Re: Help for for loop
On 12/9/2010 12:24 PM, Cal Leeming [Simplicity Media Ltd] wrote:
> Uh, you *might* be able to use:
>
> {% for x in mylist %}
> {% if x % 2 %}
> yay: {{x}}
> {% else %}
> nay: {{x}}
> {% endif %}
> {% endfor %}
>
Blerch! This is a really good indication of why it's much better to
perform the appropriate translations in the view.
regards
Steve
> On 09/12/2010 11:18, Phani Chand wrote:
>> Can i use filter(lambda x: x%2, mylist) directly in my html page --
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Re: Help for for loop
Ahh thanks Bruno, that gave the correct solution:
>>> l
['pos 0', 'pos 1', 'pos 2', 'pos 3']
>>> l[1::2]
['pos 1', 'pos 3']
My slice-fu is clearly weak.
Cheers
Tom
On Thu, Dec 9, 2010 at 12:03 PM, bruno desthuilliers
wrote:
>
>
> On 9 déc, 12:24, Tom Evans wrote:
>> Hmm, those are the values that are odd, he wanted the values from odd
>> indices
>
> Well spotted ;)
>
> There's a builtin "slice" filter that should have done the trick but I
> just couldn't manage to make it work with a for loop :-/
>
> The only solution I could come with that does not require custom
> filters or whatever is using the cycle tag (http://
> docs.djangoproject.com/en/1.2/ref/templates/builtins/#cycle):
>
> {% for item in list %}
> {% cycle "even", "odd" as oddeven %} {# assuming standard 0-based
> indexing #}
> {% if oddeven == "odd" %}
> item {{ item }} is at odd index {{ forloop.counter }}
> {% endif %}
> {% endfor %}
>
>
> NB : not tested...
>
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Re: Help for for loop
Thanx for help. I solved the problem using divisibleby -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: Help for for loop
On 9 déc, 12:24, Tom Evans wrote:
> Hmm, those are the values that are odd, he wanted the values from odd
> indices
Well spotted ;)
There's a builtin "slice" filter that should have done the trick but I
just couldn't manage to make it work with a for loop :-/
The only solution I could come with that does not require custom
filters or whatever is using the cycle tag (http://
docs.djangoproject.com/en/1.2/ref/templates/builtins/#cycle):
{% for item in list %}
{% cycle "even", "odd" as oddeven %} {# assuming standard 0-based
indexing #}
{% if oddeven == "odd" %}
item {{ item }} is at odd index {{ forloop.counter }}
{% endif %}
{% endfor %}
NB : not tested...
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Re: Help for for loop
Because that looks at the values of the array and returns the items
which have a value that is divisible by two, not the position of the
value within the array. It is simpler to comprehend if you don't put
numbers in the list:
>>> l = [ 'pos 0', 'pos 1', 'pos 2', 'pos 3' ]
>>> filter(lambda x: not x%2, l)
Traceback (most recent call last):
File "", line 1, in
File "", line 1, in
TypeError: not all arguments converted during string formatting
>>> [ val for val, i in itertools.izip(l, itertools.count()) if i % 2 ]
['pos 1', 'pos 3']
What the OP originally asked for was for items in the i'th position in
a list, where i is odd. Your solutions all ignore the position, and
only look at the value.
On Thu, Dec 9, 2010 at 11:27 AM, Cal Leeming [Simplicity Media Ltd]
wrote:
> I see no need to get itertools involved ;) Why not just use this:
>
> filter(lambda x: not x%2, a)
>
>
> On 09/12/2010 11:24, Tom Evans wrote:
>>
>> Hmm, those are the values that are odd, he wanted the values from odd
>> indices, eg:
>>
> a=[2,3,4,5,6,7]
> filter(lambda x: x%2, a)
>>
>> [3, 5, 7]
>
> [ val for val, i in itertools.izip(a, itertools.count()) if not i % 2 ]
>>
>> [2, 4, 6]
>>
>> That could probably be written a bit nicer..
>>
>> On Thu, Dec 9, 2010 at 10:44 AM, Cal Leeming [Simplicity Media Ltd]
>> wrote:
>>
>> mylist = [1,2,3,4,5,6,7,8]
>> filter(lambda x: x%2, mylist)
>>>
>>> [1, 3, 5, 7]
>>> This what you need?
>>>
>>> On 09/12/2010 10:34, Phani Chand wrote:
i am passing though a list{1,2,3,4} but i want only the numbers with odd
index in template written in html --
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>>>
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>
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Re: Help for for loop
Can't you use the % operator within if statements in templates? I was almost sure I'd done this before :| On 09/12/2010 11:27, bruno desthuilliers wrote: On 9 déc, 12:18, Phani Chand wrote: Can i use filter(lambda x: x%2, mylist) directly in my html page s/html page/template/ And no, you cannot use Python code in a template. You can either 1/ filter the list in the view 2/ use the builtin "divisibleby" filter (http://docs.djangoproject.com/ en/1.2/ref/templates/builtins/#divisibleby) 3/ write your own "odds" and "evens" filters (http:// docs.djangoproject.com/en/1.2/howto/custom-template-tags/) HTH -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: Help for for loop
I see no need to get itertools involved ;) Why not just use this:
filter(lambda x: not x%2, a)
On 09/12/2010 11:24, Tom Evans wrote:
Hmm, those are the values that are odd, he wanted the values from odd
indices, eg:
a=[2,3,4,5,6,7]
filter(lambda x: x%2, a)
[3, 5, 7]
[ val for val, i in itertools.izip(a, itertools.count()) if not i % 2 ]
[2, 4, 6]
That could probably be written a bit nicer..
On Thu, Dec 9, 2010 at 10:44 AM, Cal Leeming [Simplicity Media Ltd]
wrote:
mylist = [1,2,3,4,5,6,7,8]
filter(lambda x: x%2, mylist)
[1, 3, 5, 7]
This what you need?
On 09/12/2010 10:34, Phani Chand wrote:
i am passing though a list{1,2,3,4} but i want only the numbers with odd
index in template written in html --
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Re: Help for for loop
On 9 déc, 12:18, Phani Chand wrote: > Can i use filter(lambda x: x%2, mylist) directly in my html page s/html page/template/ And no, you cannot use Python code in a template. You can either 1/ filter the list in the view 2/ use the builtin "divisibleby" filter (http://docs.djangoproject.com/ en/1.2/ref/templates/builtins/#divisibleby) 3/ write your own "odds" and "evens" filters (http:// docs.djangoproject.com/en/1.2/howto/custom-template-tags/) HTH -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: Help for for loop
Hmm, those are the values that are odd, he wanted the values from odd
indices, eg:
>>> a=[2,3,4,5,6,7]
>>> filter(lambda x: x%2, a)
[3, 5, 7]
>>> [ val for val, i in itertools.izip(a, itertools.count()) if not i % 2 ]
[2, 4, 6]
That could probably be written a bit nicer..
On Thu, Dec 9, 2010 at 10:44 AM, Cal Leeming [Simplicity Media Ltd]
wrote:
mylist = [1,2,3,4,5,6,7,8]
filter(lambda x: x%2, mylist)
> [1, 3, 5, 7]
>
> This what you need?
>
> On 09/12/2010 10:34, Phani Chand wrote:
>>
>> i am passing though a list{1,2,3,4} but i want only the numbers with odd
>> index in template written in html --
>> You received this message because you are subscribed to the Google Groups
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>
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>
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Re: Help for for loop
Uh, you *might* be able to use:
{% for x in mylist %}
{% if x % 2 %}
yay: {{x}}
{% else %}
nay: {{x}}
{% endif %}
{% endfor %}
On 09/12/2010 11:18, Phani Chand wrote:
Can i use filter(lambda x: x%2, mylist) directly in my html page --
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Re: Help for for loop
Can i use filter(lambda x: x%2, mylist) directly in my html page -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: Help for for loop
>>> mylist = [1,2,3,4,5,6,7,8]
>>> filter(lambda x: x%2, mylist)
[1, 3, 5, 7]
>>>
This what you need?
On 09/12/2010 10:34, Phani Chand wrote:
i am passing though a list{1,2,3,4} but i want only the numbers with
odd index in template written in html --
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