Re: how to get count of each distinct value
Thank you.
--
22 Kasım 2013 Cuma 18:07:47 UTC+2 tarihinde larry@gmail.com yazdı:
>
> On Fri, Nov 22, 2013 at 10:44 AM, Fatih Tiryakioglu
>
> > wrote:
>
>> Hi all,
>>
>> How can I get distribution of values in a field? For example, I have the
>> scores below:
>>
>> (score)
>> (raw1)1
>> (raw2)1
>> (raw3)3
>> (raw4)4
>> (raw5)4
>> (raw6)5
>> (raw7)8
>> (raw8)8
>> (raw9)9
>> (raw10)10
>>
>> I want to have a result like that: {1: 2}, {3: 1}, {4: 2}, {5: 1}, {8:
>> 2}, {9: 1}, {10: 1}. So it is {score: count}.
>>
>> How can I evaluate this only one db hit?
>>
>> Thanks all.
>>
>
> In SQL:
>
> SELECT score, COUNT(*) FROM foo GROUP BY score;
>
> In Django:
>
> from django.db.models import Count
> q = Foo.objects.values('score').annotate(Count('score'))
> for r in q:
> print r, r.score__count
>
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Re: how to get count of each distinct value
On Fri, Nov 22, 2013 at 10:44 AM, Fatih Tiryakioglu wrote:
> Hi all,
>
> How can I get distribution of values in a field? For example, I have the
> scores below:
>
> (score)
> (raw1)1
> (raw2)1
> (raw3)3
> (raw4)4
> (raw5)4
> (raw6)5
> (raw7)8
> (raw8)8
> (raw9)9
> (raw10)10
>
> I want to have a result like that: {1: 2}, {3: 1}, {4: 2}, {5: 1}, {8: 2},
> {9: 1}, {10: 1}. So it is {score: count}.
>
> How can I evaluate this only one db hit?
>
> Thanks all.
>
In SQL:
SELECT score, COUNT(*) FROM foo GROUP BY score;
In Django:
from django.db.models import Count
q = Foo.objects.values('score').annotate(Count('score'))
for r in q:
print r, r.score__count
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how to get count of each distinct value
Hi all,
How can I get distribution of values in a field? For example, I have the
scores below:
(score)
(raw1)1
(raw2)1
(raw3)3
(raw4)4
(raw5)4
(raw6)5
(raw7)8
(raw8)8
(raw9)9
(raw10)10
I want to have a result like that: {1: 2}, {3: 1}, {4: 2}, {5: 1}, {8: 2},
{9: 1}, {10: 1}. So it is {score: count}.
How can I evaluate this only one db hit?
Thanks all.
--
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