Re: Get current user outside a view / without an request object
Hello, I'have a little problem with this code??
when I'l trying to put :
" def __init__(self, inputUser, *args, **kwargs):"
I have the following error :
__init__() takes at least 2 non-keyword arguments (1 given)
So, I suppose I need to set the inputUser in a specific place, but I
can' figure out where?
For information, I'm working with the django admin site .
Any idea?
On 7 août, 03:28, Julián C. Pérez wrote:
> Bingo!!!
> :D
> I follow
> this:http://oebfare.com/blog/2008/feb/23/changing-modelchoicefield-queryset/
> and now I'm happy with mi desired current user based queryset
> Thank you all!
>
> BTW, my form class finally looks like...
> ---
> class SendMessageForm(forms.Form):
>
> recipientUser = ShowValidContactList
> (queryset=None,label=u'Send to')
> messageSubject= forms.CharField(label=u'Subject')
> messageContent = forms.CharField
> (label=u'Content',widget=forms.Textarea())
>
> def __init__(self, inputUser, *args, **kwargs):
> self.user= inputUser
> super(SendMessageForm, self).__init__(*args, **kwargs)
> self.fields['recipientUser'].queryset = # Anything with
> the current user, in this case 'self.user'
> ---
>
> On Aug 6, 11:14 am, Julián C. Pérez wrote:
>
> > Thanks for reply, Paulo
> > But if I...
> > ---
> > class SendMessageForm(forms.Form):
>
> > recipientUser = ShowValidContactList(currentUser=self.user,
> > label=u'Send to')
> > messageSubject= forms.CharField(label=u'Subject')
> > messageContent = forms.CharField(label=u'Content',
> > widget=forms.Textarea())
>
> > def __init__(self, inputUser, *args, **kwargs):
> > self.user= inputUser
> > super(SendMessageForm, self).__init__(*args, **kwargs)
> > ---
> > the 'recipientUser = ShowValidContactList(currentUser=self.user,
> > label=u'Send to')' raises error because of that 'self.user' ('self'
> > wouldn't be defined and be out of scope)
>
> > On Aug 6, 11:09 am, Paulo Almeida wrote:
>
> > > It doesn't have to be a callable, you can just do something like:
>
> > > recipientUser = ShowValidContactList(currentUser=self.currentUser)
>
> > > I never used that kwargs.pop function (I didn't know you could do that),
> > > but I have code like this:
>
> > > class ExperimentForm(ModelForm):
> > > """ Generate form to handle experiment information. """
> > > def __init__(self, user, *args, **kwargs):
> > > super(ExperimentForm, self).__init__(*args, **kwargs)
> > > try:
> > > preferences = Preferences.objects.get(user=user)
>
> > > That last 'user' is just what came from the function call in the view.
>
> > > - Paulo
>
> > > 2009/8/6 Julián C. Pérez
>
> > > > My real problem it that the field should looks like:
> > > > ---
> > > > recipientUser = ShowValidContactList(currentUser=_something_,
> > > > label=u'Send to')
> > > > ---
> > > > and if I have a form's init method like...
> > > > ---
> > > > def __init__(self, *args, **kwargs):
> > > > self.currentUser = kwargs.pop('currentUser', None)
> > > > super(SendMessageForm, self).__init__(*args, **kwargs)
> > > > ---
> > > > it won't change the current user already defined in the field
>
> > > > Now, I want to make something like...
> > > > ---
> > > > recipientUser = ShowValidContactList(currentUser=getCurrentUser,
> > > > label=u'Send to')
> > > > ---
> > > > where 'getCurrentUser' is a callable function similar to:
> > > > ---
> > > > def get_image_path(instance, filename):
> > > > return 'photos/%s/%s' % (instance.id, filename)
>
> > > > class Photo(models.Model):
> > > > image = models.ImageField(upload_to=get_image_path)
> > > > ---
> > > > how can I do that?
>
> > > > On Aug 6, 9:58 am, Daniel Roseman wrote:
> > > > > On Aug 6, 3:34 pm, Julián C. Pérez wrote:
>
> > > > > > Hi
> > > > > > I tried doing that...
> > > > > > But it does not work
> > > > > > For example, if I do something like...
> > > > > > ---
> > > > > > class SendMessageForm(forms.Form):
> > > > > > recipientUser = ShowValidContactList(label=u'Send to')
> > > > > > messageSubject= forms.CharField(label=u'Subject')
> > > > > > messageContent = forms.CharField
> > > > > > (label=u'Content',widget=forms.Textarea())
> > > > > > def __init__(self, currentUser):
> > > > > > self.currentUser = currentUser
> > > > > > super(SendMessageForm, self).__init__(*args,
> > > > > > **kwargs)
> > > > > > ---
> > > > > > that init method in my custom form class won't change anything in
> > > > > > the
> > > > > > already defined ShowValidContactList field
>
> > > > > Because you are clobbering the existing parameters to __init__. You
> > > > > should do it like this:
>
> > > > > def __init__(self, *args, **kwargs):
> > > > > self.currentUser = kwargs.pop('currentUser', None)
> > > > > super(SendMessageForm, self).__init__(*args, **kwargs)
>
> > > > > --
> > > > > DR.
--~--~-
Re: Get current user outside a view / without an request object
Bingo!!!
:D
I follow this:
http://oebfare.com/blog/2008/feb/23/changing-modelchoicefield-queryset/
and now I'm happy with mi desired current user based queryset
Thank you all!
BTW, my form class finally looks like...
---
class SendMessageForm(forms.Form):
recipientUser = ShowValidContactList
(queryset=None,label=u'Send to')
messageSubject= forms.CharField(label=u'Subject')
messageContent = forms.CharField
(label=u'Content',widget=forms.Textarea())
def __init__(self, inputUser, *args, **kwargs):
self.user= inputUser
super(SendMessageForm, self).__init__(*args, **kwargs)
self.fields['recipientUser'].queryset = # Anything with
the current user, in this case 'self.user'
---
On Aug 6, 11:14 am, Julián C. Pérez wrote:
> Thanks for reply, Paulo
> But if I...
> ---
> class SendMessageForm(forms.Form):
>
> recipientUser = ShowValidContactList(currentUser=self.user,
> label=u'Send to')
> messageSubject= forms.CharField(label=u'Subject')
> messageContent = forms.CharField(label=u'Content',
> widget=forms.Textarea())
>
> def __init__(self, inputUser, *args, **kwargs):
> self.user= inputUser
> super(SendMessageForm, self).__init__(*args, **kwargs)
> ---
> the 'recipientUser = ShowValidContactList(currentUser=self.user,
> label=u'Send to')' raises error because of that 'self.user' ('self'
> wouldn't be defined and be out of scope)
>
> On Aug 6, 11:09 am, Paulo Almeida wrote:
>
> > It doesn't have to be a callable, you can just do something like:
>
> > recipientUser = ShowValidContactList(currentUser=self.currentUser)
>
> > I never used that kwargs.pop function (I didn't know you could do that),
> > but I have code like this:
>
> > class ExperimentForm(ModelForm):
> > """ Generate form to handle experiment information. """
> > def __init__(self, user, *args, **kwargs):
> > super(ExperimentForm, self).__init__(*args, **kwargs)
> > try:
> > preferences = Preferences.objects.get(user=user)
>
> > That last 'user' is just what came from the function call in the view.
>
> > - Paulo
>
> > 2009/8/6 Julián C. Pérez
>
> > > My real problem it that the field should looks like:
> > > ---
> > > recipientUser = ShowValidContactList(currentUser=_something_,
> > > label=u'Send to')
> > > ---
> > > and if I have a form's init method like...
> > > ---
> > > def __init__(self, *args, **kwargs):
> > > self.currentUser = kwargs.pop('currentUser', None)
> > > super(SendMessageForm, self).__init__(*args, **kwargs)
> > > ---
> > > it won't change the current user already defined in the field
>
> > > Now, I want to make something like...
> > > ---
> > > recipientUser = ShowValidContactList(currentUser=getCurrentUser,
> > > label=u'Send to')
> > > ---
> > > where 'getCurrentUser' is a callable function similar to:
> > > ---
> > > def get_image_path(instance, filename):
> > > return 'photos/%s/%s' % (instance.id, filename)
>
> > > class Photo(models.Model):
> > > image = models.ImageField(upload_to=get_image_path)
> > > ---
> > > how can I do that?
>
> > > On Aug 6, 9:58 am, Daniel Roseman wrote:
> > > > On Aug 6, 3:34 pm, Julián C. Pérez wrote:
>
> > > > > Hi
> > > > > I tried doing that...
> > > > > But it does not work
> > > > > For example, if I do something like...
> > > > > ---
> > > > > class SendMessageForm(forms.Form):
> > > > > recipientUser = ShowValidContactList(label=u'Send to')
> > > > > messageSubject= forms.CharField(label=u'Subject')
> > > > > messageContent = forms.CharField
> > > > > (label=u'Content',widget=forms.Textarea())
> > > > > def __init__(self, currentUser):
> > > > > self.currentUser = currentUser
> > > > > super(SendMessageForm, self).__init__(*args, **kwargs)
> > > > > ---
> > > > > that init method in my custom form class won't change anything in the
> > > > > already defined ShowValidContactList field
>
> > > > Because you are clobbering the existing parameters to __init__. You
> > > > should do it like this:
>
> > > > def __init__(self, *args, **kwargs):
> > > > self.currentUser = kwargs.pop('currentUser', None)
> > > > super(SendMessageForm, self).__init__(*args, **kwargs)
>
> > > > --
> > > > DR.
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
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-~--~~~~--~~--~--~---
Re: Get current user outside a view / without an request object
But why don't you put:
recipientUser = ShowValidContactList(currentUser=self.user)
inside the __init__?
- Paulo
2009/8/6 Julián C. Pérez
>
> Thanks for reply, Paulo
> But if I...
> ---
> class SendMessageForm(forms.Form):
>
>recipientUser = ShowValidContactList(currentUser=self.user,
> label=u'Send to')
>messageSubject= forms.CharField(label=u'Subject')
>messageContent = forms.CharField(label=u'Content',
> widget=forms.Textarea())
>
> def __init__(self, inputUser, *args, **kwargs):
> self.user= inputUser
>super(SendMessageForm, self).__init__(*args, **kwargs)
> ---
> the 'recipientUser = ShowValidContactList(currentUser=self.user,
> label=u'Send to')' raises error because of that 'self.user' ('self'
> wouldn't be defined and be out of scope)
>
> On Aug 6, 11:09 am, Paulo Almeida wrote:
> > It doesn't have to be a callable, you can just do something like:
> >
> > recipientUser = ShowValidContactList(currentUser=self.currentUser)
> >
> > I never used that kwargs.pop function (I didn't know you could do that),
> > but I have code like this:
> >
> > class ExperimentForm(ModelForm):
> > """ Generate form to handle experiment information. """
> > def __init__(self, user, *args, **kwargs):
> > super(ExperimentForm, self).__init__(*args, **kwargs)
> > try:
> > preferences = Preferences.objects.get(user=user)
> >
> > That last 'user' is just what came from the function call in the view.
> >
> > - Paulo
> >
> > 2009/8/6 Julián C. Pérez
> >
> >
> >
> > > My real problem it that the field should looks like:
> > > ---
> > > recipientUser = ShowValidContactList(currentUser=_something_,
> > > label=u'Send to')
> > > ---
> > > and if I have a form's init method like...
> > > ---
> > > def __init__(self, *args, **kwargs):
> > >self.currentUser = kwargs.pop('currentUser', None)
> > >super(SendMessageForm, self).__init__(*args, **kwargs)
> > > ---
> > > it won't change the current user already defined in the field
> >
> > > Now, I want to make something like...
> > > ---
> > > recipientUser = ShowValidContactList(currentUser=getCurrentUser,
> > > label=u'Send to')
> > > ---
> > > where 'getCurrentUser' is a callable function similar to:
> > > ---
> > > def get_image_path(instance, filename):
> > >return 'photos/%s/%s' % (instance.id, filename)
> >
> > > class Photo(models.Model):
> > >image = models.ImageField(upload_to=get_image_path)
> > > ---
> > > how can I do that?
> >
> > > On Aug 6, 9:58 am, Daniel Roseman wrote:
> > > > On Aug 6, 3:34 pm, Julián C. Pérez wrote:
> >
> > > > > Hi
> > > > > I tried doing that...
> > > > > But it does not work
> > > > > For example, if I do something like...
> > > > > ---
> > > > > class SendMessageForm(forms.Form):
> > > > > recipientUser = ShowValidContactList(label=u'Send to')
> > > > > messageSubject= forms.CharField(label=u'Subject')
> > > > > messageContent = forms.CharField
> > > > > (label=u'Content',widget=forms.Textarea())
> > > > > def __init__(self, currentUser):
> > > > > self.currentUser = currentUser
> > > > > super(SendMessageForm, self).__init__(*args,
> **kwargs)
> > > > > ---
> > > > > that init method in my custom form class won't change anything in
> the
> > > > > already defined ShowValidContactList field
> >
> > > > Because you are clobbering the existing parameters to __init__. You
> > > > should do it like this:
> >
> > > > def __init__(self, *args, **kwargs):
> > > > self.currentUser = kwargs.pop('currentUser', None)
> > > > super(SendMessageForm, self).__init__(*args, **kwargs)
> >
> > > > --
> > > > DR.
> >
>
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-users@googlegroups.com
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-~--~~~~--~~--~--~---
Re: Get current user outside a view / without an request object
Thanks for reply, Paulo
But if I...
---
class SendMessageForm(forms.Form):
recipientUser = ShowValidContactList(currentUser=self.user,
label=u'Send to')
messageSubject= forms.CharField(label=u'Subject')
messageContent = forms.CharField(label=u'Content',
widget=forms.Textarea())
def __init__(self, inputUser, *args, **kwargs):
self.user= inputUser
super(SendMessageForm, self).__init__(*args, **kwargs)
---
the 'recipientUser = ShowValidContactList(currentUser=self.user,
label=u'Send to')' raises error because of that 'self.user' ('self'
wouldn't be defined and be out of scope)
On Aug 6, 11:09 am, Paulo Almeida wrote:
> It doesn't have to be a callable, you can just do something like:
>
> recipientUser = ShowValidContactList(currentUser=self.currentUser)
>
> I never used that kwargs.pop function (I didn't know you could do that),
> but I have code like this:
>
> class ExperimentForm(ModelForm):
> """ Generate form to handle experiment information. """
> def __init__(self, user, *args, **kwargs):
> super(ExperimentForm, self).__init__(*args, **kwargs)
> try:
> preferences = Preferences.objects.get(user=user)
>
> That last 'user' is just what came from the function call in the view.
>
> - Paulo
>
> 2009/8/6 Julián C. Pérez
>
>
>
> > My real problem it that the field should looks like:
> > ---
> > recipientUser = ShowValidContactList(currentUser=_something_,
> > label=u'Send to')
> > ---
> > and if I have a form's init method like...
> > ---
> > def __init__(self, *args, **kwargs):
> > self.currentUser = kwargs.pop('currentUser', None)
> > super(SendMessageForm, self).__init__(*args, **kwargs)
> > ---
> > it won't change the current user already defined in the field
>
> > Now, I want to make something like...
> > ---
> > recipientUser = ShowValidContactList(currentUser=getCurrentUser,
> > label=u'Send to')
> > ---
> > where 'getCurrentUser' is a callable function similar to:
> > ---
> > def get_image_path(instance, filename):
> > return 'photos/%s/%s' % (instance.id, filename)
>
> > class Photo(models.Model):
> > image = models.ImageField(upload_to=get_image_path)
> > ---
> > how can I do that?
>
> > On Aug 6, 9:58 am, Daniel Roseman wrote:
> > > On Aug 6, 3:34 pm, Julián C. Pérez wrote:
>
> > > > Hi
> > > > I tried doing that...
> > > > But it does not work
> > > > For example, if I do something like...
> > > > ---
> > > > class SendMessageForm(forms.Form):
> > > > recipientUser = ShowValidContactList(label=u'Send to')
> > > > messageSubject= forms.CharField(label=u'Subject')
> > > > messageContent = forms.CharField
> > > > (label=u'Content',widget=forms.Textarea())
> > > > def __init__(self, currentUser):
> > > > self.currentUser = currentUser
> > > > super(SendMessageForm, self).__init__(*args, **kwargs)
> > > > ---
> > > > that init method in my custom form class won't change anything in the
> > > > already defined ShowValidContactList field
>
> > > Because you are clobbering the existing parameters to __init__. You
> > > should do it like this:
>
> > > def __init__(self, *args, **kwargs):
> > > self.currentUser = kwargs.pop('currentUser', None)
> > > super(SendMessageForm, self).__init__(*args, **kwargs)
>
> > > --
> > > DR.
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-users@googlegroups.com
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-~--~~~~--~~--~--~---
Re: Get current user outside a view / without an request object
It doesn't have to be a callable, you can just do something like:
recipientUser = ShowValidContactList(currentUser=self.currentUser)
I never used that kwargs.pop function (I didn't know you could do that),
but I have code like this:
class ExperimentForm(ModelForm):
""" Generate form to handle experiment information. """
def __init__(self, user, *args, **kwargs):
super(ExperimentForm, self).__init__(*args, **kwargs)
try:
preferences = Preferences.objects.get(user=user)
That last 'user' is just what came from the function call in the view.
- Paulo
2009/8/6 Julián C. Pérez
>
> My real problem it that the field should looks like:
> ---
> recipientUser = ShowValidContactList(currentUser=_something_,
> label=u'Send to')
> ---
> and if I have a form's init method like...
> ---
> def __init__(self, *args, **kwargs):
>self.currentUser = kwargs.pop('currentUser', None)
>super(SendMessageForm, self).__init__(*args, **kwargs)
> ---
> it won't change the current user already defined in the field
>
> Now, I want to make something like...
> ---
> recipientUser = ShowValidContactList(currentUser=getCurrentUser,
> label=u'Send to')
> ---
> where 'getCurrentUser' is a callable function similar to:
> ---
> def get_image_path(instance, filename):
>return 'photos/%s/%s' % (instance.id, filename)
>
> class Photo(models.Model):
>image = models.ImageField(upload_to=get_image_path)
> ---
> how can I do that?
>
> On Aug 6, 9:58 am, Daniel Roseman wrote:
> > On Aug 6, 3:34 pm, Julián C. Pérez wrote:
> >
> >
> >
> > > Hi
> > > I tried doing that...
> > > But it does not work
> > > For example, if I do something like...
> > > ---
> > > class SendMessageForm(forms.Form):
> > > recipientUser = ShowValidContactList(label=u'Send to')
> > > messageSubject= forms.CharField(label=u'Subject')
> > > messageContent = forms.CharField
> > > (label=u'Content',widget=forms.Textarea())
> > > def __init__(self, currentUser):
> > > self.currentUser = currentUser
> > > super(SendMessageForm, self).__init__(*args, **kwargs)
> > > ---
> > > that init method in my custom form class won't change anything in the
> > > already defined ShowValidContactList field
> >
> > Because you are clobbering the existing parameters to __init__. You
> > should do it like this:
> >
> > def __init__(self, *args, **kwargs):
> > self.currentUser = kwargs.pop('currentUser', None)
> > super(SendMessageForm, self).__init__(*args, **kwargs)
> >
> > --
> > DR.
> >
>
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-users@googlegroups.com
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django-users+unsubscr...@googlegroups.com
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-~--~~~~--~~--~--~---
Re: Get current user outside a view / without an request object
My real problem it that the field should looks like:
---
recipientUser = ShowValidContactList(currentUser=_something_,
label=u'Send to')
---
and if I have a form's init method like...
---
def __init__(self, *args, **kwargs):
self.currentUser = kwargs.pop('currentUser', None)
super(SendMessageForm, self).__init__(*args, **kwargs)
---
it won't change the current user already defined in the field
Now, I want to make something like...
---
recipientUser = ShowValidContactList(currentUser=getCurrentUser,
label=u'Send to')
---
where 'getCurrentUser' is a callable function similar to:
---
def get_image_path(instance, filename):
return 'photos/%s/%s' % (instance.id, filename)
class Photo(models.Model):
image = models.ImageField(upload_to=get_image_path)
---
how can I do that?
On Aug 6, 9:58 am, Daniel Roseman wrote:
> On Aug 6, 3:34 pm, Julián C. Pérez wrote:
>
>
>
> > Hi
> > I tried doing that...
> > But it does not work
> > For example, if I do something like...
> > ---
> > class SendMessageForm(forms.Form):
> > recipientUser = ShowValidContactList(label=u'Send to')
> > messageSubject= forms.CharField(label=u'Subject')
> > messageContent = forms.CharField
> > (label=u'Content',widget=forms.Textarea())
> > def __init__(self, currentUser):
> > self.currentUser = currentUser
> > super(SendMessageForm, self).__init__(*args, **kwargs)
> > ---
> > that init method in my custom form class won't change anything in the
> > already defined ShowValidContactList field
>
> Because you are clobbering the existing parameters to __init__. You
> should do it like this:
>
> def __init__(self, *args, **kwargs):
> self.currentUser = kwargs.pop('currentUser', None)
> super(SendMessageForm, self).__init__(*args, **kwargs)
>
> --
> DR.
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-users@googlegroups.com
To unsubscribe from this group, send email to
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-~--~~~~--~~--~--~---
Re: Get current user outside a view / without an request object
On Aug 6, 3:34 pm, Julián C. Pérez wrote:
> Hi
> I tried doing that...
> But it does not work
> For example, if I do something like...
> ---
> class SendMessageForm(forms.Form):
> recipientUser = ShowValidContactList(label=u'Send to')
> messageSubject= forms.CharField(label=u'Subject')
> messageContent = forms.CharField
> (label=u'Content',widget=forms.Textarea())
> def __init__(self, currentUser):
> self.currentUser = currentUser
> super(SendMessageForm, self).__init__(*args, **kwargs)
> ---
> that init method in my custom form class won't change anything in the
> already defined ShowValidContactList field
Because you are clobbering the existing parameters to __init__. You
should do it like this:
def __init__(self, *args, **kwargs):
self.currentUser = kwargs.pop('currentUser', None)
super(SendMessageForm, self).__init__(*args, **kwargs)
--
DR.
--~--~-~--~~~---~--~~
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Re: Get current user outside a view / without an request object
Hi I tried doing that... But it does not work For example, if I do something like... --- class SendMessageForm(forms.Form): recipientUser = ShowValidContactList(label=u'Send to') messageSubject= forms.CharField(label=u'Subject') messageContent = forms.CharField (label=u'Content',widget=forms.Textarea()) def __init__(self, currentUser): self.currentUser = currentUser super(SendMessageForm, self).__init__(*args, **kwargs) --- that init method in my custom form class won't change anything in the already defined ShowValidContactList field I also tried threadlocal's approach... but it didn't work either and it's a weird way to do that... I'm gonna go in a different direction, inspired by similar former problem Thank you alll, now I'll report with my status On Aug 6, 1:40 am, Daniel Roseman wrote: > On Aug 6, 2:24 am, Julián C. Pérez wrote: > > > > > Hi everyone > > I'm in trouble because of a form class > > I have a form class with attributes defined, but with one thing: > > One of the attributes requires the current user, or al least its > > username > > > The form definition in as shown below: > > --- > > class SendMessageForm(forms.Form): > > recipientUser = ShowValidContactList(label=u'Send to') > > messageSubject= forms.CharField(label=u'Subject') > > messageContent = forms.CharField(label=u'Content', > > widget=forms.Textarea()) > > --- > > > As you can tell I'm trying to make a 'Send message' form to make > > message sending available in my project... but the recipient user must > > be in the contacts list of the current user... > > The 'recipientUser' field is a ShowValidContactList > > (forms.ModelChoiceField) instance... so it works with a fixed queryset > > based on that user (the currently logged-in one) > > > My problem is that... how can I get the current user information > > outside a view and without request objects?? > > Or... how can I make that form works with a different approach?? > > > Any help would be appreciate! > > This is asked frequently on this group. The answer is to override the > form's __init__ method and pass the request in there, and store it on > a form attribute for later use. > -- > DR. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Get current user outside a view / without an request object
> ..go back and read the original poster's > message. Having the user in threadlocals doesn't solve any problem, > since he's trying to create a form class based on information in the > request and that only happens at import time, not every time something > in the file is looked at. Yes, my mistake --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Get current user outside a view / without an request object
On Thu, 2009-08-06 at 03:33 -0700, krylatij wrote: > Why do you think so? It's bad encapsulation practice, for a start. It breaks Python's namespacing habits. In this particular case, however, go back and read the original poster's message. Having the user in threadlocals doesn't solve any problem, since he's trying to create a form class based on information in the request and that only happens at import time, not every time something in the file is looked at. Regards, Malcolm --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Get current user outside a view / without an request object
Why do you think so? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Get current user outside a view / without an request object
On Aug 6, 9:14 am, krylatij wrote: > You can also use threadlocals middleware (ask google about it =)) > to get current user without request object No, really, don't. Just don't. -- DR. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Get current user outside a view / without an request object
You can also use threadlocals middleware (ask google about it =)) to get current user without request object --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
Re: Get current user outside a view / without an request object
On Aug 6, 2:24 am, Julián C. Pérez wrote: > Hi everyone > I'm in trouble because of a form class > I have a form class with attributes defined, but with one thing: > One of the attributes requires the current user, or al least its > username > > The form definition in as shown below: > --- > class SendMessageForm(forms.Form): > recipientUser = ShowValidContactList(label=u'Send to') > messageSubject= forms.CharField(label=u'Subject') > messageContent = forms.CharField(label=u'Content', > widget=forms.Textarea()) > --- > > As you can tell I'm trying to make a 'Send message' form to make > message sending available in my project... but the recipient user must > be in the contacts list of the current user... > The 'recipientUser' field is a ShowValidContactList > (forms.ModelChoiceField) instance... so it works with a fixed queryset > based on that user (the currently logged-in one) > > My problem is that... how can I get the current user information > outside a view and without request objects?? > Or... how can I make that form works with a different approach?? > > Any help would be appreciate! This is asked frequently on this group. The answer is to override the form's __init__ method and pass the request in there, and store it on a form attribute for later use. -- DR. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
