Re: Paginator and foreign key

2010-12-14 Thread bruno desthuilliers 


On 13 déc, 19:49, refreegrata  wrote:
> thanks for the answer, but the solution don't show anything. I must be
> doing something wrong.
> if now I have
> ---
> class Myline(models.mode):
>    fk_myDoc = models.ForeignKey(MyDoc, related_name="")
> ---
>
> How Can I use {% for line doc.X_set.all %} in the template?
> I'm sorry for this asking, but I can't find the _set.all option in the
> Django documentation.

http://docs.djangoproject.com/en/dev/topics/db/queries/#backwards-related-objects

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Re: Paginator and foreign key

2010-12-13 Thread refreegrata 
thanks for the answer, but the solution don't show anything. I must be
doing something wrong.
if now I have
---
class Myline(models.mode):
   fk_myDoc = models.ForeignKey(MyDoc, related_name="")
---

How Can I use {% for line doc.X_set.all %} in the template?
I'm sorry for this asking, but I can't find the _set.all option in the
Django documentation.

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Re: Paginator and foreign key

2010-12-13 Thread bruno desthuilliers 
On 13 déc, 16:59, refreegrata  wrote:
> Hello list, I have a question. Take a look to the next models.
> 
> class MyDoc(models.Model):
>     code = models.BigIntegerField()
>
> class Myline(models.mode):
>    fk_myDoc = models.ForeignKey(MyDoc)
> ---
>
> In my view I do something like
>
> myPaginator = Paginator(MyDoc.objects.filter(codigo=1), 10)
> myDocs = myPaginator.page(page_number)
>
> This return all the Docs with a code=1, but I too want to return all
> the objects with the type "MyLine" associated to the results of this
> query.

for doc in myDocs.object_list:
print doc.MyLine_set.all()


or in your template:


{% for doc in myDocs.object_list %}
  
 {{ doc.code }}
 
   {% for line doc.MyLine_set.all %}
   {{ line }}
   {% endfor %}
 
   
{% endfor %}


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Re: Paginator and foreign key

2010-12-13 Thread refreegrata 
if I return another list:
---
for i in range(len(paginatorDocs.object_list)):
resultados = {'myDoc': paginatorDocs.object_list[i],
  'myLines':
Myline.objects.filter(fk_myDoc=paginatorDocs.object_list[i].id),}

---
With this I can get the values, but I'm not sure if this is the best
way to solve the problem

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Paginator and foreign key

2010-12-13 Thread refreegrata 
Hello list, I have a question. Take a look to the next models.

class MyDoc(models.Model):
code = models.BigIntegerField()

class Myline(models.mode):
   fk_myDoc = models.ForeignKey(MyDoc)
---

In my view I do something like

myPaginator = Paginator(MyDoc.objects.filter(codigo=1), 10)
myDocs = myPaginator.page(page_number)

This return all the Docs with a code=1, but I too want to return all
the objects with the type "MyLine" associated to the results of this
query.

I try to do something like

for i in range(len(myDocs.object_list))
myDocs.object_list[i].append(Myline.objects.filter(fk_myDoc=myDocs.object_list[i].id))
-
but don't work

I know that I can do 2 queries and return two list, one with the myDoc
list and other with the myLine list, but in that case in my template I
must to do something like

{% for myDoc im MyDocs.object.list %}
{% for myline in Mylines %}
   {%if myDoc.id == myline.fk_myDoc %}
   ..
   {% endif %}
{% endfor %}
{% endfor %}

I don't want to do this, because I think a big "for" inside a big
"for" is innecessary.

Somebody have an idea??
Thanks for read, and sorry for my bad english.

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