Re: how to activate DJANGO.CORE.CONTEXT_PROCESSORS.REQUEST
Thanks a lot, i did miss to pass
context_instance=RequestContext(request) in
my view code
def access(request):
return
render_to_response('tool.html',context_instance=RequestContext(request))
after I added "context_instance=RequestContext(request)"
It is working now like a charm!
Thanks again!
On Feb 4, 11:54 am, Karen Tracey wrote:
> On Thu, Feb 4, 2010 at 2:39 PM, weiwei wrote:
> > Thanks..
>
> > Here is my code
>
> You repeated the code for the template tag and the context processors
> setting; that's not what I asked for.
>
> I still don't see the code for the view that renders the template that
> includes the template tag you are working with. That is the code that must
> specify a RequestContext if you want to access the variables set by the
> request context processor in your template tag. The context processor won't
> set variables in a plain Context, the view code (or whatever code is
> supplying the context for the template render) must specify a
> RequestContext. See for example 'some_view' under:
>
> http://docs.djangoproject.com/en/dev/ref/templates/api/#id1
>
> Karen
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Re: how to activate DJANGO.CORE.CONTEXT_PROCESSORS.REQUEST
On Thu, Feb 4, 2010 at 2:39 PM, weiwei wrote: > Thanks.. > > Here is my code > > You repeated the code for the template tag and the context processors setting; that's not what I asked for. I still don't see the code for the view that renders the template that includes the template tag you are working with. That is the code that must specify a RequestContext if you want to access the variables set by the request context processor in your template tag. The context processor won't set variables in a plain Context, the view code (or whatever code is supplying the context for the template render) must specify a RequestContext. See for example 'some_view' under: http://docs.djangoproject.com/en/dev/ref/templates/api/#id1 Karen -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: how to activate DJANGO.CORE.CONTEXT_PROCESSORS.REQUEST
Thanks..
Here is my code
from django import template
from django.template import RequestContext
register = template.Library()
@register.inclusion_tag('userinfo.html',takes_context = True)
def userinfo(context):
request = context['request']
address = request.session['address']
return {'address':address}
and request = context['request'] causing problem, seems context
doesn't have a key 'request'
And i do have
TEMPLATE_CONTEXT_PROCESSORS =(
"django.core.context_processors.request",
"django.core.context_processors.auth",
"django.core.context_processors.debug",
"django.core.context_processors.i18n",
"django.core.context_processors.media",
)
in settings.py
On Feb 4, 11:17 am, Karen Tracey wrote:
> On Thu, Feb 4, 2010 at 1:41 PM, weiwei wrote:
> > "DJANGO.CORE.CONTEXT_PROCESSORS.REQUEST
> > If TEMPLATE_CONTEXT_PROCESSORS contains this processor, every
> > RequestContext will contain a variable request, which is the current
> > HttpRequest. Note that this processor is not enabled by default;
> > you'll have to activate it. " from this page
>
> >http://docs.djangoproject.com/en/dev/ref/templates/api/
>
> > But i didn't find how to activate it
>
> You activate it by including it in TEMPLATE_CONTEXT_PROCESSORS in
> settings.py. That is all you have to do.
>
> > Here is my question
>
> >http://stackoverflow.com/questions/2160261/access-request-in-django-c...
>
> > after i followed the answer i still got errors
>
> I do not see where you show the view code in that question. Possibly you are
> not using a RequestContext to render the template?
>
> Karen
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Re: how to activate DJANGO.CORE.CONTEXT_PROCESSORS.REQUEST
On Thu, Feb 4, 2010 at 1:41 PM, weiwei wrote: > "DJANGO.CORE.CONTEXT_PROCESSORS.REQUEST > If TEMPLATE_CONTEXT_PROCESSORS contains this processor, every > RequestContext will contain a variable request, which is the current > HttpRequest. Note that this processor is not enabled by default; > you'll have to activate it. " from this page > > http://docs.djangoproject.com/en/dev/ref/templates/api/ > > But i didn't find how to activate it > > You activate it by including it in TEMPLATE_CONTEXT_PROCESSORS in settings.py. That is all you have to do. > Here is my question > > > http://stackoverflow.com/questions/2160261/access-request-in-django-custom-template-tags > > after i followed the answer i still got errors > > I do not see where you show the view code in that question. Possibly you are not using a RequestContext to render the template? Karen -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
how to activate DJANGO.CORE.CONTEXT_PROCESSORS.REQUEST
"DJANGO.CORE.CONTEXT_PROCESSORS.REQUEST If TEMPLATE_CONTEXT_PROCESSORS contains this processor, every RequestContext will contain a variable request, which is the current HttpRequest. Note that this processor is not enabled by default; you'll have to activate it. " from this page http://docs.djangoproject.com/en/dev/ref/templates/api/ But i didn't find how to activate it Here is my question http://stackoverflow.com/questions/2160261/access-request-in-django-custom-template-tags after i followed the answer i still got errors TemplateSyntaxError at / Caught an exception while rendering: 'request' Original Traceback (most recent call last): File "C: \Python25\lib\site-packages\django\template\debug.py", line 71, in render_node result = node.render(context) File "C:\Python25\lib\site- packages\django\template__init__.py", line 936, in render dict = func(*args) File "c:\...\myapp_extras.py", line 7, in login request = context['request'] File "C:\Python25\lib\site-packages\django\template \context.py", line 44, in getitem raise KeyError(key) KeyError: 'request' tho code causing problem is request = context['request'] Thanks for any help! -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
