Re: numeric formatting
Quick and nasty:
from django.core import template
register = template.Library()
@register.filter(name='commas')
def commas(value):
return "".join(commafy(value))
def commafy(s):
pieces = s.split(".")
l = len(pieces[0])
for i in range(0,l):
if (l - i) % 3 or not i:
yield pieces[0][i]
else:
yield ","
yield pieces[0][i]
if len(pieces) > 1:
yield "." + pieces[1]
value should be a string (eg your preformatted number).
obviously does not care about your locale.
jtm
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Re: numeric formatting
On Friday 24 March 2006 12:23, Jacob Kaplan-Moss wrote:
> > I don't think that python built-in formatting can do this. (Am I
> > wrong?)
>
> Actually, locale.format will do it for you, IIRC.
>>> import locale
>>> locale.setlocale(locale.LC_ALL, '')
'en_US.UTF-8'
>>> locale.format("%d", 1234567, True)
'1,234,567'
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Re: numeric formatting
On Mar 24, 2006, at 1:48 PM, Rock wrote: > Is there a template filter for turning a large integer into a human > readable number? > > 1234567 --> 1,234,567 > 12345 --> 12,345 > > I don't think that python built-in formatting can do this. (Am I > wrong?) Actually, locale.format will do it for you, IIRC. But there's not a Django filter for it (probably should be, though...) > Assuming there isn't already a simple filter that will do this, > what do > I need to learn about in order to create my own filter? You want the template language for Python programmers doc, and specificaly the part about writing filters: http:// www.djangoproject.com/documentation/templates_python/#writing-custom- template-filters Jacob --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users -~--~~~~--~~--~--~---
