> --
> DR.
>
> On Thursday, 7 May 2020 11:40:09 UTC+1, Ronald Kamulegeya wrote:
>>
>> I am learning Django and progressing well but i am stuck on how to
>> configure the different urls to view functions.
>> I have gone through tutorials and URL routing seems pretty
>> straight forward but i cant make it work in my apps.
>>
>> I am almost hitting a brick wall. I dont see anything wrong i have done.
>>
>> What happens is that the index view and admin interface opens.
>>
>> But connecting from the index view to other pages raises the 404 error.
>>
>> [image: project-s.png]
>> I created a project TenancyMGt and added app rentals as shown above.
>> I have created several views in the module views.py Two are relevant here:
>>
>> def createTenant(request):
>> form = TenantsForm
>> context = {'form': form}
>> html_form = render_to_string('rentals/partial_tenant_create.html',
>> context,
>> request=request,
>> )
>> return JsonResponse({'html_form': html_form})class
>> TenantsListView(ListView):
>> model = Tenants
>> context_object_name = 'tenant_list'
>> template_name = 'rentals/tenants_list.html'
>> paginate_by = 5
>> def get_queryset(self):
>> return Tenants.objects.all()
>>
>> Now i created a file urls.py under the app rentals:
>>
>> from . import viewsfrom django.urls import path
>> app_name='rentals'
>> urlpatterns = [
>> path("", views.TenantsListView.as_view(), name="index"),
>> path("",views.TenantDetailView.as_view,name="detail"),
>> path("",views.createTenant, name='createTenant'),
>> path("/",views.TenantUpdateView.as_view, name='edit'),
>> path("/",views.delete, name='delete'),
>> ]
>>
>> under TenancyMgr/urls, i add the following:
>>
>> from django.contrib import adminfrom django.urls import path,includefrom
>> rentals import views
>>
>> urlpatterns = [
>> path('admin/', admin.site.urls),
>> path('', include('rentals.urls')),
>> ]
>>
>> When i run the server, the index view opens successfully! From the index, i
>> want to open the createTenant view as below.
>>
>>
>> New Tenant
>>
>>
>> When the button is clicked, i get the urls below:
>>
>> http://127.0.0.1:8000/rentals/createTenant/
>>
>> Then i get the response is 404,page not found error.
>>
>> But this opens admin page:
>>
>> http://127.0.0.1:8000/admin/
>>
>> So far i have failed to crack the secret of how the Urls work. I have gone
>> through several tutorials and i see the same set up as mine.
>>
>> I am requesting for guidance on how to crack the puzzle i.e make the other
>> urls work.
>>
>> Ronald
>>
>> --
> You received this message because you are subscribed to the Google Groups
> "Django users" group.
> To unsubscribe from this group and stop receiving emails from it, send an
> email to django-users+unsubscr...@googlegroups.com.
> To view this discussion on the web visit
> https://groups.google.com/d/msgid/django-users/4cc1d70b-119e-4f07-9867-f4c9786fbabc%40googlegroups.com
>
> .
>
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Re: Django URL routing
You have multiple URLs that are the same path. That can't work. One URL
maps to one view.
--
DR.
On Thursday, 7 May 2020 11:40:09 UTC+1, Ronald Kamulegeya wrote:
>
> I am learning Django and progressing well but i am stuck on how to
> configure the different urls to view functions.
> I have gone through tutorials and URL routing seems pretty
> straight forward but i cant make it work in my apps.
>
> I am almost hitting a brick wall. I dont see anything wrong i have done.
>
> What happens is that the index view and admin interface opens.
>
> But connecting from the index view to other pages raises the 404 error.
>
> [image: project-s.png]
> I created a project TenancyMGt and added app rentals as shown above.
> I have created several views in the module views.py Two are relevant here:
>
> def createTenant(request):
> form = TenantsForm
> context = {'form': form}
> html_form = render_to_string('rentals/partial_tenant_create.html',
> context,
> request=request,
> )
> return JsonResponse({'html_form': html_form})class
> TenantsListView(ListView):
> model = Tenants
> context_object_name = 'tenant_list'
> template_name = 'rentals/tenants_list.html'
> paginate_by = 5
> def get_queryset(self):
> return Tenants.objects.all()
>
> Now i created a file urls.py under the app rentals:
>
> from . import viewsfrom django.urls import path
> app_name='rentals'
> urlpatterns = [
> path("", views.TenantsListView.as_view(), name="index"),
> path("",views.TenantDetailView.as_view,name="detail"),
> path("",views.createTenant, name='createTenant'),
> path("/",views.TenantUpdateView.as_view, name='edit'),
> path("/",views.delete, name='delete'),
> ]
>
> under TenancyMgr/urls, i add the following:
>
> from django.contrib import adminfrom django.urls import path,includefrom
> rentals import views
>
> urlpatterns = [
> path('admin/', admin.site.urls),
> path('', include('rentals.urls')),
> ]
>
> When i run the server, the index view opens successfully! From the index, i
> want to open the createTenant view as below.
>
>
> New Tenant
>
>
> When the button is clicked, i get the urls below:
>
> http://127.0.0.1:8000/rentals/createTenant/
>
> Then i get the response is 404,page not found error.
>
> But this opens admin page:
>
> http://127.0.0.1:8000/admin/
>
> So far i have failed to crack the secret of how the Urls work. I have gone
> through several tutorials and i see the same set up as mine.
>
> I am requesting for guidance on how to crack the puzzle i.e make the other
> urls work.
>
> Ronald
>
>
--
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Re: Django URL routing
You are missing parenteses right after as_view in urls.py
Enviado do meu iPhone
Em 7 de mai de 2020, à(s) 03:22, Ronald Kamulegeya
escreveu:
> I am learning Django and progressing well but i am stuck on how to configure
> the different urls to view functions.
> I have gone through tutorials and URL routing seems pretty straight forward
> but i cant make it work in my apps.
>
> I am almost hitting a brick wall. I dont see anything wrong i have done.
>
> What happens is that the index view and admin interface opens.
>
> But connecting from the index view to other pages raises the 404 error.
>
>
>
> I created a project TenancyMGt and added app rentals as shown above.
> I have created several views in the module views.py Two are relevant here:
> def createTenant(request):
> form = TenantsForm
> context = {'form': form}
> html_form = render_to_string('rentals/partial_tenant_create.html',
> context,
> request=request,
> )
> return JsonResponse({'html_form': html_form})
> class TenantsListView(ListView):
> model = Tenants
> context_object_name = 'tenant_list'
> template_name = 'rentals/tenants_list.html'
> paginate_by = 5
> def get_queryset(self):
> return Tenants.objects.all()
> Now i created a file urls.py under the app rentals:
> from . import views
> from django.urls import path
> app_name='rentals'
> urlpatterns = [
> path("", views.TenantsListView.as_view(), name="index"),
> path("",views.TenantDetailView.as_view,name="detail"),
> path("",views.createTenant, name='createTenant'),
> path("/",views.TenantUpdateView.as_view, name='edit'),
> path("/",views.delete, name='delete'),
>
> ]
> under TenancyMgr/urls, i add the following:
> from django.contrib import admin
> from django.urls import path,include
> from rentals import views
>
> urlpatterns = [
> path('admin/', admin.site.urls),
> path('', include('rentals.urls')),
>
> ]
> When i run the server, the index view opens successfully! From the index, i
> want to open the createTenant view as below.
>
> New Tenant
>
> When the button is clicked, i get the urls below:
> http://127.0.0.1:8000/rentals/createTenant/
> Then i get the response is 404,page not found error.
> But this opens admin page:
> http://127.0.0.1:8000/admin/
> So far i have failed to crack the secret of how the Urls work. I have gone
> through several tutorials and i see the same set up as mine.
>
> I am requesting for guidance on how to crack the puzzle i.e make the other
> urls work.
>
> Ronald
>
> --
> You received this message because you are subscribed to the Google Groups
> "Django users" group.
> To unsubscribe from this group and stop receiving emails from it, send an
> email to django-users+unsubscr...@googlegroups.com.
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> https://groups.google.com/d/msgid/django-users/29c8fdd0-5c82-4ccf-98f9-33e05b8e5ab1%40googlegroups.com.
>
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