Re: How to pass URL to a view
Thanks Ilya ! Perfect ! That is what I was missing.
And point noted about reverse.
V.
On Wed, May 28, 2014 at 6:04 PM, Ilya Kazakevich <
ilya.kazakev...@jetbrains.com> wrote:
> Hello,
>
> 1) Never hardcode urls in Django. Use reverse:
> https://docs.djangoproject.com/en/dev/ref/urlresolvers/#django.core.urlresolvers.reverse
> 2) If I understood you correctly, you need to redirect user back. Use
> request header REFERER' (check rfc2616 section 14.36). For Django:
> http://stackoverflow.com/questions/12758786/redirect-return-to-same-previous-page-in-django
> See also: https://docs.djangoproject.com/en/dev/ref/request-response/
>
> Be sure to check this header exists.
>
>
> Ilya Kazakevich,
> JetBrains PyCharm (Best Python/Django IDE)
> http://www.jetbrains.com/pycharm/
> "Develop with pleasure!"
>
>
> >-Original Message-
> >From: django-users@googlegroups.com
> >[mailto:django-users@googlegroups.com] On Behalf Of Vibhu Rishi
> >Sent: Wednesday, May 28, 2014 4:23 PM
> >To: django-users@googlegroups.com
> >Subject: How to pass URL to a view
> >
> >Hi,
> >
> >
> >Maybe there is a better way to achieve what I am trying - so any
> suggestion is
> >welcome :)
> >
> >
> >I have a small view. It does nothing much - if the user clicks a button
> for being
> >interested in something he is looking at - it adds to the table of
> interested things.
> >e.g. as below :
> >
> >@login_required
> >def add_interested_project(request, project_id):
> >project = get_object_or_404(Project, pk=project_id)
> >try:
> >InterestedProject.objects.get(user__pk=request.user.id,
> >project__pk=project.id)
> >except InterestedProject.DoesNotExist:
> >InterestedProject.objects.create(user=request.user,
> project=project)
> >return HttpResponseRedirect("/projects/" + project_id)
> >
> >
> >
> >Now this works fine if he is in the details page e.g. as per the url
> /projects/4 . It
> >works as expected, I am able to add to the table and it redirects back to
> the
> >same page.
> >
> >However, since this is something which I can call from any place, it
> fails in the
> >sense that it gets redirected back to the project details page. E.g. I
> have a listing
> >of projects, on /projects/ , i click the interested button, it
> unfortunately instead of
> >going back to /projects/ goes to /projects/
> >
> >
> >The code in my template file which calls this :
> >
> > class="glyphicon
> >glyphicon-heart"> Interested
> >
> >
> >The relevant urls.py hookup :
> >url(r'^(?P\d+)/add_interested_project$',
> >views.add_interested_project, name="interestedProjects"),
> >
> >
> >
> >The solution seems apparent that I should just pass the current URL to
> the view
> >so that I can do a redirect back to it - but I am not able to get an
> example of how
> >to actually implement it.
> >
> >
> >Regards,
> >
> >Vibhu
> >
> >
> >--
> >Simplicity is the ultimate sophistication. - Leonardo da Vinci Life is
> really simple,
> >but we insist on making it complicated. - Confucius
> >
> >--
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> >dJ%2BD8ViYbQvkAk34wBRgD--3e8iQQ%40mail.gmail.com
> ><https://groups.google.com/d/msgid/django-users/CAPiONwmgaEG5cCO2LDOh
> >3dJ%2BD8ViYbQvkAk34wBRgD--3e8iQQ%40mail.gmail.com?utm_medium=emai
> >l_source=footer> .
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> >
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> >
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RE: How to pass URL to a view
Hello,
1) Never hardcode urls in Django. Use reverse:
https://docs.djangoproject.com/en/dev/ref/urlresolvers/#django.core.urlresolvers.reverse
2) If I understood you correctly, you need to redirect user back. Use request
header REFERER' (check rfc2616 section 14.36). For Django:
http://stackoverflow.com/questions/12758786/redirect-return-to-same-previous-page-in-django
See also: https://docs.djangoproject.com/en/dev/ref/request-response/
Be sure to check this header exists.
Ilya Kazakevich,
JetBrains PyCharm (Best Python/Django IDE)
http://www.jetbrains.com/pycharm/
"Develop with pleasure!"
>-Original Message-
>From: django-users@googlegroups.com
>[mailto:django-users@googlegroups.com] On Behalf Of Vibhu Rishi
>Sent: Wednesday, May 28, 2014 4:23 PM
>To: django-users@googlegroups.com
>Subject: How to pass URL to a view
>
>Hi,
>
>
>Maybe there is a better way to achieve what I am trying - so any suggestion is
>welcome :)
>
>
>I have a small view. It does nothing much - if the user clicks a button for
>being
>interested in something he is looking at - it adds to the table of interested
>things.
>e.g. as below :
>
>@login_required
>def add_interested_project(request, project_id):
>project = get_object_or_404(Project, pk=project_id)
>try:
>InterestedProject.objects.get(user__pk=request.user.id,
>project__pk=project.id)
>except InterestedProject.DoesNotExist:
>InterestedProject.objects.create(user=request.user, project=project)
>return HttpResponseRedirect("/projects/" + project_id)
>
>
>
>Now this works fine if he is in the details page e.g. as per the url
>/projects/4 . It
>works as expected, I am able to add to the table and it redirects back to the
>same page.
>
>However, since this is something which I can call from any place, it fails in
>the
>sense that it gets redirected back to the project details page. E.g. I have a
>listing
>of projects, on /projects/ , i click the interested button, it unfortunately
>instead of
>going back to /projects/ goes to /projects/
>
>
>The code in my template file which calls this :
>
> Interested
>
>
>The relevant urls.py hookup :
>url(r'^(?P\d+)/add_interested_project$',
>views.add_interested_project, name="interestedProjects"),
>
>
>
>The solution seems apparent that I should just pass the current URL to the view
>so that I can do a redirect back to it - but I am not able to get an example
>of how
>to actually implement it.
>
>
>Regards,
>
>Vibhu
>
>
>--
>Simplicity is the ultimate sophistication. - Leonardo da Vinci Life is really
>simple,
>but we insist on making it complicated. - Confucius
>
>--
>You received this message because you are subscribed to the Google Groups
>"Django users" group.
>To unsubscribe from this group and stop receiving emails from it, send an
>email to
>django-users+unsubscr...@googlegroups.com.
>To post to this group, send email to django-users@googlegroups.com.
>Visit this group at http://groups.google.com/group/django-users.
>To view this discussion on the web visit
>https://groups.google.com/d/msgid/django-users/CAPiONwmgaEG5cCO2LDOh3
>dJ%2BD8ViYbQvkAk34wBRgD--3e8iQQ%40mail.gmail.com
><https://groups.google.com/d/msgid/django-users/CAPiONwmgaEG5cCO2LDOh
>3dJ%2BD8ViYbQvkAk34wBRgD--3e8iQQ%40mail.gmail.com?utm_medium=emai
>l_source=footer> .
>For more options, visit https://groups.google.com/d/optout.
>
>
>No virus found in this message.
>Checked by AVG - www.avg.com
>Version: 2014.0.4592 / Virus Database: 3950/7573 - Release Date: 05/27/14
>
>
>
>No virus found in this message.
>Checked by AVG - www.avg.com
>Version: 2014.0.4592 / Virus Database: 3950/7563 - Release Date: 05/26/14
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How to pass URL to a view
Hi,
Maybe there is a better way to achieve what I am trying - so any suggestion
is welcome :)
I have a small view. It does nothing much - if the user clicks a button for
being interested in something he is looking at - it adds to the table of
interested things. e.g. as below :
@login_required
def add_interested_project(request, project_id):
project = get_object_or_404(Project, pk=project_id)
try:
InterestedProject.objects.get(user__pk=request.user.id, project__pk=
project.id)
except InterestedProject.DoesNotExist:
InterestedProject.objects.create(user=request.user, project=project)
return HttpResponseRedirect("/projects/" + project_id)
Now this works fine if he is in the details page e.g. as per the url
/projects/4 . It works as expected, I am able to add to the table and it
redirects back to the same page.
However, since this is something which I can call from any place, it fails
in the sense that it gets redirected back to the project details page. E.g.
I have a listing of projects, on /projects/ , i click the interested
button, it unfortunately instead of going back to /projects/ goes to
/projects/
The code in my template file which calls this :
Interested
The relevant urls.py hookup :
url(r'^(?P\d+)/add_interested_project$',
views.add_interested_project, name="interestedProjects"),
The solution seems apparent that I should just pass the current URL to the
view so that I can do a redirect back to it - but I am not able to get an
example of how to actually implement it.
Regards,
Vibhu
--
Simplicity is the ultimate sophistication. - Leonardo da Vinci
Life is really simple, but we insist on making it complicated. - Confucius
--
You received this message because you are subscribed to the Google Groups
"Django users" group.
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Visit this group at http://groups.google.com/group/django-users.
To view this discussion on the web visit
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For more options, visit https://groups.google.com/d/optout.
