On Fri, 2009-04-17 at 12:45 -0700, LeeRisq wrote:
> Hey all,
>
> Thanks for reading. I have gone over and over the section first half
> of the chapter about having a simple search form. Here are my views:
>
> from django.shortcuts import render_to_response
> from mysite.books.models import Book
>
> def search_form(request):
> return render_to_response('search_form.html')
>
> def search(request):
> errors = []
> if 'q' in request.GET:
> q = request.GET['q']
> if not q:
> errors.append('Enter a search term.')
> elif len(q) > 20:
> errors.append('Please enter at most 20 characters,
> dumbass.')
> else:
> books = Book.objects.filter(title_icontains=q)
> return render_to_response('search_results.html',
> {'books': books, 'query': q})
> return render_to_response('search_form.html', {'errors': errors})
>
> The error part of the view works fine, but when I get to the 'else'
> clause I always get this error:
>
> cannot resolve keyword 'title_icontains' into field. Choices are:
> authors, id, publication_date, publisher, title
>
> Can anyone enlighten me. I'm new to programming, so I'm sure it's just
> a stupid mistake, but I can't see it. Thanks.
>
> ~Lee
>
You need to use title__icontains. That's two underscores, rather than
one.
Cheers,
Cliff
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