Re: Creating an object with a FileField programmatically

[Malcolm Tredinnick]

On Sun, 2009-04-26 at 17:21 -0700, chachra wrote:
> I am trying something similar and getting:
> 
> Cannot create a consistent method resolution
> order (MRO) for bases File, FieldFile

Then you're not doing something too similar, because that's quite
different to the error in the post you quote. It involved file fields,
but that's it. 

So what are you doing to trigger this error? What's a really small
example that demonstrates the problem?

Based on the error, you may have found the same thing as ticket #10249,
in which case the solution is to wait for that to be fixed. It's on the
1.1 milestone.

Regards,
Malcolm



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Re: Creating an object with a FileField programmatically

[chachra]

I am trying something similar and getting:

Cannot create a consistent method resolution
order (MRO) for bases File, FieldFile

Using Django 1.1b

Cheers!
Sumit


On Apr 14, 1:11 pm, Alex Gaynor  wrote:
> On Tue, Apr 14, 2009 at 4:04 PM, Vincent Foley  wrote:
>
> > Hello,
>
> > I want to be able to add files inside a model to test that model.
> > However, I'm unable to find in the documentation any mention on how to
> > do so.  I asked on IRC and somebody suggested the following:
>
> > from django.core.files import File
> > from myproject.myapp.models import MyModel
> > fd = open('/path/to/file')
> > f = File(fd)
> > obj = MyModel.objects.create(file_field=f)
> > f.close()
> > fd.close()
>
> > However, when I try to access obj, I get the following exception:
> > SuspiciousOperation: Attempted access to '/path/to/file' denied.
>
> > Is it how one is supposed to "attach" file into a model?  If so, what
> > could be causing my problem?
>
> > Thanks,
>
> > Vincent
>
> If the file isn't already relative to your MEDIA_ROOT you need to do:
>
> m = MyModel()
> m.file_field.save('new_file_name', open('/path/to/file').read()).
>
> Alex
> --
> "I disapprove of what you say, but I will defend to the death your right to
> say it." --Voltaire
> "The people's good is the highest law."--Cicero
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Re: Creating an object with a FileField programmatically

[Alex Gaynor]

On Tue, Apr 14, 2009 at 4:04 PM, Vincent Foley  wrote:

>
> Hello,
>
> I want to be able to add files inside a model to test that model.
> However, I'm unable to find in the documentation any mention on how to
> do so.  I asked on IRC and somebody suggested the following:
>
> from django.core.files import File
> from myproject.myapp.models import MyModel
> fd = open('/path/to/file')
> f = File(fd)
> obj = MyModel.objects.create(file_field=f)
> f.close()
> fd.close()
>
>
> However, when I try to access obj, I get the following exception:
> SuspiciousOperation: Attempted access to '/path/to/file' denied.
>
> Is it how one is supposed to "attach" file into a model?  If so, what
> could be causing my problem?
>
> Thanks,
>
> Vincent
>
> >
>
If the file isn't already relative to your MEDIA_ROOT you need to do:

m = MyModel()
m.file_field.save('new_file_name', open('/path/to/file').read()).

Alex
-- 
"I disapprove of what you say, but I will defend to the death your right to
say it." --Voltaire
"The people's good is the highest law."--Cicero

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