Hi, http://www.djangoproject.com/documentation/files/, section `The File Object' states that after opening a file and passing it to File from django.core.files, I should be able to use the File attributes like size, url, etc.
I'm trying to do something similar: >>> f = open('image.jpg', 'r') >>> f <open file '......'> >>> from django.core.files import File >>> File(f) <File: image.jpg> >>> File(f).url Traceback (most recent call last): File "<console>", line 1, in <module> AttributeError: 'File' object has no attribute 'url' 1. Investigating django/core/files/base.py shows that the File class does not provide aforementioned attributes, but maybe I am completely missing something? (django svn-8684) 2. Is there another way to create a File object without opening the file first? I just need the name, path and url in a template, but I don't want to store these things in an ImageField, instead just glob it from the directory. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---